How to get Custom object in java spring?

I'm using java spring for my server.

My question is how can I get custom object through the controller.

Example for what I mean:

I know I can do that by doing two functions:

      @RequestMapping(

        path = arrayOf("getObject", "getObject/"),

        method = arrayOf(RequestMethod.GET))

open fun getRecord1(@RequestBody data: CustomObjectOption1): ResponseEntity<*> {

    return ResponseEntity<Any>(data.name,HttpStatus.OK)



}



     @RequestMapping(

        path = arrayOf("getObject", "getObject/"),

        method = arrayOf(RequestMethod.GET))

open fun getRecord2(@RequestBody data: CustomObjectOption2): ResponseEntity<*> {

    return ResponseEntity<Any>(data.number,HttpStatus.OK)



}

but I want to do it by only one endpoint:

 @RequestMapping(

        path = arrayOf("getObject", "getObject/"),

        method = arrayOf(RequestMethod.GET))

open fun getRecord(@RequestBody data: CustomObjectOption): ResponseEntity<*> {



  if(data instance option1)

    return ResponseEntity<Any>(data.name,HttpStatus.OK)

else
return ResponseEntity(data.number,HttpStatus.OK)
else
}

such that the object can be like this:

option 1:

  public class CustomObject {



      private String name;

      private Long id;



   }

or option 2:

     public class CustomObject {



      private List<Integer> number;

      private List<Long> count;



   }

Is that possible to do that in java spring?

The only solution I was thinking is to use inheritance but I would like to know if there's different way...

Thank you for the help

edited Nov 20 '18 at 2:00

Jayson Minard

39.1k17108172

asked Nov 19 '18 at 20:33

JJ Redikes

255

I can't understand what you're asking. What are you trying to achieve?

– JB Nizet
Nov 19 '18 at 21:01

@JBNizet can you tell me what you don't understand? in general I'm trying to pass to the controller the same object but I want that this object could be from type A or from type B

– JJ Redikes
Nov 19 '18 at 21:08

Just don't. There is no good reason to send two completely different objects to the same resource. Create two different controller (or controller methods), doing two different things, and accepting two different types of objects.

– JB Nizet
Nov 19 '18 at 21:12

Also, using GET to send a request body doesn't make any sense. GET requests don't have a body.

– JB Nizet
Nov 19 '18 at 21:13

add a comment |

I'm using java spring for my server.

My question is how can I get custom object through the controller.

Example for what I mean:

I know I can do that by doing two functions:

      @RequestMapping(

        path = arrayOf("getObject", "getObject/"),

        method = arrayOf(RequestMethod.GET))

open fun getRecord1(@RequestBody data: CustomObjectOption1): ResponseEntity<*> {

    return ResponseEntity<Any>(data.name,HttpStatus.OK)



}



     @RequestMapping(

        path = arrayOf("getObject", "getObject/"),

        method = arrayOf(RequestMethod.GET))

open fun getRecord2(@RequestBody data: CustomObjectOption2): ResponseEntity<*> {

    return ResponseEntity<Any>(data.number,HttpStatus.OK)



}

but I want to do it by only one endpoint:

 @RequestMapping(

        path = arrayOf("getObject", "getObject/"),

        method = arrayOf(RequestMethod.GET))

open fun getRecord(@RequestBody data: CustomObjectOption): ResponseEntity<*> {



  if(data instance option1)

    return ResponseEntity<Any>(data.name,HttpStatus.OK)

else
return ResponseEntity(data.number,HttpStatus.OK)
else
}

such that the object can be like this:

option 1:

  public class CustomObject {



      private String name;

      private Long id;



   }

or option 2:

     public class CustomObject {



      private List<Integer> number;

      private List<Long> count;



   }

Is that possible to do that in java spring?

The only solution I was thinking is to use inheritance but I would like to know if there's different way...

Thank you for the help

edited Nov 20 '18 at 2:00

Jayson Minard

39.1k17108172

asked Nov 19 '18 at 20:33

JJ Redikes

255

I can't understand what you're asking. What are you trying to achieve?

– JB Nizet
Nov 19 '18 at 21:01

@JBNizet can you tell me what you don't understand? in general I'm trying to pass to the controller the same object but I want that this object could be from type A or from type B

– JJ Redikes
Nov 19 '18 at 21:08

Just don't. There is no good reason to send two completely different objects to the same resource. Create two different controller (or controller methods), doing two different things, and accepting two different types of objects.

