create a ranking and statistics with repeated database records
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}
Today I want to get a help in creating scores per user in my database. I have this query:
SELECT
r1.id,
r1.nickname,
r1.fecha,
r1.bestia1,
r1.bestia2,
r1.bestia3,
r1.bestia4
r1.bestia5
FROM
reporte AS r1
INNER JOIN
( SELECT
nickname, MAX(fecha) AS max_date
FROM
reporte
GROUP BY
nickname ) AS latests_reports
ON latests_reports.nickname = r1.nickname
AND latests_reports.max_date = r1.fecha
ORDER BY
r1.fecha DESC
that's from a friend from this site who helped me in get "the last record per user in each day", based on this I am looking how to count the results in a ranking daily, weekly or monthly, in order to use statistics charts or google datastudio, I've tried the next:
select id, nickname, sum(bestia1), sum(bestia2), etc...
But its not giving the complete result wich I want. thats why I am looking for help. Additionaly I know datastudio filters where I can show many charts but still I can count completely.
for example, one player in the last 30 days reported 265 monsters killed, but when I use in datastudio my query it counts only the latest value (it can be 12). so I want to count correctly in order to use with charts
SQL records filtered with my query:
mysql sql highcharts ranking
add a comment |
Today I want to get a help in creating scores per user in my database. I have this query:
SELECT
r1.id,
r1.nickname,
r1.fecha,
r1.bestia1,
r1.bestia2,
r1.bestia3,
r1.bestia4
r1.bestia5
FROM
reporte AS r1
INNER JOIN
( SELECT
nickname, MAX(fecha) AS max_date
FROM
reporte
GROUP BY
nickname ) AS latests_reports
ON latests_reports.nickname = r1.nickname
AND latests_reports.max_date = r1.fecha
ORDER BY
r1.fecha DESC
that's from a friend from this site who helped me in get "the last record per user in each day", based on this I am looking how to count the results in a ranking daily, weekly or monthly, in order to use statistics charts or google datastudio, I've tried the next:
select id, nickname, sum(bestia1), sum(bestia2), etc...
But its not giving the complete result wich I want. thats why I am looking for help. Additionaly I know datastudio filters where I can show many charts but still I can count completely.
for example, one player in the last 30 days reported 265 monsters killed, but when I use in datastudio my query it counts only the latest value (it can be 12). so I want to count correctly in order to use with charts
SQL records filtered with my query:
mysql sql highcharts ranking
2
Any time you find yourself with enumerated columns, alarm bells should start ringing. Consider revising your schema
– Strawberry
Nov 22 '18 at 21:58
Just to clarify and like a starting point, do you need to group by user (columnnickname
) and then get the sum of monster (columnbestia1
+ columnbestia2
+ columnbestia3
+ columnbestia4
+ columnbestia5
) they killed on some day (maybe the current one)? Then, later, do you need this same calculation but over the last week and month?. Also if you can add add some sample of data, and the output you expect to get from they, that will help a lot.
– Shidersz
Nov 23 '18 at 2:25
yes, i need to put in a report who killed more monsters in the current week, the last week or last month, additionally i was thinking in something like that sum(bestia1*1),sum(bestia2*2) in order to create an "score" where each monster is counting for ranking.
– G. Romero
Nov 23 '18 at 5:19
add a comment |
Today I want to get a help in creating scores per user in my database. I have this query:
SELECT
r1.id,
r1.nickname,
r1.fecha,
r1.bestia1,
r1.bestia2,
r1.bestia3,
r1.bestia4
r1.bestia5
FROM
reporte AS r1
INNER JOIN
( SELECT
nickname, MAX(fecha) AS max_date
FROM
reporte
GROUP BY
nickname ) AS latests_reports
ON latests_reports.nickname = r1.nickname
AND latests_reports.max_date = r1.fecha
ORDER BY
r1.fecha DESC
that's from a friend from this site who helped me in get "the last record per user in each day", based on this I am looking how to count the results in a ranking daily, weekly or monthly, in order to use statistics charts or google datastudio, I've tried the next:
select id, nickname, sum(bestia1), sum(bestia2), etc...
