Proving Pivots Statistics
$begingroup$
Suppose that $X_1, ldots, X_n$ are iid from
$$f_X(xmidθ) = atheta^{−a}x^{a−1}I(0 < x < theta)$$
, where $theta > 0$ is an unknown parameter and $a ge 1$ is a known constant.
Show that $T = X_{(n)}/theta$ is a pivotal quantity.
I know that $Q = Q(X, theta)$ is a pivot if the distribution of $Q$ does not depend on $θ$.
I honestly have no idea where to start with proving this. I have read the entire section in a textbook on pivots and even articles online. Any help is welcome.
statistics probability-distributions
$endgroup$
add a comment |
$begingroup$
Suppose that $X_1, ldots, X_n$ are iid from
$$f_X(xmidθ) = atheta^{−a}x^{a−1}I(0 < x < theta)$$
, where $theta > 0$ is an unknown parameter and $a ge 1$ is a known constant.
Show that $T = X_{(n)}/theta$ is a pivotal quantity.
I know that $Q = Q(X, theta)$ is a pivot if the distribution of $Q$ does not depend on $θ$.
I honestly have no idea where to start with proving this. I have read the entire section in a textbook on pivots and even articles online. Any help is welcome.
statistics probability-distributions
$endgroup$
1
$begingroup$
Try to find distribution of $T$.
$endgroup$
– NCh
Dec 5 '18 at 7:12
add a comment |
$begingroup$
Suppose that $X_1, ldots, X_n$ are iid from
$$f_X(xmidθ) = atheta^{−a}x^{a−1}I(0 < x < theta)$$
, where $theta > 0$ is an unknown parameter and $a ge 1$ is a known constant.
Show that $T = X_{(n)}/theta$ is a pivotal quantity.
I know that $Q = Q(X, theta)$ is a pivot if the distribution of $Q$ does not depend on $θ$.
I honestly have no idea where to start with proving this. I have read the entire section in a textbook on pivots and even articles online. Any help is welcome.
statistics probability-distributions
$endgroup$
Suppose that $X_1, ldots, X_n$ are iid from
$$f_X(xmidθ) = atheta^{−a}x^{a−1}I(0 < x < theta)$$
, where $theta > 0$ is an unknown parameter and $a ge 1$ is a known constant.
Show that $T = X_{(n)}/theta$ is a pivotal quantity.
I know that $Q = Q(X, theta)$ is a pivot if the distribution of $Q$ does not depend on $θ$.
I honestly have no idea where to start with proving this. I have read the entire section in a textbook on pivots and even articles online. Any help is welcome.
statistics probability-distributions
statistics probability-distributions
edited Dec 5 '18 at 19:04
StubbornAtom
6,06811239
6,06811239
asked Dec 5 '18 at 4:42
FireFire
6
6
1
$begingroup$
Try to find distribution of $T$.
$endgroup$
– NCh
Dec 5 '18 at 7:12
add a comment |
1
$begingroup$
Try to find distribution of $T$.
$endgroup$
– NCh
Dec 5 '18 at 7:12
1
1
$begingroup$
Try to find distribution of $T$.
$endgroup$
– NCh
Dec 5 '18 at 7:12
$begingroup$
Try to find distribution of $T$.
$endgroup$
– NCh
Dec 5 '18 at 7:12
add a comment |
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$begingroup$
Try to find distribution of $T$.
$endgroup$
– NCh
Dec 5 '18 at 7:12