PowerShell Dynamic Arrays
I have been testing something new I learned in Powershell recently, creating dynamic arrays. So my inital idea was to create arrays based on AD groups and their members, and then do somthing with this information. Then I asked myself if powershell could do this for me from a search of AD. The answer was yes and I used the code below to do it.
$Groups = (Get-ADGroup -Filter {name -Like 'My_Group*'}).name
foreach ($Group in $Groups) {
New-Variable -Name "$($group)" -Value (Get-ADGroupMember -Identity $group -Recursive | Select -ExpandProperty SAMAccountName)
}
This is perfect as it creates arrays in powershell with the name of the AD group as the array name, and array items are members of that group.
My question now is how can I refer to the groups created in a script, if I dont actually know the names of the groups?
I am still fairly new to powershell so this may just be a daft idea, but it was something I wanted to know regardless.
Cheers
powershell dynamic-arrays
edited Nov 21 '18 at 15:02
Mathias R. Jessen
58.6k463109
asked Nov 21 '18 at 14:47
Cjones108Cjones108
203
add a comment |
I have been testing something new I learned in Powershell recently, creating dynamic arrays. So my inital idea was to create arrays based on AD groups and their members, and then do somthing with this information. Then I asked myself if powershell could do this for me from a search of AD. The answer was yes and I used the code below to do it.
$Groups = (Get-ADGroup -Filter {name -Like 'My_Group*'}).name
foreach ($Group in $Groups) {
New-Variable -Name "$($group)" -Value (Get-ADGroupMember -Identity $group -Recursive | Select -ExpandProperty SAMAccountName)
}
This is perfect as it creates arrays in powershell with the name of the AD group as the array name, and array items are members of that group.
My question now is how can I refer to the groups created in a script, if I dont actually know the names of the groups?
I am still fairly new to powershell so this may just be a daft idea, but it was something I wanted to know regardless.
Cheers
powershell dynamic-arrays
edited Nov 21 '18 at 15:02
Mathias R. Jessen
58.6k463109
asked Nov 21 '18 at 14:47
Cjones108Cjones108
203
As an aside: It's best to avoid the use of script blocks ({ ... }) as-Filterarguments.
– mklement0
Nov 21 '18 at 15:55
You're welcome; (mis-)using script blocks is very widespread, unfortunately, and there's even official documentation that makes use of them.
– mklement0
Nov 22 '18 at 17:34
add a comment |
I have been testing something new I learned in Powershell recently, creating dynamic arrays. So my inital idea was to create arrays based on AD groups and their members, and then do somthing with this information. Then I asked myself if powershell could do this for me from a search of AD. The answer was yes and I used the code below to do it.
$Groups = (Get-ADGroup -Filter {name -Like 'My_Group*'}).name
foreach ($Group in $Groups) {
New-Variable -Name "$($group)" -Value (Get-ADGroupMember -Identity $group -Recursive | Select -ExpandProperty SAMAccountName)
}
This is perfect as it creates arrays in powershell with the name of the AD group as the array name, and array items are members of that group.
My question now is how can I refer to the groups created in a script, if I dont actually know the names of the groups?
I am still fairly new to powershell so this may just be a daft idea, but it was something I wanted to know regardless.
Cheers
powershell dynamic-arrays
edited Nov 21 '18 at 15:02
Mathias R. Jessen
58.6k463109
asked Nov 21 '18 at 14:47
Cjones108Cjones108
203
I have been testing something new I learned in Powershell recently, creating dynamic arrays. So my inital idea was to create arrays based on AD groups and their members, and then do somthing with this information. Then I asked myself if powershell could do this for me from a search of AD. The answer was yes and I used the code below to do it.
$Groups = (Get-ADGroup -Filter {name -Like 'My_Group*'}).name
foreach ($Group in $Groups) {
New-Variable -Name "$($group)" -Value (Get-ADGroupMember -Identity $group -Recursive | Select -ExpandProperty SAMAccountName)
}
This is perfect as it creates arrays in powershell with the name of the AD group as the array name, and array items are members of that group.
My question now is how can I refer to the groups created in a script, if I dont actually know the names of the groups?
I am still fairly new to powershell so this may just be a daft idea, but it was something I wanted to know regardless.
