Constraints in SVM optimization problem

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I am studying SVM optimization problem for SMO algorithm.
When we are constructing optimization problem, we say, that we are searching for such separating hyperplane, so that we rescale $w$ and $b$, so that $|w^T x + b|=1$ for those points in each class nearest to the hyperplane.
After the rescaling, the distance from the nearest point in each class to the hyperplane is $frac{1}{||W||}$.



So we state optimization problem



$$min_{ w, b} frac{1}{2}{||W||^2}$$
s.t. :
$$y^{(i)}(w^Tx^{(i)}+b)geq 1, i=1,dots m.$$



Question: I don't see which constraint ensures, that for the nearest point to hyperplane in each class is going to hold $y^i(w^Tx^{(i)}+b)= 1$. I understand that there will be some point for which $y^{(i)}(w^Tx^{(i)}+b)=1$, but I don't understand which constraint ensures that on both sides of margin there will be such point.



I think I don't understand something simple here. If you have any explanation for this I would appreciate it very much.










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    $begingroup$


    I am studying SVM optimization problem for SMO algorithm.
    When we are constructing optimization problem, we say, that we are searching for such separating hyperplane, so that we rescale $w$ and $b$, so that $|w^T x + b|=1$ for those points in each class nearest to the hyperplane.
    After the rescaling, the distance from the nearest point in each class to the hyperplane is $frac{1}{||W||}$.



    So we state optimization problem



    $$min_{ w, b} frac{1}{2}{||W||^2}$$
    s.t. :
    $$y^{(i)}(w^Tx^{(i)}+b)geq 1, i=1,dots m.$$



    Question: I don't see which constraint ensures, that for the nearest point to hyperplane in each class is going to hold $y^i(w^Tx^{(i)}+b)= 1$. I understand that there will be some point for which $y^{(i)}(w^Tx^{(i)}+b)=1$, but I don't understand which constraint ensures that on both sides of margin there will be such point.



    I think I don't understand something simple here. If you have any explanation for this I would appreciate it very much.










    share|cite|improve this question









    $endgroup$















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      0





      $begingroup$


      I am studying SVM optimization problem for SMO algorithm.
      When we are constructing optimization problem, we say, that we are searching for such separating hyperplane, so that we rescale $w$ and $b$, so that $|w^T x + b|=1$ for those points in each class nearest to the hyperplane.
      After the rescaling, the distance from the nearest point in each class to the hyperplane is $frac{1}{||W||}$.



      So we state optimization problem



      $$min_{ w, b} frac{1}{2}{||W||^2}$$
      s.t. :
      $$y^{(i)}(w^Tx^{(i)}+b)geq 1, i=1,dots m.$$



      Question: I don't see which constraint ensures, that for the nearest point to hyperplane in each class is going to hold $y^i(w^Tx^{(i)}+b)= 1$. I understand that there will be some point for which $y^{(i)}(w^Tx^{(i)}+b)=1$, but I don't understand which constraint ensures that on both sides of margin there will be such point.



      I think I don't understand something simple here. If you have any explanation for this I would appreciate it very much.










      share|cite|improve this question









      $endgroup$




      I am studying SVM optimization problem for SMO algorithm.
      When we are constructing optimization problem, we say, that we are searching for such separating hyperplane, so that we rescale $w$ and $b$, so that $|w^T x + b|=1$ for those points in each class nearest to the hyperplane.
      After the rescaling, the distance from the nearest point in each class to the hyperplane is $frac{1}{||W||}$.



      So we state optimization problem



      $$min_{ w, b} frac{1}{2}{||W||^2}$$
      s.t. :
      $$y^{(i)}(w^Tx^{(i)}+b)geq 1, i=1,dots m.$$



      Question: I don't see which constraint ensures, that for the nearest point to hyperplane in each class is going to hold $y^i(w^Tx^{(i)}+b)= 1$. I understand that there will be some point for which $y^{(i)}(w^Tx^{(i)}+b)=1$, but I don't understand which constraint ensures that on both sides of margin there will be such point.



      I think I don't understand something simple here. If you have any explanation for this I would appreciate it very much.







      optimization machine-learning






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      asked Dec 28 '18 at 9:23









      User1999User1999

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