How to change the rotation of the angle with tikz

I have the following code:

documentclass{article}



usepackage{tikz}

usetikzlibrary{calc,patterns,angles,quotes}



begin{document}

begin{figure}

begin{tikzpicture}[scale=1]

node (x1)  at (0, 0, 0) {};

node (x2)  at (2, 0, 0) {};

node (x3)  at (3.45, 1.45, 0) {};

node (x4)  at (4, 0, 0) {};

shade [ball color=black] (x1) circle (0.15);

shade [ball color=black] (x2) circle (0.15);

shade [ball color=black] (x3) circle (0.15);

shade [ball color=gray] (x4) circle (0.15);

draw (x1) -- (x2) -- (x3);

draw[gray] (x1) -- (x2) -- (x4);

draw[gray,dashed] (4, 0, 0) arc (0:26:3cm);

pic [draw, ->, "$theta$", angle eccentricity=1.5] {angle = x1--x2--x3};

end{tikzpicture}

end{figure}

end{document}

I get the following figure:

enter image description here

But I want the rotation of the angle arrow to be the opposite. Any help is appreciated.

edited Mar 16 at 15:02

asked Mar 16 at 14:57

beliz

277

add a comment |

I have the following code:

documentclass{article}



usepackage{tikz}

usetikzlibrary{calc,patterns,angles,quotes}



begin{document}

begin{figure}

begin{tikzpicture}[scale=1]

node (x1)  at (0, 0, 0) {};

node (x2)  at (2, 0, 0) {};

node (x3)  at (3.45, 1.45, 0) {};

node (x4)  at (4, 0, 0) {};

shade [ball color=black] (x1) circle (0.15);

shade [ball color=black] (x2) circle (0.15);

shade [ball color=black] (x3) circle (0.15);

shade [ball color=gray] (x4) circle (0.15);

draw (x1) -- (x2) -- (x3);

draw[gray] (x1) -- (x2) -- (x4);

draw[gray,dashed] (4, 0, 0) arc (0:26:3cm);

pic [draw, ->, "$theta$", angle eccentricity=1.5] {angle = x1--x2--x3};

end{tikzpicture}

end{figure}

end{document}

I get the following figure:

enter image description here

But I want the rotation of the angle arrow to be the opposite. Any help is appreciated.

edited Mar 16 at 15:02

asked Mar 16 at 14:57

beliz

277

add a comment |

I have the following code:

documentclass{article}



usepackage{tikz}

usetikzlibrary{calc,patterns,angles,quotes}



begin{document}

begin{figure}

begin{tikzpicture}[scale=1]

node (x1)  at (0, 0, 0) {};

node (x2)  at (2, 0, 0) {};

node (x3)  at (3.45, 1.45, 0) {};

node (x4)  at (4, 0, 0) {};

shade [ball color=black] (x1) circle (0.15);

shade [ball color=black] (x2) circle (0.15);

shade [ball color=black] (x3) circle (0.15);

shade [ball color=gray] (x4) circle (0.15);

draw (x1) -- (x2) -- (x3);

draw[gray] (x1) -- (x2) -- (x4);

draw[gray,dashed] (4, 0, 0) arc (0:26:3cm);

pic [draw, ->, "$theta$", angle eccentricity=1.5] {angle = x1--x2--x3};

end{tikzpicture}

end{figure}

end{document}

I get the following figure:

enter image description here

But I want the rotation of the angle arrow to be the opposite. Any help is appreciated.

edited Mar 16 at 15:02

asked Mar 16 at 14:57

beliz

277

I have the following code:

documentclass{article}



usepackage{tikz}

usetikzlibrary{calc,patterns,angles,quotes}



begin{document}

begin{figure}

begin{tikzpicture}[scale=1]

node (x1)  at (0, 0, 0) {};

node (x2)  at (2, 0, 0) {};

node (x3)  at (3.45, 1.45, 0) {};

node (x4)  at (4, 0, 0) {};

shade [ball color=black] (x1) circle (0.15);

shade [ball color=black] (x2) circle (0.15);

shade [ball color=black] (x3) circle (0.15);

shade [ball color=gray] (x4) circle (0.15);

draw (x1) -- (x2) -- (x3);

draw[gray] (x1) -- (x2) -- (x4);

draw[gray,dashed] (4, 0, 0) arc (0:26:3cm);

pic [draw, ->, "$theta$", angle eccentricity=1.5] {angle = x1--x2--x3};

end{tikzpicture}

end{figure}

end{document}

I get the following figure:

enter image description here

But I want the rotation of the angle arrow to be the opposite. Any help is appreciated.

tikz-pgf

edited Mar 16 at 15:02

asked Mar 16 at 14:57

beliz

277

edited Mar 16 at 15:02

asked Mar 16 at 14:57

beliz

277

edited Mar 16 at 15:02

asked Mar 16 at 14:57

beliz

277

asked Mar 16 at 14:57

beliz

277

asked Mar 16 at 14:57

beliz

277

add a comment |

1 Answer
1

active

oldest

votes

As far as I know, pic makes angles anti-clockwise. Therefore, it should be x3--x2--x1 instead of x1--x2--x3.

