Python - Additional “members” appended to JSON object when passing it to function












2














I have the following JSON object located in its own file called build.json:



{
"name": "utils",
"version": "1.0.0",
"includes": ,
"libraries": ,
"testLibraries":
}


I obtain this object in my Python program using the following method:



def getPackage(packageName):
jsonFilePath = os.path.join(SRCDIR, packageName, "build.json")
packageJson = None
try:
with open(jsonFilePath, "r") as jsonFile:
packageJson = json.load(jsonFile)
except:
return None
return packageJson


I verify that the JSON object for the current package (which is one of many packages I am iterating over) did not come back None in the following method. Note that I am temporarily printing out the keys of the dictionary:



def compileAllPackages():
global COMPILED_PACKAGES

for packageName in os.listdir(SRCDIR):
package = getPackage(packageName)
if package == None:
continue

# TEMP ==============
for i in package:
print(i)
# ===================

compiledSuccessfully = compilePackage(package)
if not compiledSuccessfully:
return False
return True


Lastly, I am currently also printing out the keys of the dictionary once it is received in the compilePackage function:



def compilePackage(package):
global COMPILED_PACKAGES, INCLUDE_TESTS

# TEMP ==============
for i in package:
print(i)
# ===================

...


Output from compileAllPackages function:



name
version
includes
libraries
testLibraries


Output from compilePackage function:



name
version
includes
libraries
testLibraries
u
t
i
l
s


I can not for the life of me figure out what is happening to my dictionary during that function call??? Please note that the build.json file is located within a directory named "utils".



Edit:
The Python script is located separate from the build.json file and works on absolute paths. It should also be noted that after getting that strange output, I also get the following exception when trying to access a valid key later (it seems to think the dictionary is a string?...):



Traceback (most recent call last):
File "/Users/nate/bin/BuildTool/unix/build.py", line 493, in <module>
main()
File "/Users/nate/bin/BuildTool/unix/build.py", line 481, in main
compiledSuccessfully = compileAllPackages()
File "/Users/nate/bin/BuildTool/unix/build.py", line 263, in compileAllPackages
compiledSuccessfully = compilePackage(package)
File "/Users/nate/bin/BuildTool/unix/build.py", line 287, in compilePackage
compiledSuccessfully = compilePackage(include)
File "/Users/nate/bin/BuildTool/unix/build.py", line 279, in compilePackage
includes = getPackageIncludes(package)
File "/Users/nate/bin/BuildTool/unix/build.py", line 194, in getPackageIncludes
includes = [package["name"]] # A package always includes itself
TypeError: string indices must be integers


Edit: If I change the parameter name to something other than 'package', I no longer get that weird output or an exception later on. This is not necessarily a fix, however, as I do not know what could be wrong with the name 'package'. There are no globals named as such either.










share|improve this question




















  • 2




    I'm with @benediktwerner. I don't think the 'utils' part comes from anywhere in this code. Try searching for all other points in your code where you print and see if it might be coming from one of them. Better yet, print something before and after the for loops like say ######## so you can properly demarcate where that part's output starts and ends.
    – Karuhanga
    Nov 9 '18 at 3:28












  • @Karuhanga I can comment out all of my printouts such that I get no output except for the exception. Then if I only allow that one print loop in the compilePackage function, the result is as seen above. I don't believe there is anything in the print buffer either that wasn't flushed before-hand.
    – Nathaniel Rex
    Nov 9 '18 at 3:55












  • Have you tried just print(package) and see what you got?
    – Idlehands
    Nov 9 '18 at 13:16










  • @Idlehands yes. If I replace each looping print with print(package) above, from compileAllPackages, I get: {'name': 'utils', 'version': '1.0.0', 'includes': , 'libraries': , 'testLibraries': } and from compilePackage, I get (still with that weird utils string tacked onto the end): {'name': 'utils', 'version': '1.0.0', 'includes': , 'libraries': , 'testLibraries': } utils
    – Nathaniel Rex
    Nov 9 '18 at 14:46


