But its not giving the complete result wich I want. thats why I am looking for help. Additionaly I know datastudio filters where I can show many charts but still I can count completely.
for example, one player in the last 30 days reported 265 monsters killed, but when I use in datastudio my query it counts only the latest value (it can be 12). so I want to count correctly in order to use with charts
SQL records filtered with my query:
mysql sql highcharts ranking
Today I want to get a help in creating scores per user in my database. I have this query:
SELECT
r1.id,
r1.nickname,
r1.fecha,
r1.bestia1,
r1.bestia2,
r1.bestia3,
r1.bestia4
r1.bestia5
FROM
reporte AS r1
INNER JOIN
( SELECT
nickname, MAX(fecha) AS max_date
FROM
reporte
GROUP BY
nickname ) AS latests_reports
ON latests_reports.nickname = r1.nickname
AND latests_reports.max_date = r1.fecha
ORDER BY
r1.fecha DESC
that's from a friend from this site who helped me in get "the last record per user in each day", based on this I am looking how to count the results in a ranking daily, weekly or monthly, in order to use statistics charts or google datastudio, I've tried the next:
select id, nickname, sum(bestia1), sum(bestia2), etc...
But its not giving the complete result wich I want. thats why I am looking for help. Additionaly I know datastudio filters where I can show many charts but still I can count completely.
for example, one player in the last 30 days reported 265 monsters killed, but when I use in datastudio my query it counts only the latest value (it can be 12). so I want to count correctly in order to use with charts
SQL records filtered with my query:
mysql sql highcharts ranking
mysql sql highcharts ranking
edited Nov 23 '18 at 2:46
Parfait
54.3k104872
54.3k104872
asked Nov 22 '18 at 21:20
G. RomeroG. Romero
166
166
2
Any time you find yourself with enumerated columns, alarm bells should start ringing. Consider revising your schema
– Strawberry
Nov 22 '18 at 21:58
Just to clarify and like a starting point, do you need to group by user (columnnickname
) and then get the sum of monster (columnbestia1
+ columnbestia2
+ columnbestia3
+ columnbestia4
+ columnbestia5
) they killed on some day (maybe the current one)? Then, later, do you need this same calculation but over the last week and month?. Also if you can add add some sample of data, and the output you expect to get from they, that will help a lot.
– Shidersz
Nov 23 '18 at 2:25
yes, i need to put in a report who killed more monsters in the current week, the last week or last month, additionally i was thinking in something like that sum(bestia1*1),sum(bestia2*2) in order to create an "score" where each monster is counting for ranking.
– G. Romero
Nov 23 '18 at 5:19
add a comment |
2
Any time you find yourself with enumerated columns, alarm bells should start ringing. Consider revising your schema
– Strawberry
Nov 22 '18 at 21:58
Just to clarify and like a starting point, do you need to group by user (columnnickname
) and then get the sum of monster (columnbestia1
+ columnbestia2
+ columnbestia3
+ columnbestia4
+ columnbestia5
) they killed on some day (maybe the current one)? Then, later, do you need this same calculation but over the last week and month?. Also if you can add add some sample of data, and the output you expect to get from they, that will help a lot.
– Shidersz
Nov 23 '18 at 2:25
yes, i need to put in a report who killed more monsters in the current week, the last week or last month, additionally i was thinking in something like that sum(bestia1*1),sum(bestia2*2) in order to create an "score" where each monster is counting for ranking.
