Find coordinate from distance and coordinate
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I know that this topic has been done already but i believe that my issues is a bit more annoying.
I have a circle which I know its center's coordinate that cross a line like this :
*****
-*-------*---- <-- The line
* *
* * <------ The circle
* *
*******
In addition to that i know the Y coordinates of my line. My problem is the following :
x1,y1 : the coordinates of the circle's center
x2,y2 : the coordinates of the intersection between the circle and the line
r : the radius of the circle
Knowing x1,y1,y2,r is it possible to get x2 on an equation where x2 is the only element of the right part of our equation (i mean 'x2 = ?')
coordinate-systems
asked Nov 12 at 17:23
OgL0C
1
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OgL0C is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment |
up vote
0
down vote
favorite
I know that this topic has been done already but i believe that my issues is a bit more annoying.
I have a circle which I know its center's coordinate that cross a line like this :
*****
-*-------*---- <-- The line
* *
* * <------ The circle
* *
*******
In addition to that i know the Y coordinates of my line. My problem is the following :
x1,y1 : the coordinates of the circle's center
x2,y2 : the coordinates of the intersection between the circle and the line
r : the radius of the circle
Knowing x1,y1,y2,r is it possible to get x2 on an equation where x2 is the only element of the right part of our equation (i mean 'x2 = ?')
coordinate-systems
asked Nov 12 at 17:23
OgL0C
1
New contributor
OgL0C is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Use the Pythagorean theorem.
– amd
Nov 12 at 17:35
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I know that this topic has been done already but i believe that my issues is a bit more annoying.
I have a circle which I know its center's coordinate that cross a line like this :
*****
-*-------*---- <-- The line
* *
* * <------ The circle
* *
*******
In addition to that i know the Y coordinates of my line. My problem is the following :
x1,y1 : the coordinates of the circle's center
x2,y2 : the coordinates of the intersection between the circle and the line
r : the radius of the circle
Knowing x1,y1,y2,r is it possible to get x2 on an equation where x2 is the only element of the right part of our equation (i mean 'x2 = ?')
coordinate-systems
asked Nov 12 at 17:23
OgL0C
1
New contributor
OgL0C is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I know that this topic has been done already but i believe that my issues is a bit more annoying.
I have a circle which I know its center's coordinate that cross a line like this :
*****
-*-------*---- <-- The line
* *
* * <------ The circle
* *
*******
In addition to that i know the Y coordinates of my line. My problem is the following :
x1,y1 : the coordinates of the circle's center
x2,y2 : the coordinates of the intersection between the circle and the line
r : the radius of the circle
Knowing x1,y1,y2,r is it possible to get x2 on an equation where x2 is the only element of the right part of our equation (i mean 'x2 = ?')
coordinate-systems
coordinate-systems
asked Nov 12 at 17:23
OgL0C
1
New contributor
OgL0C is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Nov 12 at 17:23
OgL0C
1
New contributor
OgL0C is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Nov 12 at 17:23
OgL0C
1
New contributor
OgL0C is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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asked Nov 12 at 17:23
OgL0C
1
asked Nov 12 at 17:23
OgL0C
1
1
New contributor
OgL0C is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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New contributor
OgL0C is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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OgL0C is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Use the Pythagorean theorem.
– amd
Nov 12 at 17:35
add a comment |
Use the Pythagorean theorem.
– amd
Nov 12 at 17:35
Use the Pythagorean theorem.
– amd
Nov 12 at 17:35
Use the Pythagorean theorem.
– amd
Nov 12 at 17:35
add a comment |
2 Answers
2
active
oldest
votes
up vote
0
down vote
Yes it is possible to get $x_2$ such that the above mentioned property satisfies, by the distance formula,
$$(x_1-x_2)^2+(y_1-y_2)^2 = r^2$$
This is a quadratic equation in $x_2$, thus will give two solution, one for each intersection point.
Hope it helps:)
answered Nov 12 at 17:28
Crazy for maths
4948
Yeah i did find that but i can't manage to get x2 alone on the left part of the equation that you mention. Thanks though !
– OgL0C
Nov 12 at 17:43
add a comment |
up vote
0
down vote
Yes, you can use the distance between points formula
a^2 = (x2-x1)^2 + (y2-y2)^2
The solutions of this equation is the answer you are looking for.
answered Nov 12 at 17:31
rad
11
New contributor
rad is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Yeah i did find that but i can't manage to get x2 alone on the left part of the equation that you and crazy for math mention. Thanks for responding as well
– OgL0C
Nov 12 at 17:47
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
Yes it is possible to get $x_2$ such that the above mentioned property satisfies, by the distance formula,
$$(x_1-x_2)^2+(y_1-y_2)^2 = r^2$$
This is a quadratic equation in $x_2$, thus will give two solution, one for each intersection point.
Hope it helps:)
answered Nov 12 at 17:28
Crazy for maths
4948
Yeah i did find that but i can't manage to get x2 alone on the left part of the equation that you mention. Thanks though !