Cheers
powershell dynamic-arrays
powershell dynamic-arrays
edited Nov 21 '18 at 15:02
Mathias R. Jessen
58.6k463109
asked Nov 21 '18 at 14:47
Cjones108Cjones108
203
edited Nov 21 '18 at 15:02
Mathias R. Jessen
58.6k463109
asked Nov 21 '18 at 14:47
Cjones108Cjones108
203
edited Nov 21 '18 at 15:02
Mathias R. Jessen
58.6k463109
edited Nov 21 '18 at 15:02
Mathias R. Jessen
58.6k463109
edited Nov 21 '18 at 15:02
Mathias R. Jessen
58.6k463109
58.6k463109
asked Nov 21 '18 at 14:47
Cjones108Cjones108
203
asked Nov 21 '18 at 14:47
Cjones108Cjones108
203
asked Nov 21 '18 at 14:47
Cjones108Cjones108
203
203
As an aside: It's best to avoid the use of script blocks ({ ... }) as-Filterarguments.
– mklement0
Nov 21 '18 at 15:55
You're welcome; (mis-)using script blocks is very widespread, unfortunately, and there's even official documentation that makes use of them.
– mklement0
Nov 22 '18 at 17:34
add a comment |
As an aside: It's best to avoid the use of script blocks ({ ... }) as-Filterarguments.
– mklement0
Nov 21 '18 at 15:55
You're welcome; (mis-)using script blocks is very widespread, unfortunately, and there's even official documentation that makes use of them.
– mklement0
Nov 22 '18 at 17:34
As an aside: It's best to avoid the use of script blocks (
{ ... }) as -Filter arguments.– mklement0
Nov 21 '18 at 15:55
As an aside: It's best to avoid the use of script blocks (
{ ... }) as -Filter arguments.– mklement0
Nov 21 '18 at 15:55
You're welcome; (mis-)using script blocks is very widespread, unfortunately, and there's even official documentation that makes use of them.
– mklement0
Nov 22 '18 at 17:34
You're welcome; (mis-)using script blocks is very widespread, unfortunately, and there's even official documentation that makes use of them.
– mklement0
Nov 22 '18 at 17:34
add a comment |
1 Answer
1
active
oldest
votes
Instead of variables, use a hashtable!
A hashtable is an unordered dictionary, perfect for storing things by name:
# Create an empty hashtable
$GroupMembers = @{}
# populate it with the relevant samaccountname values:
foreach($Group in (Get-ADGroup -Filter {Name -like 'My_Group*'}).Name) {
$GroupMembers["$Group"] = Get-ADGroupMember -Identity $Group -Recursive |Select -Expand SAMAccountName
}
Now you'll have a reference to all the group names via the $GroupMembers.Keys list, so you can easily discover them all again:
foreach($GroupName in $GroupMembers.Keys){
"$GroupName contains the members: $($GroupMembers[$GroupName] -join ', ')"
}
answered Nov 21 '18 at 15:07
Mathias R. JessenMathias R. Jessen
58.6k463109
1
Cool; worth noting that in PSv3+ you can also create an ordered dictionary with[ordered] @{ ... }, which enumerates the keys in the order in which they were added.
– mklement0
Nov 21 '18 at 15:58
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Instead of variables, use a hashtable!
A hashtable is an unordered dictionary, perfect for storing things by name:
# Create an empty hashtable
$GroupMembers = @{}
# populate it with the relevant samaccountname values:
foreach($Group in (Get-ADGroup -Filter {Name -like 'My_Group*'}).Name) {
$GroupMembers["$Group"] = Get-ADGroupMember -Identity $Group -Recursive |Select -Expand SAMAccountName
}
Now you'll have a reference to all the group names via the $GroupMembers.Keys list, so you can easily discover them all again:
foreach($GroupName in $GroupMembers.Keys){
"$GroupName contains the members: $($GroupMembers[$GroupName] -join ', ')"
}
answered Nov 21 '18 at 15:07
Mathias R. JessenMathias R. Jessen
58.6k463109
1
Cool; worth noting that in PSv3+ you can also create an ordered dictionary with[ordered] @{ ... }, which enumerates the keys in the order in which they were added.
