How to search specific number using regular expressions





.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}







0















I have a comma separated values for each row in table.
Suppose in test table



Value
1,5,12
2,4,15
5,2,6


I would like to find records with value =5
Using normal ms sql, I had used like operator which gave me all the 3 records.
Could you please help if can it be possible with regular expression.










share|improve this question

























  • Don't store data as comma separated items, it will only cause you lots of trouble.

    – jarlh
    Nov 22 '18 at 10:27






  • 1





    Are you using MySQL or MS SQL Server?

    – jarlh
    Nov 22 '18 at 10:27











  • MySQL you can use : SELECT ..... WHERE CONCAT(',',value,',') LIKE '%,5,%'; - but it is always a FULL TABLE SCAN. see @ jarlh

    – Bernd Buffen
    Nov 22 '18 at 10:31











  • Possible duplicate of Is storing a delimited list in a database column really that bad?

    – Madhur Bhaiya
    Nov 22 '18 at 10:41











  • @jarlh I am using mssql

    – PNG
    Nov 22 '18 at 10:54


















0















I have a comma separated values for each row in table.
Suppose in test table



Value
1,5,12
2,4,15
5,2,6


I would like to find records with value =5
Using normal ms sql, I had used like operator which gave me all the 3 records.
Could you please help if can it be possible with regular expression.










share|improve this question

























  • Don't store data as comma separated items, it will only cause you lots of trouble.

    – jarlh
    Nov 22 '18 at 10:27






  • 1





    Are you using MySQL or MS SQL Server?

    – jarlh
    Nov 22 '18 at 10:27











  • MySQL you can use : SELECT ..... WHERE CONCAT(',',value,',') LIKE '%,5,%'; - but it is always a FULL TABLE SCAN. see @ jarlh

    – Bernd Buffen
    Nov 22 '18 at 10:31











  • Possible duplicate of Is storing a delimited list in a database column really that bad?

    – Madhur Bhaiya
    Nov 22 '18 at 10:41











  • @jarlh I am using mssql

    – PNG
    Nov 22 '18 at 10:54














0












0








0








I have a comma separated values for each row in table.
Suppose in test table



Value
1,5,12
2,4,15
5,2,6


I would like to find records with value =5
Using normal ms sql, I had used like operator which gave me all the 3 records.
Could you please help if can it be possible with regular expression.










share|improve this question
















I have a comma separated values for each row in table.
Suppose in test table



Value
1,5,12
2,4,15
5,2,6


I would like to find records with value =5
Using normal ms sql, I had used like operator which gave me all the 3 records.
Could you please help if can it be possible with regular expression.







sql sql-server






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 22 '18 at 10:55







PNG

















asked Nov 22 '18 at 10:25









PNGPNG

82




82













  • Don't store data as comma separated items, it will only cause you lots of trouble.

    – jarlh
    Nov 22 '18 at 10:27






  • 1





    Are you using MySQL or MS SQL Server?

    – jarlh
    Nov 22 '18 at 10:27











  • MySQL you can use : SELECT ..... WHERE CONCAT(',',value,',') LIKE '%,5,%'; - but it is always a FULL TABLE SCAN. see @ jarlh

    – Bernd Buffen
    Nov 22 '18 at 10:31











  • Possible duplicate of Is storing a delimited list in a database column really that bad?

    – Madhur Bhaiya
    Nov 22 '18 at 10:41











  • @jarlh I am using mssql

    – PNG
    Nov 22 '18 at 10:54



















  • Don't store data as comma separated items, it will only cause you lots of trouble.

    – jarlh
    Nov 22 '18 at 10:27






  • 1





    Are you using MySQL or MS SQL Server?

    – jarlh
    Nov 22 '18 at 10:27











  • MySQL you can use : SELECT ..... WHERE CONCAT(',',value,',') LIKE '%,5,%'; - but it is always a FULL TABLE SCAN. see @ jarlh

    – Bernd Buffen
    Nov 22 '18 at 10:31











  • Possible duplicate of Is storing a delimited list in a database column really that bad?

    – Madhur Bhaiya
    Nov 22 '18 at 10:41











  • @jarlh I am using mssql

    – PNG
    Nov 22 '18 at 10:54

















Don't store data as comma separated items, it will only cause you lots of trouble.