– OgL0C
Nov 12 at 17:43
add a comment |
up vote
0
down vote
Yes it is possible to get $x_2$ such that the above mentioned property satisfies, by the distance formula,
$$(x_1-x_2)^2+(y_1-y_2)^2 = r^2$$
This is a quadratic equation in $x_2$, thus will give two solution, one for each intersection point.
Hope it helps:)
answered Nov 12 at 17:28
Crazy for maths
4948
Yeah i did find that but i can't manage to get x2 alone on the left part of the equation that you mention. Thanks though !
– OgL0C
Nov 12 at 17:43
add a comment |
up vote
0
down vote
up vote
0
down vote
Yes it is possible to get $x_2$ such that the above mentioned property satisfies, by the distance formula,
$$(x_1-x_2)^2+(y_1-y_2)^2 = r^2$$
This is a quadratic equation in $x_2$, thus will give two solution, one for each intersection point.
Hope it helps:)
answered Nov 12 at 17:28
Crazy for maths
4948
Yes it is possible to get $x_2$ such that the above mentioned property satisfies, by the distance formula,
$$(x_1-x_2)^2+(y_1-y_2)^2 = r^2$$
This is a quadratic equation in $x_2$, thus will give two solution, one for each intersection point.
Hope it helps:)
answered Nov 12 at 17:28
Crazy for maths
4948
answered Nov 12 at 17:28
Crazy for maths
4948
answered Nov 12 at 17:28
Crazy for maths
4948
answered Nov 12 at 17:28
Crazy for maths
4948
4948
Yeah i did find that but i can't manage to get x2 alone on the left part of the equation that you mention. Thanks though !
– OgL0C
Nov 12 at 17:43
add a comment |
Yeah i did find that but i can't manage to get x2 alone on the left part of the equation that you mention. Thanks though !
– OgL0C
Nov 12 at 17:43
Yeah i did find that but i can't manage to get x2 alone on the left part of the equation that you mention. Thanks though !
– OgL0C
Nov 12 at 17:43
Yeah i did find that but i can't manage to get x2 alone on the left part of the equation that you mention. Thanks though !
– OgL0C
Nov 12 at 17:43
add a comment |
up vote
0
down vote
Yes, you can use the distance between points formula
a^2 = (x2-x1)^2 + (y2-y2)^2
The solutions of this equation is the answer you are looking for.
answered Nov 12 at 17:31
rad
11
New contributor
rad is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Yeah i did find that but i can't manage to get x2 alone on the left part of the equation that you and crazy for math mention. Thanks for responding as well
– OgL0C
Nov 12 at 17:47
add a comment |
up vote
0
down vote
Yes, you can use the distance between points formula
a^2 = (x2-x1)^2 + (y2-y2)^2
The solutions of this equation is the answer you are looking for.
answered Nov 12 at 17:31
rad
11
New contributor
rad is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Yeah i did find that but i can't manage to get x2 alone on the left part of the equation that you and crazy for math mention. Thanks for responding as well
– OgL0C
Nov 12 at 17:47
add a comment |
up vote
0
down vote
up vote
0
down vote
Yes, you can use the distance between points formula
a^2 = (x2-x1)^2 + (y2-y2)^2
The solutions of this equation is the answer you are looking for.
answered Nov 12 at 17:31
rad
11
New contributor
rad is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Yes, you can use the distance between points formula
a^2 = (x2-x1)^2 + (y2-y2)^2
The solutions of this equation is the answer you are looking for.
answered Nov 12 at 17:31
rad
11
New contributor
rad is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered Nov 12 at 17:31
rad
11
New contributor
rad is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered Nov 12 at 17:31
rad
11
answered Nov 12 at 17:31
rad
11
11
New contributor
rad is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
rad is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
rad is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Yeah i did find that but i can't manage to get x2 alone on the left part of the equation that you and crazy for math mention. Thanks for responding as well
– OgL0C
Nov 12 at 17:47
add a comment |
Yeah i did find that but i can't manage to get x2 alone on the left part of the equation that you and crazy for math mention. Thanks for responding as well
– OgL0C
Nov 12 at 17:47
Yeah i did find that but i can't manage to get x2 alone on the left part of the equation that you and crazy for math mention. Thanks for responding as well
– OgL0C
Nov 12 at 17:47
Yeah i did find that but i can't manage to get x2 alone on the left part of the equation that you and crazy for math mention. Thanks for responding as well
– OgL0C
Nov 12 at 17:47
add a comment |
OgL0C is a new contributor. Be nice, and check out our Code of Conduct.
OgL0C is a new contributor. Be nice, and check out our Code of Conduct.
OgL0C is a new contributor. Be nice, and check out our Code of Conduct.
OgL0C is a new contributor. Be nice, and check out our Code of Conduct.
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Use the Pythagorean theorem.
– amd
Nov 12 at 17:35