Every linearly-ordered real-parametrized family of asymptotic classes is nowhere dense?
$begingroup$
Upon writing this post, I had the following natural conjecture:
$
defnn{mathbb{N}}
defrr{mathbb{R}}
$
Take any family ${ C_r : rinrr }$ of functions from $nn$ to $rr$ where $0 < C_s(n) ll C_t(n)$ as $n to infty$ for every $s,t in rr$ such that $s < t$. Then for every $r in rr$ there is some function $D_r$ from $nn$ to $rr$ such that for every $ε in rr^+$ we have $C_r(n) ll D_r(n) ll C_{r+ε}(n)$ as $n to infty$. (By considering the reciprocal family this immediately implies the other side as well.)
Intuitively, I claim that there will always be some asymptotic class that falls between the cracks of any linearly-ordered real-parametrized family of asymptotic classes. I think that this is equivalent to the stronger claim of nowhere-denseness, but I am not sure.
For example:
If $C_r(n) = n^r$ for every $r in rr$ and $r in nn$, then $D_r$ where $D_r(n) = n^r·ln(n)$ for every $n in nn$ provides a suitable witness, since $n^0 ll ln(n) ll n^ε$ as $n to infty$ for every $ε in rr^+$.
If $C_r(n) = r^n$ for every $r in rr$ and $r in nn$, then $D_r$ where $D_r(n) = n^r·n$ for every $n in nn$ provides a suitable witness, since $r^0 ll n ll (1+frac{ε}{r})^n$ as $n to infty$ for every $ε in rr^+$.
It is easy to show that $C$ has strict upper and lower bounds since $C_{-n}(n) ll C_r(n) ll C_n(n)$ as $n to infty$ for every $r in rr$. But I cannot find a general way to construct 'in-between' functions. I know that $C_{r+frac1n}(n) ll C_{r+ε}(n)$ as $n to infty$ for every $r in rr$ and $ε in rr^+$, but it is possible that $C_{r+frac1n}(n) sim C_r(n)$, as is indeed the case in both the above examples.
Is my conjecture true? If so, it suffices to prove that $C_0(n) ll D_0(n) ll C_ε(n)$ as $n to infty$ for some function $D_0$ from $nn$ to $rr$, since the general claim follows by translation. If not, it suffices to prove that for some family $C$ there is no such $D_0$, again due to translation.
real-analysis general-topology asymptotics order-theory
$endgroup$
add a comment |
$begingroup$
Upon writing this post, I had the following natural conjecture:
$
defnn{mathbb{N}}
defrr{mathbb{R}}
$
Take any family ${ C_r : rinrr }$ of functions from $nn$ to $rr$ where $0 < C_s(n) ll C_t(n)$ as $n to infty$ for every $s,t in rr$ such that $s < t$. Then for every $r in rr$ there is some function $D_r$ from $nn$ to $rr$ such that for every $ε in rr^+$ we have $C_r(n) ll D_r(n) ll C_{r+ε}(n)$ as $n to infty$. (By considering the reciprocal family this immediately implies the other side as well.)
Intuitively, I claim that there will always be some asymptotic class that falls between the cracks of any linearly-ordered real-parametrized family of asymptotic classes. I think that this is equivalent to the stronger claim of nowhere-denseness, but I am not sure.
For example:
If $C_r(n) = n^r$ for every $r in rr$ and $r in nn$, then $D_r$ where $D_r(n) = n^r·ln(n)$ for every $n in nn$ provides a suitable witness, since $n^0 ll ln(n) ll n^ε$ as $n to infty$ for every $ε in rr^+$.
If $C_r(n) = r^n$ for every $r in rr$ and $r in nn$, then $D_r$ where $D_r(n) = n^r·n$ for every $n in nn$ provides a suitable witness, since $r^0 ll n ll (1+frac{ε}{r})^n$ as $n to infty$ for every $ε in rr^+$.
It is easy to show that $C$ has strict upper and lower bounds since $C_{-n}(n) ll C_r(n) ll C_n(n)$ as $n to infty$ for every $r in rr$. But I cannot find a general way to construct 'in-between' functions. I know that $C_{r+frac1n}(n) ll C_{r+ε}(n)$ as $n to infty$ for every $r in rr$ and $ε in rr^+$, but it is possible that $C_{r+frac1n}(n) sim C_r(n)$, as is indeed the case in both the above examples.
