Making Linear Transformations Using Tikz












2















I am trying to create a visual for a linear transformation done by matrices. Here is an example of what I am shooting for:



enter image description here



I would like to have the original gridlines in place, but like faded out a bit, and the newly transformed gridlines more visible.



Here is my attempt using pgftransformcm:



documentclass{article}
usepackage{amsmath}
usepackage{xcolor}
usepackage{pgfplots}

begin{document}

begin{tikzpicture}[scale=1,line width=1pt]

begin{axis}[
color= black,
thick,
xmin=-3.9,
xmax=3.9,
ymin=-3.9,
ymax=3.9,
axis equal image,
axis lines=middle,
font=scriptsize,
xtick distance=1,
ytick distance=1,
inner axis line style={stealth-stealth},
xlabel = {},
ylabel = {},
grid=major,
ticks=none
]

end{axis}

begin{axis}[
color= blue,
thick,
xmin=-3.9,
xmax=3.9,
ymin=-3.9,
ymax=3.9,
axis equal image,
axis lines=middle,
font=scriptsize,
xtick distance=1,
ytick distance=1,
inner axis line style={stealth-stealth},
xlabel = {},
ylabel = {},
grid=major,
grid style={blue!50},
ticks=none
]

pgftransformcm{1}{1}{0}{1}{pgfpoint{0}{0}};

end{axis}

end{tikzpicture}

end{document}


And here is my result:



enter image description here



I am very unfamiliar with pgftransformcm, and so I am sure there is an easy fix to this that I am not seeing. It seems that for some reason the shifted gridlines are no longer centered at the origin when I use this command, which I do not want.



I also have used the axis environment only because I am used to using it for making graphs with pgfplots, and for me, having a coordinate system is much more desirable than using arbitrary points that you do without the environment (so for example, I would be able to draw a vector to the point (2,2) and know exactly where it would land). But that is just my personal preference, and if no solution is possible without removing the environment, then so be it.



I apologize if this seems like a long-winded question, but I have no idea how to approach this question. Any help would be appreciated!










share|improve this question



























    2















    I am trying to create a visual for a linear transformation done by matrices. Here is an example of what I am shooting for:



    enter image description here



    I would like to have the original gridlines in place, but like faded out a bit, and the newly transformed gridlines more visible.



    Here is my attempt using pgftransformcm:



    documentclass{article}
    usepackage{amsmath}
    usepackage{xcolor}
    usepackage{pgfplots}

    begin{document}

    begin{tikzpicture}[scale=1,line width=1pt]

    begin{axis}[
    color= black,
    thick,
    xmin=-3.9,
    xmax=3.9,
    ymin=-3.9,
    ymax=3.9,
    axis equal image,
    axis lines=middle,
    font=scriptsize,
    xtick distance=1,
    ytick distance=1,
    inner axis line style={stealth-stealth},
    xlabel = {},
    ylabel = {},
    grid=major,
    ticks=none
    ]

    end{axis}

    begin{axis}[
    color= blue,
    thick,
    xmin=-3.9,
    xmax=3.9,
    ymin=-3.9,
    ymax=3.9,
    axis equal image,
    axis lines=middle,
    font=scriptsize,
    xtick distance=1,
    ytick distance=1,
    inner axis line style={stealth-stealth},
    xlabel = {},
    ylabel = {},
    grid=major,
    grid style={blue!50},
    ticks=none
    ]

    pgftransformcm{1}{1}{0}{1}{pgfpoint{0}{0}};

    end{axis}

    end{tikzpicture}

    end{document}


    And here is my result:



    enter image description here



    I am very unfamiliar with pgftransformcm, and so I am sure there is an easy fix to this that I am not seeing. It seems that for some reason the shifted gridlines are no longer centered at the origin when I use this command, which I do not want.



    I also have used the axis environment only because I am used to using it for making graphs with pgfplots, and for me, having a coordinate system is much more desirable than using arbitrary points that you do without the environment (so for example, I would be able to draw a vector to the point (2,2) and know exactly where it would land). But that is just my personal preference, and if no solution is possible without removing the environment, then so be it.



