Strange error defining a macro with arguments for math mode
When I delete the second item, it compiles fine. However, with the second item, I get ERROR: Missing $ inserted and the math renders incorrectly:
documentclass[12pt]{article}
newcommand frob[2] {langle #1,#2 rangle_F}
begin{document}
begin{itemize}
item What I want: $
langle A,B rangle_F
geq
langle C,D rangle_F
$.
item What I get: $
frob{A,B}
geq
frob{A,B}
$.
end{itemize}
end{document}
Would appreciate any help with this issue!
math-mode macros
asked Feb 2 at 1:27
Elliot GorokhovskyElliot Gorokhovsky
355112
add a comment |
When I delete the second item, it compiles fine. However, with the second item, I get ERROR: Missing $ inserted and the math renders incorrectly:
documentclass[12pt]{article}
newcommand frob[2] {langle #1,#2 rangle_F}
begin{document}
begin{itemize}
item What I want: $
langle A,B rangle_F
geq
langle C,D rangle_F
$.
item What I get: $
frob{A,B}
geq
frob{A,B}
$.
end{itemize}
end{document}
Would appreciate any help with this issue!
math-mode macros
asked Feb 2 at 1:27
Elliot GorokhovskyElliot Gorokhovsky
355112
Don't usefrobasfrob{A,B}but use it asfrob{A}{B}. Yourfrob-macro does process two arguments which are not comma-separated. As result it delivers something where the phrases delivered via the arguments will be comma-separated. Maybe this confused you. ;-) If you dofrob{A,B}geq,frob's first undelimited argument will be formed from{A,B}andfrob's second undelimited argument will be formed fromgeq. So all in allfrob{A,B} geq frob{A,B}should befrob{A}{B}geqfrob{C}{D}.
– Ulrich Diez
Feb 2 at 1:45
add a comment |
When I delete the second item, it compiles fine. However, with the second item, I get ERROR: Missing $ inserted and the math renders incorrectly:
documentclass[12pt]{article}
newcommand frob[2] {langle #1,#2 rangle_F}
begin{document}
begin{itemize}
item What I want: $
langle A,B rangle_F
geq
langle C,D rangle_F
$.
item What I get: $
frob{A,B}
geq
frob{A,B}
$.
end{itemize}
end{document}
Would appreciate any help with this issue!
math-mode macros
asked Feb 2 at 1:27
Elliot GorokhovskyElliot Gorokhovsky
355112
When I delete the second item, it compiles fine. However, with the second item, I get ERROR: Missing $ inserted and the math renders incorrectly:
documentclass[12pt]{article}
newcommand frob[2] {langle #1,#2 rangle_F}
begin{document}
begin{itemize}
item What I want: $
langle A,B rangle_F
geq
langle C,D rangle_F
$.
item What I get: $
frob{A,B}
geq
frob{A,B}
$.
end{itemize}
end{document}
Would appreciate any help with this issue!
math-mode macros
math-mode macros
asked Feb 2 at 1:27
Elliot GorokhovskyElliot Gorokhovsky
355112
asked Feb 2 at 1:27
Elliot GorokhovskyElliot Gorokhovsky
355112
asked Feb 2 at 1:27
Elliot GorokhovskyElliot Gorokhovsky
355112
asked Feb 2 at 1:27
Elliot GorokhovskyElliot Gorokhovsky
355112
asked Feb 2 at 1:27
Elliot GorokhovskyElliot Gorokhovsky
355112
355112
Don't usefrobasfrob{A,B}but use it asfrob{A}{B}. Yourfrob-macro does process two arguments which are not comma-separated. As result it delivers something where the phrases delivered via the arguments will be comma-separated. Maybe this confused you. ;-) If you dofrob{A,B}geq,frob's first undelimited argument will be formed from{A,B}andfrob's second undelimited argument will be formed fromgeq. So all in allfrob{A,B} geq frob{A,B}should befrob{A}{B}geqfrob{C}{D}.
