variable assigned at the end of a module











up vote
0
down vote

favorite












I have a quick question about how variables are passed from 1 module to another.



Scenarios:



I have 2 scripts, 1 name a.py and b.py.



## a.py
import datetime
import numpy as np
import os

class LOG:
testid = ""
log_f = None
perf_log_f = None

def __init__(self):
self.testid = ""

def setTestId (testid, log_f , perf_log_f):
log_v.testid = comp
log_v.log_f = open(log_f , 'w')
log_v.perf_log_f = open(perf_log_f, 'w')

log_v = LOG()


l is initiated



## b.py
from a import *

testid = 999
log_f = "kk.log"
perf_log_f = "kk_perf.log"
setTestId (testid, log_f , perf_log_f)

#### Does this setTestId do this step?
"log_v.log_f = open("kk.log", 'w')
"log_v.perf_log_f = open("kk_perf.log", 'w')


Make the amendment. So when I call setTestId (imported from a) into b.py, log_v = LOG() is only contained within a.py, right?



I would like to check if the the variable log_v in a.py will be overwritten if we assign log_v to another variable in b.py










share|improve this question




















  • 2




    assuming your indentation is correct the answer is no.
    – Red Cricket
    Nov 15 at 5:56










  • you are calling l.selfTestId on l but your method is not part of the class LOG. Check your indentation or refresh OOP concepts
    – Prakash Palnati
    Nov 15 at 5:58












  • Naming a variable "l" is too ambiguous, try to name it properly and for your answer it is no.
    – Vishnudev
    Nov 15 at 6:05










  • Let's put it this way: l in b.py will be exactly what l is in a.py.
    – deceze
    Nov 15 at 6:09










  • so the c = Clog() is contain within scripts a.py? and if I have a variable c in b.py, this is not related to the c in a.py>? I apologise for my bad OOP concepts. Also, the indentation is correct.
    – snookrun
    Nov 15 at 6:44















up vote
0
down vote

favorite












I have a quick question about how variables are passed from 1 module to another.



Scenarios:



I have 2 scripts, 1 name a.py and b.py.



## a.py
import datetime
import numpy as np
import os

class LOG:
testid = ""
log_f = None
perf_log_f = None

def __init__(self):
self.testid = ""

def setTestId (testid, log_f , perf_log_f):
log_v.testid = comp
log_v.log_f = open(log_f , 'w')
log_v.perf_log_f = open(perf_log_f, 'w')

log_v = LOG()


l is initiated



## b.py
from a import *

testid = 999
log_f = "kk.log"
perf_log_f = "kk_perf.log"
setTestId (testid, log_f , perf_log_f)

#### Does this setTestId do this step?
"log_v.log_f = open("kk.log", 'w')
"log_v.perf_log_f = open("kk_perf.log", 'w')


Make the amendment. So when I call setTestId (imported from a) into b.py, log_v = LOG() is only contained within a.py, right?



I would like to check if the the variable log_v in a.py will be overwritten if we assign log_v to another variable in b.py










share|improve this question




















  • 2




    assuming your indentation is correct the answer is no.
    – Red Cricket
    Nov 15 at 5:56










  • you are calling l.selfTestId on l but your method is not part of the class LOG. Check your indentation or refresh OOP concepts
    – Prakash Palnati
    Nov 15 at 5:58












  • Naming a variable "l" is too ambiguous, try to name it properly and for your answer it is no.
    – Vishnudev
    Nov 15 at 6:05










  • Let's put it this way: l in b.py will be exactly what l is in a.py.
    – deceze
    Nov 15 at 6:09










  • so the c = Clog() is contain within scripts a.py? and if I have a variable c in b.py, this is not related to the c in a.py>? I apologise for my bad OOP concepts. Also, the indentation is correct.
    – snookrun
    Nov 15 at 6:44













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I have a quick question about how variables are passed from 1 module to another.



Scenarios:



I have 2 scripts, 1 name a.py and b.py.



