How to align coordinates vertically and horizontally in TikZ












2















I have points with irrational coordinates, because I'm mixing polar and Cartesian coordinates. I'd like to specify a coordinate as the x-value of one thing and the y-value of another thing.



In this specific example, I want the two lines on the left to have the same left endpoints.



documentclass{standalone}

usepackage{tikz}

usetikzlibrary{calc}



begin{document}



  begin{tikzpicture}

    coordinate (left) at (155:2);

    coordinate (top) at (65:2);

    coordinate (bottom) at (245:2);

    coordinate (right) at (335:2);



    coordinate (leftEdge) at ($ (left) + (-2,0) $);

    coordinate (bottomEdge) at ($ (bottom) + (0,-2) $);



    path[draw=black] (left) -- (top) -- (right) -- (bottom) -- cycle;

    path[draw=blue] (left) -- (leftEdge);

    path[draw=black] (bottom) -- (bottomEdge);

    path[draw=red] (bottom) -- ++(-2,0);

  end{tikzpicture}



end{document}


I think there's a way to do this with something like (leftEdge.x,bottom.y), but I've been unsuccessful in getting it to work.



enter image description here



How can I get the red edge to go as far left as the blue edge?






tikz-pgf positioning coordinates







share|improve this question



























    2















    I have points with irrational coordinates, because I'm mixing polar and Cartesian coordinates. I'd like to specify a coordinate as the x-value of one thing and the y-value of another thing.



    In this specific example, I want the two lines on the left to have the same left endpoints.



    documentclass{standalone}
    
usepackage{tikz}
    
usetikzlibrary{calc}
    

    
begin{document}
    

    
  begin{tikzpicture}
    
    coordinate (left) at (155:2);
    
    coordinate (top) at (65:2);
    
    coordinate (bottom) at (245:2);
    
    coordinate (right) at (335:2);
    

    
    coordinate (leftEdge) at ($ (left) + (-2,0) $);
    
    coordinate (bottomEdge) at ($ (bottom) + (0,-2) $);
    

    
    path[draw=black] (left) -- (top) -- (right) -- (bottom) -- cycle;
    
    path[draw=blue] (left) -- (leftEdge);
    
    path[draw=black] (bottom) -- (bottomEdge);
    
    path[draw=red] (bottom) -- ++(-2,0);
    
  end{tikzpicture}
    

    
end{document}


    I think there's a way to do this with something like (leftEdge.x,bottom.y), but I've been unsuccessful in getting it to work.



    enter image description here



    How can I get the red edge to go as far left as the blue edge?






    tikz-pgf positioning coordinates







    share|improve this question

























      2












      2








      2








      I have points with irrational coordinates, because I'm mixing polar and Cartesian coordinates. I'd like to specify a coordinate as the x-value of one thing and the y-value of another thing.



      In this specific example, I want the two lines on the left to have the same left endpoints.



      documentclass{standalone}
      
usepackage{tikz}
      
usetikzlibrary{calc}
      

      
begin{document}
      

      
  begin{tikzpicture}
      
    coordinate (left) at (155:2);
      
    coordinate (top) at (65:2);
      
    coordinate (bottom) at (245:2);
      
    coordinate (right) at (335:2);
      

      
    coordinate (leftEdge) at ($ (left) + (-2,0) $);
      
    coordinate (bottomEdge) at ($ (bottom) + (0,-2) $);
      

      
    path[draw=black] (left) -- (top) -- (right) -- (bottom) -- cycle;
      
    path[draw=blue] (left) -- (leftEdge);
      
    path[draw=black] (bottom) -- (bottomEdge);
      
    path[draw=red] (bottom) -- ++(-2,0);
      
  end{tikzpicture}
      

      
end{document}


      I think there's a way to do this with something like (leftEdge.x,bottom.y), but I've been unsuccessful in getting it to work.



      enter image description here



      How can I get the red edge to go as far left as the blue edge?






      tikz-pgf positioning coordinates







      share|improve this question














      I have points with irrational coordinates, because I'm mixing polar and Cartesian coordinates. I'd like to specify a coordinate as the x-value of one thing and the y-value of another thing.



      In this specific example, I want the two lines on the left to have the same left endpoints.



      documentclass{standalone}
      
usepackage{tikz}
      
usetikzlibrary{calc}
      

      
begin{document}
      

      
  begin{tikzpicture}
      
    coordinate (left) at (155:2);
      
    coordinate (top) at (65:2);
      
    coordinate (bottom) at (245:2);
      
    coordinate (right) at (335:2);
      

      
    coordinate (leftEdge) at ($ (left) + (-2,0) $);
      
    coordinate (bottomEdge) at ($ (bottom) + (0,-2) $);
      

      
    path[draw=black] (left) -- (top) -- (right) -- (bottom) -- cycle;
      
    path[draw=blue] (left) -- (leftEdge);
      
    path[draw=black] (bottom) -- (bottomEdge);
      
    path[draw=red] (bottom) -- ++(-2,0);
      
  end{tikzpicture}
      

      
end{document}


      I think there's a way to do this with something like (leftEdge.x,bottom.y), but I've been unsuccessful in getting it to work.



