Closed morphism of products of k-schemes with a field extension of k implies closed
$begingroup$
This is from exercise 9.2.J of Ravi Vakil's notes on algebraic geometry here
We have a morphism of $k$ schemes $pi:X rightarrow Y$. $l/k$ is a field extension. We want to show if $pitimes_k l: Xtimes_k lrightarrow Ytimes_k l$ is a closed embedding then $pi$ also is one.
If you assume $pi$ is affine this is fairly simple. I am having a lot of trouble proving it without that hypothesis. Any help would be appreciated.
algebraic-geometry extension-field schemes
$endgroup$
add a comment |
$begingroup$
This is from exercise 9.2.J of Ravi Vakil's notes on algebraic geometry here
We have a morphism of $k$ schemes $pi:X rightarrow Y$. $l/k$ is a field extension. We want to show if $pitimes_k l: Xtimes_k lrightarrow Ytimes_k l$ is a closed embedding then $pi$ also is one.
If you assume $pi$ is affine this is fairly simple. I am having a lot of trouble proving it without that hypothesis. Any help would be appreciated.
algebraic-geometry extension-field schemes
$endgroup$
$begingroup$
Have you done the exercise establishing that "closed immersions are affine-local on the target"? If so, what difficulties do you encounter applying that to this exercise?
$endgroup$
– KReiser
Dec 13 '18 at 22:22
$begingroup$
So I can reduce it to the case where $Y$ can be affine but $X$ is still arbitrary. Now I am able to show $pitimes_k l$ will induce an isomorphism between $text{Spec}(Y/Jotimes_{k}l)$ and $Xtimes_k l$ where $J$ is some ideal of $Y$. I am unable to show X must be $text{Spec}(Y/J)$.
$endgroup$
– Niareh
Dec 13 '18 at 23:06
$begingroup$
In the earlier comment I had misunderstood some of the subtlety involved here, and for that I apologize. One potential answer is that the property of $pi$ being affine is stable under descent, so in fact $pi_l$ affine (as it's a closed immersion) implies $pi$ affine. A source for this is Stacksproject 02L5 or EGA IV2 2.7.1.
$endgroup$
– KReiser
Dec 14 '18 at 3:58
$begingroup$
Thanks this seems to be exactly what I need.
$endgroup$
– Niareh
Dec 16 '18 at 16:56
add a comment |
$begingroup$
This is from exercise 9.2.J of Ravi Vakil's notes on algebraic geometry here
We have a morphism of $k$ schemes $pi:X rightarrow Y$. $l/k$ is a field extension. We want to show if $pitimes_k l: Xtimes_k lrightarrow Ytimes_k l$ is a closed embedding then $pi$ also is one.
If you assume $pi$ is affine this is fairly simple. I am having a lot of trouble proving it without that hypothesis. Any help would be appreciated.
algebraic-geometry extension-field schemes
$endgroup$
This is from exercise 9.2.J of Ravi Vakil's notes on algebraic geometry here
We have a morphism of $k$ schemes $pi:X rightarrow Y$. $l/k$ is a field extension. We want to show if $pitimes_k l: Xtimes_k lrightarrow Ytimes_k l$ is a closed embedding then $pi$ also is one.
If you assume $pi$ is affine this is fairly simple. I am having a lot of trouble proving it without that hypothesis. Any help would be appreciated.
algebraic-geometry extension-field schemes
algebraic-geometry extension-field schemes
asked Dec 13 '18 at 22:18
NiarehNiareh
112
112
$begingroup$
Have you done the exercise establishing that "closed immersions are affine-local on the target"? If so, what difficulties do you encounter applying that to this exercise?
$endgroup$
– KReiser
Dec 13 '18 at 22:22
$begingroup$
So I can reduce it to the case where $Y$ can be affine but $X$ is still arbitrary. Now I am able to show $pitimes_k l$ will induce an isomorphism between $text{Spec}(Y/Jotimes_{k}l)$ and $Xtimes_k l$ where $J$ is some ideal of $Y$. I am unable to show X must be $text{Spec}(Y/J)$.
$endgroup$
– Niareh
Dec 13 '18 at 23:06
$begingroup$
In the earlier comment I had misunderstood some of the subtlety involved here, and for that I apologize. One potential answer is that the property of $pi$ being affine is stable under descent, so in fact $pi_l$ affine (as it's a closed immersion) implies $pi$ affine. A source for this is Stacksproject 02L5 or EGA IV2 2.7.1.
$endgroup$
– KReiser
Dec 14 '18 at 3:58
$begingroup$
Thanks this seems to be exactly what I need.
$endgroup$
– Niareh
Dec 16 '18 at 16:56
add a comment |
$begingroup$
Have you done the exercise establishing that "closed immersions are affine-local on the target"? If so, what difficulties do you encounter applying that to this exercise?