2














I have the following JSON object located in its own file called build.json:



{
"name": "utils",
"version": "1.0.0",
"includes": ,
"libraries": ,
"testLibraries":
}


I obtain this object in my Python program using the following method:



def getPackage(packageName):
jsonFilePath = os.path.join(SRCDIR, packageName, "build.json")
packageJson = None
try:
with open(jsonFilePath, "r") as jsonFile:
packageJson = json.load(jsonFile)
except:
return None
return packageJson


I verify that the JSON object for the current package (which is one of many packages I am iterating over) did not come back None in the following method. Note that I am temporarily printing out the keys of the dictionary:



def compileAllPackages():
global COMPILED_PACKAGES

for packageName in os.listdir(SRCDIR):
package = getPackage(packageName)
if package == None:
continue

# TEMP ==============
for i in package:
print(i)
# ===================

compiledSuccessfully = compilePackage(package)
if not compiledSuccessfully:
return False
return True


Lastly, I am currently also printing out the keys of the dictionary once it is received in the compilePackage function:



def compilePackage(package):
global COMPILED_PACKAGES, INCLUDE_TESTS

# TEMP ==============
for i in package:
print(i)
# ===================

...


Output from compileAllPackages function:



name
version
includes
libraries
testLibraries


Output from compilePackage function:



name
version
includes
libraries
testLibraries
u
t
i
l
s


I can not for the life of me figure out what is happening to my dictionary during that function call??? Please note that the build.json file is located within a directory named "utils".



Edit:
The Python script is located separate from the build.json file and works on absolute paths. It should also be noted that after getting that strange output, I also get the following exception when trying to access a valid key later (it seems to think the dictionary is a string?...):



Traceback (most recent call last):
File "/Users/nate/bin/BuildTool/unix/build.py", line 493, in <module>
main()
File "/Users/nate/bin/BuildTool/unix/build.py", line 481, in main
compiledSuccessfully = compileAllPackages()
File "/Users/nate/bin/BuildTool/unix/build.py", line 263, in compileAllPackages
compiledSuccessfully = compilePackage(package)
File "/Users/nate/bin/BuildTool/unix/build.py", line 287, in compilePackage
compiledSuccessfully = compilePackage(include)
File "/Users/nate/bin/BuildTool/unix/build.py", line 279, in compilePackage
includes = getPackageIncludes(package)
File "/Users/nate/bin/BuildTool/unix/build.py", line 194, in getPackageIncludes
includes = [package["name"]] # A package always includes itself
TypeError: string indices must be integers


Edit: If I change the parameter name to something other than 'package', I no longer get that weird output or an exception later on. This is not necessarily a fix, however, as I do not know what could be wrong with the name 'package'. There are no globals named as such either.










share|improve this question




















  • 2




    I'm with @benediktwerner. I don't think the 'utils' part comes from anywhere in this code. Try searching for all other points in your code where you print and see if it might be coming from one of them. Better yet, print something before and after the for loops like say ######## so you can properly demarcate where that part's output starts and ends.
    – Karuhanga
    Nov 9 '18 at 3:28












  • @Karuhanga I can comment out all of my printouts such that I get no output except for the exception. Then if I only allow that one print loop in the compilePackage function, the result is as seen above. I don't believe there is anything in the print buffer either that wasn't flushed before-hand.
    – Nathaniel Rex
    Nov 9 '18 at 3:55












  • Have you tried just print(package) and see what you got?
    – Idlehands
    Nov 9 '18 at 13:16










  • @Idlehands yes. If I replace each looping print with print(package) above, from compileAllPackages, I get: {'name': 'utils', 'version': '1.0.0', 'includes': , 'libraries': , 'testLibraries': } and from compilePackage, I get (still with that weird utils string tacked onto the end): {'name': 'utils', 'version': '1.0.0', 'includes': , 'libraries': , 'testLibraries': } utils
    – Nathaniel Rex
    Nov 9 '18 at 14:46
