Is my conjecture true? If so, it suffices to prove that $C_0(n) ll D_0(n) ll C_ε(n)$ as $n to infty$ for some function $D_0$ from $nn$ to $rr$, since the general claim follows by translation. If not, it suffices to prove that for some family $C$ there is no such $D_0$, again due to translation.
real-analysis general-topology asymptotics order-theory
$endgroup$
$begingroup$
You'll want to look at Gordon Fisher's 1981 paper The infinite and infinitesimal quantities of du Bois-Reymond and their reception and Hausdorff gaps (see this survey).
$endgroup$
– Dave L. Renfro
Jan 16 '18 at 17:56
$begingroup$
@DaveL.Renfro: If you have an answer to my question, could you kindly post an answer that doesn't rely on links or articles hidden behind a great paywall? Thank you!
$endgroup$
– user21820
Jan 17 '18 at 2:02
$begingroup$
I've been too busy at work lately (non-academic) to spend time trying to dig into this topic, but maybe the following will help. First, even if you can't visit a library to access the Gordon Fisher paper (my copy is a photocopy I made back in the late 1980s; I don't have online access either), the title of the paper itself provides words and phrases you can use in searches for relevant work and for books/papers that cite Fisher's paper. Second, Math Origins: Orders of Growth at the MAA website should be useful.
$endgroup$
– Dave L. Renfro
Jan 23 '18 at 11:11
$begingroup$
@DaveL.Renfro: Thanks for that! I'm too busy these few weeks to have time for mathematical research, but I'll try to get to them eventually. I took a look at the last link you provided, and I already know everything on that page, I think.
$endgroup$
– user21820
Jan 23 '18 at 14:32
add a comment |
$begingroup$
Upon writing this post, I had the following natural conjecture:
$
defnn{mathbb{N}}
defrr{mathbb{R}}
$
Take any family ${ C_r : rinrr }$ of functions from $nn$ to $rr$ where $0 < C_s(n) ll C_t(n)$ as $n to infty$ for every $s,t in rr$ such that $s < t$. Then for every $r in rr$ there is some function $D_r$ from $nn$ to $rr$ such that for every $ε in rr^+$ we have $C_r(n) ll D_r(n) ll C_{r+ε}(n)$ as $n to infty$. (By considering the reciprocal family this immediately implies the other side as well.)
Intuitively, I claim that there will always be some asymptotic class that falls between the cracks of any linearly-ordered real-parametrized family of asymptotic classes. I think that this is equivalent to the stronger claim of nowhere-denseness, but I am not sure.
For example:
If $C_r(n) = n^r$ for every $r in rr$ and $r in nn$, then $D_r$ where $D_r(n) = n^r·ln(n)$ for every $n in nn$ provides a suitable witness, since $n^0 ll ln(n) ll n^ε$ as $n to infty$ for every $ε in rr^+$.
If $C_r(n) = r^n$ for every $r in rr$ and $r in nn$, then $D_r$ where $D_r(n) = n^r·n$ for every $n in nn$ provides a suitable witness, since $r^0 ll n ll (1+frac{ε}{r})^n$ as $n to infty$ for every $ε in rr^+$.
It is easy to show that $C$ has strict upper and lower bounds since $C_{-n}(n) ll C_r(n) ll C_n(n)$ as $n to infty$ for every $r in rr$. But I cannot find a general way to construct 'in-between' functions. I know that $C_{r+frac1n}(n) ll C_{r+ε}(n)$ as $n to infty$ for every $r in rr$ and $ε in rr^+$, but it is possible that $C_{r+frac1n}(n) sim C_r(n)$, as is indeed the case in both the above examples.