    I apologize if this seems like a long-winded question, but I have no idea how to approach this question. Any help would be appreciated!










    share|improve this question

























      2












      2








      2








      I am trying to create a visual for a linear transformation done by matrices. Here is an example of what I am shooting for:



      enter image description here



      I would like to have the original gridlines in place, but like faded out a bit, and the newly transformed gridlines more visible.



      Here is my attempt using pgftransformcm:



      documentclass{article}
      usepackage{amsmath}
      usepackage{xcolor}
      usepackage{pgfplots}

      begin{document}

      begin{tikzpicture}[scale=1,line width=1pt]

      begin{axis}[
      color= black,
      thick,
      xmin=-3.9,
      xmax=3.9,
      ymin=-3.9,
      ymax=3.9,
      axis equal image,
      axis lines=middle,
      font=scriptsize,
      xtick distance=1,
      ytick distance=1,
      inner axis line style={stealth-stealth},
      xlabel = {},
      ylabel = {},
      grid=major,
      ticks=none
      ]

      end{axis}

      begin{axis}[
      color= blue,
      thick,
      xmin=-3.9,
      xmax=3.9,
      ymin=-3.9,
      ymax=3.9,
      axis equal image,
      axis lines=middle,
      font=scriptsize,
      xtick distance=1,
      ytick distance=1,
      inner axis line style={stealth-stealth},
      xlabel = {},
      ylabel = {},
      grid=major,
      grid style={blue!50},
      ticks=none
      ]

      pgftransformcm{1}{1}{0}{1}{pgfpoint{0}{0}};

      end{axis}

      end{tikzpicture}

      end{document}


      And here is my result:



      enter image description here



      I am very unfamiliar with pgftransformcm, and so I am sure there is an easy fix to this that I am not seeing. It seems that for some reason the shifted gridlines are no longer centered at the origin when I use this command, which I do not want.



      I also have used the axis environment only because I am used to using it for making graphs with pgfplots, and for me, having a coordinate system is much more desirable than using arbitrary points that you do without the environment (so for example, I would be able to draw a vector to the point (2,2) and know exactly where it would land). But that is just my personal preference, and if no solution is possible without removing the environment, then so be it.



      I apologize if this seems like a long-winded question, but I have no idea how to approach this question. Any help would be appreciated!










      share|improve this question














      I am trying to create a visual for a linear transformation done by matrices. Here is an example of what I am shooting for:



      enter image description here



      I would like to have the original gridlines in place, but like faded out a bit, and the newly transformed gridlines more visible.



      Here is my attempt using pgftransformcm:



      documentclass{article}
      usepackage{amsmath}
      usepackage{xcolor}
      usepackage{pgfplots}

      begin{document}

      begin{tikzpicture}[scale=1,line width=1pt]

      begin{axis}[
      color= black,
      thick,
      xmin=-3.9,
      xmax=3.9,
      ymin=-3.9,
      ymax=3.9,
      axis equal image,
      axis lines=middle,
      font=scriptsize,
      xtick distance=1,
      ytick distance=1,
      inner axis line style={stealth-stealth},
      xlabel = {},
      ylabel = {},
      grid=major,
      ticks=none
      ]

      end{axis}

      begin{axis}[
      color= blue,
      thick,
      xmin=-3.9,
      xmax=3.9,
      ymin=-3.9,
      ymax=3.9,
      axis equal image,
      axis lines=middle,
      font=scriptsize,
      xtick distance=1,
      ytick distance=1,
      inner axis line style={stealth-stealth},
      xlabel = {},
      ylabel = {},
      grid=major,
      grid style={blue!50},
      ticks=none
      ]

      pgftransformcm{1}{1}{0}{1}{pgfpoint{0}{0}};

      end{axis}

      end{tikzpicture}

      end{document}


      And here is my result:



      enter image description here



      I am very unfamiliar with pgftransformcm, and so I am sure there is an easy fix to this that I am not seeing. It seems that for some reason the shifted gridlines are no longer centered at the origin when I use this command, which I do not want.