2












2








2


2





I have the following JSON object located in its own file called build.json:



{
"name": "utils",
"version": "1.0.0",
"includes": ,
"libraries": ,
"testLibraries":
}


I obtain this object in my Python program using the following method:



def getPackage(packageName):
jsonFilePath = os.path.join(SRCDIR, packageName, "build.json")
packageJson = None
try:
with open(jsonFilePath, "r") as jsonFile:
packageJson = json.load(jsonFile)
except:
return None
return packageJson


I verify that the JSON object for the current package (which is one of many packages I am iterating over) did not come back None in the following method. Note that I am temporarily printing out the keys of the dictionary:



def compileAllPackages():
global COMPILED_PACKAGES

for packageName in os.listdir(SRCDIR):
package = getPackage(packageName)
if package == None:
continue

# TEMP ==============
for i in package:
print(i)
# ===================

compiledSuccessfully = compilePackage(package)
if not compiledSuccessfully:
return False
return True


Lastly, I am currently also printing out the keys of the dictionary once it is received in the compilePackage function:



def compilePackage(package):
global COMPILED_PACKAGES, INCLUDE_TESTS

# TEMP ==============
for i in package:
print(i)
# ===================

...


Output from compileAllPackages function:



name
version
includes
libraries
testLibraries


Output from compilePackage function:



name
version
includes
libraries
testLibraries
u
t
i
l
s


I can not for the life of me figure out what is happening to my dictionary during that function call??? Please note that the build.json file is located within a directory named "utils".



Edit:
The Python script is located separate from the build.json file and works on absolute paths. It should also be noted that after getting that strange output, I also get the following exception when trying to access a valid key later (it seems to think the dictionary is a string?...):



Traceback (most recent call last):
File "/Users/nate/bin/BuildTool/unix/build.py", line 493, in <module>
main()
File "/Users/nate/bin/BuildTool/unix/build.py", line 481, in main
compiledSuccessfully = compileAllPackages()
File "/Users/nate/bin/BuildTool/unix/build.py", line 263, in compileAllPackages
compiledSuccessfully = compilePackage(package)
File "/Users/nate/bin/BuildTool/unix/build.py", line 287, in compilePackage
compiledSuccessfully = compilePackage(include)
File "/Users/nate/bin/BuildTool/unix/build.py", line 279, in compilePackage
includes = getPackageIncludes(package)
File "/Users/nate/bin/BuildTool/unix/build.py", line 194, in getPackageIncludes
includes = [package["name"]] # A package always includes itself
TypeError: string indices must be integers


Edit: If I change the parameter name to something other than 'package', I no longer get that weird output or an exception later on. This is not necessarily a fix, however, as I do not know what could be wrong with the name 'package'. There are no globals named as such either.










share|improve this question















I have the following JSON object located in its own file called build.json:



{
"name": "utils",
"version": "1.0.0",
"includes": ,
"libraries": ,
"testLibraries":
}


I obtain this object in my Python program using the following method:



def getPackage(packageName):
jsonFilePath = os.path.join(SRCDIR, packageName, "build.json")
packageJson = None
try:
with open(jsonFilePath, "r") as jsonFile:
packageJson = json.load(jsonFile)
except:
return None
return packageJson


I verify that the JSON object for the current package (which is one of many packages I am iterating over) did not come back None in the following method. Note that I am temporarily printing out the keys of the dictionary:



def compileAllPackages():
global COMPILED_PACKAGES

for packageName in os.listdir(SRCDIR):
package = getPackage(packageName)
if package == None:
continue

# TEMP ==============
for i in package:
print(i)
# ===================

compiledSuccessfully = compilePackage(package)
if not compiledSuccessfully:
return False
return True


Lastly, I am currently also printing out the keys of the dictionary once it is received in the compilePackage function:



def compilePackage(package):
global COMPILED_PACKAGES, INCLUDE_TESTS

# TEMP ==============
for i in package:
print(i)
# ===================

...


