how to hide a component if all sub-components are hidden ngIf
For example consider the code:
<div *ngIf="-------NOTEMPTY-------">
Parent
<div *ngFor = 'let child of offsprings'>
<div name="c1" *ngIf="conditions[child.name]">
Child0
</div>
</div>
</div>
I want Parent division's ngIf to be false if all its child divisions' ngIf are false.
Note : It is not possible to me to collect all the child conditions in the ts file.
javascript
angular typescript ngif add a comment |
For example consider the code:
<div *ngIf="-------NOTEMPTY-------">
Parent
<div *ngFor = 'let child of offsprings'>
<div name="c1" *ngIf="conditions[child.name]">
Child0
</div>
</div>
</div>
I want Parent division's ngIf to be false if all its child divisions' ngIf are false.
Note : It is not possible to me to collect all the child conditions in the ts file.
javascript
angular typescript ngif
offsprings.every(c => !c.condition)
– bugs
Nov 21 '18 at 10:13
add a comment |
For example consider the code:
<div *ngIf="-------NOTEMPTY-------">
Parent
<div *ngFor = 'let child of offsprings'>
<div name="c1" *ngIf="conditions[child.name]">
Child0
</div>
</div>
</div>
I want Parent division's ngIf to be false if all its child divisions' ngIf are false.
Note : It is not possible to me to collect all the child conditions in the ts file.
javascript
angular typescript ngif For example consider the code:
<div *ngIf="-------NOTEMPTY-------">
Parent
<div *ngFor = 'let child of offsprings'>
<div name="c1" *ngIf="conditions[child.name]">
Child0
</div>
</div>
</div>
I want Parent division's ngIf to be false if all its child divisions' ngIf are false.
Note : It is not possible to me to collect all the child conditions in the ts file.
javascript
angular typescript ngif javascript
angular typescript ngif edited Nov 21 '18 at 10:46
asked Nov 21 '18 at 10:10
user8401765
offsprings.every(c => !c.condition)
– bugs
Nov 21 '18 at 10:13
add a comment |
offsprings.every(c => !c.condition)
– bugs
Nov 21 '18 at 10:13
offsprings.every(c => !c.condition)– bugs
Nov 21 '18 at 10:13
offsprings.every(c => !c.condition)– bugs
Nov 21 '18 at 10:13
add a comment |
2 Answers
2
active
oldest
votes
Try adding in the Parent *ngIf condition
!offsprings.every(child => !conditions[child.name]);
answered Nov 21 '18 at 10:13
Nil LlisterriNil Llisterri
452415
Edited the answer to search the condition in the conditions map
– Nil Llisterri
Nov 21 '18 at 11:00
add a comment |
Used a function call as *ngIf = checkIfExists() on parent.
<div *ngIf="checkIfExists()">
Parent with children existing
<div *ngFor = 'let child of offsprings'>
<div name="c1" *ngIf="conditions[child.name]">
Child0 {{conditions[child.name]}}
</div>
</div>
</div>
Function For Parent ngIf:
Appraoch is to traverse every element of offsprings array,
and check if conditions[child.name] exists.
checkIfExists() {
let ifDefined: boolean;
this.offsprings.forEach(e=> {
if (this.conditions[e.name]) {
ifDefined = true;
}
});
return ifDefined;
}
StackBlitz Working Demo
answered Nov 21 '18 at 11:41
Abhishek KumarAbhishek Kumar
1,165416
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Try adding in the Parent *ngIf condition
!offsprings.every(child => !conditions[child.name]);
answered Nov 21 '18 at 10:13
Nil LlisterriNil Llisterri
452415
Edited the answer to search the condition in the conditions map
– Nil Llisterri
Nov 21 '18 at 11:00
add a comment |
Try adding in the Parent *ngIf condition
!offsprings.every(child => !conditions[child.name]);
answered Nov 21 '18 at 10:13
Nil LlisterriNil Llisterri
452415
Edited the answer to search the condition in the conditions map
– Nil Llisterri
Nov 21 '18 at 11:00
add a comment |
Try adding in the Parent *ngIf condition
!offsprings.every(child => !conditions[child.name]);
answered Nov 21 '18 at 10:13
Nil LlisterriNil Llisterri
452415
Try adding in the Parent *ngIf condition
!offsprings.every(child => !conditions[child.name]);
answered Nov 21 '18 at 10:13
Nil LlisterriNil Llisterri
452415
edited Nov 21 '18 at 10:56
answered Nov 21 '18 at 10:13
Nil LlisterriNil Llisterri
452415
answered Nov 21 '18 at 10:13
Nil LlisterriNil Llisterri
452415
answered Nov 21 '18 at 10:13
Nil LlisterriNil Llisterri
452415
452415
Edited the answer to search the condition in the conditions map
– Nil Llisterri
Nov 21 '18 at 11:00
add a comment |
Edited the answer to search the condition in the conditions map
– Nil Llisterri
Nov 21 '18 at 11:00
Edited the answer to search the condition in the conditions map
– Nil Llisterri
Nov 21 '18 at 11:00
Edited the answer to search the condition in the conditions map
– Nil Llisterri
Nov 21 '18 at 11:00
add a comment |
Used a function call as *ngIf = checkIfExists() on parent.