– G. Romero
Nov 23 '18 at 5:19
2
2
Any time you find yourself with enumerated columns, alarm bells should start ringing. Consider revising your schema
– Strawberry
Nov 22 '18 at 21:58
Any time you find yourself with enumerated columns, alarm bells should start ringing. Consider revising your schema
– Strawberry
Nov 22 '18 at 21:58
Just to clarify and like a starting point, do you need to group by user (column
nickname
) and then get the sum of monster (column bestia1
+ column bestia2
+ column bestia3
+ column bestia4
+ column bestia5
) they killed on some day (maybe the current one)? Then, later, do you need this same calculation but over the last week and month?. Also if you can add add some sample of data, and the output you expect to get from they, that will help a lot.– Shidersz
Nov 23 '18 at 2:25
Just to clarify and like a starting point, do you need to group by user (column
nickname
) and then get the sum of monster (column bestia1
+ column bestia2
+ column bestia3
+ column bestia4
+ column bestia5
) they killed on some day (maybe the current one)? Then, later, do you need this same calculation but over the last week and month?. Also if you can add add some sample of data, and the output you expect to get from they, that will help a lot.– Shidersz
Nov 23 '18 at 2:25
yes, i need to put in a report who killed more monsters in the current week, the last week or last month, additionally i was thinking in something like that sum(bestia1*1),sum(bestia2*2) in order to create an "score" where each monster is counting for ranking.
– G. Romero
Nov 23 '18 at 5:19
yes, i need to put in a report who killed more monsters in the current week, the last week or last month, additionally i was thinking in something like that sum(bestia1*1),sum(bestia2*2) in order to create an "score" where each monster is counting for ranking.
– G. Romero
Nov 23 '18 at 5:19
add a comment |
2 Answers
2
active
oldest
votes
One general approach for get the total monsters killed by each user on the latest X days and make a score calculation like the one you propose on the commentaries can be like this:
SET @daysOnHistory = X; -- Where X should be an integer positive number (like 10).
SELECT
nickname,
SUM(bestia1) AS total_bestia1_killed,
SUM(bestia2) AS total_bestia2_killed,
SUM(bestia3) AS total_bestia3_killed,
SUM(bestia4) AS total_bestia4_killed,
SUM(bestia5) AS total_bestia5_killed,
SUM(bestia1 + bestia2 + bestia3 + bestia4 + bestia5) AS total_monsters_killed,
SUM(bestia1 + 2 * bestia2 + 3 * bestia3 + 4 * bestia4 + 5 * bestia5) AS total_score
FROM
reporte
WHERE
fecha >= DATE_ADD(DATE(NOW()), INTERVAL -@daysOnHistory DAY)
GROUP BY
nickname
ORDER BY
total_score DESC
Now, if you want the same calculation but only taking into account the days of the current week (assuming a week starts on Monday), you need to replace the previous WHERE
clause by next one:
WHERE
fecha >= DATE_ADD(DATE(NOW()), INTERVAL -WEEKDAY(NOW()) DAY)
Even more, if you want all the same, but only taking into account the days of the current month, you need to replace the WHERE
clause by:
WHERE
MONTH(fecha) = MONTH(NOW())
For evaluate the statistics on the days of the current year, you need to replace the WHERE
clause by:
WHERE
YEAR(fecha) = YEAR(NOW())
And finally, for evaluation on a specific range of days you can use, for example:
WHERE
DATE(fecha) BETWEEN CAST("2018-10-15" AS DATE) AND CAST('2018-11-10' AS DATE)
I hope this guide will help you and clarify your outlook.
wow this solves a lot about what i am looking!! thank you man!!!
– G. Romero
Nov 24 '18 at 18:14
sir, how can i get the report from yesterday or x days ago? but only from these day? because i tried tu put the exact date or range of days but it sums all monsters
– G. Romero
Nov 26 '18 at 14:33
Check the first query of my guide, but changewhere
clause byDATE(fecha) = DATE_ADD(DATE(NOW()), INTERVAL -@daysOnHistory DAY )
.
– Shidersz
Nov 26 '18 at 23:25
Hello sir, the ranking for current week is bot working properly, i created a ranking in PHP and today i AM not getting any data
– G. Romero
Dec 2 '18 at 15:40
@G.Romero I have updated my answer. Use this for week ranking:WHERE fecha >= DATE_ADD(DATE(NOW()), INTERVAL -WEEKDAY(NOW()) DAY)
. Tellme if it works as you expect now... Also, if you could vote me up, i will appeciate it.