      I also have used the axis environment only because I am used to using it for making graphs with pgfplots, and for me, having a coordinate system is much more desirable than using arbitrary points that you do without the environment (so for example, I would be able to draw a vector to the point (2,2) and know exactly where it would land). But that is just my personal preference, and if no solution is possible without removing the environment, then so be it.



      I apologize if this seems like a long-winded question, but I have no idea how to approach this question. Any help would be appreciated!







      tikz-pgf transformation






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Mar 28 at 23:06









      Aiden KennyAiden Kenny

      4677




      4677






















          1 Answer
          1






          active

          oldest

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          4














          I take back what I wrote in my comment. pgftransformcm is actually the easier option here. This code provides two ways to achieve the result.



          documentclass[border=3.14mm,tikz]{standalone}
          begin{document}
          begin{tikzpicture}
          fill[clip] (-8,-5) rectangle (8,5);
          draw[white] (-8,-5) grid (8,5);
          begin{scope}[x={(3,-2)},y={(2/3,7/3)}]
          foreach X in {-2,...,2}
          {draw[red!30] (X,-5) -- ++ (0,10);}
          foreach Y in {-4,...,4}
          {draw[blue!30] (-3,Y) -- ++ (6,0);}
          draw[yellow,thick,-latex] (0,0) -- (1,0) node[above right]{$x'$};
          draw[orange,thick,-latex] (0,0) -- (0,1) node[above left]{$y'$};
          end{scope}
          end{tikzpicture}

          begin{tikzpicture}
          fill[clip] (-8,-5) rectangle (8,5);
          draw[white] (-8,-5) grid (8,5);
          begin{scope}
          pgftransformcm{3}{-2}{2}{1}{pgfpoint{0cm}{0cm}}
          foreach X in {-2,...,2}
          {draw[red!30] (X,-5) -- ++ (0,10);}
          foreach Y in {-4,...,4}
          {draw[blue!30] (-3,Y) -- ++ (6,0);}
          draw[yellow,thick,-latex] (0,0) -- (1,0) node[above right]{$x'$};
          draw[orange,thick,-latex] (0,0) -- (0,1) node[above left]{$y'$};
          end{scope}
          end{tikzpicture}
          end{document}


          enter image description here






          share|improve this answer
























          • Amazing answer! So is there no way to keep using the axis environment? Just curious

            – Aiden Kenny
            Mar 29 at 0:29






          • 1





            @AidenKenny Most likely there is but pgfplots does its own tricks (which, among other things, allows us to deal with very large coordinates and so on). However, judging from section 4.21 Symbolic Coordinates and User Transformations of the pgfplots manual I would assume it is nontrivial. I once tried some related things in here but gave up.

            – marmot
            Mar 29 at 0:34






          • 1





            @AidenKenny You can install the transformations by moving the pgftransformcm before the second axis, e.g. pgftransformcm{3}{-2}{2}{1}{pgfpoint{0cm}{0cm}} begin{axis}[shift={(-3.33cm,-0.67cm)},.... in your code but I personally do not find the shift very intuitive nor pleasing.

            – marmot
            Mar 29 at 0:47






          • 1





            @AidenKenny clip (-8,-5) rectangle (8,5); draw (-8,-5) grid (8,5); instead of fill[clip] (-8,-5) rectangle (8,5); draw[white] (-8,-5) grid (8,5); should do.

            – marmot
            Mar 29 at 0:53








          • 1





            @AidenKenny The problem is that when you specify y, x is already installed. Call the new coordinates x' and y'. In the first step, we tell TikZ that it should use x'=(3,-2) instead of x. So far, so good. But when we tell TikZ what the new y should be, we need to give it coordinates in the basis x' and y. You can check that (2/3)*(3,-2)+(7/3)*(0,1)=(2,-4/3+7/3)=(2,1).