– Ulrich Diez
Feb 2 at 1:45
add a comment |
Don't usefrobasfrob{A,B}but use it asfrob{A}{B}. Yourfrob-macro does process two arguments which are not comma-separated. As result it delivers something where the phrases delivered via the arguments will be comma-separated. Maybe this confused you. ;-) If you dofrob{A,B}geq,frob's first undelimited argument will be formed from{A,B}andfrob's second undelimited argument will be formed fromgeq. So all in allfrob{A,B} geq frob{A,B}should befrob{A}{B}geqfrob{C}{D}.
– Ulrich Diez
Feb 2 at 1:45
Don't use
frob as frob{A,B} but use it as frob{A}{B}. Your frob-macro does process two arguments which are not comma-separated. As result it delivers something where the phrases delivered via the arguments will be comma-separated. Maybe this confused you. ;-) If you do frob{A,B}geq, frob's first undelimited argument will be formed from {A,B} and frob's second undelimited argument will be formed from geq. So all in all frob{A,B} geq frob{A,B} should be frob{A}{B}geqfrob{C}{D} .– Ulrich Diez
Feb 2 at 1:45
Don't use
frob as frob{A,B} but use it as frob{A}{B}. Your frob-macro does process two arguments which are not comma-separated. As result it delivers something where the phrases delivered via the arguments will be comma-separated. Maybe this confused you. ;-) If you do frob{A,B}geq, frob's first undelimited argument will be formed from {A,B} and frob's second undelimited argument will be formed from geq. So all in all frob{A,B} geq frob{A,B} should be frob{A}{B}geqfrob{C}{D} .– Ulrich Diez
Feb 2 at 1:45
add a comment |
1 Answer
1
active
oldest
votes
You defined frob to take two arguments
newcommand{frob}[2]
However, you're only passing it one argument when you use it like this
frob{A,B}
That's because arguments are specified as tokens or using braces {...}, not a comma-separated list of elements.
Since you're printing the same thing as you're passing, the following might be simpler:
documentclass{article}
newcommand{frob}[1]{langle #1 rangle_F}
begin{document}
begin{itemize}
item
What I want: $
langle A,B rangle_F
geq
langle C,D rangle_F
$.
item
What I get: $
frob{A,B}
geq
frob{A,B}
$.
end{itemize}
end{document}
If you really want to pass two arguments, then your definition should be
newcommand{frob}[2]{langle #1, #2 rangle_F}
and you'll use it via frob{A}{B}.
answered Feb 2 at 1:50
WernerWerner
443k679791676
Ah, obviously! I've usedfracthat way, but somehow had a brain fart when defining my own function. Thanks!
– Elliot Gorokhovsky
Feb 2 at 22:13
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You defined frob to take two arguments
newcommand{frob}[2]
However, you're only passing it one argument when you use it like this
frob{A,B}
That's because arguments are specified as tokens or using braces {...}, not a comma-separated list of elements.
Since you're printing the same thing as you're passing, the following might be simpler:
documentclass{article}
newcommand{frob}[1]{langle #1 rangle_F}
begin{document}
begin{itemize}
item
What I want: $
langle A,B rangle_F
geq
langle C,D rangle_F
$.
item
What I get: $
frob{A,B}
geq
frob{A,B}
$.
end{itemize}
end{document}
If you really want to pass two arguments, then your definition should be
newcommand{frob}[2]{langle #1, #2 rangle_F}
and you'll use it via frob{A}{B}.
answered Feb 2 at 1:50
WernerWerner
443k679791676
Ah, obviously! I've usedfracthat way, but somehow had a brain fart when defining my own function. Thanks!
– Elliot Gorokhovsky
Feb 2 at 22:13
add a comment |
You defined frob to take two arguments
newcommand{frob}[2]
However, you're only passing it one argument when you use it like this
frob{A,B}
That's because arguments are specified as tokens or using braces {...}, not a comma-separated list of elements.
