The space to valuation systems of Lukasiewicz logic is a dense set?
$begingroup$
Let $n$ be a integer number such that $n geq 2$, define the set $L_n = Big{ frac{i}{n-1} mid 0 leq i leq n-1 Big}$.
Now define the space to valuation systems of Lukasiewicz logic:
$L = displaystylebigcup_{i=2}^infty L_i$
My question is: "L is dense set"?
general-topology
edited Dec 30 '18 at 5:23
Andrés E. Caicedo
66.1k8160252
asked Dec 30 '18 at 2:59
ValdigleisValdigleis
62
$endgroup$
add a comment |
$begingroup$
Let $n$ be a integer number such that $n geq 2$, define the set $L_n = Big{ frac{i}{n-1} mid 0 leq i leq n-1 Big}$.
Now define the space to valuation systems of Lukasiewicz logic:
$L = displaystylebigcup_{i=2}^infty L_i$
My question is: "L is dense set"?
general-topology
edited Dec 30 '18 at 5:23
Andrés E. Caicedo
66.1k8160252
asked Dec 30 '18 at 2:59
ValdigleisValdigleis
62
$endgroup$
add a comment |
$begingroup$
Let $n$ be a integer number such that $n geq 2$, define the set $L_n = Big{ frac{i}{n-1} mid 0 leq i leq n-1 Big}$.
Now define the space to valuation systems of Lukasiewicz logic:
$L = displaystylebigcup_{i=2}^infty L_i$
My question is: "L is dense set"?
general-topology
edited Dec 30 '18 at 5:23
Andrés E. Caicedo
66.1k8160252
asked Dec 30 '18 at 2:59
ValdigleisValdigleis
62
$endgroup$
Let $n$ be a integer number such that $n geq 2$, define the set $L_n = Big{ frac{i}{n-1} mid 0 leq i leq n-1 Big}$.
Now define the space to valuation systems of Lukasiewicz logic:
$L = displaystylebigcup_{i=2}^infty L_i$
My question is: "L is dense set"?
general-topology
general-topology
edited Dec 30 '18 at 5:23
Andrés E. Caicedo
66.1k8160252
asked Dec 30 '18 at 2:59
ValdigleisValdigleis
62
edited Dec 30 '18 at 5:23
Andrés E. Caicedo
66.1k8160252
asked Dec 30 '18 at 2:59
ValdigleisValdigleis
62
edited Dec 30 '18 at 5:23
Andrés E. Caicedo
66.1k8160252
edited Dec 30 '18 at 5:23
Andrés E. Caicedo
66.1k8160252
edited Dec 30 '18 at 5:23
Andrés E. Caicedo
66.1k8160252
66.1k8160252
asked Dec 30 '18 at 2:59
ValdigleisValdigleis
62
asked Dec 30 '18 at 2:59
ValdigleisValdigleis
62
asked Dec 30 '18 at 2:59
ValdigleisValdigleis
62
62
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
$L$ is the set of all rationals between $0$ and $1$ (inclusive) - basically, $aover b$ is the $a$th element of $L_b$ - so it's dense in $[0,1]$. (Of course, it's not dense in $mathbb{R}$, but I suspect that's not what you're interested in.)
answered Dec 30 '18 at 3:30
Noah SchweberNoah Schweber
129k10152294
$endgroup$
add a comment |
Your Answer
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3056470%2fthe-space-to-valuation-systems-of-lukasiewicz-logic-is-a-dense-set%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
$L$ is the set of all rationals between $0$ and $1$ (inclusive) - basically, $aover b$ is the $a$th element of $L_b$ - so it's dense in $[0,1]$. (Of course, it's not dense in $mathbb{R}$, but I suspect that's not what you're interested in.)
answered Dec 30 '18 at 3:30
Noah SchweberNoah Schweber
129k10152294
$endgroup$
add a comment |
$begingroup$
$L$ is the set of all rationals between $0$ and $1$ (inclusive) - basically, $aover b$ is the $a$th element of $L_b$ - so it's dense in $[0,1]$. (Of course, it's not dense in $mathbb{R}$, but I suspect that's not what you're interested in.)
answered Dec 30 '18 at 3:30
Noah SchweberNoah Schweber
129k10152294
$endgroup$
add a comment |
$begingroup$
$L$ is the set of all rationals between $0$ and $1$ (inclusive) - basically, $aover b$ is the $a$th element of $L_b$ - so it's dense in $[0,1]$. (Of course, it's not dense in $mathbb{R}$, but I suspect that's not what you're interested in.)
answered Dec 30 '18 at 3:30
Noah SchweberNoah Schweber
129k10152294
$endgroup$
$L$ is the set of all rationals between $0$ and $1$ (inclusive) - basically, $aover b$ is the $a$th element of $L_b$ - so it's dense in $[0,1]$. (Of course, it's not dense in $mathbb{R}$, but I suspect that's not what you're interested in.)
answered Dec 30 '18 at 3:30
Noah SchweberNoah Schweber
129k10152294
answered Dec 30 '18 at 3:30
Noah SchweberNoah Schweber
129k10152294
answered Dec 30 '18 at 3:30
Noah SchweberNoah Schweber
129k10152294
answered Dec 30 '18 at 3:30
Noah SchweberNoah Schweber
129k10152294
129k10152294
add a comment |
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3056470%2fthe-space-to-valuation-systems-of-lukasiewicz-logic-is-a-dense-set%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
