Why isn’t ‘because’ a logical connective in propositional logic?
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28
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In simple terms, could someone explain why there is not a logical connective for ‘because’ in propositional logic like there is for ‘and’ and ‘or’?
Is this because the equivalent of ‘because’ is the argument of the form ‘if p, then q’, or am I missing something?
Please illustrate your answer with example(s) if possible.
logic propositional-calculus
add a comment |
up vote
28
down vote
favorite
In simple terms, could someone explain why there is not a logical connective for ‘because’ in propositional logic like there is for ‘and’ and ‘or’?
Is this because the equivalent of ‘because’ is the argument of the form ‘if p, then q’, or am I missing something?
Please illustrate your answer with example(s) if possible.
logic propositional-calculus
13
"because" is about causality, not implication
– Hagen von Eitzen
yesterday
Folks might find basicbooks.com/titles/judea-pearl/the-book-of-why/9780465097609 of interest.
– Barry Cipra
yesterday
1
I would love to see a complete prepositional logic theory where P→Q is not equivalent to ¬P∨Q but I haven't yet. :(
– Joshua
17 hours ago
@Joshua Maybe I'm misunderstanding what you mean, but that equivalence typically fails in non-classical logics. It definitely fails in constructive/intuitionistic logic. So Intuitionistic Propositional Logic would be a propositional logic where $Pto Q$ is not equivalent to $neg Plor Q$.
– Derek Elkins
6 hours ago
$(Pto Q) lor (Qto P)$ is a tautology in classical logic, so presumably $(Qleftarrow P) lor (Pleftarrow Q)$ is too. You would not want to read "$leftarrow$" as because here
– Henry
4 hours ago
add a comment |
up vote
28
down vote
favorite
up vote
28
down vote
favorite
In simple terms, could someone explain why there is not a logical connective for ‘because’ in propositional logic like there is for ‘and’ and ‘or’?
Is this because the equivalent of ‘because’ is the argument of the form ‘if p, then q’, or am I missing something?
Please illustrate your answer with example(s) if possible.
logic propositional-calculus
In simple terms, could someone explain why there is not a logical connective for ‘because’ in propositional logic like there is for ‘and’ and ‘or’?
Is this because the equivalent of ‘because’ is the argument of the form ‘if p, then q’, or am I missing something?
Please illustrate your answer with example(s) if possible.
logic propositional-calculus
logic propositional-calculus
asked yesterday
seeker
2,65855184
2,65855184
13
"because" is about causality, not implication
– Hagen von Eitzen
yesterday
Folks might find basicbooks.com/titles/judea-pearl/the-book-of-why/9780465097609 of interest.
– Barry Cipra
yesterday
1
I would love to see a complete prepositional logic theory where P→Q is not equivalent to ¬P∨Q but I haven't yet. :(
– Joshua
17 hours ago
@Joshua Maybe I'm misunderstanding what you mean, but that equivalence typically fails in non-classical logics. It definitely fails in constructive/intuitionistic logic. So Intuitionistic Propositional Logic would be a propositional logic where $Pto Q$ is not equivalent to $neg Plor Q$.
– Derek Elkins
6 hours ago
$(Pto Q) lor (Qto P)$ is a tautology in classical logic, so presumably $(Qleftarrow P) lor (Pleftarrow Q)$ is too. You would not want to read "$leftarrow$" as because here
– Henry
4 hours ago
add a comment |
13
"because" is about causality, not implication
– Hagen von Eitzen
yesterday
Folks might find basicbooks.com/titles/judea-pearl/the-book-of-why/9780465097609 of interest.
– Barry Cipra
yesterday
1
I would love to see a complete prepositional logic theory where P→Q is not equivalent to ¬P∨Q but I haven't yet. :(
– Joshua
17 hours ago
@Joshua Maybe I'm misunderstanding what you mean, but that equivalence typically fails in non-classical logics. It definitely fails in constructive/intuitionistic logic. So Intuitionistic Propositional Logic would be a propositional logic where $Pto Q$ is not equivalent to $neg Plor Q$.