Since you're printing the same thing as you're passing, the following might be simpler:
documentclass{article}
newcommand{frob}[1]{langle #1 rangle_F}
begin{document}
begin{itemize}
item
What I want: $
langle A,B rangle_F
geq
langle C,D rangle_F
$.
item
What I get: $
frob{A,B}
geq
frob{A,B}
$.
end{itemize}
end{document}
If you really want to pass two arguments, then your definition should be
newcommand{frob}[2]{langle #1, #2 rangle_F}
and you'll use it via frob{A}{B}.
answered Feb 2 at 1:50
WernerWerner
443k679791676
Ah, obviously! I've usedfracthat way, but somehow had a brain fart when defining my own function. Thanks!
– Elliot Gorokhovsky
Feb 2 at 22:13
add a comment |
You defined frob to take two arguments
newcommand{frob}[2]
However, you're only passing it one argument when you use it like this
frob{A,B}
That's because arguments are specified as tokens or using braces {...}, not a comma-separated list of elements.
Since you're printing the same thing as you're passing, the following might be simpler:
documentclass{article}
newcommand{frob}[1]{langle #1 rangle_F}
begin{document}
begin{itemize}
item
What I want: $
langle A,B rangle_F
geq
langle C,D rangle_F
$.
item
What I get: $
frob{A,B}
geq
frob{A,B}
$.
end{itemize}
end{document}
If you really want to pass two arguments, then your definition should be
newcommand{frob}[2]{langle #1, #2 rangle_F}
and you'll use it via frob{A}{B}.
answered Feb 2 at 1:50
WernerWerner
443k679791676
You defined frob to take two arguments
newcommand{frob}[2]
However, you're only passing it one argument when you use it like this
frob{A,B}
That's because arguments are specified as tokens or using braces {...}, not a comma-separated list of elements.
Since you're printing the same thing as you're passing, the following might be simpler:
documentclass{article}
newcommand{frob}[1]{langle #1 rangle_F}
begin{document}
begin{itemize}
item
What I want: $
langle A,B rangle_F
geq
langle C,D rangle_F
$.
item
What I get: $
frob{A,B}
geq
frob{A,B}
$.
end{itemize}
end{document}
If you really want to pass two arguments, then your definition should be
newcommand{frob}[2]{langle #1, #2 rangle_F}
and you'll use it via frob{A}{B}.
answered Feb 2 at 1:50
WernerWerner
443k679791676
answered Feb 2 at 1:50
WernerWerner
443k679791676
answered Feb 2 at 1:50
WernerWerner
443k679791676
answered Feb 2 at 1:50
WernerWerner
443k679791676
443k679791676
Ah, obviously! I've usedfracthat way, but somehow had a brain fart when defining my own function. Thanks!
– Elliot Gorokhovsky
Feb 2 at 22:13
add a comment |
Ah, obviously! I've usedfracthat way, but somehow had a brain fart when defining my own function. Thanks!
– Elliot Gorokhovsky
Feb 2 at 22:13
Ah, obviously! I've used
frac that way, but somehow had a brain fart when defining my own function. Thanks!– Elliot Gorokhovsky
Feb 2 at 22:13
Ah, obviously! I've used
frac that way, but somehow had a brain fart when defining my own function. Thanks!– Elliot Gorokhovsky
Feb 2 at 22:13
add a comment |
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Don't use
frobasfrob{A,B}but use it asfrob{A}{B}. Yourfrob-macro does process two arguments which are not comma-separated. As result it delivers something where the phrases delivered via the arguments will be comma-separated. Maybe this confused you. ;-) If you dofrob{A,B}geq,frob's first undelimited argument will be formed from{A,B}andfrob's second undelimited argument will be formed fromgeq. So all in allfrob{A,B} geq frob{A,B}should befrob{A}{B}geqfrob{C}{D}.– Ulrich Diez
Feb 2 at 1:45