– JB Nizet
Nov 19 '18 at 21:12

Also, using GET to send a request body doesn't make any sense. GET requests don't have a body.

– JB Nizet
Nov 19 '18 at 21:13

add a comment |

I'm using java spring for my server.

My question is how can I get custom object through the controller.

Example for what I mean:

I know I can do that by doing two functions:

      @RequestMapping(

        path = arrayOf("getObject", "getObject/"),

        method = arrayOf(RequestMethod.GET))

open fun getRecord1(@RequestBody data: CustomObjectOption1): ResponseEntity<*> {

    return ResponseEntity<Any>(data.name,HttpStatus.OK)



}



     @RequestMapping(

        path = arrayOf("getObject", "getObject/"),

        method = arrayOf(RequestMethod.GET))

open fun getRecord2(@RequestBody data: CustomObjectOption2): ResponseEntity<*> {

    return ResponseEntity<Any>(data.number,HttpStatus.OK)



}

but I want to do it by only one endpoint:

 @RequestMapping(

        path = arrayOf("getObject", "getObject/"),

        method = arrayOf(RequestMethod.GET))

open fun getRecord(@RequestBody data: CustomObjectOption): ResponseEntity<*> {



  if(data instance option1)

    return ResponseEntity<Any>(data.name,HttpStatus.OK)

else
return ResponseEntity(data.number,HttpStatus.OK)
else
}

such that the object can be like this:

option 1:

  public class CustomObject {



      private String name;

      private Long id;



   }

or option 2:

     public class CustomObject {



      private List<Integer> number;

      private List<Long> count;



   }

Is that possible to do that in java spring?

The only solution I was thinking is to use inheritance but I would like to know if there's different way...

Thank you for the help

edited Nov 20 '18 at 2:00

Jayson Minard

39.1k17108172

asked Nov 19 '18 at 20:33

JJ Redikes

255

I'm using java spring for my server.

My question is how can I get custom object through the controller.

Example for what I mean:

I know I can do that by doing two functions:

      @RequestMapping(

        path = arrayOf("getObject", "getObject/"),

        method = arrayOf(RequestMethod.GET))

open fun getRecord1(@RequestBody data: CustomObjectOption1): ResponseEntity<*> {

    return ResponseEntity<Any>(data.name,HttpStatus.OK)



}



     @RequestMapping(

        path = arrayOf("getObject", "getObject/"),

        method = arrayOf(RequestMethod.GET))

open fun getRecord2(@RequestBody data: CustomObjectOption2): ResponseEntity<*> {

    return ResponseEntity<Any>(data.number,HttpStatus.OK)



}

but I want to do it by only one endpoint:

 @RequestMapping(

        path = arrayOf("getObject", "getObject/"),

        method = arrayOf(RequestMethod.GET))

open fun getRecord(@RequestBody data: CustomObjectOption): ResponseEntity<*> {



  if(data instance option1)

    return ResponseEntity<Any>(data.name,HttpStatus.OK)

else
return ResponseEntity(data.number,HttpStatus.OK)
else
}

such that the object can be like this:

option 1:

  public class CustomObject {



      private String name;

      private Long id;



   }

or option 2:

     public class CustomObject {



      private List<Integer> number;

      private List<Long> count;



   }

Is that possible to do that in java spring?

The only solution I was thinking is to use inheritance but I would like to know if there's different way...

Thank you for the help

spring kotlin controller

edited Nov 20 '18 at 2:00

Jayson Minard

39.1k17108172

asked Nov 19 '18 at 20:33

JJ Redikes

255

edited Nov 20 '18 at 2:00

Jayson Minard

39.1k17108172

asked Nov 19 '18 at 20:33

JJ Redikes

255

edited Nov 20 '18 at 2:00

Jayson Minard

39.1k17108172

edited Nov 20 '18 at 2:00

Jayson Minard

39.1k17108172

edited Nov 20 '18 at 2:00

Jayson Minard

39.1k17108172

asked Nov 19 '18 at 20:33

JJ Redikes

255

asked Nov 19 '18 at 20:33

JJ Redikes

255

asked Nov 19 '18 at 20:33

JJ Redikes

255

I can't understand what you're asking. What are you trying to achieve?