<div *ngIf="checkIfExists()">
Parent with children existing
<div *ngFor = 'let child of offsprings'>
<div name="c1" *ngIf="conditions[child.name]">
Child0 {{conditions[child.name]}}
</div>
</div>
</div>
Function For Parent ngIf:
Appraoch is to traverse every element of offsprings array,
and check if conditions[child.name] exists.
checkIfExists() {
let ifDefined: boolean;
this.offsprings.forEach(e=> {
if (this.conditions[e.name]) {
ifDefined = true;
}
});
return ifDefined;
}
StackBlitz Working Demo
answered Nov 21 '18 at 11:41
Abhishek KumarAbhishek Kumar
1,165416
add a comment |
Used a function call as *ngIf = checkIfExists() on parent.
<div *ngIf="checkIfExists()">
Parent with children existing
<div *ngFor = 'let child of offsprings'>
<div name="c1" *ngIf="conditions[child.name]">
Child0 {{conditions[child.name]}}
</div>
</div>
</div>
Function For Parent ngIf:
Appraoch is to traverse every element of offsprings array,
and check if conditions[child.name] exists.
checkIfExists() {
let ifDefined: boolean;
this.offsprings.forEach(e=> {
if (this.conditions[e.name]) {
ifDefined = true;
}
});
return ifDefined;
}
StackBlitz Working Demo
answered Nov 21 '18 at 11:41
Abhishek KumarAbhishek Kumar
1,165416
add a comment |
Used a function call as *ngIf = checkIfExists() on parent.
<div *ngIf="checkIfExists()">
Parent with children existing
<div *ngFor = 'let child of offsprings'>
<div name="c1" *ngIf="conditions[child.name]">
Child0 {{conditions[child.name]}}
</div>
</div>
</div>
Function For Parent ngIf:
Appraoch is to traverse every element of offsprings array,
and check if conditions[child.name] exists.
checkIfExists() {
let ifDefined: boolean;
this.offsprings.forEach(e=> {
if (this.conditions[e.name]) {
ifDefined = true;
}
});
return ifDefined;
}
StackBlitz Working Demo
answered Nov 21 '18 at 11:41
Abhishek KumarAbhishek Kumar
1,165416
Used a function call as *ngIf = checkIfExists() on parent.
<div *ngIf="checkIfExists()">
Parent with children existing
<div *ngFor = 'let child of offsprings'>
<div name="c1" *ngIf="conditions[child.name]">
Child0 {{conditions[child.name]}}
</div>
</div>
</div>
Function For Parent ngIf:
Appraoch is to traverse every element of offsprings array,
and check if conditions[child.name] exists.
checkIfExists() {
let ifDefined: boolean;
this.offsprings.forEach(e=> {
if (this.conditions[e.name]) {
ifDefined = true;
}
});
return ifDefined;
}
StackBlitz Working Demo
answered Nov 21 '18 at 11:41
Abhishek KumarAbhishek Kumar
1,165416
answered Nov 21 '18 at 11:41
Abhishek KumarAbhishek Kumar
1,165416
answered Nov 21 '18 at 11:41
Abhishek KumarAbhishek Kumar
1,165416
answered Nov 21 '18 at 11:41
Abhishek KumarAbhishek Kumar
1,165416
1,165416
add a comment |
add a comment |
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offsprings.every(c => !c.condition)– bugs
Nov 21 '18 at 10:13