Evaluating a surface integral in $mathbb{R}^{n}$
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If $x=(x_{1},...,x_{n})$ is in $mathbb{R}^{n}$ ($ngeq2$), and $alpha=(alpha_{1},...,alpha_{n})$ is a multi index, we write $x^{alpha}=x_{1}^{alpha_{1}}...x_{n}^{alpha_{n}}$. How would you calculate the surface integral of $x^{alpha}$ over the circle of radius $r>0$, i.e.
$$int_{|x|=r}x^{alpha}dsigma?$$
real-analysis integration
asked Nov 16 at 5:03
M. Rahmat
289211
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If $x=(x_{1},...,x_{n})$ is in $mathbb{R}^{n}$ ($ngeq2$), and $alpha=(alpha_{1},...,alpha_{n})$ is a multi index, we write $x^{alpha}=x_{1}^{alpha_{1}}...x_{n}^{alpha_{n}}$. How would you calculate the surface integral of $x^{alpha}$ over the circle of radius $r>0$, i.e.
$$int_{|x|=r}x^{alpha}dsigma?$$
real-analysis integration
asked Nov 16 at 5:03
M. Rahmat
289211
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
If $x=(x_{1},...,x_{n})$ is in $mathbb{R}^{n}$ ($ngeq2$), and $alpha=(alpha_{1},...,alpha_{n})$ is a multi index, we write $x^{alpha}=x_{1}^{alpha_{1}}...x_{n}^{alpha_{n}}$. How would you calculate the surface integral of $x^{alpha}$ over the circle of radius $r>0$, i.e.
$$int_{|x|=r}x^{alpha}dsigma?$$
real-analysis integration
asked Nov 16 at 5:03
M. Rahmat
289211
If $x=(x_{1},...,x_{n})$ is in $mathbb{R}^{n}$ ($ngeq2$), and $alpha=(alpha_{1},...,alpha_{n})$ is a multi index, we write $x^{alpha}=x_{1}^{alpha_{1}}...x_{n}^{alpha_{n}}$. How would you calculate the surface integral of $x^{alpha}$ over the circle of radius $r>0$, i.e.
$$int_{|x|=r}x^{alpha}dsigma?$$
real-analysis integration
real-analysis integration
asked Nov 16 at 5:03
M. Rahmat
289211
asked Nov 16 at 5:03
M. Rahmat
289211
asked Nov 16 at 5:03
M. Rahmat
289211
asked Nov 16 at 5:03
M. Rahmat
289211
asked Nov 16 at 5:03
M. Rahmat
289211
289211
add a comment |
add a comment |
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