– Shidersz
Dec 2 '18 at 16:26
add a comment |
This will give you number of monster killed in the last 30 days per user :
SELECT
nickname,
sum(bestia1) as bestia1,
sum(bestia2) as bestia2,
sum(bestia3) as bestia3,
sum(bestia4) as bestia4,
sum(bestia5) as bestia5
FROM
reporte
WHERE fecha >= DATE_ADD(curdate(), interval -30 day)
GROUP BY nickName
ORDER BY
thankyou for that sir, i am working with this code just now in order to replace interval days per current week or last week, for example i want to get the monster killed per user this week from 19/11 to 25/11, if you know that please explain to me... thanks
– G. Romero
Nov 23 '18 at 5:21
For monster killed between 19 to 25, replace where clause forWHERE fecha between '2018-11-19' and '2018-11-25 23:59:59'
If you omit 23:59:59, you will be missing entries of the last day in the range.between '2018-11-19' and '2018-11-25'
will be from 11-19 midnight to 11-25 midnight (night between 24 and 25).
– DanB
Nov 23 '18 at 18:41
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
One general approach for get the total monsters killed by each user on the latest X days and make a score calculation like the one you propose on the commentaries can be like this:
SET @daysOnHistory = X; -- Where X should be an integer positive number (like 10).
SELECT
nickname,
SUM(bestia1) AS total_bestia1_killed,
SUM(bestia2) AS total_bestia2_killed,
SUM(bestia3) AS total_bestia3_killed,
SUM(bestia4) AS total_bestia4_killed,
SUM(bestia5) AS total_bestia5_killed,
SUM(bestia1 + bestia2 + bestia3 + bestia4 + bestia5) AS total_monsters_killed,
SUM(bestia1 + 2 * bestia2 + 3 * bestia3 + 4 * bestia4 + 5 * bestia5) AS total_score
FROM
reporte
WHERE
fecha >= DATE_ADD(DATE(NOW()), INTERVAL -@daysOnHistory DAY)
GROUP BY
nickname
ORDER BY
total_score DESC
Now, if you want the same calculation but only taking into account the days of the current week (assuming a week starts on Monday), you need to replace the previous WHERE
clause by next one:
WHERE
fecha >= DATE_ADD(DATE(NOW()), INTERVAL -WEEKDAY(NOW()) DAY)
Even more, if you want all the same, but only taking into account the days of the current month, you need to replace the WHERE
clause by:
WHERE
MONTH(fecha) = MONTH(NOW())
For evaluate the statistics on the days of the current year, you need to replace the WHERE
clause by:
WHERE
YEAR(fecha) = YEAR(NOW())
And finally, for evaluation on a specific range of days you can use, for example:
WHERE
DATE(fecha) BETWEEN CAST("2018-10-15" AS DATE) AND CAST('2018-11-10' AS DATE)
I hope this guide will help you and clarify your outlook.
wow this solves a lot about what i am looking!! thank you man!!!
– G. Romero
Nov 24 '18 at 18:14
sir, how can i get the report from yesterday or x days ago? but only from these day? because i tried tu put the exact date or range of days but it sums all monsters
– G. Romero
Nov 26 '18 at 14:33
Check the first query of my guide, but changewhere
clause byDATE(fecha) = DATE_ADD(DATE(NOW()), INTERVAL -@daysOnHistory DAY )
.
– Shidersz
Nov 26 '18 at 23:25
Hello sir, the ranking for current week is bot working properly, i created a ranking in PHP and today i AM not getting any data
– G. Romero
Dec 2 '18 at 15:40
@G.Romero I have updated my answer. Use this for week ranking:WHERE fecha >= DATE_ADD(DATE(NOW()), INTERVAL -WEEKDAY(NOW()) DAY)
. Tellme if it works as you expect now... Also, if you could vote me up, i will appeciate it.
– Shidersz
Dec 2 '18 at 16:26
add a comment |
One general approach for get the total monsters killed by each user on the latest X days and make a score calculation like the one you propose on the commentaries can be like this:
SET @daysOnHistory = X; -- Where X should be an integer positive number (like 10).
