In Dart, in a sequential list of integers, how do I find a number between the items?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}
In a list of sequential integers, is there a simple way to locate where another integer would be placed (between two of the list members)?
main() {
var myList = new List();
myList.addAll([0, 4, 10, 20, 33, 45, 55, 64]);
int setStart;
int currentPosition;
currentPosition = 12;
// if currentPosition is greater than or equal to myList[fooPosition]
// but less than myList[barPosition]
// setStart = myList[foo]
}
So since the currentPosition is 12, the correct answer for setStart would be 10.
dart
asked Nov 22 '18 at 21:29
LeeHunterLeeHunter
266
add a comment |
In a list of sequential integers, is there a simple way to locate where another integer would be placed (between two of the list members)?
main() {
var myList = new List();
myList.addAll([0, 4, 10, 20, 33, 45, 55, 64]);
int setStart;
int currentPosition;
currentPosition = 12;
// if currentPosition is greater than or equal to myList[fooPosition]
// but less than myList[barPosition]
// setStart = myList[foo]
}
So since the currentPosition is 12, the correct answer for setStart would be 10.
dart
asked Nov 22 '18 at 21:29
LeeHunterLeeHunter
266
add a comment |
In a list of sequential integers, is there a simple way to locate where another integer would be placed (between two of the list members)?
main() {
var myList = new List();
myList.addAll([0, 4, 10, 20, 33, 45, 55, 64]);
int setStart;
int currentPosition;
currentPosition = 12;
// if currentPosition is greater than or equal to myList[fooPosition]
// but less than myList[barPosition]
// setStart = myList[foo]
}
So since the currentPosition is 12, the correct answer for setStart would be 10.
dart
asked Nov 22 '18 at 21:29
LeeHunterLeeHunter
266
In a list of sequential integers, is there a simple way to locate where another integer would be placed (between two of the list members)?
main() {
var myList = new List();
myList.addAll([0, 4, 10, 20, 33, 45, 55, 64]);
int setStart;
int currentPosition;
currentPosition = 12;
// if currentPosition is greater than or equal to myList[fooPosition]
// but less than myList[barPosition]
// setStart = myList[foo]
}
So since the currentPosition is 12, the correct answer for setStart would be 10.
dart
dart
asked Nov 22 '18 at 21:29
LeeHunterLeeHunter
266
asked Nov 22 '18 at 21:29
LeeHunterLeeHunter
266
asked Nov 22 '18 at 21:29
LeeHunterLeeHunter
266
asked Nov 22 '18 at 21:29
LeeHunterLeeHunter
266
asked Nov 22 '18 at 21:29
LeeHunterLeeHunter
266
266
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
Try checking out package:collection's binarySearch.
answered Nov 23 '18 at 6:55
lrnlrn
11.3k1527
add a comment |
Ok, figured it out myself. Pretty simple really. I just needed to add another variable (x) to indicate the list position of the upper number:
for (var i = 0; i < myList.length; i++) {
var x = i + 1;
if (currentPosition >= myList[i] && currentPosition < myList [x]) {
setStart = myList[i];
};
};
answered Nov 23 '18 at 10:00
LeeHunterLeeHunter
266
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53438162%2fin-dart-in-a-sequential-list-of-integers-how-do-i-find-a-number-between-the-it%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Try checking out package:collection's binarySearch.
answered Nov 23 '18 at 6:55
lrnlrn
11.3k1527
add a comment |
Try checking out package:collection's binarySearch.
answered Nov 23 '18 at 6:55
lrnlrn
11.3k1527
add a comment |
Try checking out package:collection's binarySearch.
answered Nov 23 '18 at 6:55
lrnlrn
11.3k1527
Try checking out package:collection's binarySearch.
answered Nov 23 '18 at 6:55
lrnlrn
11.3k1527
answered Nov 23 '18 at 6:55
lrnlrn
11.3k1527
answered Nov 23 '18 at 6:55
lrnlrn
11.3k1527
answered Nov 23 '18 at 6:55
lrnlrn
11.3k1527
11.3k1527
add a comment |
add a comment |
Ok, figured it out myself. Pretty simple really. I just needed to add another variable (x) to indicate the list position of the upper number:
for (var i = 0; i < myList.length; i++) {
var x = i + 1;
if (currentPosition >= myList[i] && currentPosition < myList [x]) {
setStart = myList[i];
};
};
answered Nov 23 '18 at 10:00
LeeHunterLeeHunter
266
add a comment |
Ok, figured it out myself. Pretty simple really. I just needed to add another variable (x) to indicate the list position of the upper number:
for (var i = 0; i < myList.length; i++) {
var x = i + 1;
if (currentPosition >= myList[i] && currentPosition < myList [x]) {
setStart = myList[i];
};
};
answered Nov 23 '18 at 10:00
LeeHunterLeeHunter
266
add a comment |
Ok, figured it out myself. Pretty simple really. I just needed to add another variable (x) to indicate the list position of the upper number:
for (var i = 0; i < myList.length; i++) {
var x = i + 1;
if (currentPosition >= myList[i] && currentPosition < myList [x]) {
setStart = myList[i];
};
};
answered Nov 23 '18 at 10:00
LeeHunterLeeHunter
266
Ok, figured it out myself. Pretty simple really. I just needed to add another variable (x) to indicate the list position of the upper number:
for (var i = 0; i < myList.length; i++) {
var x = i + 1;
if (currentPosition >= myList[i] && currentPosition < myList [x]) {
setStart = myList[i];
};
};
answered Nov 23 '18 at 10:00
LeeHunterLeeHunter
266
edited Nov 23 '18 at 12:18
answered Nov 23 '18 at 10:00
LeeHunterLeeHunter
266
answered Nov 23 '18 at 10:00
LeeHunterLeeHunter
266
answered Nov 23 '18 at 10:00
LeeHunterLeeHunter
266
266
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53438162%2fin-dart-in-a-sequential-list-of-integers-how-do-i-find-a-number-between-the-it%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