– Derek Elkins
6 hours ago
$(Pto Q) lor (Qto P)$ is a tautology in classical logic, so presumably $(Qleftarrow P) lor (Pleftarrow Q)$ is too. You would not want to read "$leftarrow$" as because here
– Henry
4 hours ago
13
13
"because" is about causality, not implication
– Hagen von Eitzen
yesterday
"because" is about causality, not implication
– Hagen von Eitzen
yesterday
Folks might find basicbooks.com/titles/judea-pearl/the-book-of-why/9780465097609 of interest.
– Barry Cipra
yesterday
Folks might find basicbooks.com/titles/judea-pearl/the-book-of-why/9780465097609 of interest.
– Barry Cipra
yesterday
1
1
I would love to see a complete prepositional logic theory where P→Q is not equivalent to ¬P∨Q but I haven't yet. :(
– Joshua
17 hours ago
I would love to see a complete prepositional logic theory where P→Q is not equivalent to ¬P∨Q but I haven't yet. :(
– Joshua
17 hours ago
@Joshua Maybe I'm misunderstanding what you mean, but that equivalence typically fails in non-classical logics. It definitely fails in constructive/intuitionistic logic. So Intuitionistic Propositional Logic would be a propositional logic where $Pto Q$ is not equivalent to $neg Plor Q$.
– Derek Elkins
6 hours ago
@Joshua Maybe I'm misunderstanding what you mean, but that equivalence typically fails in non-classical logics. It definitely fails in constructive/intuitionistic logic. So Intuitionistic Propositional Logic would be a propositional logic where $Pto Q$ is not equivalent to $neg Plor Q$.
– Derek Elkins
6 hours ago
$(Pto Q) lor (Qto P)$ is a tautology in classical logic, so presumably $(Qleftarrow P) lor (Pleftarrow Q)$ is too. You would not want to read "$leftarrow$" as because here
– Henry
4 hours ago
$(Pto Q) lor (Qto P)$ is a tautology in classical logic, so presumably $(Qleftarrow P) lor (Pleftarrow Q)$ is too. You would not want to read "$leftarrow$" as because here
– Henry
4 hours ago
add a comment |
4 Answers
4
active
oldest
votes
up vote
86
down vote
accepted
It is because 'because' is not truth-functional.
That is, knowing the truth-values of $P$ and $Q$ does not tell you the truth-value of '$P$ because of $Q$'
For example, the two statements 'Grass is green' and 'Snow is white' are both true, but 'Grass is green because snow is white' is an invalid argument, and hence, as a statement as to the validity of that argument, a false statement.
On the other hand,'Grass is green because grass is green' is a true statement as to the validity of this as an argument, but yet again it involves two true statements.
This shows that with $P$ and $Q$ both being true, the statement '$P$ because of $Q$' can either be true or false, and hence it is not truth-functional.
10
This is an exceedingly better answer than I expected possible. Kudos!
– Daniel R. Collins
yesterday
1
@DanielR.Collins Thanks! :)
– Bram28
yesterday
3
Wouldn't this reaoning also apply to if statements? "If snow is white, then grass is green" happens to be true, despite not making much sense in common English.
– Vaelus
yesterday
3
@Vaelus If I've understood the answer correctly, the point is that the truth of "if P then Q" is uniquely determined by the truth values of P and Q, whereas the truth of "P because Q" is not determined by the truth values of P and Q. That is, there are cases where "[true statement] because [true statement]" is true, and also cases where "[true statement] because [true statement]" is false, which is not the case for logical if statements.
– David Z
yesterday
5
@Vaelus Yes, the English 'if ... then ...' does not seem to be teuth-functional either .... so why do logicians define a truth-functional operator (called the material implication) to try and capture it? There is a long standing debate about this. Please look up 'Paradox of Material Implication' if you want to know more.
– Bram28
yesterday
|
show 5 more comments
up vote
11
down vote
Why isn’t ‘because’ a logical connective in propositional logic?
Is this because the equivalent of ‘because’ is the argument of the form ‘if $p$, then $q$’ ?
Exactly.
Either the connective "because" is truth-functional, in which case it is the same as "if..., then...", or it is not truth-functional, in which case we need a different way of modelling it.