Output from compileAllPackages function:



name
version
includes
libraries
testLibraries


Output from compilePackage function:



name
version
includes
libraries
testLibraries
u
t
i
l
s


I can not for the life of me figure out what is happening to my dictionary during that function call??? Please note that the build.json file is located within a directory named "utils".



Edit:
The Python script is located separate from the build.json file and works on absolute paths. It should also be noted that after getting that strange output, I also get the following exception when trying to access a valid key later (it seems to think the dictionary is a string?...):



Traceback (most recent call last):
File "/Users/nate/bin/BuildTool/unix/build.py", line 493, in <module>
main()
File "/Users/nate/bin/BuildTool/unix/build.py", line 481, in main
compiledSuccessfully = compileAllPackages()
File "/Users/nate/bin/BuildTool/unix/build.py", line 263, in compileAllPackages
compiledSuccessfully = compilePackage(package)
File "/Users/nate/bin/BuildTool/unix/build.py", line 287, in compilePackage
compiledSuccessfully = compilePackage(include)
File "/Users/nate/bin/BuildTool/unix/build.py", line 279, in compilePackage
includes = getPackageIncludes(package)
File "/Users/nate/bin/BuildTool/unix/build.py", line 194, in getPackageIncludes
includes = [package["name"]] # A package always includes itself
TypeError: string indices must be integers


Edit: If I change the parameter name to something other than 'package', I no longer get that weird output or an exception later on. This is not necessarily a fix, however, as I do not know what could be wrong with the name 'package'. There are no globals named as such either.







python json python-3.x python-2.7 typeerror






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edited Nov 9 '18 at 4:34







Nathaniel Rex

















asked Nov 9 '18 at 2:57









Nathaniel RexNathaniel Rex

414




414








  • 2




    I'm with @benediktwerner. I don't think the 'utils' part comes from anywhere in this code. Try searching for all other points in your code where you print and see if it might be coming from one of them. Better yet, print something before and after the for loops like say ######## so you can properly demarcate where that part's output starts and ends.
    – Karuhanga
    Nov 9 '18 at 3:28












  • @Karuhanga I can comment out all of my printouts such that I get no output except for the exception. Then if I only allow that one print loop in the compilePackage function, the result is as seen above. I don't believe there is anything in the print buffer either that wasn't flushed before-hand.
    – Nathaniel Rex
    Nov 9 '18 at 3:55












  • Have you tried just print(package) and see what you got?
    – Idlehands
    Nov 9 '18 at 13:16










  • @Idlehands yes. If I replace each looping print with print(package) above, from compileAllPackages, I get: {'name': 'utils', 'version': '1.0.0', 'includes': , 'libraries': , 'testLibraries': } and from compilePackage, I get (still with that weird utils string tacked onto the end): {'name': 'utils', 'version': '1.0.0', 'includes': , 'libraries': , 'testLibraries': } utils
    – Nathaniel Rex
    Nov 9 '18 at 14:46
















  • 2




    I'm with @benediktwerner. I don't think the 'utils' part comes from anywhere in this code. Try searching for all other points in your code where you print and see if it might be coming from one of them. Better yet, print something before and after the for loops like say ######## so you can properly demarcate where that part's output starts and ends.
    – Karuhanga
    Nov 9 '18 at 3:28












  • @Karuhanga I can comment out all of my printouts such that I get no output except for the exception. Then if I only allow that one print loop in the compilePackage function, the result is as seen above. I don't believe there is anything in the print buffer either that wasn't flushed before-hand.
    – Nathaniel Rex
    Nov 9 '18 at 3:55












  • Have you tried just print(package) and see what you got?
    – Idlehands
    Nov 9 '18 at 13:16










  • @Idlehands yes. If I replace each looping print with print(package) above, from compileAllPackages, I get: {'name': 'utils', 'version': '1.0.0', 'includes': , 'libraries': , 'testLibraries': } and from compilePackage, I get (still with that weird utils string tacked onto the end): {'name': 'utils', 'version': '1.0.0', 'includes': , 'libraries': , 'testLibraries': } utils
    – Nathaniel Rex
    Nov 9 '18 at 14:46










