Slurm Question: Array Job VS srun in a sbatch












1















What's the difference between the two following parallelization schemes on Slurm?



Scheme 1



Run sbatch script.sh



#!/bin/bash
#SBATCH --ntasks=8
## more options
srun echo hello


This summons 8 jobs that run echo hello



Scheme 2
I've accomplished something similar using array jobs.



#!/bin/bash

#SBATCH --job-name=arrayJob
#SBATCH --output=arrayJob_%A_%a.out
#SBATCH --error=arrayJob_%A_%a.err
#SBATCH --array=1-8
#SBATCH --time=01:00:00
#SBATCH --ntasks=1

# Print this sub-job's task ID
echo hello


Is there any difference between the two schemes? They both seem to accomplish the same thing.










share|improve this question



























    1















    What's the difference between the two following parallelization schemes on Slurm?



    Scheme 1



    Run sbatch script.sh



    #!/bin/bash
    #SBATCH --ntasks=8
    ## more options
    srun echo hello


    This summons 8 jobs that run echo hello



    Scheme 2
    I've accomplished something similar using array jobs.



    #!/bin/bash

    #SBATCH --job-name=arrayJob
    #SBATCH --output=arrayJob_%A_%a.out
    #SBATCH --error=arrayJob_%A_%a.err
    #SBATCH --array=1-8
    #SBATCH --time=01:00:00
    #SBATCH --ntasks=1

    # Print this sub-job's task ID
    echo hello


    Is there any difference between the two schemes? They both seem to accomplish the same thing.










    share|improve this question

























      1












      1








      1








      What's the difference between the two following parallelization schemes on Slurm?



      Scheme 1



      Run sbatch script.sh



      #!/bin/bash
      #SBATCH --ntasks=8
      ## more options
      srun echo hello


      This summons 8 jobs that run echo hello



      Scheme 2
      I've accomplished something similar using array jobs.



      #!/bin/bash

      #SBATCH --job-name=arrayJob
      #SBATCH --output=arrayJob_%A_%a.out
      #SBATCH --error=arrayJob_%A_%a.err
      #SBATCH --array=1-8
      #SBATCH --time=01:00:00
      #SBATCH --ntasks=1

      # Print this sub-job's task ID
      echo hello


      Is there any difference between the two schemes? They both seem to accomplish the same thing.










      share|improve this question














      What's the difference between the two following parallelization schemes on Slurm?



      Scheme 1



      Run sbatch script.sh



      #!/bin/bash
      #SBATCH --ntasks=8
      ## more options
      srun echo hello


      This summons 8 jobs that run echo hello



      Scheme 2
      I've accomplished something similar using array jobs.



      #!/bin/bash

      #SBATCH --job-name=arrayJob
      #SBATCH --output=arrayJob_%A_%a.out
      #SBATCH --error=arrayJob_%A_%a.err
      #SBATCH --array=1-8
      #SBATCH --time=01:00:00
      #SBATCH --ntasks=1

      # Print this sub-job's task ID
      echo hello


      Is there any difference between the two schemes? They both seem to accomplish the same thing.







      slurm






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      asked Nov 22 '18 at 3:39









      dksadmsaklaslksalddksadmsaklaslksald

      83




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          Scheme 1 is one single job (with 8 tasks) while Scheme 2 is 8 distinct jobs (each with one task). In the first case, all the tasks will be scheduled at the same time, while in the second case, the 8 tasks will be scheduled independently one of another.



          With the job array (Scheme 2), if 8 CPUs become available at once, they will all start at the same time, but if only 4 CPUs become available at first, 4 tasks will run, the other 4 remaining pending. When the initial 4 are done, the other 4 are started. It is typically used in the case of embarrassingly parallel jobs, where the processes do not need to communicate or synchronise, like for applying the same program to a list of files.



          By contrast, with a single job (Scheme 1), Slurm will start the 8 tasks at the same time, so it will need 8 CPUS to become available at the same time. This is typically only used with parallel jobs where processes need to communicate with each others, for instance using an Message Passing Interface library.






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            Scheme 1 is one single job (with 8 tasks) while Scheme 2 is 8 distinct jobs (each with one task). In the first case, all the tasks will be scheduled at the same time, while in the second case, the 8 tasks will be scheduled independently one of another.



            With the job array (Scheme 2), if 8 CPUs become available at once, they will all start at the same time, but if only 4 CPUs become available at first, 4 tasks will run, the other 4 remaining pending. When the initial 4 are done, the other 4 are started. It is typically used in the case of embarrassingly parallel jobs, where the processes do not need to communicate or synchronise, like for applying the same program to a list of files.



            By contrast, with a single job (Scheme 1), Slurm will start the 8 tasks at the same time, so it will need 8 CPUS to become available at the same time. This is typically only used with parallel jobs where processes need to communicate with each others, for instance using an Message Passing Interface library.






            share|improve this answer




























              1














              Scheme 1 is one single job (with 8 tasks) while Scheme 2 is 8 distinct jobs (each with one task). In the first case, all the tasks will be scheduled at the same time, while in the second case, the 8 tasks will be scheduled independently one of another.



              With the job array (Scheme 2), if 8 CPUs become available at once, they will all start at the same time, but if only 4 CPUs become available at first, 4 tasks will run, the other 4 remaining pending. When the initial 4 are done, the other 4 are started. It is typically used in the case of embarrassingly parallel jobs, where the processes do not need to communicate or synchronise, like for applying the same program to a list of files.



              By contrast, with a single job (Scheme 1), Slurm will start the 8 tasks at the same time, so it will need 8 CPUS to become available at the same time. This is typically only used with parallel jobs where processes need to communicate with each others, for instance using an Message Passing Interface library.






              share|improve this answer


























                1












                1








                1







                Scheme 1 is one single job (with 8 tasks) while Scheme 2 is 8 distinct jobs (each with one task). In the first case, all the tasks will be scheduled at the same time, while in the second case, the 8 tasks will be scheduled independently one of another.



                With the job array (Scheme 2), if 8 CPUs become available at once, they will all start at the same time, but if only 4 CPUs become available at first, 4 tasks will run, the other 4 remaining pending. When the initial 4 are done, the other 4 are started. It is typically used in the case of embarrassingly parallel jobs, where the processes do not need to communicate or synchronise, like for applying the same program to a list of files.



                By contrast, with a single job (Scheme 1), Slurm will start the 8 tasks at the same time, so it will need 8 CPUS to become available at the same time. This is typically only used with parallel jobs where processes need to communicate with each others, for instance using an Message Passing Interface library.






                share|improve this answer













                Scheme 1 is one single job (with 8 tasks) while Scheme 2 is 8 distinct jobs (each with one task). In the first case, all the tasks will be scheduled at the same time, while in the second case, the 8 tasks will be scheduled independently one of another.



                With the job array (Scheme 2), if 8 CPUs become available at once, they will all start at the same time, but if only 4 CPUs become available at first, 4 tasks will run, the other 4 remaining pending. When the initial 4 are done, the other 4 are started. It is typically used in the case of embarrassingly parallel jobs, where the processes do not need to communicate or synchronise, like for applying the same program to a list of files.



                By contrast, with a single job (Scheme 1), Slurm will start the 8 tasks at the same time, so it will need 8 CPUS to become available at the same time. This is typically only used with parallel jobs where processes need to communicate with each others, for instance using an Message Passing Interface library.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 22 '18 at 22:55









                damienfrancoisdamienfrancois

                26.5k55064




                26.5k55064
































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