See e.g. Counterfactual Theories of Causation.
See also Arthur Burks, The Logic of Causal Proposition, Mind (1951).
I would have thought a truth-functional because might be considered the reverse of if..., then... rather than the same
– Henry
4 hours ago
@Henry - reverse ?
– Mauro ALLEGRANZA
3 hours ago
1
What does the first word (exactly) refer to?
– Carsten S
2 hours ago
add a comment |
up vote
4
down vote
I agree with the other answers, however I want to add that the closest thing might be the turnstyle symbol $vdash$, although this is usually read as "yields", and thus points the other way. If I write
$$A vdash B$$
this is read as "A yields B", or "knowing A, I can prove B". If you wanted to encode because, you could probably read it backwards as "B because of A".
Note however that this is not used as part of a logical formula, but as a shorthand between formulas when writing down a proof. So $A vdash B$ is no longer a formula, but rather a statement on how to prove $B$. (In most of the rest of mathematics, you would write $Rightarrow$ in your proof instead, however in logic this is of course easily confused with the implication inside formulas)
1
Yes, this would therefore be a 'meta-logical' symbol;: a symbol used to say something about logic exprssion .. but it is not a logical connective or operator.
– Bram28
yesterday
add a comment |
up vote
0
down vote
You can define things however you want. (Be careful; you may accidentally be inconsistent.)
Either:
- "because" is logically equivalent to a binary operator
- or it's not
If it is, it's probably the same as "only if" (Or take your pick of the other 15 operators). Adding a "because" overload would create an additional word to remember: unneeded complexity. We like simplicity.
If it isn't, you can define a binary function because(a, b)
however you want.
add a comment |
4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
86
down vote
accepted
It is because 'because' is not truth-functional.
That is, knowing the truth-values of $P$ and $Q$ does not tell you the truth-value of '$P$ because of $Q$'
For example, the two statements 'Grass is green' and 'Snow is white' are both true, but 'Grass is green because snow is white' is an invalid argument, and hence, as a statement as to the validity of that argument, a false statement.
On the other hand,'Grass is green because grass is green' is a true statement as to the validity of this as an argument, but yet again it involves two true statements.
This shows that with $P$ and $Q$ both being true, the statement '$P$ because of $Q$' can either be true or false, and hence it is not truth-functional.
10
This is an exceedingly better answer than I expected possible. Kudos!
– Daniel R. Collins
yesterday
1
@DanielR.Collins Thanks! :)
– Bram28
yesterday
3
Wouldn't this reaoning also apply to if statements? "If snow is white, then grass is green" happens to be true, despite not making much sense in common English.
– Vaelus
yesterday
3
@Vaelus If I've understood the answer correctly, the point is that the truth of "if P then Q" is uniquely determined by the truth values of P and Q, whereas the truth of "P because Q" is not determined by the truth values of P and Q. That is, there are cases where "[true statement] because [true statement]" is true, and also cases where "[true statement] because [true statement]" is false, which is not the case for logical if statements.
– David Z
yesterday
5
@Vaelus Yes, the English 'if ... then ...' does not seem to be teuth-functional either .... so why do logicians define a truth-functional operator (called the material implication) to try and capture it? There is a long standing debate about this. Please look up 'Paradox of Material Implication' if you want to know more.
– Bram28
yesterday
|
show 5 more comments
up vote
86
down vote
accepted
It is because 'because' is not truth-functional.
That is, knowing the truth-values of $P$ and $Q$ does not tell you the truth-value of '$P$ because of $Q$'
For example, the two statements 'Grass is green' and 'Snow is white' are both true, but 'Grass is green because snow is white' is an invalid argument, and hence, as a statement as to the validity of that argument, a false statement.
On the other hand,'Grass is green because grass is green' is a true statement as to the validity of this as an argument, but yet again it involves two true statements.
This shows that with $P$ and $Q$ both being true, the statement '$P$ because of $Q$' can either be true or false, and hence it is not truth-functional.
10
This is an exceedingly better answer than I expected possible. Kudos!