– mklement0
Nov 21 '18 at 15:58
add a comment |
Instead of variables, use a hashtable!
A hashtable is an unordered dictionary, perfect for storing things by name:
# Create an empty hashtable
$GroupMembers = @{}
# populate it with the relevant samaccountname values:
foreach($Group in (Get-ADGroup -Filter {Name -like 'My_Group*'}).Name) {
$GroupMembers["$Group"] = Get-ADGroupMember -Identity $Group -Recursive |Select -Expand SAMAccountName
}
Now you'll have a reference to all the group names via the $GroupMembers.Keys list, so you can easily discover them all again:
foreach($GroupName in $GroupMembers.Keys){
"$GroupName contains the members: $($GroupMembers[$GroupName] -join ', ')"
}
answered Nov 21 '18 at 15:07
Mathias R. JessenMathias R. Jessen
58.6k463109
1
Cool; worth noting that in PSv3+ you can also create an ordered dictionary with[ordered] @{ ... }, which enumerates the keys in the order in which they were added.
– mklement0
Nov 21 '18 at 15:58
add a comment |
Instead of variables, use a hashtable!
A hashtable is an unordered dictionary, perfect for storing things by name:
# Create an empty hashtable
$GroupMembers = @{}
# populate it with the relevant samaccountname values:
foreach($Group in (Get-ADGroup -Filter {Name -like 'My_Group*'}).Name) {
$GroupMembers["$Group"] = Get-ADGroupMember -Identity $Group -Recursive |Select -Expand SAMAccountName
}
Now you'll have a reference to all the group names via the $GroupMembers.Keys list, so you can easily discover them all again:
foreach($GroupName in $GroupMembers.Keys){
"$GroupName contains the members: $($GroupMembers[$GroupName] -join ', ')"
}
answered Nov 21 '18 at 15:07
Mathias R. JessenMathias R. Jessen
58.6k463109
Instead of variables, use a hashtable!
A hashtable is an unordered dictionary, perfect for storing things by name:
# Create an empty hashtable
$GroupMembers = @{}
# populate it with the relevant samaccountname values:
foreach($Group in (Get-ADGroup -Filter {Name -like 'My_Group*'}).Name) {
$GroupMembers["$Group"] = Get-ADGroupMember -Identity $Group -Recursive |Select -Expand SAMAccountName
}
Now you'll have a reference to all the group names via the $GroupMembers.Keys list, so you can easily discover them all again:
foreach($GroupName in $GroupMembers.Keys){
"$GroupName contains the members: $($GroupMembers[$GroupName] -join ', ')"
}
answered Nov 21 '18 at 15:07
Mathias R. JessenMathias R. Jessen
58.6k463109
answered Nov 21 '18 at 15:07
Mathias R. JessenMathias R. Jessen
58.6k463109
answered Nov 21 '18 at 15:07
Mathias R. JessenMathias R. Jessen
58.6k463109
answered Nov 21 '18 at 15:07
Mathias R. JessenMathias R. Jessen
58.6k463109
58.6k463109
1
Cool; worth noting that in PSv3+ you can also create an ordered dictionary with[ordered] @{ ... }, which enumerates the keys in the order in which they were added.
– mklement0
Nov 21 '18 at 15:58
add a comment |
1
Cool; worth noting that in PSv3+ you can also create an ordered dictionary with[ordered] @{ ... }, which enumerates the keys in the order in which they were added.
– mklement0
Nov 21 '18 at 15:58
1
1
Cool; worth noting that in PSv3+ you can also create an ordered dictionary with
[ordered] @{ ... }, which enumerates the keys in the order in which they were added.– mklement0
Nov 21 '18 at 15:58
Cool; worth noting that in PSv3+ you can also create an ordered dictionary with
[ordered] @{ ... }, which enumerates the keys in the order in which they were added.– mklement0
Nov 21 '18 at 15:58
add a comment |
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As an aside: It's best to avoid the use of script blocks (
{ ... }) as-Filterarguments.– mklement0
Nov 21 '18 at 15:55
You're welcome; (mis-)using script blocks is very widespread, unfortunately, and there's even official documentation that makes use of them.
– mklement0
Nov 22 '18 at 17:34