            – marmot
            Mar 29 at 17:17












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          1 Answer
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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          4














          I take back what I wrote in my comment. pgftransformcm is actually the easier option here. This code provides two ways to achieve the result.



          documentclass[border=3.14mm,tikz]{standalone}
          begin{document}
          begin{tikzpicture}
          fill[clip] (-8,-5) rectangle (8,5);
          draw[white] (-8,-5) grid (8,5);
          begin{scope}[x={(3,-2)},y={(2/3,7/3)}]
          foreach X in {-2,...,2}
          {draw[red!30] (X,-5) -- ++ (0,10);}
          foreach Y in {-4,...,4}
          {draw[blue!30] (-3,Y) -- ++ (6,0);}
          draw[yellow,thick,-latex] (0,0) -- (1,0) node[above right]{$x'$};
          draw[orange,thick,-latex] (0,0) -- (0,1) node[above left]{$y'$};
          end{scope}
          end{tikzpicture}

          begin{tikzpicture}
          fill[clip] (-8,-5) rectangle (8,5);
          draw[white] (-8,-5) grid (8,5);
          begin{scope}
          pgftransformcm{3}{-2}{2}{1}{pgfpoint{0cm}{0cm}}
          foreach X in {-2,...,2}
          {draw[red!30] (X,-5) -- ++ (0,10);}
          foreach Y in {-4,...,4}
          {draw[blue!30] (-3,Y) -- ++ (6,0);}
          draw[yellow,thick,-latex] (0,0) -- (1,0) node[above right]{$x'$};
          draw[orange,thick,-latex] (0,0) -- (0,1) node[above left]{$y'$};
          end{scope}
          end{tikzpicture}
          end{document}


          enter image description here






          share|improve this answer
























          • Amazing answer! So is there no way to keep using the axis environment? Just curious

            – Aiden Kenny
            Mar 29 at 0:29






          • 1





            @AidenKenny Most likely there is but pgfplots does its own tricks (which, among other things, allows us to deal with very large coordinates and so on). However, judging from section 4.21 Symbolic Coordinates and User Transformations of the pgfplots manual I would assume it is nontrivial. I once tried some related things in here but gave up.

            – marmot
            Mar 29 at 0:34






          • 1





            @AidenKenny You can install the transformations by moving the pgftransformcm before the second axis, e.g. pgftransformcm{3}{-2}{2}{1}{pgfpoint{0cm}{0cm}} begin{axis}[shift={(-3.33cm,-0.67cm)},.... in your code but I personally do not find the shift very intuitive nor pleasing.

            – marmot
            Mar 29 at 0:47






          • 1





            @AidenKenny clip (-8,-5) rectangle (8,5); draw (-8,-5) grid (8,5); instead of fill[clip] (-8,-5) rectangle (8,5); draw[white] (-8,-5) grid (8,5); should do.

            – marmot
            Mar 29 at 0:53








          • 1





            @AidenKenny The problem is that when you specify y, x is already installed. Call the new coordinates x' and y'. In the first step, we tell TikZ that it should use x'=(3,-2) instead of x. So far, so good. But when we tell TikZ what the new y should be, we need to give it coordinates in the basis x' and y. You can check that (2/3)*(3,-2)+(7/3)*(0,1)=(2,-4/3+7/3)=(2,1).

            – marmot
            Mar 29 at 17:17
















          4














          I take back what I wrote in my comment. pgftransformcm is actually the easier option here. This code provides two ways to achieve the result.



          documentclass[border=3.14mm,tikz]{standalone}
          begin{document}
          begin{tikzpicture}
          fill[clip] (-8,-5) rectangle (8,5);
          draw[white] (-8,-5) grid (8,5);
          begin{scope}[x={(3,-2)},y={(2/3,7/3)}]
          foreach X in {-2,...,2}
          {draw[red!30] (X,-5) -- ++ (0,10);}
          foreach Y in {-4,...,4}
          {draw[blue!30] (-3,Y) -- ++ (6,0);}
          draw[yellow,thick,-latex] (0,0) -- (1,0) node[above right]{$x'$};
          draw[orange,thick,-latex] (0,0) -- (0,1) node[above left]{$y'$};
          end{scope}
          end{tikzpicture}