By the way, option scale=1 is unnecessary.

documentclass[tikz]{standalone}

usetikzlibrary{calc,patterns,angles,quotes}



begin{document}

begin{tikzpicture}

node (x1)  at (0, 0, 0) {};

node (x2)  at (2, 0, 0) {};

node (x3)  at (3.45, 1.45, 0) {};

node (x4)  at (4, 0, 0) {};

shade [ball color=black] (x1) circle (0.15);

shade [ball color=black] (x2) circle (0.15);

shade [ball color=black] (x3) circle (0.15);

shade [ball color=gray] (x4) circle (0.15);

draw (x1) -- (x2) -- (x3);

draw[gray] (x1) -- (x2) -- (x4);

draw[gray,dashed] (4, 0, 0) arc (0:26:3cm);

pic [draw, <-, "$theta$", angle eccentricity=1.5] {angle = x3--x2--x1};

end{tikzpicture}

end{document}

enter image description here

Edit 1

Better version IMHO

documentclass[tikz]{standalone}

usetikzlibrary{calc,patterns,angles,quotes}



begin{document}

begin{tikzpicture}

node (x1)  at (0, 0, 0) {};

node (x2)  at (2, 0, 0) {};

node (x3)  at ({cos(26)*3+1}, {sin(26)*3}, 0) {};

node (x4)  at (4, 0, 0) {};

pic [draw, <-, "$theta$", angle eccentricity=1.5] {angle = x3--x2--x1};

draw (x1) -- (x2) -- (x3);

draw[gray] (x1) -- (x2) -- (x4);

draw[gray,dashed] (4, 0, 0) arc (0:26:3cm);

shade [ball color=black] (x1) circle (0.15);

shade [ball color=black] (x2) circle (0.15);

shade [ball color=black] (x3) circle (0.15);

shade [ball color=gray] (x4) circle (0.15);

end{tikzpicture}

end{document}

enter image description here

edited Mar 16 at 17:14

answered Mar 16 at 15:01

JouleV

7,89222053

Very nice :-). For my humble opinion the two gray horizontal segments should be in the background. So for the balls you don't see the dashes upstairs.

– Sebastiano
Mar 16 at 16:57

1

@Sebastiano Edited!

– JouleV
Mar 16 at 17:14

That's really good. I didn't know I could put cos and sin there. Thanks

– beliz
Mar 16 at 19:56

@beliz You are welcome.

– JouleV
Mar 17 at 4:14

add a comment |

Your Answer

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "85"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});

}
});

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f479797%2fhow-to-change-the-rotation-of-the-angle-with-tikz%23new-answer', 'question_page');
}
);

Post as a guest

Name

Required, but never shown

1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

As far as I know, pic makes angles anti-clockwise. Therefore, it should be x3--x2--x1 instead of x1--x2--x3.

By the way, option scale=1 is unnecessary.

documentclass[tikz]{standalone}

usetikzlibrary{calc,patterns,angles,quotes}



begin{document}

begin{tikzpicture}

node (x1)  at (0, 0, 0) {};

node (x2)  at (2, 0, 0) {};

node (x3)  at (3.45, 1.45, 0) {};

node (x4)  at (4, 0, 0) {};

shade [ball color=black] (x1) circle (0.15);

shade [ball color=black] (x2) circle (0.15);

shade [ball color=black] (x3) circle (0.15);

shade [ball color=gray] (x4) circle (0.15);

draw (x1) -- (x2) -- (x3);

draw[gray] (x1) -- (x2) -- (x4);

draw[gray,dashed] (4, 0, 0) arc (0:26:3cm);

pic [draw, <-, "$theta$", angle eccentricity=1.5] {angle = x3--x2--x1};

end{tikzpicture}

end{document}

enter image description here

Edit 1

Better version IMHO

documentclass[tikz]{standalone}

usetikzlibrary{calc,patterns,angles,quotes}



begin{document}

begin{tikzpicture}

node (x1)  at (0, 0, 0) {};

node (x2)  at (2, 0, 0) {};

node (x3)  at ({cos(26)*3+1}, {sin(26)*3}, 0) {};

node (x4)  at (4, 0, 0) {};

pic [draw, <-, "$theta$", angle eccentricity=1.5] {angle = x3--x2--x1};

draw (x1) -- (x2) -- (x3);

draw[gray] (x1) -- (x2) -- (x4);

draw[gray,dashed] (4, 0, 0) arc (0:26:3cm);

shade [ball color=black] (x1) circle (0.15);

shade [ball color=black] (x2) circle (0.15);

shade [ball color=black] (x3) circle (0.15);

shade [ball color=gray] (x4) circle (0.15);

end{tikzpicture}

end{document}

enter image description here

edited Mar 16 at 17:14

answered Mar 16 at 15:01

JouleV

7,89222053

Very nice :-). For my humble opinion the two gray horizontal segments should be in the background. So for the balls you don't see the dashes upstairs.