## a.py
import datetime
import numpy as np
import os

class LOG:
testid = ""
log_f = None
perf_log_f = None

def __init__(self):
self.testid = ""

def setTestId (testid, log_f , perf_log_f):
log_v.testid = comp
log_v.log_f = open(log_f , 'w')
log_v.perf_log_f = open(perf_log_f, 'w')

log_v = LOG()


l is initiated



## b.py
from a import *

testid = 999
log_f = "kk.log"
perf_log_f = "kk_perf.log"
setTestId (testid, log_f , perf_log_f)

#### Does this setTestId do this step?
"log_v.log_f = open("kk.log", 'w')
"log_v.perf_log_f = open("kk_perf.log", 'w')


Make the amendment. So when I call setTestId (imported from a) into b.py, log_v = LOG() is only contained within a.py, right?



I would like to check if the the variable log_v in a.py will be overwritten if we assign log_v to another variable in b.py










share|improve this question















I have a quick question about how variables are passed from 1 module to another.



Scenarios:



I have 2 scripts, 1 name a.py and b.py.



## a.py
import datetime
import numpy as np
import os

class LOG:
testid = ""
log_f = None
perf_log_f = None

def __init__(self):
self.testid = ""

def setTestId (testid, log_f , perf_log_f):
log_v.testid = comp
log_v.log_f = open(log_f , 'w')
log_v.perf_log_f = open(perf_log_f, 'w')

log_v = LOG()


l is initiated



## b.py
from a import *

testid = 999
log_f = "kk.log"
perf_log_f = "kk_perf.log"
setTestId (testid, log_f , perf_log_f)

#### Does this setTestId do this step?
"log_v.log_f = open("kk.log", 'w')
"log_v.perf_log_f = open("kk_perf.log", 'w')


Make the amendment. So when I call setTestId (imported from a) into b.py, log_v = LOG() is only contained within a.py, right?



I would like to check if the the variable log_v in a.py will be overwritten if we assign log_v to another variable in b.py







python class variables






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 15 at 7:02









tripleee

87.6k12122177




87.6k12122177










asked Nov 15 at 5:52









snookrun

255




255








  • 2




    assuming your indentation is correct the answer is no.
    – Red Cricket
    Nov 15 at 5:56










  • you are calling l.selfTestId on l but your method is not part of the class LOG. Check your indentation or refresh OOP concepts
    – Prakash Palnati
    Nov 15 at 5:58












  • Naming a variable "l" is too ambiguous, try to name it properly and for your answer it is no.
    – Vishnudev
    Nov 15 at 6:05










  • Let's put it this way: l in b.py will be exactly what l is in a.py.
    – deceze
    Nov 15 at 6:09










  • so the c = Clog() is contain within scripts a.py? and if I have a variable c in b.py, this is not related to the c in a.py>? I apologise for my bad OOP concepts. Also, the indentation is correct.
    – snookrun
    Nov 15 at 6:44














  • 2




    assuming your indentation is correct the answer is no.
    – Red Cricket
    Nov 15 at 5:56










  • you are calling l.selfTestId on l but your method is not part of the class LOG. Check your indentation or refresh OOP concepts
    – Prakash Palnati
    Nov 15 at 5:58












  • Naming a variable "l" is too ambiguous, try to name it properly and for your answer it is no.
    – Vishnudev
    Nov 15 at 6:05










  • Let's put it this way: l in b.py will be exactly what l is in a.py.
    – deceze
    Nov 15 at 6:09










  • so the c = Clog() is contain within scripts a.py? and if I have a variable c in b.py, this is not related to the c in a.py>? I apologise for my bad OOP concepts. Also, the indentation is correct.
    – snookrun
    Nov 15 at 6:44








2




2




assuming your indentation is correct the answer is no.
– Red Cricket
Nov 15 at 5:56




assuming your indentation is correct the answer is no.
– Red Cricket
Nov 15 at 5:56












you are calling l.selfTestId on l but your method is not part of the class LOG. Check your indentation or refresh OOP concepts
– Prakash Palnati
Nov 15 at 5:58






you are calling l.selfTestId on l but your method is not part of the class LOG. Check your indentation or refresh OOP concepts
– Prakash Palnati
Nov 15 at 5:58














Naming a variable "l" is too ambiguous, try to name it properly and for your answer it is no.
– Vishnudev
Nov 15 at 6:05




Naming a variable "l" is too ambiguous, try to name it properly and for your answer it is no.
– Vishnudev
Nov 15 at 6:05