– Daniel R. Collins
yesterday
1
@DanielR.Collins Thanks! :)
– Bram28
yesterday
3
Wouldn't this reaoning also apply to if statements? "If snow is white, then grass is green" happens to be true, despite not making much sense in common English.
– Vaelus
yesterday
3
@Vaelus If I've understood the answer correctly, the point is that the truth of "if P then Q" is uniquely determined by the truth values of P and Q, whereas the truth of "P because Q" is not determined by the truth values of P and Q. That is, there are cases where "[true statement] because [true statement]" is true, and also cases where "[true statement] because [true statement]" is false, which is not the case for logical if statements.
– David Z
yesterday
5
@Vaelus Yes, the English 'if ... then ...' does not seem to be teuth-functional either .... so why do logicians define a truth-functional operator (called the material implication) to try and capture it? There is a long standing debate about this. Please look up 'Paradox of Material Implication' if you want to know more.
– Bram28
yesterday
|
show 5 more comments
up vote
86
down vote
accepted
up vote
86
down vote
accepted
It is because 'because' is not truth-functional.
That is, knowing the truth-values of $P$ and $Q$ does not tell you the truth-value of '$P$ because of $Q$'
For example, the two statements 'Grass is green' and 'Snow is white' are both true, but 'Grass is green because snow is white' is an invalid argument, and hence, as a statement as to the validity of that argument, a false statement.
On the other hand,'Grass is green because grass is green' is a true statement as to the validity of this as an argument, but yet again it involves two true statements.
This shows that with $P$ and $Q$ both being true, the statement '$P$ because of $Q$' can either be true or false, and hence it is not truth-functional.
It is because 'because' is not truth-functional.
That is, knowing the truth-values of $P$ and $Q$ does not tell you the truth-value of '$P$ because of $Q$'
For example, the two statements 'Grass is green' and 'Snow is white' are both true, but 'Grass is green because snow is white' is an invalid argument, and hence, as a statement as to the validity of that argument, a false statement.
On the other hand,'Grass is green because grass is green' is a true statement as to the validity of this as an argument, but yet again it involves two true statements.
This shows that with $P$ and $Q$ both being true, the statement '$P$ because of $Q$' can either be true or false, and hence it is not truth-functional.
answered yesterday
Bram28
57.6k34185
57.6k34185
10
This is an exceedingly better answer than I expected possible. Kudos!
– Daniel R. Collins
yesterday
1
@DanielR.Collins Thanks! :)
– Bram28
yesterday
3
Wouldn't this reaoning also apply to if statements? "If snow is white, then grass is green" happens to be true, despite not making much sense in common English.
– Vaelus
yesterday
3
@Vaelus If I've understood the answer correctly, the point is that the truth of "if P then Q" is uniquely determined by the truth values of P and Q, whereas the truth of "P because Q" is not determined by the truth values of P and Q. That is, there are cases where "[true statement] because [true statement]" is true, and also cases where "[true statement] because [true statement]" is false, which is not the case for logical if statements.
– David Z
yesterday
5
@Vaelus Yes, the English 'if ... then ...' does not seem to be teuth-functional either .... so why do logicians define a truth-functional operator (called the material implication) to try and capture it? There is a long standing debate about this. Please look up 'Paradox of Material Implication' if you want to know more.
– Bram28
yesterday
|
show 5 more comments
10
This is an exceedingly better answer than I expected possible. Kudos!
– Daniel R. Collins
yesterday
1
@DanielR.Collins Thanks! :)
– Bram28
yesterday
3
Wouldn't this reaoning also apply to if statements? "If snow is white, then grass is green" happens to be true, despite not making much sense in common English.
– Vaelus
yesterday
3
@Vaelus If I've understood the answer correctly, the point is that the truth of "if P then Q" is uniquely determined by the truth values of P and Q, whereas the truth of "P because Q" is not determined by the truth values of P and Q. That is, there are cases where "[true statement] because [true statement]" is true, and also cases where "[true statement] because [true statement]" is false, which is not the case for logical if statements.