– Sebastiano
Mar 16 at 16:57

1

@Sebastiano Edited!

– JouleV
Mar 16 at 17:14

That's really good. I didn't know I could put cos and sin there. Thanks

– beliz
Mar 16 at 19:56

@beliz You are welcome.

– JouleV
Mar 17 at 4:14

add a comment |

As far as I know, pic makes angles anti-clockwise. Therefore, it should be x3--x2--x1 instead of x1--x2--x3.

By the way, option scale=1 is unnecessary.

documentclass[tikz]{standalone}

usetikzlibrary{calc,patterns,angles,quotes}



begin{document}

begin{tikzpicture}

node (x1)  at (0, 0, 0) {};

node (x2)  at (2, 0, 0) {};

node (x3)  at (3.45, 1.45, 0) {};

node (x4)  at (4, 0, 0) {};

shade [ball color=black] (x1) circle (0.15);

shade [ball color=black] (x2) circle (0.15);

shade [ball color=black] (x3) circle (0.15);

shade [ball color=gray] (x4) circle (0.15);

draw (x1) -- (x2) -- (x3);

draw[gray] (x1) -- (x2) -- (x4);

draw[gray,dashed] (4, 0, 0) arc (0:26:3cm);

pic [draw, <-, "$theta$", angle eccentricity=1.5] {angle = x3--x2--x1};

end{tikzpicture}

end{document}

enter image description here

Edit 1

Better version IMHO

documentclass[tikz]{standalone}

usetikzlibrary{calc,patterns,angles,quotes}



begin{document}

begin{tikzpicture}

node (x1)  at (0, 0, 0) {};

node (x2)  at (2, 0, 0) {};

node (x3)  at ({cos(26)*3+1}, {sin(26)*3}, 0) {};

node (x4)  at (4, 0, 0) {};

pic [draw, <-, "$theta$", angle eccentricity=1.5] {angle = x3--x2--x1};

draw (x1) -- (x2) -- (x3);

draw[gray] (x1) -- (x2) -- (x4);

draw[gray,dashed] (4, 0, 0) arc (0:26:3cm);

shade [ball color=black] (x1) circle (0.15);

shade [ball color=black] (x2) circle (0.15);

shade [ball color=black] (x3) circle (0.15);

shade [ball color=gray] (x4) circle (0.15);

end{tikzpicture}

end{document}

enter image description here

edited Mar 16 at 17:14

answered Mar 16 at 15:01

JouleV

7,89222053

Very nice :-). For my humble opinion the two gray horizontal segments should be in the background. So for the balls you don't see the dashes upstairs.

– Sebastiano
Mar 16 at 16:57

1

@Sebastiano Edited!

– JouleV
Mar 16 at 17:14

That's really good. I didn't know I could put cos and sin there. Thanks

– beliz
Mar 16 at 19:56

@beliz You are welcome.

– JouleV
Mar 17 at 4:14

add a comment |

As far as I know, pic makes angles anti-clockwise. Therefore, it should be x3--x2--x1 instead of x1--x2--x3.

By the way, option scale=1 is unnecessary.

documentclass[tikz]{standalone}

usetikzlibrary{calc,patterns,angles,quotes}



begin{document}

begin{tikzpicture}

node (x1)  at (0, 0, 0) {};

node (x2)  at (2, 0, 0) {};

node (x3)  at (3.45, 1.45, 0) {};

node (x4)  at (4, 0, 0) {};

shade [ball color=black] (x1) circle (0.15);

shade [ball color=black] (x2) circle (0.15);

shade [ball color=black] (x3) circle (0.15);

shade [ball color=gray] (x4) circle (0.15);

draw (x1) -- (x2) -- (x3);

draw[gray] (x1) -- (x2) -- (x4);

draw[gray,dashed] (4, 0, 0) arc (0:26:3cm);

pic [draw, <-, "$theta$", angle eccentricity=1.5] {angle = x3--x2--x1};

end{tikzpicture}

end{document}

enter image description here

Edit 1

Better version IMHO

documentclass[tikz]{standalone}

usetikzlibrary{calc,patterns,angles,quotes}



begin{document}

begin{tikzpicture}

node (x1)  at (0, 0, 0) {};

node (x2)  at (2, 0, 0) {};

node (x3)  at ({cos(26)*3+1}, {sin(26)*3}, 0) {};

