Magic variable for entire command, including &&
I'm trying to write a little function for bash like so:
alias timesec='/usr/bin/time --format="%C took %e seconds"'
prun() {
echo $ $@
timesec $*
}
But when I use it, I get:
mpen@mpen:/topsecret$ prun echo foo && echo bar
$ echo foo
foo
echo foo took 0.00 seconds
bar
I want that first line to say $ echo foo && echo bar and the timesec should also apply to the entirety of the command (echo foo && echo bar) not just the first half.
How would I do this?
bash
asked Nov 22 '18 at 2:00
mpenmpen
126k177658956
add a comment |
I'm trying to write a little function for bash like so:
alias timesec='/usr/bin/time --format="%C took %e seconds"'
prun() {
echo $ $@
timesec $*
}
But when I use it, I get:
mpen@mpen:/topsecret$ prun echo foo && echo bar
$ echo foo
foo
echo foo took 0.00 seconds
bar
I want that first line to say $ echo foo && echo bar and the timesec should also apply to the entirety of the command (echo foo && echo bar) not just the first half.
How would I do this?
bash
asked Nov 22 '18 at 2:00
mpenmpen
126k177658956
1
No way. That's the reason why thetimereserved word exists in bash.
– hek2mgl
Nov 22 '18 at 3:56
add a comment |
I'm trying to write a little function for bash like so:
alias timesec='/usr/bin/time --format="%C took %e seconds"'
prun() {
echo $ $@
timesec $*
}
But when I use it, I get:
mpen@mpen:/topsecret$ prun echo foo && echo bar
$ echo foo
foo
echo foo took 0.00 seconds
bar
I want that first line to say $ echo foo && echo bar and the timesec should also apply to the entirety of the command (echo foo && echo bar) not just the first half.
How would I do this?
bash
asked Nov 22 '18 at 2:00
mpenmpen
126k177658956
I'm trying to write a little function for bash like so:
alias timesec='/usr/bin/time --format="%C took %e seconds"'
prun() {
echo $ $@
timesec $*
}
But when I use it, I get:
mpen@mpen:/topsecret$ prun echo foo && echo bar
$ echo foo
foo
echo foo took 0.00 seconds
bar
I want that first line to say $ echo foo && echo bar and the timesec should also apply to the entirety of the command (echo foo && echo bar) not just the first half.
How would I do this?
bash
bash
asked Nov 22 '18 at 2:00
mpenmpen
126k177658956
asked Nov 22 '18 at 2:00
mpenmpen
126k177658956
asked Nov 22 '18 at 2:00
mpenmpen
126k177658956
asked Nov 22 '18 at 2:00
mpenmpen
126k177658956
asked Nov 22 '18 at 2:00
mpenmpen
126k177658956
126k177658956
1
No way. That's the reason why thetimereserved word exists in bash.
– hek2mgl
Nov 22 '18 at 3:56
add a comment |
1
No way. That's the reason why thetimereserved word exists in bash.
– hek2mgl
Nov 22 '18 at 3:56
1
1
No way. That's the reason why the
time reserved word exists in bash.– hek2mgl
Nov 22 '18 at 3:56
No way. That's the reason why the
time reserved word exists in bash.– hek2mgl
Nov 22 '18 at 3:56
add a comment |
1 Answer
1
active
oldest
votes
You can use the TIMEFORMAT variable to customize the output of bash's time builtin:
cmd="/bin/echo foo && /bin/echo bar"
# See man bash for the TIMEFORMAT variable
PREV_TIMEFORMAT="${TIMEFORMAT}"
TIMEFORMAT="The command ${cmd} took %lR"
# You could use time eval "${cmd}". I don't recommend that
time /bin/echo foo && /bin/echo bar
Output:
foo
bar
The command /bin/echo foo && /bin/echo bar took 0m0.00s
Note: The above "solution" doesn't work when you use bash's echo builtin.
answered Nov 22 '18 at 4:11
hek2mglhek2mgl
109k13148173
How does this solution work with variables though? That's the part I'm having trouble with.