          begin{tikzpicture}
          fill[clip] (-8,-5) rectangle (8,5);
          draw[white] (-8,-5) grid (8,5);
          begin{scope}
          pgftransformcm{3}{-2}{2}{1}{pgfpoint{0cm}{0cm}}
          foreach X in {-2,...,2}
          {draw[red!30] (X,-5) -- ++ (0,10);}
          foreach Y in {-4,...,4}
          {draw[blue!30] (-3,Y) -- ++ (6,0);}
          draw[yellow,thick,-latex] (0,0) -- (1,0) node[above right]{$x'$};
          draw[orange,thick,-latex] (0,0) -- (0,1) node[above left]{$y'$};
          end{scope}
          end{tikzpicture}
          end{document}


          enter image description here






          share|improve this answer
























          • Amazing answer! So is there no way to keep using the axis environment? Just curious

            – Aiden Kenny
            Mar 29 at 0:29






          • 1





            @AidenKenny Most likely there is but pgfplots does its own tricks (which, among other things, allows us to deal with very large coordinates and so on). However, judging from section 4.21 Symbolic Coordinates and User Transformations of the pgfplots manual I would assume it is nontrivial. I once tried some related things in here but gave up.

            – marmot
            Mar 29 at 0:34






          • 1





            @AidenKenny You can install the transformations by moving the pgftransformcm before the second axis, e.g. pgftransformcm{3}{-2}{2}{1}{pgfpoint{0cm}{0cm}} begin{axis}[shift={(-3.33cm,-0.67cm)},.... in your code but I personally do not find the shift very intuitive nor pleasing.

            – marmot
            Mar 29 at 0:47






          • 1





            @AidenKenny clip (-8,-5) rectangle (8,5); draw (-8,-5) grid (8,5); instead of fill[clip] (-8,-5) rectangle (8,5); draw[white] (-8,-5) grid (8,5); should do.

            – marmot
            Mar 29 at 0:53








          • 1





            @AidenKenny The problem is that when you specify y, x is already installed. Call the new coordinates x' and y'. In the first step, we tell TikZ that it should use x'=(3,-2) instead of x. So far, so good. But when we tell TikZ what the new y should be, we need to give it coordinates in the basis x' and y. You can check that (2/3)*(3,-2)+(7/3)*(0,1)=(2,-4/3+7/3)=(2,1).

            – marmot
            Mar 29 at 17:17














          4












          4








          4







          I take back what I wrote in my comment. pgftransformcm is actually the easier option here. This code provides two ways to achieve the result.



          documentclass[border=3.14mm,tikz]{standalone}
          begin{document}
          begin{tikzpicture}
          fill[clip] (-8,-5) rectangle (8,5);
          draw[white] (-8,-5) grid (8,5);
          begin{scope}[x={(3,-2)},y={(2/3,7/3)}]
          foreach X in {-2,...,2}
          {draw[red!30] (X,-5) -- ++ (0,10);}
          foreach Y in {-4,...,4}
          {draw[blue!30] (-3,Y) -- ++ (6,0);}
          draw[yellow,thick,-latex] (0,0) -- (1,0) node[above right]{$x'$};
          draw[orange,thick,-latex] (0,0) -- (0,1) node[above left]{$y'$};
          end{scope}
          end{tikzpicture}

          begin{tikzpicture}
          fill[clip] (-8,-5) rectangle (8,5);
          draw[white] (-8,-5) grid (8,5);
          begin{scope}
          pgftransformcm{3}{-2}{2}{1}{pgfpoint{0cm}{0cm}}
          foreach X in {-2,...,2}
          {draw[red!30] (X,-5) -- ++ (0,10);}
          foreach Y in {-4,...,4}
          {draw[blue!30] (-3,Y) -- ++ (6,0);}
          draw[yellow,thick,-latex] (0,0) -- (1,0) node[above right]{$x'$};
          draw[orange,thick,-latex] (0,0) -- (0,1) node[above left]{$y'$};
          end{scope}
          end{tikzpicture}
          end{document}


          enter image description here






          share|improve this answer













          I take back what I wrote in my comment. pgftransformcm is actually the easier option here. This code provides two ways to achieve the result.