node (x4)  at (4, 0, 0) {};

pic [draw, <-, "$theta$", angle eccentricity=1.5] {angle = x3--x2--x1};

draw (x1) -- (x2) -- (x3);

draw[gray] (x1) -- (x2) -- (x4);

draw[gray,dashed] (4, 0, 0) arc (0:26:3cm);

shade [ball color=black] (x1) circle (0.15);

shade [ball color=black] (x2) circle (0.15);

shade [ball color=black] (x3) circle (0.15);

shade [ball color=gray] (x4) circle (0.15);

end{tikzpicture}

end{document}

enter image description here

edited Mar 16 at 17:14

answered Mar 16 at 15:01

JouleV

7,89222053

As far as I know, pic makes angles anti-clockwise. Therefore, it should be x3--x2--x1 instead of x1--x2--x3.

By the way, option scale=1 is unnecessary.

documentclass[tikz]{standalone}

usetikzlibrary{calc,patterns,angles,quotes}



begin{document}

begin{tikzpicture}

node (x1)  at (0, 0, 0) {};

node (x2)  at (2, 0, 0) {};

node (x3)  at (3.45, 1.45, 0) {};

node (x4)  at (4, 0, 0) {};

shade [ball color=black] (x1) circle (0.15);

shade [ball color=black] (x2) circle (0.15);

shade [ball color=black] (x3) circle (0.15);

shade [ball color=gray] (x4) circle (0.15);

draw (x1) -- (x2) -- (x3);

draw[gray] (x1) -- (x2) -- (x4);

draw[gray,dashed] (4, 0, 0) arc (0:26:3cm);

pic [draw, <-, "$theta$", angle eccentricity=1.5] {angle = x3--x2--x1};

end{tikzpicture}

end{document}

enter image description here

Edit 1

Better version IMHO

documentclass[tikz]{standalone}

usetikzlibrary{calc,patterns,angles,quotes}



begin{document}

begin{tikzpicture}

node (x1)  at (0, 0, 0) {};

node (x2)  at (2, 0, 0) {};

node (x3)  at ({cos(26)*3+1}, {sin(26)*3}, 0) {};

node (x4)  at (4, 0, 0) {};

pic [draw, <-, "$theta$", angle eccentricity=1.5] {angle = x3--x2--x1};

draw (x1) -- (x2) -- (x3);

draw[gray] (x1) -- (x2) -- (x4);

draw[gray,dashed] (4, 0, 0) arc (0:26:3cm);

shade [ball color=black] (x1) circle (0.15);

shade [ball color=black] (x2) circle (0.15);

shade [ball color=black] (x3) circle (0.15);

shade [ball color=gray] (x4) circle (0.15);

end{tikzpicture}

end{document}

enter image description here

edited Mar 16 at 17:14

answered Mar 16 at 15:01

JouleV

7,89222053

edited Mar 16 at 17:14

answered Mar 16 at 15:01

JouleV

7,89222053

answered Mar 16 at 15:01

JouleV

7,89222053

answered Mar 16 at 15:01

JouleV

7,89222053

Very nice :-). For my humble opinion the two gray horizontal segments should be in the background. So for the balls you don't see the dashes upstairs.

– Sebastiano
Mar 16 at 16:57

1

@Sebastiano Edited!

– JouleV
Mar 16 at 17:14

That's really good. I didn't know I could put cos and sin there. Thanks

– beliz
Mar 16 at 19:56

@beliz You are welcome.

– JouleV
Mar 17 at 4:14

add a comment |

Very nice :-). For my humble opinion the two gray horizontal segments should be in the background. So for the balls you don't see the dashes upstairs.

– Sebastiano
Mar 16 at 16:57

1

@Sebastiano Edited!

– JouleV
Mar 16 at 17:14

That's really good. I didn't know I could put cos and sin there. Thanks

– beliz
Mar 16 at 19:56

@beliz You are welcome.

– JouleV
Mar 17 at 4:14

Very nice :-). For my humble opinion the two gray horizontal segments should be in the background. So for the balls you don't see the dashes upstairs.

– Sebastiano
Mar 16 at 16:57

@Sebastiano Edited!

– JouleV
Mar 16 at 17:14

That's really good. I didn't know I could put cos and sin there. Thanks

– beliz
Mar 16 at 19:56

@beliz You are welcome.

– JouleV
Mar 17 at 4:14

add a comment |

draft saved

draft discarded

Thanks for contributing an answer to TeX - LaTeX Stack Exchange!

Please be sure to answer the question. Provide details and share your research!

But avoid …

Asking for help, clarification, or responding to other answers.

Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Name

Required, but never shown

Name

Required, but never shown

This page is only for reference, If you need detailed information, please check here

搜尋此網誌

Cfrgtkky