– mpen
Nov 23 '18 at 19:05
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use the TIMEFORMAT variable to customize the output of bash's time builtin:
cmd="/bin/echo foo && /bin/echo bar"
# See man bash for the TIMEFORMAT variable
PREV_TIMEFORMAT="${TIMEFORMAT}"
TIMEFORMAT="The command ${cmd} took %lR"
# You could use time eval "${cmd}". I don't recommend that
time /bin/echo foo && /bin/echo bar
Output:
foo
bar
The command /bin/echo foo && /bin/echo bar took 0m0.00s
Note: The above "solution" doesn't work when you use bash's echo builtin.
answered Nov 22 '18 at 4:11
hek2mglhek2mgl
109k13148173
How does this solution work with variables though? That's the part I'm having trouble with.
– mpen
Nov 23 '18 at 19:05
add a comment |
You can use the TIMEFORMAT variable to customize the output of bash's time builtin:
cmd="/bin/echo foo && /bin/echo bar"
# See man bash for the TIMEFORMAT variable
PREV_TIMEFORMAT="${TIMEFORMAT}"
TIMEFORMAT="The command ${cmd} took %lR"
# You could use time eval "${cmd}". I don't recommend that
time /bin/echo foo && /bin/echo bar
Output:
foo
bar
The command /bin/echo foo && /bin/echo bar took 0m0.00s
Note: The above "solution" doesn't work when you use bash's echo builtin.
answered Nov 22 '18 at 4:11
hek2mglhek2mgl
109k13148173
How does this solution work with variables though? That's the part I'm having trouble with.
– mpen
Nov 23 '18 at 19:05
add a comment |
You can use the TIMEFORMAT variable to customize the output of bash's time builtin:
cmd="/bin/echo foo && /bin/echo bar"
# See man bash for the TIMEFORMAT variable
PREV_TIMEFORMAT="${TIMEFORMAT}"
TIMEFORMAT="The command ${cmd} took %lR"
# You could use time eval "${cmd}". I don't recommend that
time /bin/echo foo && /bin/echo bar
Output:
foo
bar
The command /bin/echo foo && /bin/echo bar took 0m0.00s
Note: The above "solution" doesn't work when you use bash's echo builtin.
answered Nov 22 '18 at 4:11
hek2mglhek2mgl
109k13148173
You can use the TIMEFORMAT variable to customize the output of bash's time builtin:
cmd="/bin/echo foo && /bin/echo bar"
# See man bash for the TIMEFORMAT variable
PREV_TIMEFORMAT="${TIMEFORMAT}"
TIMEFORMAT="The command ${cmd} took %lR"
# You could use time eval "${cmd}". I don't recommend that
time /bin/echo foo && /bin/echo bar
Output:
foo
bar
The command /bin/echo foo && /bin/echo bar took 0m0.00s
Note: The above "solution" doesn't work when you use bash's echo builtin.
answered Nov 22 '18 at 4:11
hek2mglhek2mgl
109k13148173
edited Nov 22 '18 at 4:17
answered Nov 22 '18 at 4:11
hek2mglhek2mgl
109k13148173
answered Nov 22 '18 at 4:11
hek2mglhek2mgl
109k13148173
answered Nov 22 '18 at 4:11
hek2mglhek2mgl
109k13148173
109k13148173
How does this solution work with variables though? That's the part I'm having trouble with.
– mpen
Nov 23 '18 at 19:05
add a comment |
How does this solution work with variables though? That's the part I'm having trouble with.
– mpen
Nov 23 '18 at 19:05
How does this solution work with variables though? That's the part I'm having trouble with.
– mpen
Nov 23 '18 at 19:05
How does this solution work with variables though? That's the part I'm having trouble with.
– mpen
Nov 23 '18 at 19:05
add a comment |
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1
No way. That's the reason why the
timereserved word exists in bash.– hek2mgl
Nov 22 '18 at 3:56