– JB Nizet
Nov 19 '18 at 21:01

@JBNizet can you tell me what you don't understand? in general I'm trying to pass to the controller the same object but I want that this object could be from type A or from type B

– JJ Redikes
Nov 19 '18 at 21:08

Just don't. There is no good reason to send two completely different objects to the same resource. Create two different controller (or controller methods), doing two different things, and accepting two different types of objects.

– JB Nizet
Nov 19 '18 at 21:12

Also, using GET to send a request body doesn't make any sense. GET requests don't have a body.

– JB Nizet
Nov 19 '18 at 21:13

add a comment |

I can't understand what you're asking. What are you trying to achieve?

– JB Nizet
Nov 19 '18 at 21:01

@JBNizet can you tell me what you don't understand? in general I'm trying to pass to the controller the same object but I want that this object could be from type A or from type B

– JJ Redikes
Nov 19 '18 at 21:08

Just don't. There is no good reason to send two completely different objects to the same resource. Create two different controller (or controller methods), doing two different things, and accepting two different types of objects.

– JB Nizet
Nov 19 '18 at 21:12

Also, using GET to send a request body doesn't make any sense. GET requests don't have a body.

– JB Nizet
Nov 19 '18 at 21:13

I can't understand what you're asking. What are you trying to achieve?

– JB Nizet
Nov 19 '18 at 21:01

@JBNizet can you tell me what you don't understand? in general I'm trying to pass to the controller the same object but I want that this object could be from type A or from type B

– JJ Redikes
Nov 19 '18 at 21:08

Just don't. There is no good reason to send two completely different objects to the same resource. Create two different controller (or controller methods), doing two different things, and accepting two different types of objects.

– JB Nizet
Nov 19 '18 at 21:12

Also, using GET to send a request body doesn't make any sense. GET requests don't have a body.

– JB Nizet
Nov 19 '18 at 21:13

add a comment |

1 Answer
1

active

oldest

votes

Just as you have written, you can do it just like that:

@RequestMapping(...)

public void method(@RequestBody YourCustomClass body)

YourCustomClass can be either option 1 or option 2.

And that's all :)

answered Nov 19 '18 at 21:01

J. Doe

the only problem that you can't create to different objects with the same name in java... so YourCustomClass can be only one of the option. how can I know if its option 1 or 2?

– JJ Redikes
Nov 19 '18 at 21:06

Then do it like this: @RequestBody Object body if(body instance of com.example.class.CustomClass){} else if (body instance of com.example.another.class.CustomClass){}

– J. Doe
Nov 19 '18 at 21:45

its almost fine. the problem here that java recognize the 'body' as list of key and value like a Jason... what do you recommenced to fix that?

– JJ Redikes
Nov 19 '18 at 21:55

As far as I know if you give it the proper Json it should map it to Object without any problem. Just add the annotation @RestController for the whole controller class

– J. Doe
Nov 19 '18 at 22:18

I know how to map to object but not on the way that you recommends. it not working this way, im sure there is different way to do it...

– JJ Redikes
Nov 20 '18 at 15:17

add a comment |

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1 Answer
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active

oldest

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1 Answer
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active

oldest

votes

Just as you have written, you can do it just like that:

@RequestMapping(...)

public void method(@RequestBody YourCustomClass body)

YourCustomClass can be either option 1 or option 2.

And that's all :)

answered Nov 19 '18 at 21:01

J. Doe

the only problem that you can't create to different objects with the same name in java... so YourCustomClass can be only one of the option. how can I know if its option 1 or 2?

– JJ Redikes
Nov 19 '18 at 21:06

Then do it like this: @RequestBody Object body if(body instance of com.example.class.CustomClass){} else if (body instance of com.example.another.class.CustomClass){}

– J. Doe
Nov 19 '18 at 21:45

its almost fine. the problem here that java recognize the 'body' as list of key and value like a Jason... what do you recommenced to fix that?

– JJ Redikes
Nov 19 '18 at 21:55

As far as I know if you give it the proper Json it should map it to Object without any problem. Just add the annotation @RestController for the whole controller class

– J. Doe
Nov 19 '18 at 22:18

I know how to map to object but not on the way that you recommends. it not working this way, im sure there is different way to do it...

– JJ Redikes
Nov 20 '18 at 15:17

add a comment |

Just as you have written, you can do it just like that:

@RequestMapping(...)

public void method(@RequestBody YourCustomClass body)

YourCustomClass can be either option 1 or option 2.