      enter image description here



      How can I get the red edge to go as far left as the blue edge?






      tikz-pgf positioning coordinates




      tikz-pgf positioning coordinates






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Mar 1 at 3:49









      Pi FisherPi Fisher

      1278




      1278






















          1 Answer
          1






          active

          oldest

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          3














          In your example, you all you need to do is to say path[draw=red] (bottom) -- (bottom-|leftEdge);. This great answer provides you with a very nce discussion of this syntax.



          documentclass[tikz]{standalone}
          
usetikzlibrary{calc}
          

          
begin{document}
          

          
  begin{tikzpicture}
          
    coordinate (left) at (155:2);
          
    coordinate (top) at (65:2);
          
    coordinate (bottom) at (245:2);
          
    coordinate (right) at (335:2);
          

          
    coordinate (leftEdge) at ($ (left) + (-2,0) $);
          
    coordinate (bottomEdge) at ($ (bottom) + (0,-2) $);
          

          
    path[draw=black] (left) -- (top) -- (right) -- (bottom) -- cycle;
          
    path[draw=blue] (left) -- (leftEdge);
          
    path[draw=black] (bottom) -- (bottomEdge);
          
    path[draw=red] (bottom) -- (bottom-|leftEdge);
          
  end{tikzpicture}
          

          
end{document}


          enter image description here






          share|improve this answer
























          • Thanks! Follow-up question: suppose I want to specify a direction and a line to end on. For example, draw a line at 225 degrees from (right), and make it long enough to reach the bottom border of the image. Is there a similarly quick way to do that?

            – Pi Fisher
            Mar 1 at 15:00






          • 1





            @PiFisher Yes, with the calc library, which you are already loading : draw[purple] (right) -- (intersection cs:first line={(right)--($(right)+(225:3)$)},second line={(bottomEdge)--($(bottomEdge)+(3,0)$)});.

            – marmot
            Mar 1 at 15:09











          Your Answer








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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          3














          In your example, you all you need to do is to say path[draw=red] (bottom) -- (bottom-|leftEdge);. This great answer provides you with a very nce discussion of this syntax.



          documentclass[tikz]{standalone}
          
usetikzlibrary{calc}
          

          
begin{document}
          

          
  begin{tikzpicture}
          
    coordinate (left) at (155:2);
          
    coordinate (top) at (65:2);
          
    coordinate (bottom) at (245:2);
          
    coordinate (right) at (335:2);
          

          
    coordinate (leftEdge) at ($ (left) + (-2,0) $);
          
    coordinate (bottomEdge) at ($ (bottom) + (0,-2) $);
          

          
    path[draw=black] (left) -- (top) -- (right) -- (bottom) -- cycle;
          
    path[draw=blue] (left) -- (leftEdge);
          
    path[draw=black] (bottom) -- (bottomEdge);
          
    path[draw=red] (bottom) -- (bottom-|leftEdge);
          
  end{tikzpicture}
          

          
end{document}


          enter image description here






          share|improve this answer
























          • Thanks! Follow-up question: suppose I want to specify a direction and a line to end on. For example, draw a line at 225 degrees from (right), and make it long enough to reach the bottom border of the image. Is there a similarly quick way to do that?

            – Pi Fisher
            Mar 1 at 15:00






          • 1





            @PiFisher Yes, with the calc library, which you are already loading : draw[purple] (right) -- (intersection cs:first line={(right)--($(right)+(225:3)$)},second line={(bottomEdge)--($(bottomEdge)+(3,0)$)});.

            – marmot
            Mar 1 at 15:09
















          3














          In your example, you all you need to do is to say path[draw=red] (bottom) -- (bottom-|leftEdge);. This great answer provides you with a very nce discussion of this syntax.



          documentclass[tikz]{standalone}
          
usetikzlibrary{calc}
          

          
begin{document}
          

          
  begin{tikzpicture}
          
    coordinate (left) at (155:2);
          
    coordinate (top) at (65:2);
          
    coordinate (bottom) at (245:2);
          
    coordinate (right) at (335:2);
          

          
    coordinate (leftEdge) at ($ (left) + (-2,0) $);
          
    coordinate (bottomEdge) at ($ (bottom) + (0,-2) $);
          

          
    path[draw=black] (left) -- (top) -- (right) -- (bottom) -- cycle;
          
    path[draw=blue] (left) -- (leftEdge);
          
    path[draw=black] (bottom) -- (bottomEdge);
          
    path[draw=red] (bottom) -- (bottom-|leftEdge);
          
  end{tikzpicture}
          

          
end{document}


          enter image description here






          share|improve this answer
























          • Thanks! Follow-up question: suppose I want to specify a direction and a line to end on. For example, draw a line at 225 degrees from (right), and make it long enough to reach the bottom border of the image. Is there a similarly quick way to do that?