2




2




I'm with @benediktwerner. I don't think the 'utils' part comes from anywhere in this code. Try searching for all other points in your code where you print and see if it might be coming from one of them. Better yet, print something before and after the for loops like say ######## so you can properly demarcate where that part's output starts and ends.
– Karuhanga
Nov 9 '18 at 3:28






I'm with @benediktwerner. I don't think the 'utils' part comes from anywhere in this code. Try searching for all other points in your code where you print and see if it might be coming from one of them. Better yet, print something before and after the for loops like say ######## so you can properly demarcate where that part's output starts and ends.
– Karuhanga
Nov 9 '18 at 3:28














@Karuhanga I can comment out all of my printouts such that I get no output except for the exception. Then if I only allow that one print loop in the compilePackage function, the result is as seen above. I don't believe there is anything in the print buffer either that wasn't flushed before-hand.
– Nathaniel Rex
Nov 9 '18 at 3:55






@Karuhanga I can comment out all of my printouts such that I get no output except for the exception. Then if I only allow that one print loop in the compilePackage function, the result is as seen above. I don't believe there is anything in the print buffer either that wasn't flushed before-hand.
– Nathaniel Rex
Nov 9 '18 at 3:55














Have you tried just print(package) and see what you got?
– Idlehands
Nov 9 '18 at 13:16




Have you tried just print(package) and see what you got?
– Idlehands
Nov 9 '18 at 13:16












@Idlehands yes. If I replace each looping print with print(package) above, from compileAllPackages, I get: {'name': 'utils', 'version': '1.0.0', 'includes': , 'libraries': , 'testLibraries': } and from compilePackage, I get (still with that weird utils string tacked onto the end): {'name': 'utils', 'version': '1.0.0', 'includes': , 'libraries': , 'testLibraries': } utils
– Nathaniel Rex
Nov 9 '18 at 14:46






@Idlehands yes. If I replace each looping print with print(package) above, from compileAllPackages, I get: {'name': 'utils', 'version': '1.0.0', 'includes': , 'libraries': , 'testLibraries': } and from compilePackage, I get (still with that weird utils string tacked onto the end): {'name': 'utils', 'version': '1.0.0', 'includes': , 'libraries': , 'testLibraries': } utils
– Nathaniel Rex
Nov 9 '18 at 14:46














2 Answers
2






active

oldest

votes


















0














The answer ended up being very stupid. compilePackage() has the possibility of being called recursively, due to any dependencies the package may rely on. In recursive calls to the function, I was passing a string to the function rather than a dictionary.






share|improve this answer





























    -2














    I tried your code and the result is like this



    Output from compileAllPackages function:



    name
    version
    includes
    libraries
    testLibraries


    Output from compilePackage function:



    name
    version
    includes
    libraries
    testLibraries


    My directory structure is like this



    ├── test.py
    └── tt
    └── cc
    └── utils
    └── build.json


    I think your code is correct, it should be that the path parameter you passed is incorrect.






    share|improve this answer





















    • it should be that the path parameter you passed is incorrect. This does not explain why you would have different output for identical pieces of code.
      – Karuhanga
      Nov 9 '18 at 3:31










    • This is not an answer and must be posted as a comment.
      – DYZ
      Nov 9 '18 at 3:40











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    2 Answers
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    2 Answers
    2






    active

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    active

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    active

    oldest

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    0














    The answer ended up being very stupid. compilePackage() has the possibility of being called recursively, due to any dependencies the package may rely on. In recursive calls to the function, I was passing a string to the function rather than a dictionary.






    share|improve this answer


























      0














      The answer ended up being very stupid. compilePackage() has the possibility of being called recursively, due to any dependencies the package may rely on. In recursive calls to the function, I was passing a string to the function rather than a dictionary.