And that's all :)

answered Nov 19 '18 at 21:01

J. Doe

the only problem that you can't create to different objects with the same name in java... so YourCustomClass can be only one of the option. how can I know if its option 1 or 2?

– JJ Redikes
Nov 19 '18 at 21:06

Then do it like this: @RequestBody Object body if(body instance of com.example.class.CustomClass){} else if (body instance of com.example.another.class.CustomClass){}

– J. Doe
Nov 19 '18 at 21:45

its almost fine. the problem here that java recognize the 'body' as list of key and value like a Jason... what do you recommenced to fix that?

– JJ Redikes
Nov 19 '18 at 21:55

As far as I know if you give it the proper Json it should map it to Object without any problem. Just add the annotation @RestController for the whole controller class

– J. Doe
Nov 19 '18 at 22:18

I know how to map to object but not on the way that you recommends. it not working this way, im sure there is different way to do it...

– JJ Redikes
Nov 20 '18 at 15:17

add a comment |

Just as you have written, you can do it just like that:

@RequestMapping(...)

public void method(@RequestBody YourCustomClass body)

YourCustomClass can be either option 1 or option 2.

And that's all :)

answered Nov 19 '18 at 21:01

J. Doe

Just as you have written, you can do it just like that:

@RequestMapping(...)

public void method(@RequestBody YourCustomClass body)

YourCustomClass can be either option 1 or option 2.

And that's all :)

answered Nov 19 '18 at 21:01

J. Doe

answered Nov 19 '18 at 21:01

J. Doe

answered Nov 19 '18 at 21:01

J. Doe

answered Nov 19 '18 at 21:01

J. Doe

the only problem that you can't create to different objects with the same name in java... so YourCustomClass can be only one of the option. how can I know if its option 1 or 2?

– JJ Redikes
Nov 19 '18 at 21:06

Then do it like this: @RequestBody Object body if(body instance of com.example.class.CustomClass){} else if (body instance of com.example.another.class.CustomClass){}

– J. Doe
Nov 19 '18 at 21:45

its almost fine. the problem here that java recognize the 'body' as list of key and value like a Jason... what do you recommenced to fix that?

– JJ Redikes
Nov 19 '18 at 21:55

As far as I know if you give it the proper Json it should map it to Object without any problem. Just add the annotation @RestController for the whole controller class

– J. Doe
Nov 19 '18 at 22:18

I know how to map to object but not on the way that you recommends. it not working this way, im sure there is different way to do it...

– JJ Redikes
Nov 20 '18 at 15:17

add a comment |

the only problem that you can't create to different objects with the same name in java... so YourCustomClass can be only one of the option. how can I know if its option 1 or 2?

– JJ Redikes
Nov 19 '18 at 21:06

Then do it like this: @RequestBody Object body if(body instance of com.example.class.CustomClass){} else if (body instance of com.example.another.class.CustomClass){}

– J. Doe
Nov 19 '18 at 21:45

its almost fine. the problem here that java recognize the 'body' as list of key and value like a Jason... what do you recommenced to fix that?

– JJ Redikes
Nov 19 '18 at 21:55

As far as I know if you give it the proper Json it should map it to Object without any problem. Just add the annotation @RestController for the whole controller class

– J. Doe
Nov 19 '18 at 22:18

I know how to map to object but not on the way that you recommends. it not working this way, im sure there is different way to do it...

– JJ Redikes
Nov 20 '18 at 15:17

the only problem that you can't create to different objects with the same name in java... so YourCustomClass can be only one of the option. how can I know if its option 1 or 2?

– JJ Redikes
Nov 19 '18 at 21:06

Then do it like this: @RequestBody Object body if(body instance of com.example.class.CustomClass){} else if (body instance of com.example.another.class.CustomClass){}

– J. Doe
Nov 19 '18 at 21:45

its almost fine. the problem here that java recognize the 'body' as list of key and value like a Jason... what do you recommenced to fix that?

– JJ Redikes
Nov 19 '18 at 21:55

As far as I know if you give it the proper Json it should map it to Object without any problem. Just add the annotation @RestController for the whole controller class

– J. Doe
Nov 19 '18 at 22:18

I know how to map to object but not on the way that you recommends. it not working this way, im sure there is different way to do it...

– JJ Redikes
Nov 20 '18 at 15:17

add a comment |

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