          documentclass[border=3.14mm,tikz]{standalone}
          begin{document}
          begin{tikzpicture}
          fill[clip] (-8,-5) rectangle (8,5);
          draw[white] (-8,-5) grid (8,5);
          begin{scope}[x={(3,-2)},y={(2/3,7/3)}]
          foreach X in {-2,...,2}
          {draw[red!30] (X,-5) -- ++ (0,10);}
          foreach Y in {-4,...,4}
          {draw[blue!30] (-3,Y) -- ++ (6,0);}
          draw[yellow,thick,-latex] (0,0) -- (1,0) node[above right]{$x'$};
          draw[orange,thick,-latex] (0,0) -- (0,1) node[above left]{$y'$};
          end{scope}
          end{tikzpicture}

          begin{tikzpicture}
          fill[clip] (-8,-5) rectangle (8,5);
          draw[white] (-8,-5) grid (8,5);
          begin{scope}
          pgftransformcm{3}{-2}{2}{1}{pgfpoint{0cm}{0cm}}
          foreach X in {-2,...,2}
          {draw[red!30] (X,-5) -- ++ (0,10);}
          foreach Y in {-4,...,4}
          {draw[blue!30] (-3,Y) -- ++ (6,0);}
          draw[yellow,thick,-latex] (0,0) -- (1,0) node[above right]{$x'$};
          draw[orange,thick,-latex] (0,0) -- (0,1) node[above left]{$y'$};
          end{scope}
          end{tikzpicture}
          end{document}


          enter image description here







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Mar 28 at 23:43









          marmotmarmot

          116k5146277




          116k5146277













          • Amazing answer! So is there no way to keep using the axis environment? Just curious

            – Aiden Kenny
            Mar 29 at 0:29






          • 1





            @AidenKenny Most likely there is but pgfplots does its own tricks (which, among other things, allows us to deal with very large coordinates and so on). However, judging from section 4.21 Symbolic Coordinates and User Transformations of the pgfplots manual I would assume it is nontrivial. I once tried some related things in here but gave up.

            – marmot
            Mar 29 at 0:34






          • 1





            @AidenKenny You can install the transformations by moving the pgftransformcm before the second axis, e.g. pgftransformcm{3}{-2}{2}{1}{pgfpoint{0cm}{0cm}} begin{axis}[shift={(-3.33cm,-0.67cm)},.... in your code but I personally do not find the shift very intuitive nor pleasing.

            – marmot
            Mar 29 at 0:47






          • 1





            @AidenKenny clip (-8,-5) rectangle (8,5); draw (-8,-5) grid (8,5); instead of fill[clip] (-8,-5) rectangle (8,5); draw[white] (-8,-5) grid (8,5); should do.

            – marmot
            Mar 29 at 0:53








          • 1





            @AidenKenny The problem is that when you specify y, x is already installed. Call the new coordinates x' and y'. In the first step, we tell TikZ that it should use x'=(3,-2) instead of x. So far, so good. But when we tell TikZ what the new y should be, we need to give it coordinates in the basis x' and y. You can check that (2/3)*(3,-2)+(7/3)*(0,1)=(2,-4/3+7/3)=(2,1).

            – marmot
            Mar 29 at 17:17



















          • Amazing answer! So is there no way to keep using the axis environment? Just curious

            – Aiden Kenny
            Mar 29 at 0:29






          • 1





            @AidenKenny Most likely there is but pgfplots does its own tricks (which, among other things, allows us to deal with very large coordinates and so on). However, judging from section 4.21 Symbolic Coordinates and User Transformations of the pgfplots manual I would assume it is nontrivial. I once tried some related things in here but gave up.

            – marmot
            Mar 29 at 0:34






          • 1





            @AidenKenny You can install the transformations by moving the pgftransformcm before the second axis, e.g. pgftransformcm{3}{-2}{2}{1}{pgfpoint{0cm}{0cm}} begin{axis}[shift={(-3.33cm,-0.67cm)},.... in your code but I personally do not find the shift very intuitive nor pleasing.