SELECT
nickname,
SUM(bestia1) AS total_bestia1_killed,
SUM(bestia2) AS total_bestia2_killed,
SUM(bestia3) AS total_bestia3_killed,
SUM(bestia4) AS total_bestia4_killed,
SUM(bestia5) AS total_bestia5_killed,
SUM(bestia1 + bestia2 + bestia3 + bestia4 + bestia5) AS total_monsters_killed,
SUM(bestia1 + 2 * bestia2 + 3 * bestia3 + 4 * bestia4 + 5 * bestia5) AS total_score
FROM
reporte
WHERE
fecha >= DATE_ADD(DATE(NOW()), INTERVAL -@daysOnHistory DAY)
GROUP BY
nickname
ORDER BY
total_score DESC
Now, if you want the same calculation but only taking into account the days of the current week (assuming a week starts on Monday), you need to replace the previous WHERE
clause by next one:
WHERE
fecha >= DATE_ADD(DATE(NOW()), INTERVAL -WEEKDAY(NOW()) DAY)
Even more, if you want all the same, but only taking into account the days of the current month, you need to replace the WHERE
clause by:
WHERE
MONTH(fecha) = MONTH(NOW())
For evaluate the statistics on the days of the current year, you need to replace the WHERE
clause by:
WHERE
YEAR(fecha) = YEAR(NOW())
And finally, for evaluation on a specific range of days you can use, for example:
WHERE
DATE(fecha) BETWEEN CAST("2018-10-15" AS DATE) AND CAST('2018-11-10' AS DATE)
I hope this guide will help you and clarify your outlook.
wow this solves a lot about what i am looking!! thank you man!!!
– G. Romero
Nov 24 '18 at 18:14
sir, how can i get the report from yesterday or x days ago? but only from these day? because i tried tu put the exact date or range of days but it sums all monsters
– G. Romero
Nov 26 '18 at 14:33
Check the first query of my guide, but changewhere
clause byDATE(fecha) = DATE_ADD(DATE(NOW()), INTERVAL -@daysOnHistory DAY )
.
– Shidersz
Nov 26 '18 at 23:25
Hello sir, the ranking for current week is bot working properly, i created a ranking in PHP and today i AM not getting any data
– G. Romero
Dec 2 '18 at 15:40
@G.Romero I have updated my answer. Use this for week ranking:WHERE fecha >= DATE_ADD(DATE(NOW()), INTERVAL -WEEKDAY(NOW()) DAY)
. Tellme if it works as you expect now... Also, if you could vote me up, i will appeciate it.
– Shidersz
Dec 2 '18 at 16:26
add a comment |
One general approach for get the total monsters killed by each user on the latest X days and make a score calculation like the one you propose on the commentaries can be like this:
SET @daysOnHistory = X; -- Where X should be an integer positive number (like 10).
SELECT
nickname,
SUM(bestia1) AS total_bestia1_killed,
SUM(bestia2) AS total_bestia2_killed,
SUM(bestia3) AS total_bestia3_killed,
SUM(bestia4) AS total_bestia4_killed,
SUM(bestia5) AS total_bestia5_killed,
SUM(bestia1 + bestia2 + bestia3 + bestia4 + bestia5) AS total_monsters_killed,
SUM(bestia1 + 2 * bestia2 + 3 * bestia3 + 4 * bestia4 + 5 * bestia5) AS total_score
FROM
reporte
WHERE
fecha >= DATE_ADD(DATE(NOW()), INTERVAL -@daysOnHistory DAY)
GROUP BY
nickname
ORDER BY
total_score DESC
Now, if you want the same calculation but only taking into account the days of the current week (assuming a week starts on Monday), you need to replace the previous WHERE
clause by next one:
WHERE
fecha >= DATE_ADD(DATE(NOW()), INTERVAL -WEEKDAY(NOW()) DAY)
Even more, if you want all the same, but only taking into account the days of the current month, you need to replace the WHERE
clause by:
WHERE
MONTH(fecha) = MONTH(NOW())
For evaluate the statistics on the days of the current year, you need to replace the WHERE
clause by:
WHERE
YEAR(fecha) = YEAR(NOW())
And finally, for evaluation on a specific range of days you can use, for example:
WHERE
DATE(fecha) BETWEEN CAST("2018-10-15" AS DATE) AND CAST('2018-11-10' AS DATE)
I hope this guide will help you and clarify your outlook.