– jarlh
Nov 22 '18 at 10:27





Don't store data as comma separated items, it will only cause you lots of trouble.

– jarlh
Nov 22 '18 at 10:27




1




1





Are you using MySQL or MS SQL Server?

– jarlh
Nov 22 '18 at 10:27





Are you using MySQL or MS SQL Server?

– jarlh
Nov 22 '18 at 10:27













MySQL you can use : SELECT ..... WHERE CONCAT(',',value,',') LIKE '%,5,%'; - but it is always a FULL TABLE SCAN. see @ jarlh

– Bernd Buffen
Nov 22 '18 at 10:31





MySQL you can use : SELECT ..... WHERE CONCAT(',',value,',') LIKE '%,5,%'; - but it is always a FULL TABLE SCAN. see @ jarlh

– Bernd Buffen
Nov 22 '18 at 10:31













Possible duplicate of Is storing a delimited list in a database column really that bad?

– Madhur Bhaiya
Nov 22 '18 at 10:41





Possible duplicate of Is storing a delimited list in a database column really that bad?

– Madhur Bhaiya
Nov 22 '18 at 10:41













@jarlh I am using mssql

– PNG
Nov 22 '18 at 10:54





@jarlh I am using mssql

– PNG
Nov 22 '18 at 10:54












2 Answers
2






active

oldest

votes


















0














Try this too. Does not look very efficient but working.



    /* Create a table called NAMES */
CREATE TABLE test(Id integer PRIMARY KEY, Name text);

/* Create few records in this table */
INSERT INTO test VALUES(1,'1,5,12');
INSERT INTO test VALUES(2,'2,4,15');
INSERT INTO test VALUES(3,'5,2,6');
INSERT INTO test VALUES(5,'1,2,5');
-- SELECT * FROM test;

SELECT * from test WHERE Name LIKE '%,5,%' OR
Name LIKE '%5,%' OR
Name LIKE '%,5%';





share|improve this answer































    0














    You probably already know this is a bad data format and you should fix it. If you are stuck with it, you can use like:



    SELECT t.* 
    FROM test t
    WHERE ',' + Name + ',' LIKE '%,5,%';





    share|improve this answer
























      Your Answer






      StackExchange.ifUsing("editor", function () {
      StackExchange.using("externalEditor", function () {
      StackExchange.using("snippets", function () {
      StackExchange.snippets.init();
      });
      });
      }, "code-snippets");

      StackExchange.ready(function() {
      var channelOptions = {
      tags: "".split(" "),
      id: "1"
      };
      initTagRenderer("".split(" "), "".split(" "), channelOptions);

      StackExchange.using("externalEditor", function() {
      // Have to fire editor after snippets, if snippets enabled
      if (StackExchange.settings.snippets.snippetsEnabled) {
      StackExchange.using("snippets", function() {
      createEditor();
      });
      }
      else {
      createEditor();
      }
      });

      function createEditor() {
      StackExchange.prepareEditor({
      heartbeatType: 'answer',
      autoActivateHeartbeat: false,
      convertImagesToLinks: true,
      noModals: true,
      showLowRepImageUploadWarning: true,
      reputationToPostImages: 10,
      bindNavPrevention: true,
      postfix: "",
      imageUploader: {
      brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
      contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
      allowUrls: true
      },
      onDemand: true,
      discardSelector: ".discard-answer"
      ,immediatelyShowMarkdownHelp:true
      });


      }
      });














      draft saved

      draft discarded


















      StackExchange.ready(
      function () {
      StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53428803%2fhow-to-search-specific-number-using-regular-expressions%23new-answer', 'question_page');
      }
      );

      Post as a guest















      Required, but never shown

























      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      0














      Try this too. Does not look very efficient but working.



          /* Create a table called NAMES */
      CREATE TABLE test(Id integer PRIMARY KEY, Name text);

      /* Create few records in this table */
      INSERT INTO test VALUES(1,'1,5,12');
      INSERT INTO test VALUES(2,'2,4,15');
      INSERT INTO test VALUES(3,'5,2,6');
      INSERT INTO test VALUES(5,'1,2,5');
      -- SELECT * FROM test;

      SELECT * from test WHERE Name LIKE '%,5,%' OR
      Name LIKE '%5,%' OR
      Name LIKE '%,5%';





      share|improve this answer




























        0














        Try this too. Does not look very efficient but working.