Let's put it this way: l in b.py will be exactly what l is in a.py.
– deceze
Nov 15 at 6:09




Let's put it this way: l in b.py will be exactly what l is in a.py.
– deceze
Nov 15 at 6:09












so the c = Clog() is contain within scripts a.py? and if I have a variable c in b.py, this is not related to the c in a.py>? I apologise for my bad OOP concepts. Also, the indentation is correct.
– snookrun
Nov 15 at 6:44




so the c = Clog() is contain within scripts a.py? and if I have a variable c in b.py, this is not related to the c in a.py>? I apologise for my bad OOP concepts. Also, the indentation is correct.
– snookrun
Nov 15 at 6:44












1 Answer
1






active

oldest

votes

















up vote
0
down vote



accepted










I figured it out.



LOG() class is initiated at importing of a.py. It is assigned to the instance log_v



In b.py, when I call the functions setTestId (testid, log_f , perf_log_f), it passes the arguments, testid, log_f , perf_log_f to log_v to a.py and allow the initialization of the class with these variables.



Hence suppose I have a new functions logging() in a.py that uses log_v, by simply importing a.py and call the function logging(), I am able to access the class LOG() using the instance log_v that is contained within a.py and make any modification or updates to the class. This log_v is also protected from the scripts in b.py so it does not get overwritten if we also have another instance or variable name log_v in b.py






share|improve this answer





















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    1 Answer
    1






    active

    oldest

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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    0
    down vote



    accepted










    I figured it out.



    LOG() class is initiated at importing of a.py. It is assigned to the instance log_v



    In b.py, when I call the functions setTestId (testid, log_f , perf_log_f), it passes the arguments, testid, log_f , perf_log_f to log_v to a.py and allow the initialization of the class with these variables.



    Hence suppose I have a new functions logging() in a.py that uses log_v, by simply importing a.py and call the function logging(), I am able to access the class LOG() using the instance log_v that is contained within a.py and make any modification or updates to the class. This log_v is also protected from the scripts in b.py so it does not get overwritten if we also have another instance or variable name log_v in b.py






    share|improve this answer

























      up vote
      0
      down vote



      accepted










      I figured it out.



      LOG() class is initiated at importing of a.py. It is assigned to the instance log_v



      In b.py, when I call the functions setTestId (testid, log_f , perf_log_f), it passes the arguments, testid, log_f , perf_log_f to log_v to a.py and allow the initialization of the class with these variables.



      Hence suppose I have a new functions logging() in a.py that uses log_v, by simply importing a.py and call the function logging(), I am able to access the class LOG() using the instance log_v that is contained within a.py and make any modification or updates to the class. This log_v is also protected from the scripts in b.py so it does not get overwritten if we also have another instance or variable name log_v in b.py






      share|improve this answer























        up vote
        0
        down vote



        accepted







        up vote
        0
        down vote



        accepted






        I figured it out.



        LOG() class is initiated at importing of a.py. It is assigned to the instance log_v



        In b.py, when I call the functions setTestId (testid, log_f , perf_log_f), it passes the arguments, testid, log_f , perf_log_f to log_v to a.py and allow the initialization of the class with these variables.



        Hence suppose I have a new functions logging() in a.py that uses log_v, by simply importing a.py and call the function logging(), I am able to access the class LOG() using the instance log_v that is contained within a.py and make any modification or updates to the class. This log_v is also protected from the scripts in b.py so it does not get overwritten if we also have another instance or variable name log_v in b.py






        share|improve this answer












        I figured it out.



        LOG() class is initiated at importing of a.py. It is assigned to the instance log_v



        In b.py, when I call the functions setTestId (testid, log_f , perf_log_f), it passes the arguments, testid, log_f , perf_log_f to log_v to a.py and allow the initialization of the class with these variables.



        Hence suppose I have a new functions logging() in a.py that uses log_v, by simply importing a.py and call the function logging(), I am able to access the class LOG() using the instance log_v that is contained within a.py and make any modification or updates to the class. This log_v is also protected from the scripts in b.py so it does not get overwritten if we also have another instance or variable name log_v in b.py







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 19 at 0:27









        snookrun

        255




        255






























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