            – Pi Fisher
            Mar 1 at 15:00






          • 1





            @PiFisher Yes, with the calc library, which you are already loading : draw[purple] (right) -- (intersection cs:first line={(right)--($(right)+(225:3)$)},second line={(bottomEdge)--($(bottomEdge)+(3,0)$)});.

            – marmot
            Mar 1 at 15:09














          3












          3








          3







          In your example, you all you need to do is to say path[draw=red] (bottom) -- (bottom-|leftEdge);. This great answer provides you with a very nce discussion of this syntax.



          documentclass[tikz]{standalone}
          
usetikzlibrary{calc}
          

          
begin{document}
          

          
  begin{tikzpicture}
          
    coordinate (left) at (155:2);
          
    coordinate (top) at (65:2);
          
    coordinate (bottom) at (245:2);
          
    coordinate (right) at (335:2);
          

          
    coordinate (leftEdge) at ($ (left) + (-2,0) $);
          
    coordinate (bottomEdge) at ($ (bottom) + (0,-2) $);
          

          
    path[draw=black] (left) -- (top) -- (right) -- (bottom) -- cycle;
          
    path[draw=blue] (left) -- (leftEdge);
          
    path[draw=black] (bottom) -- (bottomEdge);
          
    path[draw=red] (bottom) -- (bottom-|leftEdge);
          
  end{tikzpicture}
          

          
end{document}


          enter image description here






          share|improve this answer













          In your example, you all you need to do is to say path[draw=red] (bottom) -- (bottom-|leftEdge);. This great answer provides you with a very nce discussion of this syntax.



          documentclass[tikz]{standalone}
          
usetikzlibrary{calc}
          

          
begin{document}
          

          
  begin{tikzpicture}
          
    coordinate (left) at (155:2);
          
    coordinate (top) at (65:2);
          
    coordinate (bottom) at (245:2);
          
    coordinate (right) at (335:2);
          

          
    coordinate (leftEdge) at ($ (left) + (-2,0) $);
          
    coordinate (bottomEdge) at ($ (bottom) + (0,-2) $);
          

          
    path[draw=black] (left) -- (top) -- (right) -- (bottom) -- cycle;
          
    path[draw=blue] (left) -- (leftEdge);
          
    path[draw=black] (bottom) -- (bottomEdge);
          
    path[draw=red] (bottom) -- (bottom-|leftEdge);
          
  end{tikzpicture}
          

          
end{document}


          enter image description here







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Mar 1 at 3:58









          marmotmarmot

          107k5129243




          107k5129243













          • Thanks! Follow-up question: suppose I want to specify a direction and a line to end on. For example, draw a line at 225 degrees from (right), and make it long enough to reach the bottom border of the image. Is there a similarly quick way to do that?

            – Pi Fisher
            Mar 1 at 15:00






          • 1





            @PiFisher Yes, with the calc library, which you are already loading : draw[purple] (right) -- (intersection cs:first line={(right)--($(right)+(225:3)$)},second line={(bottomEdge)--($(bottomEdge)+(3,0)$)});.

            – marmot
            Mar 1 at 15:09



















          • Thanks! Follow-up question: suppose I want to specify a direction and a line to end on. For example, draw a line at 225 degrees from (right), and make it long enough to reach the bottom border of the image. Is there a similarly quick way to do that?

            – Pi Fisher
            Mar 1 at 15:00






          • 1





            @PiFisher Yes, with the calc library, which you are already loading : draw[purple] (right) -- (intersection cs:first line={(right)--($(right)+(225:3)$)},second line={(bottomEdge)--($(bottomEdge)+(3,0)$)});.

            – marmot
            Mar 1 at 15:09

















          Thanks! Follow-up question: suppose I want to specify a direction and a line to end on. For example, draw a line at 225 degrees from (right), and make it long enough to reach the bottom border of the image. Is there a similarly quick way to do that?

          – Pi Fisher
          Mar 1 at 15:00





          Thanks! Follow-up question: suppose I want to specify a direction and a line to end on. For example, draw a line at 225 degrees from (right), and make it long enough to reach the bottom border of the image. Is there a similarly quick way to do that?

          – Pi Fisher
          Mar 1 at 15:00




          1




          1





          @PiFisher Yes, with the calc library, which you are already loading : draw[purple] (right) -- (intersection cs:first line={(right)--($(right)+(225:3)$)},second line={(bottomEdge)--($(bottomEdge)+(3,0)$)});.

          – marmot
          Mar 1 at 15:09





          @PiFisher Yes, with the calc library, which you are already loading : draw[purple] (right) -- (intersection cs:first line={(right)--($(right)+(225:3)$)},second line={(bottomEdge)--($(bottomEdge)+(3,0)$)});.

          – marmot
          Mar 1 at 15:09


















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