Exact sequences of sheaves
I don't understand something : in the notes by Justin Campell "Some examples of the Riemann-Hilbert correspondence", it is stated that there is an exact sequence $$ 0 to delta_{infty} to j_!IC_{Bbb A^1} to IC_{Bbb P^1}to 0$$ where $Bbb P^1$ is stratified as $Bbb A^1 sqcup {infty}$ and $delta_{infty} $ is the skyscraper sheaf with constant stalk $Bbb Q$.
However, taking the stalk at infinity gives $0 to Bbb Q to 0 to Bbb Q to 0 $ which is clearly a contradiction. As far as I understand, that this sequence was obtained by taking the Verdier dual of the sequence $$ 0 to IC_{Bbb P^1} to j_*IC_{Bbb A^1} to delta_{infty} to 0 $$ which seems plausible but where is my mistake ?
algebraic-geometry algebraic-topology sheaf-cohomology
|
show 1 more comment
I don't understand something : in the notes by Justin Campell "Some examples of the Riemann-Hilbert correspondence", it is stated that there is an exact sequence $$ 0 to delta_{infty} to j_!IC_{Bbb A^1} to IC_{Bbb P^1}to 0$$ where $Bbb P^1$ is stratified as $Bbb A^1 sqcup {infty}$ and $delta_{infty} $ is the skyscraper sheaf with constant stalk $Bbb Q$.
However, taking the stalk at infinity gives $0 to Bbb Q to 0 to Bbb Q to 0 $ which is clearly a contradiction. As far as I understand, that this sequence was obtained by taking the Verdier dual of the sequence $$ 0 to IC_{Bbb P^1} to j_*IC_{Bbb A^1} to delta_{infty} to 0 $$ which seems plausible but where is my mistake ?
algebraic-geometry algebraic-topology sheaf-cohomology
I think the author meant exact sequence of perverse sheaves.
– Roland
Nov 20 at 18:25
@Roland : I see, so is there a "concrete" description of what is an exact sequence of perverse sheaves ? Is there a way I can think of it in term of classical exact sequence of sheaves ? I find it really confusing that perverse epimorphism does not induce surjective map on stalks.
– student
Nov 20 at 18:30
Think in term of derived category. For a sequence $0to Ato Bto Cto 0$ in a triangulated category $mathcal{T}$ to be exact for a $t$-structure, it is enough that they all lie in the heart and that $Ato Bto Cto A[1]$ is distinguished (Just take the long exact sequence of cohomology). I'm not sure about the converse though. But here, you have the triangle $delta_{infty}to j_! IC_{mathbb{A}^1}to IC_{mathbb{P}^1}todelta_{infty}[1]$ (which is just a rotation of a triangle of sheaves), and they all are perverse sheaves. So this is an exact sequence of perverse sheaves.
– Roland
Nov 20 at 18:42
But yes, the stalk functor is not exact in the category of perverse sheaves.
– Roland
Nov 20 at 18:43
@Roland : thanks a lot, your explanations are wonderful as always !
– student
Nov 20 at 19:54
|
show 1 more comment
I don't understand something : in the notes by Justin Campell "Some examples of the Riemann-Hilbert correspondence", it is stated that there is an exact sequence $$ 0 to delta_{infty} to j_!IC_{Bbb A^1} to IC_{Bbb P^1}to 0$$ where $Bbb P^1$ is stratified as $Bbb A^1 sqcup {infty}$ and $delta_{infty} $ is the skyscraper sheaf with constant stalk $Bbb Q$.
However, taking the stalk at infinity gives $0 to Bbb Q to 0 to Bbb Q to 0 $ which is clearly a contradiction. As far as I understand, that this sequence was obtained by taking the Verdier dual of the sequence $$ 0 to IC_{Bbb P^1} to j_*IC_{Bbb A^1} to delta_{infty} to 0 $$ which seems plausible but where is my mistake ?
algebraic-geometry algebraic-topology sheaf-cohomology
I don't understand something : in the notes by Justin Campell "Some examples of the Riemann-Hilbert correspondence", it is stated that there is an exact sequence $$ 0 to delta_{infty} to j_!IC_{Bbb A^1} to IC_{Bbb P^1}to 0$$ where $Bbb P^1$ is stratified as $Bbb A^1 sqcup {infty}$ and $delta_{infty} $ is the skyscraper sheaf with constant stalk $Bbb Q$.
However, taking the stalk at infinity gives $0 to Bbb Q to 0 to Bbb Q to 0 $ which is clearly a contradiction. As far as I understand, that this sequence was obtained by taking the Verdier dual of the sequence $$ 0 to IC_{Bbb P^1} to j_*IC_{Bbb A^1} to delta_{infty} to 0 $$ which seems plausible but where is my mistake ?
algebraic-geometry algebraic-topology sheaf-cohomology
algebraic-geometry algebraic-topology sheaf-cohomology
asked Nov 20 at 18:01
student
1078
1078
I think the author meant exact sequence of perverse sheaves.
– Roland
Nov 20 at 18:25
@Roland : I see, so is there a "concrete" description of what is an exact sequence of perverse sheaves ? Is there a way I can think of it in term of classical exact sequence of sheaves ? I find it really confusing that perverse epimorphism does not induce surjective map on stalks.
– student
Nov 20 at 18:30
Think in term of derived category. For a sequence $0to Ato Bto Cto 0$ in a triangulated category $mathcal{T}$ to be exact for a $t$-structure, it is enough that they all lie in the heart and that $Ato Bto Cto A[1]$ is distinguished (Just take the long exact sequence of cohomology). I'm not sure about the converse though. But here, you have the triangle $delta_{infty}to j_! IC_{mathbb{A}^1}to IC_{mathbb{P}^1}todelta_{infty}[1]$ (which is just a rotation of a triangle of sheaves), and they all are perverse sheaves. So this is an exact sequence of perverse sheaves.