            /* Create a table called NAMES */
        CREATE TABLE test(Id integer PRIMARY KEY, Name text);

        /* Create few records in this table */
        INSERT INTO test VALUES(1,'1,5,12');
        INSERT INTO test VALUES(2,'2,4,15');
        INSERT INTO test VALUES(3,'5,2,6');
        INSERT INTO test VALUES(5,'1,2,5');
        -- SELECT * FROM test;

        SELECT * from test WHERE Name LIKE '%,5,%' OR
        Name LIKE '%5,%' OR
        Name LIKE '%,5%';





        share|improve this answer


























          0












          0








          0







          Try this too. Does not look very efficient but working.



              /* Create a table called NAMES */
          CREATE TABLE test(Id integer PRIMARY KEY, Name text);

          /* Create few records in this table */
          INSERT INTO test VALUES(1,'1,5,12');
          INSERT INTO test VALUES(2,'2,4,15');
          INSERT INTO test VALUES(3,'5,2,6');
          INSERT INTO test VALUES(5,'1,2,5');
          -- SELECT * FROM test;

          SELECT * from test WHERE Name LIKE '%,5,%' OR
          Name LIKE '%5,%' OR
          Name LIKE '%,5%';





          share|improve this answer













          Try this too. Does not look very efficient but working.



              /* Create a table called NAMES */
          CREATE TABLE test(Id integer PRIMARY KEY, Name text);

          /* Create few records in this table */
          INSERT INTO test VALUES(1,'1,5,12');
          INSERT INTO test VALUES(2,'2,4,15');
          INSERT INTO test VALUES(3,'5,2,6');
          INSERT INTO test VALUES(5,'1,2,5');
          -- SELECT * FROM test;

          SELECT * from test WHERE Name LIKE '%,5,%' OR
          Name LIKE '%5,%' OR
          Name LIKE '%,5%';






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 22 '18 at 11:09









          Prashant Deshmukh.....Prashant Deshmukh.....

          68658




          68658

























              0














              You probably already know this is a bad data format and you should fix it. If you are stuck with it, you can use like:



              SELECT t.* 
              FROM test t
              WHERE ',' + Name + ',' LIKE '%,5,%';





              share|improve this answer




























                0














                You probably already know this is a bad data format and you should fix it. If you are stuck with it, you can use like:



                SELECT t.* 
                FROM test t
                WHERE ',' + Name + ',' LIKE '%,5,%';





                share|improve this answer


























                  0












                  0








                  0







                  You probably already know this is a bad data format and you should fix it. If you are stuck with it, you can use like:



                  SELECT t.* 
                  FROM test t
                  WHERE ',' + Name + ',' LIKE '%,5,%';





                  share|improve this answer













                  You probably already know this is a bad data format and you should fix it. If you are stuck with it, you can use like:



                  SELECT t.* 
                  FROM test t
                  WHERE ',' + Name + ',' LIKE '%,5,%';






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 22 '18 at 12:10









                  Gordon LinoffGordon Linoff

                  794k37318423




                  794k37318423






























                      draft saved

                      draft discarded




















































                      Thanks for contributing an answer to Stack Overflow!


                      • Please be sure to answer the question. Provide details and share your research!

                      But avoid



                      • Asking for help, clarification, or responding to other answers.

                      • Making statements based on opinion; back them up with references or personal experience.


                      To learn more, see our tips on writing great answers.




                      draft saved


                      draft discarded














                      StackExchange.ready(
                      function () {
                      StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53428803%2fhow-to-search-specific-number-using-regular-expressions%23new-answer', 'question_page');
                      }
                      );

                      Post as a guest















                      Required, but never shown





















































                      Required, but never shown














                      Required, but never shown












                      Required, but never shown







                      Required, but never shown

































                      Required, but never shown














                      Required, but never shown












                      Required, but never shown







                      Required, but never shown







                      Popular posts from this blog

                      How to send String Array data to Server using php in android

                      Title Spacing in Bjornstrup Chapter, Removing Chapter Number From Contents

                      Is anime1.com a legal site for watching anime?