One general approach for get the total monsters killed by each user on the latest X days and make a score calculation like the one you propose on the commentaries can be like this:
SET @daysOnHistory = X; -- Where X should be an integer positive number (like 10).
SELECT
nickname,
SUM(bestia1) AS total_bestia1_killed,
SUM(bestia2) AS total_bestia2_killed,
SUM(bestia3) AS total_bestia3_killed,
SUM(bestia4) AS total_bestia4_killed,
SUM(bestia5) AS total_bestia5_killed,
SUM(bestia1 + bestia2 + bestia3 + bestia4 + bestia5) AS total_monsters_killed,
SUM(bestia1 + 2 * bestia2 + 3 * bestia3 + 4 * bestia4 + 5 * bestia5) AS total_score
FROM
reporte
WHERE
fecha >= DATE_ADD(DATE(NOW()), INTERVAL -@daysOnHistory DAY)
GROUP BY
nickname
ORDER BY
total_score DESC
Now, if you want the same calculation but only taking into account the days of the current week (assuming a week starts on Monday), you need to replace the previous WHERE
clause by next one:
WHERE
fecha >= DATE_ADD(DATE(NOW()), INTERVAL -WEEKDAY(NOW()) DAY)
Even more, if you want all the same, but only taking into account the days of the current month, you need to replace the WHERE
clause by:
WHERE
MONTH(fecha) = MONTH(NOW())
For evaluate the statistics on the days of the current year, you need to replace the WHERE
clause by:
WHERE
YEAR(fecha) = YEAR(NOW())
And finally, for evaluation on a specific range of days you can use, for example:
WHERE
DATE(fecha) BETWEEN CAST("2018-10-15" AS DATE) AND CAST('2018-11-10' AS DATE)
I hope this guide will help you and clarify your outlook.
edited Dec 2 '18 at 16:24
answered Nov 23 '18 at 21:58
ShiderszShidersz
10.4k2933
10.4k2933
wow this solves a lot about what i am looking!! thank you man!!!
– G. Romero
Nov 24 '18 at 18:14
sir, how can i get the report from yesterday or x days ago? but only from these day? because i tried tu put the exact date or range of days but it sums all monsters
– G. Romero
Nov 26 '18 at 14:33
Check the first query of my guide, but changewhere
clause byDATE(fecha) = DATE_ADD(DATE(NOW()), INTERVAL -@daysOnHistory DAY )
.
– Shidersz
Nov 26 '18 at 23:25
Hello sir, the ranking for current week is bot working properly, i created a ranking in PHP and today i AM not getting any data
– G. Romero
Dec 2 '18 at 15:40
@G.Romero I have updated my answer. Use this for week ranking:WHERE fecha >= DATE_ADD(DATE(NOW()), INTERVAL -WEEKDAY(NOW()) DAY)
. Tellme if it works as you expect now... Also, if you could vote me up, i will appeciate it.
– Shidersz
Dec 2 '18 at 16:26
add a comment |
wow this solves a lot about what i am looking!! thank you man!!!
– G. Romero
Nov 24 '18 at 18:14
sir, how can i get the report from yesterday or x days ago? but only from these day? because i tried tu put the exact date or range of days but it sums all monsters
– G. Romero
Nov 26 '18 at 14:33
Check the first query of my guide, but changewhere
clause byDATE(fecha) = DATE_ADD(DATE(NOW()), INTERVAL -@daysOnHistory DAY )
.
– Shidersz
Nov 26 '18 at 23:25
Hello sir, the ranking for current week is bot working properly, i created a ranking in PHP and today i AM not getting any data
– G. Romero
Dec 2 '18 at 15:40
@G.Romero I have updated my answer. Use this for week ranking:WHERE fecha >= DATE_ADD(DATE(NOW()), INTERVAL -WEEKDAY(NOW()) DAY)
. Tellme if it works as you expect now... Also, if you could vote me up, i will appeciate it.
– Shidersz
Dec 2 '18 at 16:26
wow this solves a lot about what i am looking!! thank you man!!!