– David Z
yesterday
5
@Vaelus Yes, the English 'if ... then ...' does not seem to be teuth-functional either .... so why do logicians define a truth-functional operator (called the material implication) to try and capture it? There is a long standing debate about this. Please look up 'Paradox of Material Implication' if you want to know more.
– Bram28
yesterday
10
10
This is an exceedingly better answer than I expected possible. Kudos!
– Daniel R. Collins
yesterday
This is an exceedingly better answer than I expected possible. Kudos!
– Daniel R. Collins
yesterday
1
1
@DanielR.Collins Thanks! :)
– Bram28
yesterday
@DanielR.Collins Thanks! :)
– Bram28
yesterday
3
3
Wouldn't this reaoning also apply to if statements? "If snow is white, then grass is green" happens to be true, despite not making much sense in common English.
– Vaelus
yesterday
Wouldn't this reaoning also apply to if statements? "If snow is white, then grass is green" happens to be true, despite not making much sense in common English.
– Vaelus
yesterday
3
3
@Vaelus If I've understood the answer correctly, the point is that the truth of "if P then Q" is uniquely determined by the truth values of P and Q, whereas the truth of "P because Q" is not determined by the truth values of P and Q. That is, there are cases where "[true statement] because [true statement]" is true, and also cases where "[true statement] because [true statement]" is false, which is not the case for logical if statements.
– David Z
yesterday
@Vaelus If I've understood the answer correctly, the point is that the truth of "if P then Q" is uniquely determined by the truth values of P and Q, whereas the truth of "P because Q" is not determined by the truth values of P and Q. That is, there are cases where "[true statement] because [true statement]" is true, and also cases where "[true statement] because [true statement]" is false, which is not the case for logical if statements.
– David Z
yesterday
5
5
@Vaelus Yes, the English 'if ... then ...' does not seem to be teuth-functional either .... so why do logicians define a truth-functional operator (called the material implication) to try and capture it? There is a long standing debate about this. Please look up 'Paradox of Material Implication' if you want to know more.
– Bram28
yesterday
@Vaelus Yes, the English 'if ... then ...' does not seem to be teuth-functional either .... so why do logicians define a truth-functional operator (called the material implication) to try and capture it? There is a long standing debate about this. Please look up 'Paradox of Material Implication' if you want to know more.
– Bram28
yesterday
|
show 5 more comments
up vote
11
down vote
Why isn’t ‘because’ a logical connective in propositional logic?
Is this because the equivalent of ‘because’ is the argument of the form ‘if $p$, then $q$’ ?
Exactly.
Either the connective "because" is truth-functional, in which case it is the same as "if..., then...", or it is not truth-functional, in which case we need a different way of modelling it.
See e.g. Counterfactual Theories of Causation.
See also Arthur Burks, The Logic of Causal Proposition, Mind (1951).
I would have thought a truth-functional because might be considered the reverse of if..., then... rather than the same
– Henry
4 hours ago
@Henry - reverse ?
– Mauro ALLEGRANZA
3 hours ago
1
What does the first word (exactly) refer to?
– Carsten S
2 hours ago
add a comment |
up vote
11
down vote
Why isn’t ‘because’ a logical connective in propositional logic?
Is this because the equivalent of ‘because’ is the argument of the form ‘if $p$, then $q$’ ?
Exactly.
Either the connective "because" is truth-functional, in which case it is the same as "if..., then...", or it is not truth-functional, in which case we need a different way of modelling it.
See e.g. Counterfactual Theories of Causation.
See also Arthur Burks, The Logic of Causal Proposition, Mind (1951).
I would have thought a truth-functional because might be considered the reverse of if..., then... rather than the same
– Henry
4 hours ago
@Henry - reverse ?
– Mauro ALLEGRANZA
3 hours ago
1
What does the first word (exactly) refer to?
– Carsten S
2 hours ago
add a comment |
up vote
11
down vote
up vote
11
down vote
Why isn’t ‘because’ a logical connective in propositional logic?
Is this because the equivalent of ‘because’ is the argument of the form ‘if $p$, then $q$’ ?
Exactly.
Either the connective "because" is truth-functional, in which case it is the same as "if..., then...", or it is not truth-functional, in which case we need a different way of modelling it.
