Is there posibility to disable “string templates”?
Kotlin have amazing, which is not present in java, but it is possible to do not use it somehow? Like for example in php:
"$foo"
'$foo'
kotlin
edited Nov 20 '18 at 19:30
yole
60.3k11151144
asked Nov 20 '18 at 19:22
majkrzakmajkrzak
709
add a comment |
Kotlin have amazing, which is not present in java, but it is possible to do not use it somehow? Like for example in php:
"$foo"
'$foo'
kotlin
edited Nov 20 '18 at 19:30
yole
60.3k11151144
asked Nov 20 '18 at 19:22
majkrzakmajkrzak
709
add a comment |
Kotlin have amazing, which is not present in java, but it is possible to do not use it somehow? Like for example in php:
"$foo"
'$foo'
kotlin
edited Nov 20 '18 at 19:30
yole
60.3k11151144
asked Nov 20 '18 at 19:22
majkrzakmajkrzak
709
Kotlin have amazing, which is not present in java, but it is possible to do not use it somehow? Like for example in php:
"$foo"
'$foo'
kotlin
kotlin
edited Nov 20 '18 at 19:30
yole
60.3k11151144
asked Nov 20 '18 at 19:22
majkrzakmajkrzak
709
edited Nov 20 '18 at 19:30
yole
60.3k11151144
asked Nov 20 '18 at 19:22
majkrzakmajkrzak
709
edited Nov 20 '18 at 19:30
yole
60.3k11151144
edited Nov 20 '18 at 19:30
yole
60.3k11151144
edited Nov 20 '18 at 19:30
yole
60.3k11151144
60.3k11151144
asked Nov 20 '18 at 19:22
majkrzakmajkrzak
709
asked Nov 20 '18 at 19:22
majkrzakmajkrzak
709
asked Nov 20 '18 at 19:22
majkrzakmajkrzak
709
709
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
You can't disable them in any way. String templates are always interpreted, even inside raw strings, as the related documentation describes.
There's a way to input a literal $ character, if that's your issue with it (described in the same docs). Otherwise, if you just find it odd or it's inconvenient for some specific use case, you're probably out of luck.
answered Nov 20 '18 at 19:26
zsmb13zsmb13
39.7k78096
nice language :D${'$'}is best stuff I've ever saw
– majkrzak
Nov 20 '18 at 19:26
definingval `$` = "$"allows"$`$`"maybe you like that better ;)
– leonardkraemer
Nov 20 '18 at 19:41
add a comment |
You can't disable. But you can escape it using .
val my_variable = "Some Value"
println("this --> $my_variable")
Above code will print this --> $my_variable
answered Nov 20 '18 at 19:44
Suryavel TRSuryavel TR
2,47311420
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
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active
oldest
votes
You can't disable them in any way. String templates are always interpreted, even inside raw strings, as the related documentation describes.
There's a way to input a literal $ character, if that's your issue with it (described in the same docs). Otherwise, if you just find it odd or it's inconvenient for some specific use case, you're probably out of luck.
answered Nov 20 '18 at 19:26
zsmb13zsmb13
39.7k78096
nice language :D${'$'}is best stuff I've ever saw
– majkrzak
Nov 20 '18 at 19:26
definingval `$` = "$"allows"$`$`"maybe you like that better ;)
– leonardkraemer
Nov 20 '18 at 19:41
add a comment |
You can't disable them in any way. String templates are always interpreted, even inside raw strings, as the related documentation describes.
There's a way to input a literal $ character, if that's your issue with it (described in the same docs). Otherwise, if you just find it odd or it's inconvenient for some specific use case, you're probably out of luck.
answered Nov 20 '18 at 19:26
zsmb13zsmb13
39.7k78096
nice language :D${'$'}is best stuff I've ever saw
– majkrzak
Nov 20 '18 at 19:26
definingval `$` = "$"allows"$`$`"maybe you like that better ;)
– leonardkraemer
Nov 20 '18 at 19:41
add a comment |
You can't disable them in any way. String templates are always interpreted, even inside raw strings, as the related documentation describes.
There's a way to input a literal $ character, if that's your issue with it (described in the same docs). Otherwise, if you just find it odd or it's inconvenient for some specific use case, you're probably out of luck.
answered Nov 20 '18 at 19:26
zsmb13zsmb13
39.7k78096
You can't disable them in any way. String templates are always interpreted, even inside raw strings, as the related documentation describes.
There's a way to input a literal $ character, if that's your issue with it (described in the same docs). Otherwise, if you just find it odd or it's inconvenient for some specific use case, you're probably out of luck.
answered Nov 20 '18 at 19:26
zsmb13zsmb13
39.7k78096
edited Nov 20 '18 at 19:26
answered Nov 20 '18 at 19:26
zsmb13zsmb13
39.7k78096
answered Nov 20 '18 at 19:26
zsmb13zsmb13
39.7k78096
answered Nov 20 '18 at 19:26
zsmb13zsmb13
39.7k78096
39.7k78096
nice language :D${'$'}is best stuff I've ever saw
– majkrzak
Nov 20 '18 at 19:26
definingval `$` = "$"allows"$`$`"maybe you like that better ;)
– leonardkraemer
Nov 20 '18 at 19:41
add a comment |
nice language :D${'$'}is best stuff I've ever saw
– majkrzak
Nov 20 '18 at 19:26
definingval `$` = "$"allows"$`$`"maybe you like that better ;)
– leonardkraemer
Nov 20 '18 at 19:41
nice language :D
${'$'} is best stuff I've ever saw– majkrzak
Nov 20 '18 at 19:26
nice language :D
${'$'} is best stuff I've ever saw– majkrzak
Nov 20 '18 at 19:26
defining
val `$` = "$" allows "$`$`" maybe you like that better ;)– leonardkraemer
Nov 20 '18 at 19:41
defining
val `$` = "$" allows "$`$`" maybe you like that better ;)– leonardkraemer
Nov 20 '18 at 19:41
add a comment |
You can't disable. But you can escape it using .
val my_variable = "Some Value"
println("this --> $my_variable")
Above code will print this --> $my_variable
answered Nov 20 '18 at 19:44
Suryavel TRSuryavel TR
2,47311420
add a comment |
You can't disable. But you can escape it using .
val my_variable = "Some Value"
println("this --> $my_variable")
Above code will print this --> $my_variable
answered Nov 20 '18 at 19:44
Suryavel TRSuryavel TR
2,47311420
add a comment |
You can't disable. But you can escape it using .
val my_variable = "Some Value"
println("this --> $my_variable")
Above code will print this --> $my_variable
answered Nov 20 '18 at 19:44
Suryavel TRSuryavel TR
2,47311420
You can't disable. But you can escape it using .
val my_variable = "Some Value"
println("this --> $my_variable")
Above code will print this --> $my_variable
answered Nov 20 '18 at 19:44
Suryavel TRSuryavel TR
2,47311420
answered Nov 20 '18 at 19:44
Suryavel TRSuryavel TR
2,47311420
answered Nov 20 '18 at 19:44
Suryavel TRSuryavel TR
2,47311420
answered Nov 20 '18 at 19:44
Suryavel TRSuryavel TR
2,47311420
2,47311420
add a comment |
add a comment |
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