            – marmot
            Mar 29 at 0:47






          • 1





            @AidenKenny clip (-8,-5) rectangle (8,5); draw (-8,-5) grid (8,5); instead of fill[clip] (-8,-5) rectangle (8,5); draw[white] (-8,-5) grid (8,5); should do.

            – marmot
            Mar 29 at 0:53








          • 1





            @AidenKenny The problem is that when you specify y, x is already installed. Call the new coordinates x' and y'. In the first step, we tell TikZ that it should use x'=(3,-2) instead of x. So far, so good. But when we tell TikZ what the new y should be, we need to give it coordinates in the basis x' and y. You can check that (2/3)*(3,-2)+(7/3)*(0,1)=(2,-4/3+7/3)=(2,1).

            – marmot
            Mar 29 at 17:17

















          Amazing answer! So is there no way to keep using the axis environment? Just curious

          – Aiden Kenny
          Mar 29 at 0:29





          Amazing answer! So is there no way to keep using the axis environment? Just curious

          – Aiden Kenny
          Mar 29 at 0:29




          1




          1





          @AidenKenny Most likely there is but pgfplots does its own tricks (which, among other things, allows us to deal with very large coordinates and so on). However, judging from section 4.21 Symbolic Coordinates and User Transformations of the pgfplots manual I would assume it is nontrivial. I once tried some related things in here but gave up.

          – marmot
          Mar 29 at 0:34





          @AidenKenny Most likely there is but pgfplots does its own tricks (which, among other things, allows us to deal with very large coordinates and so on). However, judging from section 4.21 Symbolic Coordinates and User Transformations of the pgfplots manual I would assume it is nontrivial. I once tried some related things in here but gave up.

          – marmot
          Mar 29 at 0:34




          1




          1





          @AidenKenny You can install the transformations by moving the pgftransformcm before the second axis, e.g. pgftransformcm{3}{-2}{2}{1}{pgfpoint{0cm}{0cm}} begin{axis}[shift={(-3.33cm,-0.67cm)},.... in your code but I personally do not find the shift very intuitive nor pleasing.

          – marmot
          Mar 29 at 0:47





          @AidenKenny You can install the transformations by moving the pgftransformcm before the second axis, e.g. pgftransformcm{3}{-2}{2}{1}{pgfpoint{0cm}{0cm}} begin{axis}[shift={(-3.33cm,-0.67cm)},.... in your code but I personally do not find the shift very intuitive nor pleasing.

          – marmot
          Mar 29 at 0:47




          1




          1





          @AidenKenny clip (-8,-5) rectangle (8,5); draw (-8,-5) grid (8,5); instead of fill[clip] (-8,-5) rectangle (8,5); draw[white] (-8,-5) grid (8,5); should do.

          – marmot
          Mar 29 at 0:53







          @AidenKenny clip (-8,-5) rectangle (8,5); draw (-8,-5) grid (8,5); instead of fill[clip] (-8,-5) rectangle (8,5); draw[white] (-8,-5) grid (8,5); should do.

          – marmot
          Mar 29 at 0:53






          1




          1





          @AidenKenny The problem is that when you specify y, x is already installed. Call the new coordinates x' and y'. In the first step, we tell TikZ that it should use x'=(3,-2) instead of x. So far, so good. But when we tell TikZ what the new y should be, we need to give it coordinates in the basis x' and y. You can check that (2/3)*(3,-2)+(7/3)*(0,1)=(2,-4/3+7/3)=(2,1).

          – marmot
          Mar 29 at 17:17





          @AidenKenny The problem is that when you specify y, x is already installed. Call the new coordinates x' and y'. In the first step, we tell TikZ that it should use x'=(3,-2) instead of x. So far, so good. But when we tell TikZ what the new y should be, we need to give it coordinates in the basis x' and y. You can check that (2/3)*(3,-2)+(7/3)*(0,1)=(2,-4/3+7/3)=(2,1).

          – marmot
          Mar 29 at 17:17


















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