Is my conjecture true? If so, it suffices to prove that $C_0(n) ll D_0(n) ll C_ε(n)$ as $n to infty$ for some function $D_0$ from $nn$ to $rr$, since the general claim follows by translation. If not, it suffices to prove that for some family $C$ there is no such $D_0$, again due to translation.
real-analysis general-topology asymptotics order-theory
$endgroup$
Upon writing this post, I had the following natural conjecture:
$
defnn{mathbb{N}}
defrr{mathbb{R}}
$
Take any family ${ C_r : rinrr }$ of functions from $nn$ to $rr$ where $0 < C_s(n) ll C_t(n)$ as $n to infty$ for every $s,t in rr$ such that $s < t$. Then for every $r in rr$ there is some function $D_r$ from $nn$ to $rr$ such that for every $ε in rr^+$ we have $C_r(n) ll D_r(n) ll C_{r+ε}(n)$ as $n to infty$. (By considering the reciprocal family this immediately implies the other side as well.)
Intuitively, I claim that there will always be some asymptotic class that falls between the cracks of any linearly-ordered real-parametrized family of asymptotic classes. I think that this is equivalent to the stronger claim of nowhere-denseness, but I am not sure.
For example:
If $C_r(n) = n^r$ for every $r in rr$ and $r in nn$, then $D_r$ where $D_r(n) = n^r·ln(n)$ for every $n in nn$ provides a suitable witness, since $n^0 ll ln(n) ll n^ε$ as $n to infty$ for every $ε in rr^+$.
If $C_r(n) = r^n$ for every $r in rr$ and $r in nn$, then $D_r$ where $D_r(n) = n^r·n$ for every $n in nn$ provides a suitable witness, since $r^0 ll n ll (1+frac{ε}{r})^n$ as $n to infty$ for every $ε in rr^+$.
It is easy to show that $C$ has strict upper and lower bounds since $C_{-n}(n) ll C_r(n) ll C_n(n)$ as $n to infty$ for every $r in rr$. But I cannot find a general way to construct 'in-between' functions. I know that $C_{r+frac1n}(n) ll C_{r+ε}(n)$ as $n to infty$ for every $r in rr$ and $ε in rr^+$, but it is possible that $C_{r+frac1n}(n) sim C_r(n)$, as is indeed the case in both the above examples.
Is my conjecture true? If so, it suffices to prove that $C_0(n) ll D_0(n) ll C_ε(n)$ as $n to infty$ for some function $D_0$ from $nn$ to $rr$, since the general claim follows by translation. If not, it suffices to prove that for some family $C$ there is no such $D_0$, again due to translation.
real-analysis general-topology asymptotics order-theory
real-analysis general-topology asymptotics order-theory
asked Jan 16 '18 at 11:53
user21820user21820
40.2k544162
40.2k544162
$begingroup$
You'll want to look at Gordon Fisher's 1981 paper The infinite and infinitesimal quantities of du Bois-Reymond and their reception and Hausdorff gaps (see this survey).
$endgroup$
– Dave L. Renfro
Jan 16 '18 at 17:56
$begingroup$
@DaveL.Renfro: If you have an answer to my question, could you kindly post an answer that doesn't rely on links or articles hidden behind a great paywall? Thank you!
$endgroup$
– user21820
Jan 17 '18 at 2:02
$begingroup$
I've been too busy at work lately (non-academic) to spend time trying to dig into this topic, but maybe the following will help. First, even if you can't visit a library to access the Gordon Fisher paper (my copy is a photocopy I made back in the late 1980s; I don't have online access either), the title of the paper itself provides words and phrases you can use in searches for relevant work and for books/papers that cite Fisher's paper. Second, Math Origins: Orders of Growth at the MAA website should be useful.
$endgroup$
– Dave L. Renfro
Jan 23 '18 at 11:11
$begingroup$
@DaveL.Renfro: Thanks for that! I'm too busy these few weeks to have time for mathematical research, but I'll try to get to them eventually. I took a look at the last link you provided, and I already know everything on that page, I think.
$endgroup$
– user21820
Jan 23 '18 at 14:32
add a comment |
$begingroup$
You'll want to look at Gordon Fisher's 1981 paper The infinite and infinitesimal quantities of du Bois-Reymond and their reception and Hausdorff gaps (see this survey).
$endgroup$
– Dave L. Renfro
Jan 16 '18 at 17:56
$begingroup$
@DaveL.Renfro: If you have an answer to my question, could you kindly post an answer that doesn't rely on links or articles hidden behind a great paywall? Thank you!