– G. Romero
Nov 24 '18 at 18:14
wow this solves a lot about what i am looking!! thank you man!!!
– G. Romero
Nov 24 '18 at 18:14
sir, how can i get the report from yesterday or x days ago? but only from these day? because i tried tu put the exact date or range of days but it sums all monsters
– G. Romero
Nov 26 '18 at 14:33
sir, how can i get the report from yesterday or x days ago? but only from these day? because i tried tu put the exact date or range of days but it sums all monsters
– G. Romero
Nov 26 '18 at 14:33
Check the first query of my guide, but change
where
clause by DATE(fecha) = DATE_ADD(DATE(NOW()), INTERVAL -@daysOnHistory DAY )
.– Shidersz
Nov 26 '18 at 23:25
Check the first query of my guide, but change
where
clause by DATE(fecha) = DATE_ADD(DATE(NOW()), INTERVAL -@daysOnHistory DAY )
.– Shidersz
Nov 26 '18 at 23:25
Hello sir, the ranking for current week is bot working properly, i created a ranking in PHP and today i AM not getting any data
– G. Romero
Dec 2 '18 at 15:40
Hello sir, the ranking for current week is bot working properly, i created a ranking in PHP and today i AM not getting any data
– G. Romero
Dec 2 '18 at 15:40
@G.Romero I have updated my answer. Use this for week ranking:
WHERE fecha >= DATE_ADD(DATE(NOW()), INTERVAL -WEEKDAY(NOW()) DAY)
. Tellme if it works as you expect now... Also, if you could vote me up, i will appeciate it.– Shidersz
Dec 2 '18 at 16:26
@G.Romero I have updated my answer. Use this for week ranking:
WHERE fecha >= DATE_ADD(DATE(NOW()), INTERVAL -WEEKDAY(NOW()) DAY)
. Tellme if it works as you expect now... Also, if you could vote me up, i will appeciate it.– Shidersz
Dec 2 '18 at 16:26
add a comment |
This will give you number of monster killed in the last 30 days per user :
SELECT
nickname,
sum(bestia1) as bestia1,
sum(bestia2) as bestia2,
sum(bestia3) as bestia3,
sum(bestia4) as bestia4,
sum(bestia5) as bestia5
FROM
reporte
WHERE fecha >= DATE_ADD(curdate(), interval -30 day)
GROUP BY nickName
ORDER BY
thankyou for that sir, i am working with this code just now in order to replace interval days per current week or last week, for example i want to get the monster killed per user this week from 19/11 to 25/11, if you know that please explain to me... thanks
– G. Romero
Nov 23 '18 at 5:21
For monster killed between 19 to 25, replace where clause forWHERE fecha between '2018-11-19' and '2018-11-25 23:59:59'
If you omit 23:59:59, you will be missing entries of the last day in the range.between '2018-11-19' and '2018-11-25'
will be from 11-19 midnight to 11-25 midnight (night between 24 and 25).
– DanB
Nov 23 '18 at 18:41
add a comment |
This will give you number of monster killed in the last 30 days per user :
SELECT
nickname,
sum(bestia1) as bestia1,
sum(bestia2) as bestia2,
sum(bestia3) as bestia3,
sum(bestia4) as bestia4,
sum(bestia5) as bestia5
FROM
reporte
WHERE fecha >= DATE_ADD(curdate(), interval -30 day)
GROUP BY nickName
ORDER BY
thankyou for that sir, i am working with this code just now in order to replace interval days per current week or last week, for example i want to get the monster killed per user this week from 19/11 to 25/11, if you know that please explain to me... thanks
– G. Romero
Nov 23 '18 at 5:21
For monster killed between 19 to 25, replace where clause forWHERE fecha between '2018-11-19' and '2018-11-25 23:59:59'
If you omit 23:59:59, you will be missing entries of the last day in the range.between '2018-11-19' and '2018-11-25'
will be from 11-19 midnight to 11-25 midnight (night between 24 and 25).
