Python pptx Click action examples
i'm trying to recreate a simple PP_Action.
The code below built without errors however the click action will not run in the slides.
'shape.click_action.action' returns with NONE(0) after action is being assigned.
Is there anything wrong with the code? Couldn't find a base example on this.
Please help.
from pptx import Presentation
from pptx.enum.shapes import MSO_SHAPE
from pptx.util import Cm
from pptx.enum.action import PP_ACTION
prs = Presentation('C:/Template.pptx')
slide = prs.slides.add_slide(prs.slide_layouts[0])
shape = slide.shapes.add_shape(MSO_SHAPE.RECTANGLE, Cm(-0.05),Cm(0.86),Cm(34),Cm(19))
shape.click_action.action == PP_ACTION.LAST_SLIDE
print(shape.click_action.action)
slide = prs.slides.add_slide(prs.slide_layouts[0])
slide = prs.slides.add_slide(prs.slide_layouts[0])
prs.save('C:/example.pptx')
python-pptx
asked Nov 22 '18 at 1:39
Joel HiouJoel Hiou
11
add a comment |
i'm trying to recreate a simple PP_Action.
The code below built without errors however the click action will not run in the slides.
'shape.click_action.action' returns with NONE(0) after action is being assigned.
Is there anything wrong with the code? Couldn't find a base example on this.
Please help.
from pptx import Presentation
from pptx.enum.shapes import MSO_SHAPE
from pptx.util import Cm
from pptx.enum.action import PP_ACTION
prs = Presentation('C:/Template.pptx')
slide = prs.slides.add_slide(prs.slide_layouts[0])
shape = slide.shapes.add_shape(MSO_SHAPE.RECTANGLE, Cm(-0.05),Cm(0.86),Cm(34),Cm(19))
shape.click_action.action == PP_ACTION.LAST_SLIDE
print(shape.click_action.action)
slide = prs.slides.add_slide(prs.slide_layouts[0])
slide = prs.slides.add_slide(prs.slide_layouts[0])
prs.save('C:/example.pptx')
python-pptx
asked Nov 22 '18 at 1:39
Joel HiouJoel Hiou
11
add a comment |
i'm trying to recreate a simple PP_Action.
The code below built without errors however the click action will not run in the slides.
'shape.click_action.action' returns with NONE(0) after action is being assigned.
Is there anything wrong with the code? Couldn't find a base example on this.
Please help.
from pptx import Presentation
from pptx.enum.shapes import MSO_SHAPE
from pptx.util import Cm
from pptx.enum.action import PP_ACTION
prs = Presentation('C:/Template.pptx')
slide = prs.slides.add_slide(prs.slide_layouts[0])
shape = slide.shapes.add_shape(MSO_SHAPE.RECTANGLE, Cm(-0.05),Cm(0.86),Cm(34),Cm(19))
shape.click_action.action == PP_ACTION.LAST_SLIDE
print(shape.click_action.action)
slide = prs.slides.add_slide(prs.slide_layouts[0])
slide = prs.slides.add_slide(prs.slide_layouts[0])
prs.save('C:/example.pptx')
python-pptx
asked Nov 22 '18 at 1:39
Joel HiouJoel Hiou
11
i'm trying to recreate a simple PP_Action.
The code below built without errors however the click action will not run in the slides.
'shape.click_action.action' returns with NONE(0) after action is being assigned.
Is there anything wrong with the code? Couldn't find a base example on this.
Please help.
from pptx import Presentation
from pptx.enum.shapes import MSO_SHAPE
from pptx.util import Cm
from pptx.enum.action import PP_ACTION
prs = Presentation('C:/Template.pptx')
slide = prs.slides.add_slide(prs.slide_layouts[0])
shape = slide.shapes.add_shape(MSO_SHAPE.RECTANGLE, Cm(-0.05),Cm(0.86),Cm(34),Cm(19))
shape.click_action.action == PP_ACTION.LAST_SLIDE
print(shape.click_action.action)
slide = prs.slides.add_slide(prs.slide_layouts[0])
slide = prs.slides.add_slide(prs.slide_layouts[0])
prs.save('C:/example.pptx')
python-pptx
python-pptx
asked Nov 22 '18 at 1:39
Joel HiouJoel Hiou
11
asked Nov 22 '18 at 1:39
Joel HiouJoel Hiou
11
asked Nov 22 '18 at 1:39
Joel HiouJoel Hiou
11
asked Nov 22 '18 at 1:39
Joel HiouJoel Hiou
11
asked Nov 22 '18 at 1:39
Joel HiouJoel Hiou
11
11
add a comment |
add a comment |
1 Answer
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click_action.action is read-only, so assigning to it would raise an error. In your case, you used the == comparison operator which does nothing noticeable.
It's not actual LAST_SLIDE behavior, because that is dynamic, like you can add and delete slides and it still works, but this is a step closer to what you're after:
shape.click_action.target_slide = prs.slides[-1]
answered Jan 10 at 22:59
scannyscanny
10.5k12245
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
click_action.action is read-only, so assigning to it would raise an error. In your case, you used the == comparison operator which does nothing noticeable.
It's not actual LAST_SLIDE behavior, because that is dynamic, like you can add and delete slides and it still works, but this is a step closer to what you're after:
shape.click_action.target_slide = prs.slides[-1]
answered Jan 10 at 22:59
scannyscanny
10.5k12245
add a comment |
click_action.action is read-only, so assigning to it would raise an error. In your case, you used the == comparison operator which does nothing noticeable.
It's not actual LAST_SLIDE behavior, because that is dynamic, like you can add and delete slides and it still works, but this is a step closer to what you're after:
shape.click_action.target_slide = prs.slides[-1]
answered Jan 10 at 22:59
scannyscanny
10.5k12245
add a comment |
click_action.action is read-only, so assigning to it would raise an error. In your case, you used the == comparison operator which does nothing noticeable.
It's not actual LAST_SLIDE behavior, because that is dynamic, like you can add and delete slides and it still works, but this is a step closer to what you're after:
shape.click_action.target_slide = prs.slides[-1]
answered Jan 10 at 22:59
scannyscanny
10.5k12245
click_action.action is read-only, so assigning to it would raise an error. In your case, you used the == comparison operator which does nothing noticeable.
It's not actual LAST_SLIDE behavior, because that is dynamic, like you can add and delete slides and it still works, but this is a step closer to what you're after:
shape.click_action.target_slide = prs.slides[-1]
answered Jan 10 at 22:59
scannyscanny
10.5k12245
answered Jan 10 at 22:59
scannyscanny
10.5k12245
answered Jan 10 at 22:59
scannyscanny
10.5k12245
answered Jan 10 at 22:59
scannyscanny
10.5k12245
10.5k12245
add a comment |
add a comment |
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