Don’t be arbitrary
$begingroup$
What’s the next number in the sequence?
2, 3, 2, 3, 2, 5, 2, 3, 2, 3, 10, ?
P.S
I’m new, so tell me if the question was too hard or too easy.
number-sequence
asked Feb 1 at 13:34
Arvasu KulkarniArvasu Kulkarni
573
$endgroup$
add a comment |
$begingroup$
What’s the next number in the sequence?
2, 3, 2, 3, 2, 5, 2, 3, 2, 3, 10, ?
P.S
I’m new, so tell me if the question was too hard or too easy.
number-sequence
asked Feb 1 at 13:34
Arvasu KulkarniArvasu Kulkarni
573
$endgroup$
add a comment |
$begingroup$
What’s the next number in the sequence?
2, 3, 2, 3, 2, 5, 2, 3, 2, 3, 10, ?
P.S
I’m new, so tell me if the question was too hard or too easy.
number-sequence
asked Feb 1 at 13:34
Arvasu KulkarniArvasu Kulkarni
573
$endgroup$
What’s the next number in the sequence?
2, 3, 2, 3, 2, 5, 2, 3, 2, 3, 10, ?
P.S
I’m new, so tell me if the question was too hard or too easy.
number-sequence
number-sequence
asked Feb 1 at 13:34
Arvasu KulkarniArvasu Kulkarni
573
asked Feb 1 at 13:34
Arvasu KulkarniArvasu Kulkarni
573
asked Feb 1 at 13:34
Arvasu KulkarniArvasu Kulkarni
573
asked Feb 1 at 13:34
Arvasu KulkarniArvasu Kulkarni
573
asked Feb 1 at 13:34
Arvasu KulkarniArvasu Kulkarni
573
573
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
How about
5
because
each number in the sequence is the lowest base number where the number of the term (first is 1, second is 2, etc) in that base is a palindrome.
Example:
1 = 1 in base 2
2 = 2 in base 3
3 = 11 in base 2
4 = 11 in base 3
5 = 101 in base 2
6 = 11 in base 5
7 = 111 in base 2
8 = 22 in base 3
9 = 1001 in base 2
10 = 101 in base 3
11 = 11 in base 10
12 = 22 in base 5
Note:
I solved this without OEIS, but OEIS has this sequence as sequence A016026
answered Feb 1 at 13:38
Excited RaichuExcited Raichu
6,51521166
$endgroup$
$begingroup$
That was fast! Awesome!
$endgroup$
– Arvasu Kulkarni
Feb 1 at 14:48
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
How about
5
because
each number in the sequence is the lowest base number where the number of the term (first is 1, second is 2, etc) in that base is a palindrome.
Example:
1 = 1 in base 2
2 = 2 in base 3
3 = 11 in base 2
4 = 11 in base 3
5 = 101 in base 2
6 = 11 in base 5
7 = 111 in base 2
8 = 22 in base 3
9 = 1001 in base 2
10 = 101 in base 3
11 = 11 in base 10
12 = 22 in base 5
Note:
I solved this without OEIS, but OEIS has this sequence as sequence A016026
answered Feb 1 at 13:38
Excited RaichuExcited Raichu
6,51521166
$endgroup$
$begingroup$
That was fast! Awesome!
$endgroup$
– Arvasu Kulkarni
Feb 1 at 14:48
add a comment |
$begingroup$
How about
5
because
each number in the sequence is the lowest base number where the number of the term (first is 1, second is 2, etc) in that base is a palindrome.
Example:
1 = 1 in base 2
2 = 2 in base 3
3 = 11 in base 2
4 = 11 in base 3
5 = 101 in base 2
6 = 11 in base 5
7 = 111 in base 2
8 = 22 in base 3
9 = 1001 in base 2
10 = 101 in base 3
11 = 11 in base 10
12 = 22 in base 5
Note:
I solved this without OEIS, but OEIS has this sequence as sequence A016026
answered Feb 1 at 13:38
Excited RaichuExcited Raichu
6,51521166
$endgroup$
$begingroup$
That was fast! Awesome!
$endgroup$
– Arvasu Kulkarni
Feb 1 at 14:48
add a comment |
$begingroup$
How about
5
because
each number in the sequence is the lowest base number where the number of the term (first is 1, second is 2, etc) in that base is a palindrome.
Example:
1 = 1 in base 2
2 = 2 in base 3
3 = 11 in base 2
4 = 11 in base 3
5 = 101 in base 2
6 = 11 in base 5
7 = 111 in base 2
8 = 22 in base 3
9 = 1001 in base 2
10 = 101 in base 3
11 = 11 in base 10
12 = 22 in base 5
Note:
I solved this without OEIS, but OEIS has this sequence as sequence A016026
answered Feb 1 at 13:38
Excited RaichuExcited Raichu
6,51521166
$endgroup$
How about
5
because
each number in the sequence is the lowest base number where the number of the term (first is 1, second is 2, etc) in that base is a palindrome.
Example:
1 = 1 in base 2
2 = 2 in base 3
3 = 11 in base 2
4 = 11 in base 3
5 = 101 in base 2
6 = 11 in base 5
7 = 111 in base 2
8 = 22 in base 3
9 = 1001 in base 2
10 = 101 in base 3
11 = 11 in base 10
12 = 22 in base 5
Note:
I solved this without OEIS, but OEIS has this sequence as sequence A016026
answered Feb 1 at 13:38
Excited RaichuExcited Raichu
6,51521166
answered Feb 1 at 13:38
Excited RaichuExcited Raichu
6,51521166
answered Feb 1 at 13:38
Excited RaichuExcited Raichu
6,51521166
answered Feb 1 at 13:38
Excited RaichuExcited Raichu
6,51521166
6,51521166
$begingroup$
That was fast! Awesome!
$endgroup$
– Arvasu Kulkarni
Feb 1 at 14:48
add a comment |
$begingroup$
That was fast! Awesome!
$endgroup$
– Arvasu Kulkarni
Feb 1 at 14:48
$begingroup$
That was fast! Awesome!
$endgroup$
– Arvasu Kulkarni
Feb 1 at 14:48
$begingroup$
That was fast! Awesome!
$endgroup$
– Arvasu Kulkarni
Feb 1 at 14:48
add a comment |
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