How to understand the order of convergence $|x_{k+1} - x| le C |x_k - x|^p$ (Convergence of a power function...











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By definition, a sequence $x_k in mathbb{R}, k in mathbb{N}$
converges with order $p in [1,infty)$ to $x := lim_{ktoinfty}
x_k$
if begin{align} exists C in [0,infty): forall k in
mathbb{N}: |x_{k+1} - x| le C |x_k - x|^p end{align}




Assume $x_k$ is a sequence of approximations to $x$, then $|x_k - x|$ denotes the error of approximation at $k$-th iteration, and goes to zero as $k to infty$. I can understand the inequality $|x_{k+1} - x| le C |x_k - x|$ that implies the error must go smaller and smaller along the iterations. But I don't understand the motivation to put a power of $p$ on the previous step. Any practical meaning of taking $p$-th power of error $|x_k - x|^p$?










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    By definition, a sequence $x_k in mathbb{R}, k in mathbb{N}$
    converges with order $p in [1,infty)$ to $x := lim_{ktoinfty}
    x_k$
    if begin{align} exists C in [0,infty): forall k in
    mathbb{N}: |x_{k+1} - x| le C |x_k - x|^p end{align}




    Assume $x_k$ is a sequence of approximations to $x$, then $|x_k - x|$ denotes the error of approximation at $k$-th iteration, and goes to zero as $k to infty$. I can understand the inequality $|x_{k+1} - x| le C |x_k - x|$ that implies the error must go smaller and smaller along the iterations. But I don't understand the motivation to put a power of $p$ on the previous step. Any practical meaning of taking $p$-th power of error $|x_k - x|^p$?










    share|cite|improve this question
























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      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite












      By definition, a sequence $x_k in mathbb{R}, k in mathbb{N}$
      converges with order $p in [1,infty)$ to $x := lim_{ktoinfty}
      x_k$
      if begin{align} exists C in [0,infty): forall k in
      mathbb{N}: |x_{k+1} - x| le C |x_k - x|^p end{align}




      Assume $x_k$ is a sequence of approximations to $x$, then $|x_k - x|$ denotes the error of approximation at $k$-th iteration, and goes to zero as $k to infty$. I can understand the inequality $|x_{k+1} - x| le C |x_k - x|$ that implies the error must go smaller and smaller along the iterations. But I don't understand the motivation to put a power of $p$ on the previous step. Any practical meaning of taking $p$-th power of error $|x_k - x|^p$?










      share|cite|improve this question














      By definition, a sequence $x_k in mathbb{R}, k in mathbb{N}$
      converges with order $p in [1,infty)$ to $x := lim_{ktoinfty}
      x_k$
      if begin{align} exists C in [0,infty): forall k in
      mathbb{N}: |x_{k+1} - x| le C |x_k - x|^p end{align}




      Assume $x_k$ is a sequence of approximations to $x$, then $|x_k - x|$ denotes the error of approximation at $k$-th iteration, and goes to zero as $k to infty$. I can understand the inequality $|x_{k+1} - x| le C |x_k - x|$ that implies the error must go smaller and smaller along the iterations. But I don't understand the motivation to put a power of $p$ on the previous step. Any practical meaning of taking $p$-th power of error $|x_k - x|^p$?







      numerical-methods approximation numerical-linear-algebra numerical-calculus






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      asked 5 hours ago









      Analysis Newbie

      39617




      39617






















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          Consider a sequence of positive numbers $x_n$ such that $x_{n+1} = x_n^p$ with $p > 1$ and $x_0 < 1$. That's a special case, where $C = 1$.



          Now take the logarithm. You should then be able to find an explicit formula for $x_n$. As $p$ varies, how does the rate change at which $x_n$ converges to 0? For example, how many steps are needed to guarantee $x_n < varepsilon$ for a given $varepsilon$?



          By the way, the estimate $|x_{k+1} - x| le C |x_k - x|$ does not imply that the error goes to zero. This happens only if $C < 1$.






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            Consider a sequence of positive numbers $x_n$ such that $x_{n+1} = x_n^p$ with $p > 1$ and $x_0 < 1$. That's a special case, where $C = 1$.



            Now take the logarithm. You should then be able to find an explicit formula for $x_n$. As $p$ varies, how does the rate change at which $x_n$ converges to 0? For example, how many steps are needed to guarantee $x_n < varepsilon$ for a given $varepsilon$?



            By the way, the estimate $|x_{k+1} - x| le C |x_k - x|$ does not imply that the error goes to zero. This happens only if $C < 1$.






            share|cite|improve this answer

























              up vote
              0
              down vote













              Consider a sequence of positive numbers $x_n$ such that $x_{n+1} = x_n^p$ with $p > 1$ and $x_0 < 1$. That's a special case, where $C = 1$.



              Now take the logarithm. You should then be able to find an explicit formula for $x_n$. As $p$ varies, how does the rate change at which $x_n$ converges to 0? For example, how many steps are needed to guarantee $x_n < varepsilon$ for a given $varepsilon$?



              By the way, the estimate $|x_{k+1} - x| le C |x_k - x|$ does not imply that the error goes to zero. This happens only if $C < 1$.






              share|cite|improve this answer























                up vote
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                down vote










                up vote
                0
                down vote









                Consider a sequence of positive numbers $x_n$ such that $x_{n+1} = x_n^p$ with $p > 1$ and $x_0 < 1$. That's a special case, where $C = 1$.



                Now take the logarithm. You should then be able to find an explicit formula for $x_n$. As $p$ varies, how does the rate change at which $x_n$ converges to 0? For example, how many steps are needed to guarantee $x_n < varepsilon$ for a given $varepsilon$?



                By the way, the estimate $|x_{k+1} - x| le C |x_k - x|$ does not imply that the error goes to zero. This happens only if $C < 1$.






                share|cite|improve this answer












                Consider a sequence of positive numbers $x_n$ such that $x_{n+1} = x_n^p$ with $p > 1$ and $x_0 < 1$. That's a special case, where $C = 1$.



                Now take the logarithm. You should then be able to find an explicit formula for $x_n$. As $p$ varies, how does the rate change at which $x_n$ converges to 0? For example, how many steps are needed to guarantee $x_n < varepsilon$ for a given $varepsilon$?



                By the way, the estimate $|x_{k+1} - x| le C |x_k - x|$ does not imply that the error goes to zero. This happens only if $C < 1$.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered 4 hours ago









                Hans Engler

                9,90411836




                9,90411836






























                     

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