How to find this cdf
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I am trying to solve for a bound.
This involves me finding $F_{2S_n/sqrt{n}}(x)$ where $S_n = sum_{k=1}^n X_k$ where $X$ is a random variable with mass $pm frac{1}{2}$ with probability $frac{1}{2}$
Any help would be greatly appreciated!
probability-distributions
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add a comment |
$begingroup$
I am trying to solve for a bound.
This involves me finding $F_{2S_n/sqrt{n}}(x)$ where $S_n = sum_{k=1}^n X_k$ where $X$ is a random variable with mass $pm frac{1}{2}$ with probability $frac{1}{2}$
Any help would be greatly appreciated!
probability-distributions
$endgroup$
add a comment |
$begingroup$
I am trying to solve for a bound.
This involves me finding $F_{2S_n/sqrt{n}}(x)$ where $S_n = sum_{k=1}^n X_k$ where $X$ is a random variable with mass $pm frac{1}{2}$ with probability $frac{1}{2}$
Any help would be greatly appreciated!
probability-distributions
$endgroup$
I am trying to solve for a bound.
This involves me finding $F_{2S_n/sqrt{n}}(x)$ where $S_n = sum_{k=1}^n X_k$ where $X$ is a random variable with mass $pm frac{1}{2}$ with probability $frac{1}{2}$
Any help would be greatly appreciated!
probability-distributions
probability-distributions
asked Dec 12 '18 at 1:15
An Invisible CarrotAn Invisible Carrot
1018
1018
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1 Answer
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I think going through some material about random walks would help for this problem:
https://en.wikipedia.org/wiki/Random_walk
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
I think going through some material about random walks would help for this problem:
https://en.wikipedia.org/wiki/Random_walk
$endgroup$
add a comment |
$begingroup$
I think going through some material about random walks would help for this problem:
https://en.wikipedia.org/wiki/Random_walk
$endgroup$
add a comment |
$begingroup$
I think going through some material about random walks would help for this problem:
https://en.wikipedia.org/wiki/Random_walk
$endgroup$
I think going through some material about random walks would help for this problem:
https://en.wikipedia.org/wiki/Random_walk
answered Dec 12 '18 at 1:18
MZ1113MZ1113
11
11
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