See e.g. Counterfactual Theories of Causation.
See also Arthur Burks, The Logic of Causal Proposition, Mind (1951).
Why isn’t ‘because’ a logical connective in propositional logic?
Is this because the equivalent of ‘because’ is the argument of the form ‘if $p$, then $q$’ ?
Exactly.
Either the connective "because" is truth-functional, in which case it is the same as "if..., then...", or it is not truth-functional, in which case we need a different way of modelling it.
See e.g. Counterfactual Theories of Causation.
See also Arthur Burks, The Logic of Causal Proposition, Mind (1951).
edited 2 hours ago
answered yesterday
Mauro ALLEGRANZA
63.2k448110
63.2k448110
I would have thought a truth-functional because might be considered the reverse of if..., then... rather than the same
– Henry
4 hours ago
@Henry - reverse ?
– Mauro ALLEGRANZA
3 hours ago
1
What does the first word (exactly) refer to?
– Carsten S
2 hours ago
add a comment |
I would have thought a truth-functional because might be considered the reverse of if..., then... rather than the same
– Henry
4 hours ago
@Henry - reverse ?
– Mauro ALLEGRANZA
3 hours ago
1
What does the first word (exactly) refer to?
– Carsten S
2 hours ago
I would have thought a truth-functional because might be considered the reverse of if..., then... rather than the same
– Henry
4 hours ago
I would have thought a truth-functional because might be considered the reverse of if..., then... rather than the same
– Henry
4 hours ago
@Henry - reverse ?
– Mauro ALLEGRANZA
3 hours ago
@Henry - reverse ?
– Mauro ALLEGRANZA
3 hours ago
1
1
What does the first word (exactly) refer to?
– Carsten S
2 hours ago
What does the first word (exactly) refer to?
– Carsten S
2 hours ago
add a comment |
up vote
4
down vote
I agree with the other answers, however I want to add that the closest thing might be the turnstyle symbol $vdash$, although this is usually read as "yields", and thus points the other way. If I write
$$A vdash B$$
this is read as "A yields B", or "knowing A, I can prove B". If you wanted to encode because, you could probably read it backwards as "B because of A".
Note however that this is not used as part of a logical formula, but as a shorthand between formulas when writing down a proof. So $A vdash B$ is no longer a formula, but rather a statement on how to prove $B$. (In most of the rest of mathematics, you would write $Rightarrow$ in your proof instead, however in logic this is of course easily confused with the implication inside formulas)
1
Yes, this would therefore be a 'meta-logical' symbol;: a symbol used to say something about logic exprssion .. but it is not a logical connective or operator.
– Bram28
yesterday
add a comment |
up vote
4
down vote
I agree with the other answers, however I want to add that the closest thing might be the turnstyle symbol $vdash$, although this is usually read as "yields", and thus points the other way. If I write
$$A vdash B$$
this is read as "A yields B", or "knowing A, I can prove B". If you wanted to encode because, you could probably read it backwards as "B because of A".
Note however that this is not used as part of a logical formula, but as a shorthand between formulas when writing down a proof. So $A vdash B$ is no longer a formula, but rather a statement on how to prove $B$. (In most of the rest of mathematics, you would write $Rightarrow$ in your proof instead, however in logic this is of course easily confused with the implication inside formulas)
1
Yes, this would therefore be a 'meta-logical' symbol;: a symbol used to say something about logic exprssion .. but it is not a logical connective or operator.
– Bram28
yesterday
add a comment |
up vote
4
down vote
up vote
4
down vote
I agree with the other answers, however I want to add that the closest thing might be the turnstyle symbol $vdash$, although this is usually read as "yields", and thus points the other way. If I write
$$A vdash B$$
this is read as "A yields B", or "knowing A, I can prove B". If you wanted to encode because, you could probably read it backwards as "B because of A".
