Similarity using euclidean distance, cosine similarity given co-occurrence matrix

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In class, our professor gave us a co-occurrence matrix
enter image description here



I thought that the euclidean distance for dog, cat would be:
$sqrt{(115/156 - 52/82.5)^2 + (89/156 - 58/82.5)^2 + (10/256 - 4/82.5)^2 + (42/156 - 4/82.5)^2+ (33/156 - 6/82.5)^2 + (17/156- 26/82.5)^2}$



Then you do $frac{1}{1 + d(dog, cat)} = frac{1}{1 + 0.37} = 0.7280128371$ However, this is not the same as his answer.



Is there a different way of doing euclidean distance?










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$endgroup$

















    0












    $begingroup$


    In class, our professor gave us a co-occurrence matrix
    enter image description here



    I thought that the euclidean distance for dog, cat would be:
    $sqrt{(115/156 - 52/82.5)^2 + (89/156 - 58/82.5)^2 + (10/256 - 4/82.5)^2 + (42/156 - 4/82.5)^2+ (33/156 - 6/82.5)^2 + (17/156- 26/82.5)^2}$



    Then you do $frac{1}{1 + d(dog, cat)} = frac{1}{1 + 0.37} = 0.7280128371$ However, this is not the same as his answer.



    Is there a different way of doing euclidean distance?










    share|cite|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$


      In class, our professor gave us a co-occurrence matrix
      enter image description here



      I thought that the euclidean distance for dog, cat would be:
      $sqrt{(115/156 - 52/82.5)^2 + (89/156 - 58/82.5)^2 + (10/256 - 4/82.5)^2 + (42/156 - 4/82.5)^2+ (33/156 - 6/82.5)^2 + (17/156- 26/82.5)^2}$



      Then you do $frac{1}{1 + d(dog, cat)} = frac{1}{1 + 0.37} = 0.7280128371$ However, this is not the same as his answer.



      Is there a different way of doing euclidean distance?










      share|cite|improve this question









      $endgroup$




      In class, our professor gave us a co-occurrence matrix
      enter image description here



      I thought that the euclidean distance for dog, cat would be:
      $sqrt{(115/156 - 52/82.5)^2 + (89/156 - 58/82.5)^2 + (10/256 - 4/82.5)^2 + (42/156 - 4/82.5)^2+ (33/156 - 6/82.5)^2 + (17/156- 26/82.5)^2}$



      Then you do $frac{1}{1 + d(dog, cat)} = frac{1}{1 + 0.37} = 0.7280128371$ However, this is not the same as his answer.



      Is there a different way of doing euclidean distance?







      matrices vector-spaces vectors euclidean-geometry






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Dec 5 '18 at 3:52









      MattMatt

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