$endgroup$
– user21820
Jan 17 '18 at 2:02
$begingroup$
I've been too busy at work lately (non-academic) to spend time trying to dig into this topic, but maybe the following will help. First, even if you can't visit a library to access the Gordon Fisher paper (my copy is a photocopy I made back in the late 1980s; I don't have online access either), the title of the paper itself provides words and phrases you can use in searches for relevant work and for books/papers that cite Fisher's paper. Second, Math Origins: Orders of Growth at the MAA website should be useful.
$endgroup$
– Dave L. Renfro
Jan 23 '18 at 11:11
$begingroup$
@DaveL.Renfro: Thanks for that! I'm too busy these few weeks to have time for mathematical research, but I'll try to get to them eventually. I took a look at the last link you provided, and I already know everything on that page, I think.
$endgroup$
– user21820
Jan 23 '18 at 14:32
$begingroup$
You'll want to look at Gordon Fisher's 1981 paper The infinite and infinitesimal quantities of du Bois-Reymond and their reception and Hausdorff gaps (see this survey).
$endgroup$
– Dave L. Renfro
Jan 16 '18 at 17:56
$begingroup$
You'll want to look at Gordon Fisher's 1981 paper The infinite and infinitesimal quantities of du Bois-Reymond and their reception and Hausdorff gaps (see this survey).
$endgroup$
– Dave L. Renfro
Jan 16 '18 at 17:56
$begingroup$
@DaveL.Renfro: If you have an answer to my question, could you kindly post an answer that doesn't rely on links or articles hidden behind a great paywall? Thank you!
$endgroup$
– user21820
Jan 17 '18 at 2:02
$begingroup$
@DaveL.Renfro: If you have an answer to my question, could you kindly post an answer that doesn't rely on links or articles hidden behind a great paywall? Thank you!
$endgroup$
– user21820
Jan 17 '18 at 2:02
$begingroup$
I've been too busy at work lately (non-academic) to spend time trying to dig into this topic, but maybe the following will help. First, even if you can't visit a library to access the Gordon Fisher paper (my copy is a photocopy I made back in the late 1980s; I don't have online access either), the title of the paper itself provides words and phrases you can use in searches for relevant work and for books/papers that cite Fisher's paper. Second, Math Origins: Orders of Growth at the MAA website should be useful.
$endgroup$
– Dave L. Renfro
Jan 23 '18 at 11:11
$begingroup$
I've been too busy at work lately (non-academic) to spend time trying to dig into this topic, but maybe the following will help. First, even if you can't visit a library to access the Gordon Fisher paper (my copy is a photocopy I made back in the late 1980s; I don't have online access either), the title of the paper itself provides words and phrases you can use in searches for relevant work and for books/papers that cite Fisher's paper. Second, Math Origins: Orders of Growth at the MAA website should be useful.
$endgroup$
– Dave L. Renfro
Jan 23 '18 at 11:11
$begingroup$
@DaveL.Renfro: Thanks for that! I'm too busy these few weeks to have time for mathematical research, but I'll try to get to them eventually. I took a look at the last link you provided, and I already know everything on that page, I think.
$endgroup$
– user21820
Jan 23 '18 at 14:32
$begingroup$
@DaveL.Renfro: Thanks for that! I'm too busy these few weeks to have time for mathematical research, but I'll try to get to them eventually. I took a look at the last link you provided, and I already know everything on that page, I think.
$endgroup$
– user21820
Jan 23 '18 at 14:32
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
You can diagonalize to find a sequence asymptotically bigger than $C_{r}$ but asymptotically smaller than $C_{r+epsilon}$ for any $epsilon>0$.
Fix $r$. Define $d_r(n)$ to be the greatest positive integer such that $C_{r+1/j}(n')/C_r(n')ge d_r(n)$ for all positive integer $j le d_r(n)$ and $n'ge n$, or $d_r(n)=1$ if none exists. Take $D_r(n)=C_r(n)d_r(n)$.
For any positive integer $j$, either $j le d_r(n)$ or $d_r(n) le j$, so by construction $D_r(n) le C_{r+1/j}(n)$ or $D_r(n) le j·C_r(n)$ as $n to infty$. Therefore $D_rll C_{r+epsilon}$ for any $epsilon>0.$
I claim that $d_r(n)toinfty$ as $ntoinfty$.