$endgroup$
– KReiser
Dec 13 '18 at 22:22
$begingroup$
So I can reduce it to the case where $Y$ can be affine but $X$ is still arbitrary. Now I am able to show $pitimes_k l$ will induce an isomorphism between $text{Spec}(Y/Jotimes_{k}l)$ and $Xtimes_k l$ where $J$ is some ideal of $Y$. I am unable to show X must be $text{Spec}(Y/J)$.
$endgroup$
– Niareh
Dec 13 '18 at 23:06
$begingroup$
In the earlier comment I had misunderstood some of the subtlety involved here, and for that I apologize. One potential answer is that the property of $pi$ being affine is stable under descent, so in fact $pi_l$ affine (as it's a closed immersion) implies $pi$ affine. A source for this is Stacksproject 02L5 or EGA IV2 2.7.1.
$endgroup$
– KReiser
Dec 14 '18 at 3:58
$begingroup$
Thanks this seems to be exactly what I need.
$endgroup$
– Niareh
Dec 16 '18 at 16:56
$begingroup$
Have you done the exercise establishing that "closed immersions are affine-local on the target"? If so, what difficulties do you encounter applying that to this exercise?
$endgroup$
– KReiser
Dec 13 '18 at 22:22
$begingroup$
Have you done the exercise establishing that "closed immersions are affine-local on the target"? If so, what difficulties do you encounter applying that to this exercise?
$endgroup$
– KReiser
Dec 13 '18 at 22:22
$begingroup$
So I can reduce it to the case where $Y$ can be affine but $X$ is still arbitrary. Now I am able to show $pitimes_k l$ will induce an isomorphism between $text{Spec}(Y/Jotimes_{k}l)$ and $Xtimes_k l$ where $J$ is some ideal of $Y$. I am unable to show X must be $text{Spec}(Y/J)$.
$endgroup$
– Niareh
Dec 13 '18 at 23:06
$begingroup$
So I can reduce it to the case where $Y$ can be affine but $X$ is still arbitrary. Now I am able to show $pitimes_k l$ will induce an isomorphism between $text{Spec}(Y/Jotimes_{k}l)$ and $Xtimes_k l$ where $J$ is some ideal of $Y$. I am unable to show X must be $text{Spec}(Y/J)$.
$endgroup$
– Niareh
Dec 13 '18 at 23:06
$begingroup$
In the earlier comment I had misunderstood some of the subtlety involved here, and for that I apologize. One potential answer is that the property of $pi$ being affine is stable under descent, so in fact $pi_l$ affine (as it's a closed immersion) implies $pi$ affine. A source for this is Stacksproject 02L5 or EGA IV2 2.7.1.
$endgroup$
– KReiser
Dec 14 '18 at 3:58
$begingroup$
In the earlier comment I had misunderstood some of the subtlety involved here, and for that I apologize. One potential answer is that the property of $pi$ being affine is stable under descent, so in fact $pi_l$ affine (as it's a closed immersion) implies $pi$ affine. A source for this is Stacksproject 02L5 or EGA IV2 2.7.1.
$endgroup$
– KReiser
Dec 14 '18 at 3:58
$begingroup$
Thanks this seems to be exactly what I need.
$endgroup$
– Niareh
Dec 16 '18 at 16:56
$begingroup$
Thanks this seems to be exactly what I need.
$endgroup$
– Niareh
Dec 16 '18 at 16:56
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3038643%2fclosed-morphism-of-products-of-k-schemes-with-a-field-extension-of-k-implies-clo%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3038643%2fclosed-morphism-of-products-of-k-schemes-with-a-field-extension-of-k-implies-clo%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
Have you done the exercise establishing that "closed immersions are affine-local on the target"? If so, what difficulties do you encounter applying that to this exercise?
$endgroup$
– KReiser
Dec 13 '18 at 22:22
$begingroup$
So I can reduce it to the case where $Y$ can be affine but $X$ is still arbitrary. Now I am able to show $pitimes_k l$ will induce an isomorphism between $text{Spec}(Y/Jotimes_{k}l)$ and $Xtimes_k l$ where $J$ is some ideal of $Y$. I am unable to show X must be $text{Spec}(Y/J)$.
$endgroup$
– Niareh
Dec 13 '18 at 23:06
$begingroup$
In the earlier comment I had misunderstood some of the subtlety involved here, and for that I apologize. One potential answer is that the property of $pi$ being affine is stable under descent, so in fact $pi_l$ affine (as it's a closed immersion) implies $pi$ affine. A source for this is Stacksproject 02L5 or EGA IV2 2.7.1.
$endgroup$
– KReiser
Dec 14 '18 at 3:58
$begingroup$
Thanks this seems to be exactly what I need.
$endgroup$
– Niareh
Dec 16 '18 at 16:56