– DanB
Nov 23 '18 at 18:41
add a comment |
This will give you number of monster killed in the last 30 days per user :
SELECT
nickname,
sum(bestia1) as bestia1,
sum(bestia2) as bestia2,
sum(bestia3) as bestia3,
sum(bestia4) as bestia4,
sum(bestia5) as bestia5
FROM
reporte
WHERE fecha >= DATE_ADD(curdate(), interval -30 day)
GROUP BY nickName
ORDER BY
This will give you number of monster killed in the last 30 days per user :
SELECT
nickname,
sum(bestia1) as bestia1,
sum(bestia2) as bestia2,
sum(bestia3) as bestia3,
sum(bestia4) as bestia4,
sum(bestia5) as bestia5
FROM
reporte
WHERE fecha >= DATE_ADD(curdate(), interval -30 day)
GROUP BY nickName
ORDER BY
answered Nov 23 '18 at 3:33
DanBDanB
1,7621315
1,7621315
thankyou for that sir, i am working with this code just now in order to replace interval days per current week or last week, for example i want to get the monster killed per user this week from 19/11 to 25/11, if you know that please explain to me... thanks
– G. Romero
Nov 23 '18 at 5:21
For monster killed between 19 to 25, replace where clause forWHERE fecha between '2018-11-19' and '2018-11-25 23:59:59'
If you omit 23:59:59, you will be missing entries of the last day in the range.between '2018-11-19' and '2018-11-25'
will be from 11-19 midnight to 11-25 midnight (night between 24 and 25).
– DanB
Nov 23 '18 at 18:41
add a comment |
thankyou for that sir, i am working with this code just now in order to replace interval days per current week or last week, for example i want to get the monster killed per user this week from 19/11 to 25/11, if you know that please explain to me... thanks
– G. Romero
Nov 23 '18 at 5:21
For monster killed between 19 to 25, replace where clause forWHERE fecha between '2018-11-19' and '2018-11-25 23:59:59'
If you omit 23:59:59, you will be missing entries of the last day in the range.between '2018-11-19' and '2018-11-25'
will be from 11-19 midnight to 11-25 midnight (night between 24 and 25).
– DanB
Nov 23 '18 at 18:41
thankyou for that sir, i am working with this code just now in order to replace interval days per current week or last week, for example i want to get the monster killed per user this week from 19/11 to 25/11, if you know that please explain to me... thanks
– G. Romero
Nov 23 '18 at 5:21
thankyou for that sir, i am working with this code just now in order to replace interval days per current week or last week, for example i want to get the monster killed per user this week from 19/11 to 25/11, if you know that please explain to me... thanks
– G. Romero
Nov 23 '18 at 5:21
For monster killed between 19 to 25, replace where clause for
WHERE fecha between '2018-11-19' and '2018-11-25 23:59:59'
If you omit 23:59:59, you will be missing entries of the last day in the range. between '2018-11-19' and '2018-11-25'
will be from 11-19 midnight to 11-25 midnight (night between 24 and 25).– DanB
Nov 23 '18 at 18:41
For monster killed between 19 to 25, replace where clause for
WHERE fecha between '2018-11-19' and '2018-11-25 23:59:59'
If you omit 23:59:59, you will be missing entries of the last day in the range. between '2018-11-19' and '2018-11-25'
will be from 11-19 midnight to 11-25 midnight (night between 24 and 25).– DanB
Nov 23 '18 at 18:41
add a comment |
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2
Any time you find yourself with enumerated columns, alarm bells should start ringing. Consider revising your schema
– Strawberry
Nov 22 '18 at 21:58
Just to clarify and like a starting point, do you need to group by user (column
nickname
) and then get the sum of monster (columnbestia1
+ columnbestia2
+ columnbestia3
+ columnbestia4
+ columnbestia5
) they killed on some day (maybe the current one)? Then, later, do you need this same calculation but over the last week and month?. Also if you can add add some sample of data, and the output you expect to get from they, that will help a lot.– Shidersz
Nov 23 '18 at 2:25
yes, i need to put in a report who killed more monsters in the current week, the last week or last month, additionally i was thinking in something like that sum(bestia1*1),sum(bestia2*2) in order to create an "score" where each monster is counting for ranking.
– G. Romero
Nov 23 '18 at 5:19