For any fixed positive integer $Delta$, from the conjunction of $C_rll C_{r+1/j}$ for positive integer $j le Delta$, there is a large enough $n$ such that for all $jleDelta$ and $n'ge n$ we have $C_{r+1/j}(n')/C_r(n')geDelta$. For this $n$ we have $d_r(n) ge Delta$. And $d_r$ is clearly non-decreasing. So $d_r$ tends to $infty$. Therefore $C_rll D_r$.
$endgroup$
$begingroup$
Thanks! I edited to add a bit of missing detail. =)
$endgroup$
– user21820
Dec 29 '18 at 17:02
add a comment |
Your Answer
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2607647%2fevery-linearly-ordered-real-parametrized-family-of-asymptotic-classes-is-nowhere%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You can diagonalize to find a sequence asymptotically bigger than $C_{r}$ but asymptotically smaller than $C_{r+epsilon}$ for any $epsilon>0$.
Fix $r$. Define $d_r(n)$ to be the greatest positive integer such that $C_{r+1/j}(n')/C_r(n')ge d_r(n)$ for all positive integer $j le d_r(n)$ and $n'ge n$, or $d_r(n)=1$ if none exists. Take $D_r(n)=C_r(n)d_r(n)$.
For any positive integer $j$, either $j le d_r(n)$ or $d_r(n) le j$, so by construction $D_r(n) le C_{r+1/j}(n)$ or $D_r(n) le j·C_r(n)$ as $n to infty$. Therefore $D_rll C_{r+epsilon}$ for any $epsilon>0.$
I claim that $d_r(n)toinfty$ as $ntoinfty$.
For any fixed positive integer $Delta$, from the conjunction of $C_rll C_{r+1/j}$ for positive integer $j le Delta$, there is a large enough $n$ such that for all $jleDelta$ and $n'ge n$ we have $C_{r+1/j}(n')/C_r(n')geDelta$. For this $n$ we have $d_r(n) ge Delta$. And $d_r$ is clearly non-decreasing. So $d_r$ tends to $infty$. Therefore $C_rll D_r$.
$endgroup$
$begingroup$
Thanks! I edited to add a bit of missing detail. =)
$endgroup$
– user21820
Dec 29 '18 at 17:02
add a comment |
$begingroup$
You can diagonalize to find a sequence asymptotically bigger than $C_{r}$ but asymptotically smaller than $C_{r+epsilon}$ for any $epsilon>0$.
Fix $r$. Define $d_r(n)$ to be the greatest positive integer such that $C_{r+1/j}(n')/C_r(n')ge d_r(n)$ for all positive integer $j le d_r(n)$ and $n'ge n$, or $d_r(n)=1$ if none exists. Take $D_r(n)=C_r(n)d_r(n)$.
For any positive integer $j$, either $j le d_r(n)$ or $d_r(n) le j$, so by construction $D_r(n) le C_{r+1/j}(n)$ or $D_r(n) le j·C_r(n)$ as $n to infty$. Therefore $D_rll C_{r+epsilon}$ for any $epsilon>0.$
I claim that $d_r(n)toinfty$ as $ntoinfty$.
For any fixed positive integer $Delta$, from the conjunction of $C_rll C_{r+1/j}$ for positive integer $j le Delta$, there is a large enough $n$ such that for all $jleDelta$ and $n'ge n$ we have $C_{r+1/j}(n')/C_r(n')geDelta$. For this $n$ we have $d_r(n) ge Delta$. And $d_r$ is clearly non-decreasing. So $d_r$ tends to $infty$. Therefore $C_rll D_r$.
$endgroup$
$begingroup$
Thanks! I edited to add a bit of missing detail. =)
$endgroup$
– user21820
Dec 29 '18 at 17:02
add a comment |
$begingroup$
You can diagonalize to find a sequence asymptotically bigger than $C_{r}$ but asymptotically smaller than $C_{r+epsilon}$ for any $epsilon>0$.
Fix $r$. Define $d_r(n)$ to be the greatest positive integer such that $C_{r+1/j}(n')/C_r(n')ge d_r(n)$ for all positive integer $j le d_r(n)$ and $n'ge n$, or $d_r(n)=1$ if none exists. Take $D_r(n)=C_r(n)d_r(n)$.