– Roland
Nov 20 at 18:42
But yes, the stalk functor is not exact in the category of perverse sheaves.
– Roland
Nov 20 at 18:43
@Roland : thanks a lot, your explanations are wonderful as always !
– student
Nov 20 at 19:54
|
show 1 more comment
I think the author meant exact sequence of perverse sheaves.
– Roland
Nov 20 at 18:25
@Roland : I see, so is there a "concrete" description of what is an exact sequence of perverse sheaves ? Is there a way I can think of it in term of classical exact sequence of sheaves ? I find it really confusing that perverse epimorphism does not induce surjective map on stalks.
– student
Nov 20 at 18:30
Think in term of derived category. For a sequence $0to Ato Bto Cto 0$ in a triangulated category $mathcal{T}$ to be exact for a $t$-structure, it is enough that they all lie in the heart and that $Ato Bto Cto A[1]$ is distinguished (Just take the long exact sequence of cohomology). I'm not sure about the converse though. But here, you have the triangle $delta_{infty}to j_! IC_{mathbb{A}^1}to IC_{mathbb{P}^1}todelta_{infty}[1]$ (which is just a rotation of a triangle of sheaves), and they all are perverse sheaves. So this is an exact sequence of perverse sheaves.
– Roland
Nov 20 at 18:42
But yes, the stalk functor is not exact in the category of perverse sheaves.
– Roland
Nov 20 at 18:43
@Roland : thanks a lot, your explanations are wonderful as always !
– student
Nov 20 at 19:54
I think the author meant exact sequence of perverse sheaves.
– Roland
Nov 20 at 18:25
I think the author meant exact sequence of perverse sheaves.
– Roland
Nov 20 at 18:25
@Roland : I see, so is there a "concrete" description of what is an exact sequence of perverse sheaves ? Is there a way I can think of it in term of classical exact sequence of sheaves ? I find it really confusing that perverse epimorphism does not induce surjective map on stalks.
– student
Nov 20 at 18:30
@Roland : I see, so is there a "concrete" description of what is an exact sequence of perverse sheaves ? Is there a way I can think of it in term of classical exact sequence of sheaves ? I find it really confusing that perverse epimorphism does not induce surjective map on stalks.
– student
Nov 20 at 18:30
Think in term of derived category. For a sequence $0to Ato Bto Cto 0$ in a triangulated category $mathcal{T}$ to be exact for a $t$-structure, it is enough that they all lie in the heart and that $Ato Bto Cto A[1]$ is distinguished (Just take the long exact sequence of cohomology). I'm not sure about the converse though. But here, you have the triangle $delta_{infty}to j_! IC_{mathbb{A}^1}to IC_{mathbb{P}^1}todelta_{infty}[1]$ (which is just a rotation of a triangle of sheaves), and they all are perverse sheaves. So this is an exact sequence of perverse sheaves.
– Roland
Nov 20 at 18:42
Think in term of derived category. For a sequence $0to Ato Bto Cto 0$ in a triangulated category $mathcal{T}$ to be exact for a $t$-structure, it is enough that they all lie in the heart and that $Ato Bto Cto A[1]$ is distinguished (Just take the long exact sequence of cohomology). I'm not sure about the converse though. But here, you have the triangle $delta_{infty}to j_! IC_{mathbb{A}^1}to IC_{mathbb{P}^1}todelta_{infty}[1]$ (which is just a rotation of a triangle of sheaves), and they all are perverse sheaves. So this is an exact sequence of perverse sheaves.
– Roland
Nov 20 at 18:42
But yes, the stalk functor is not exact in the category of perverse sheaves.
– Roland
Nov 20 at 18:43
But yes, the stalk functor is not exact in the category of perverse sheaves.
– Roland
Nov 20 at 18:43
@Roland : thanks a lot, your explanations are wonderful as always !
– student
Nov 20 at 19:54
@Roland : thanks a lot, your explanations are wonderful as always !
– student
Nov 20 at 19:54
|
show 1 more comment
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3006674%2fexact-sequences-of-sheaves%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3006674%2fexact-sequences-of-sheaves%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
I think the author meant exact sequence of perverse sheaves.
– Roland
Nov 20 at 18:25
@Roland : I see, so is there a "concrete" description of what is an exact sequence of perverse sheaves ? Is there a way I can think of it in term of classical exact sequence of sheaves ? I find it really confusing that perverse epimorphism does not induce surjective map on stalks.
– student
Nov 20 at 18:30
Think in term of derived category. For a sequence $0to Ato Bto Cto 0$ in a triangulated category $mathcal{T}$ to be exact for a $t$-structure, it is enough that they all lie in the heart and that $Ato Bto Cto A[1]$ is distinguished (Just take the long exact sequence of cohomology). I'm not sure about the converse though. But here, you have the triangle $delta_{infty}to j_! IC_{mathbb{A}^1}to IC_{mathbb{P}^1}todelta_{infty}[1]$ (which is just a rotation of a triangle of sheaves), and they all are perverse sheaves. So this is an exact sequence of perverse sheaves.
– Roland
Nov 20 at 18:42
But yes, the stalk functor is not exact in the category of perverse sheaves.
– Roland
Nov 20 at 18:43
@Roland : thanks a lot, your explanations are wonderful as always !
– student
Nov 20 at 19:54