Note however that this is not used as part of a logical formula, but as a shorthand between formulas when writing down a proof. So $A vdash B$ is no longer a formula, but rather a statement on how to prove $B$. (In most of the rest of mathematics, you would write $Rightarrow$ in your proof instead, however in logic this is of course easily confused with the implication inside formulas)
I agree with the other answers, however I want to add that the closest thing might be the turnstyle symbol $vdash$, although this is usually read as "yields", and thus points the other way. If I write
$$A vdash B$$
this is read as "A yields B", or "knowing A, I can prove B". If you wanted to encode because, you could probably read it backwards as "B because of A".
Note however that this is not used as part of a logical formula, but as a shorthand between formulas when writing down a proof. So $A vdash B$ is no longer a formula, but rather a statement on how to prove $B$. (In most of the rest of mathematics, you would write $Rightarrow$ in your proof instead, however in logic this is of course easily confused with the implication inside formulas)
answered yesterday
mlk
2,845915
2,845915
1
Yes, this would therefore be a 'meta-logical' symbol;: a symbol used to say something about logic exprssion .. but it is not a logical connective or operator.
– Bram28
yesterday
add a comment |
1
Yes, this would therefore be a 'meta-logical' symbol;: a symbol used to say something about logic exprssion .. but it is not a logical connective or operator.
– Bram28
yesterday
1
1
Yes, this would therefore be a 'meta-logical' symbol;: a symbol used to say something about logic exprssion .. but it is not a logical connective or operator.
– Bram28
yesterday
Yes, this would therefore be a 'meta-logical' symbol;: a symbol used to say something about logic exprssion .. but it is not a logical connective or operator.
– Bram28
yesterday
add a comment |
up vote
0
down vote
You can define things however you want. (Be careful; you may accidentally be inconsistent.)
Either:
- "because" is logically equivalent to a binary operator
- or it's not
If it is, it's probably the same as "only if" (Or take your pick of the other 15 operators). Adding a "because" overload would create an additional word to remember: unneeded complexity. We like simplicity.
If it isn't, you can define a binary function because(a, b)
however you want.
add a comment |
up vote
0
down vote
You can define things however you want. (Be careful; you may accidentally be inconsistent.)
Either:
- "because" is logically equivalent to a binary operator
- or it's not
If it is, it's probably the same as "only if" (Or take your pick of the other 15 operators). Adding a "because" overload would create an additional word to remember: unneeded complexity. We like simplicity.
If it isn't, you can define a binary function because(a, b)
however you want.
add a comment |
up vote
0
down vote
up vote
0
down vote
You can define things however you want. (Be careful; you may accidentally be inconsistent.)
Either:
- "because" is logically equivalent to a binary operator
- or it's not
If it is, it's probably the same as "only if" (Or take your pick of the other 15 operators). Adding a "because" overload would create an additional word to remember: unneeded complexity. We like simplicity.
If it isn't, you can define a binary function because(a, b)
however you want.
You can define things however you want. (Be careful; you may accidentally be inconsistent.)
Either:
- "because" is logically equivalent to a binary operator
- or it's not
If it is, it's probably the same as "only if" (Or take your pick of the other 15 operators). Adding a "because" overload would create an additional word to remember: unneeded complexity. We like simplicity.
If it isn't, you can define a binary function because(a, b)
however you want.
answered 7 hours ago
Words Like Jared
1236
1236
add a comment |
add a comment |
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13
"because" is about causality, not implication
– Hagen von Eitzen
yesterday
Folks might find basicbooks.com/titles/judea-pearl/the-book-of-why/9780465097609 of interest.
– Barry Cipra
yesterday
1
I would love to see a complete prepositional logic theory where P→Q is not equivalent to ¬P∨Q but I haven't yet. :(
– Joshua
17 hours ago
@Joshua Maybe I'm misunderstanding what you mean, but that equivalence typically fails in non-classical logics. It definitely fails in constructive/intuitionistic logic. So Intuitionistic Propositional Logic would be a propositional logic where $Pto Q$ is not equivalent to $neg Plor Q$.
– Derek Elkins
6 hours ago
$(Pto Q) lor (Qto P)$ is a tautology in classical logic, so presumably $(Qleftarrow P) lor (Pleftarrow Q)$ is too. You would not want to read "$leftarrow$" as because here
– Henry
4 hours ago