For any positive integer $j$, either $j le d_r(n)$ or $d_r(n) le j$, so by construction $D_r(n) le C_{r+1/j}(n)$ or $D_r(n) le j·C_r(n)$ as $n to infty$. Therefore $D_rll C_{r+epsilon}$ for any $epsilon>0.$
I claim that $d_r(n)toinfty$ as $ntoinfty$.
For any fixed positive integer $Delta$, from the conjunction of $C_rll C_{r+1/j}$ for positive integer $j le Delta$, there is a large enough $n$ such that for all $jleDelta$ and $n'ge n$ we have $C_{r+1/j}(n')/C_r(n')geDelta$. For this $n$ we have $d_r(n) ge Delta$. And $d_r$ is clearly non-decreasing. So $d_r$ tends to $infty$. Therefore $C_rll D_r$.
$endgroup$
You can diagonalize to find a sequence asymptotically bigger than $C_{r}$ but asymptotically smaller than $C_{r+epsilon}$ for any $epsilon>0$.
Fix $r$. Define $d_r(n)$ to be the greatest positive integer such that $C_{r+1/j}(n')/C_r(n')ge d_r(n)$ for all positive integer $j le d_r(n)$ and $n'ge n$, or $d_r(n)=1$ if none exists. Take $D_r(n)=C_r(n)d_r(n)$.
For any positive integer $j$, either $j le d_r(n)$ or $d_r(n) le j$, so by construction $D_r(n) le C_{r+1/j}(n)$ or $D_r(n) le j·C_r(n)$ as $n to infty$. Therefore $D_rll C_{r+epsilon}$ for any $epsilon>0.$
I claim that $d_r(n)toinfty$ as $ntoinfty$.
For any fixed positive integer $Delta$, from the conjunction of $C_rll C_{r+1/j}$ for positive integer $j le Delta$, there is a large enough $n$ such that for all $jleDelta$ and $n'ge n$ we have $C_{r+1/j}(n')/C_r(n')geDelta$. For this $n$ we have $d_r(n) ge Delta$. And $d_r$ is clearly non-decreasing. So $d_r$ tends to $infty$. Therefore $C_rll D_r$.
edited Dec 29 '18 at 17:02
user21820
40.2k544162
40.2k544162
answered Dec 28 '18 at 8:57
DapDap
19.8k842
19.8k842
$begingroup$
Thanks! I edited to add a bit of missing detail. =)
$endgroup$
– user21820
Dec 29 '18 at 17:02
add a comment |
$begingroup$
Thanks! I edited to add a bit of missing detail. =)
$endgroup$
– user21820
Dec 29 '18 at 17:02
$begingroup$
Thanks! I edited to add a bit of missing detail. =)
$endgroup$
– user21820
Dec 29 '18 at 17:02
$begingroup$
Thanks! I edited to add a bit of missing detail. =)
$endgroup$
– user21820
Dec 29 '18 at 17:02
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2607647%2fevery-linearly-ordered-real-parametrized-family-of-asymptotic-classes-is-nowhere%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
You'll want to look at Gordon Fisher's 1981 paper The infinite and infinitesimal quantities of du Bois-Reymond and their reception and Hausdorff gaps (see this survey).
$endgroup$
– Dave L. Renfro
Jan 16 '18 at 17:56
$begingroup$
@DaveL.Renfro: If you have an answer to my question, could you kindly post an answer that doesn't rely on links or articles hidden behind a great paywall? Thank you!
$endgroup$
– user21820
Jan 17 '18 at 2:02
$begingroup$
I've been too busy at work lately (non-academic) to spend time trying to dig into this topic, but maybe the following will help. First, even if you can't visit a library to access the Gordon Fisher paper (my copy is a photocopy I made back in the late 1980s; I don't have online access either), the title of the paper itself provides words and phrases you can use in searches for relevant work and for books/papers that cite Fisher's paper. Second, Math Origins: Orders of Growth at the MAA website should be useful.
$endgroup$
– Dave L. Renfro
Jan 23 '18 at 11:11
$begingroup$
@DaveL.Renfro: Thanks for that! I'm too busy these few weeks to have time for mathematical research, but I'll try to get to them eventually. I took a look at the last link you provided, and I already know everything on that page, I think.
$endgroup$
– user21820
Jan 23 '18 at 14:32