      share|improve this answer
























        0












        0








        0






        The answer ended up being very stupid. compilePackage() has the possibility of being called recursively, due to any dependencies the package may rely on. In recursive calls to the function, I was passing a string to the function rather than a dictionary.






        share|improve this answer












        The answer ended up being very stupid. compilePackage() has the possibility of being called recursively, due to any dependencies the package may rely on. In recursive calls to the function, I was passing a string to the function rather than a dictionary.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 18 '18 at 22:06









        Nathaniel RexNathaniel Rex

        414




        414

























            -2














            I tried your code and the result is like this



            Output from compileAllPackages function:



            name
            version
            includes
            libraries
            testLibraries


            Output from compilePackage function:



            name
            version
            includes
            libraries
            testLibraries


            My directory structure is like this



            ├── test.py
            └── tt
            └── cc
            └── utils
            └── build.json


            I think your code is correct, it should be that the path parameter you passed is incorrect.






            share|improve this answer





















            • it should be that the path parameter you passed is incorrect. This does not explain why you would have different output for identical pieces of code.
              – Karuhanga
              Nov 9 '18 at 3:31










            • This is not an answer and must be posted as a comment.
              – DYZ
              Nov 9 '18 at 3:40
















            -2














            I tried your code and the result is like this



            Output from compileAllPackages function:



            name
            version
            includes
            libraries
            testLibraries


            Output from compilePackage function:



            name
            version
            includes
            libraries
            testLibraries


            My directory structure is like this



            ├── test.py
            └── tt
            └── cc
            └── utils
            └── build.json


            I think your code is correct, it should be that the path parameter you passed is incorrect.






            share|improve this answer





















            • it should be that the path parameter you passed is incorrect. This does not explain why you would have different output for identical pieces of code.
              – Karuhanga
              Nov 9 '18 at 3:31










            • This is not an answer and must be posted as a comment.
              – DYZ
              Nov 9 '18 at 3:40














            -2












            -2








            -2






            I tried your code and the result is like this



            Output from compileAllPackages function:



            name
            version
            includes
            libraries
            testLibraries


            Output from compilePackage function:



            name
            version
            includes
            libraries
            testLibraries


            My directory structure is like this



            ├── test.py
            └── tt
            └── cc
            └── utils
            └── build.json


            I think your code is correct, it should be that the path parameter you passed is incorrect.






            share|improve this answer












            I tried your code and the result is like this



            Output from compileAllPackages function:



            name
            version
            includes
            libraries
            testLibraries


            Output from compilePackage function:



            name
            version
            includes
            libraries
            testLibraries


            My directory structure is like this



            ├── test.py
            └── tt
            └── cc
            └── utils
            └── build.json


            I think your code is correct, it should be that the path parameter you passed is incorrect.







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 9 '18 at 3:29









            老板鱼丸粗面老板鱼丸粗面

            11




            11












            • it should be that the path parameter you passed is incorrect. This does not explain why you would have different output for identical pieces of code.
              – Karuhanga
              Nov 9 '18 at 3:31










            • This is not an answer and must be posted as a comment.
              – DYZ
              Nov 9 '18 at 3:40


















            • it should be that the path parameter you passed is incorrect. This does not explain why you would have different output for identical pieces of code.
              – Karuhanga
              Nov 9 '18 at 3:31










            • This is not an answer and must be posted as a comment.
              – DYZ
              Nov 9 '18 at 3:40
















            it should be that the path parameter you passed is incorrect. This does not explain why you would have different output for identical pieces of code.
            – Karuhanga
            Nov 9 '18 at 3:31




            it should be that the path parameter you passed is incorrect. This does not explain why you would have different output for identical pieces of code.
            – Karuhanga
            Nov 9 '18 at 3:31












            This is not an answer and must be posted as a comment.
            – DYZ
            Nov 9 '18 at 3:40




            This is not an answer and must be posted as a comment.
            – DYZ
            Nov 9 '18 at 3:40


















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