Rearrange c++ const and reference specifiers
I'm trying to convert
const std::string &s
to
std::string const & s
and can't seem to get it quite right. This is the regex I'm using:
%s/const (.{-}) &/1 const &
and the result I'm getting:
std::string const const std::string &s
regular-expression c++
asked Mar 28 at 17:36
Jay MuellerJay Mueller
82
add a comment |
I'm trying to convert
const std::string &s
to
std::string const & s
and can't seem to get it quite right. This is the regex I'm using:
%s/const (.{-}) &/1 const &
and the result I'm getting:
std::string const const std::string &s
regular-expression c++
asked Mar 28 at 17:36
Jay MuellerJay Mueller
82
add a comment |
I'm trying to convert
const std::string &s
to
std::string const & s
and can't seem to get it quite right. This is the regex I'm using:
%s/const (.{-}) &/1 const &
and the result I'm getting:
std::string const const std::string &s
regular-expression c++
asked Mar 28 at 17:36
Jay MuellerJay Mueller
82
I'm trying to convert
const std::string &s
to
std::string const & s
and can't seem to get it quite right. This is the regex I'm using:
%s/const (.{-}) &/1 const &
and the result I'm getting:
std::string const const std::string &s
regular-expression c++
regular-expression c++
asked Mar 28 at 17:36
Jay MuellerJay Mueller
82
asked Mar 28 at 17:36
Jay MuellerJay Mueller
82
asked Mar 28 at 17:36
Jay MuellerJay Mueller
82
asked Mar 28 at 17:36
Jay MuellerJay Mueller
82
asked Mar 28 at 17:36
Jay MuellerJay Mueller
82
82
add a comment |
add a comment |
1 Answer
1
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oldest
votes
Just escape the & with a backslash.
%s/const (.{-}) &/1 const &
The & in the replace part inserts the entire matched pattern.
See :help s/&.
answered Mar 28 at 17:47
RalfRalf
3,2951317
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Just escape the & with a backslash.
%s/const (.{-}) &/1 const &
The & in the replace part inserts the entire matched pattern.
See :help s/&.
answered Mar 28 at 17:47
RalfRalf
3,2951317
add a comment |
Just escape the & with a backslash.
%s/const (.{-}) &/1 const &
The & in the replace part inserts the entire matched pattern.
See :help s/&.
answered Mar 28 at 17:47
RalfRalf
3,2951317
add a comment |
Just escape the & with a backslash.
%s/const (.{-}) &/1 const &
The & in the replace part inserts the entire matched pattern.
See :help s/&.
answered Mar 28 at 17:47
RalfRalf
3,2951317
Just escape the & with a backslash.
%s/const (.{-}) &/1 const &
The & in the replace part inserts the entire matched pattern.
See :help s/&.
answered Mar 28 at 17:47
RalfRalf
3,2951317
answered Mar 28 at 17:47
RalfRalf
3,2951317
answered Mar 28 at 17:47
RalfRalf
3,2951317
answered Mar 28 at 17:47
RalfRalf
3,2951317
3,2951317
add a comment |
add a comment |
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