Pandas: counter increasing each time conditions are met












2















I have a dataframe with some conditions and a Counter that Counts when condition A is met.



 date                      condition        count   
01,01,2018 08:00 A 1
01,01,2018 08:01 A 2
01,01,2018 08:03 A 3
01,01,2018 08:04 B 0
01,01,2018 08:07 B 0
01,01,2018 08:10 B 0
01,01,2018 08:13 B 0
01,01,2018 08:22 A 1
01,01,2018 08:24 A 2
01,01,2018 08:25 B 0
01,01,2018 08:27 B 0
01,01,2018 08:29 B 0
01,01,2018 08:30 A 1


I would like that the Count doesn't reset each time condition changes.



date                      condition        count   
01,01,2018 08:00 A 1
01,01,2018 08:01 A 2
01,01,2018 08:03 A 3
01,01,2018 08:04 B 3
01,01,2018 08:07 B 3
01,01,2018 08:10 B 3
01,01,2018 08:13 B 3
01,01,2018 08:22 A 4
01,01,2018 08:24 A 5
01,01,2018 08:25 B 5
01,01,2018 08:27 B 5
01,01,2018 08:29 B 5
01,01,2018 08:30 A 6


At the Moment the code for the Count Looks like:



df['count']= df.groupby((df['condition'] = 'A').cumsum()).cumcount()


Thanks!










share|improve this question



























    2















    I have a dataframe with some conditions and a Counter that Counts when condition A is met.



     date                      condition        count   
    01,01,2018 08:00 A 1
    01,01,2018 08:01 A 2
    01,01,2018 08:03 A 3
    01,01,2018 08:04 B 0
    01,01,2018 08:07 B 0
    01,01,2018 08:10 B 0
    01,01,2018 08:13 B 0
    01,01,2018 08:22 A 1
    01,01,2018 08:24 A 2
    01,01,2018 08:25 B 0
    01,01,2018 08:27 B 0
    01,01,2018 08:29 B 0
    01,01,2018 08:30 A 1


    I would like that the Count doesn't reset each time condition changes.



    date                      condition        count   
    01,01,2018 08:00 A 1
    01,01,2018 08:01 A 2
    01,01,2018 08:03 A 3
    01,01,2018 08:04 B 3
    01,01,2018 08:07 B 3
    01,01,2018 08:10 B 3
    01,01,2018 08:13 B 3
    01,01,2018 08:22 A 4
    01,01,2018 08:24 A 5
    01,01,2018 08:25 B 5
    01,01,2018 08:27 B 5
    01,01,2018 08:29 B 5
    01,01,2018 08:30 A 6


    At the Moment the code for the Count Looks like:



    df['count']= df.groupby((df['condition'] = 'A').cumsum()).cumcount()


    Thanks!










    share|improve this question

























      2












      2








      2








      I have a dataframe with some conditions and a Counter that Counts when condition A is met.



       date                      condition        count   
      01,01,2018 08:00 A 1
      01,01,2018 08:01 A 2
      01,01,2018 08:03 A 3
      01,01,2018 08:04 B 0
      01,01,2018 08:07 B 0
      01,01,2018 08:10 B 0
      01,01,2018 08:13 B 0
      01,01,2018 08:22 A 1
      01,01,2018 08:24 A 2
      01,01,2018 08:25 B 0
      01,01,2018 08:27 B 0
      01,01,2018 08:29 B 0
      01,01,2018 08:30 A 1


      I would like that the Count doesn't reset each time condition changes.



      date                      condition        count   
      01,01,2018 08:00 A 1
      01,01,2018 08:01 A 2
      01,01,2018 08:03 A 3
      01,01,2018 08:04 B 3
      01,01,2018 08:07 B 3
      01,01,2018 08:10 B 3
      01,01,2018 08:13 B 3
      01,01,2018 08:22 A 4
      01,01,2018 08:24 A 5
      01,01,2018 08:25 B 5
      01,01,2018 08:27 B 5
      01,01,2018 08:29 B 5
      01,01,2018 08:30 A 6


      At the Moment the code for the Count Looks like:



      df['count']= df.groupby((df['condition'] = 'A').cumsum()).cumcount()


      Thanks!










      share|improve this question














      I have a dataframe with some conditions and a Counter that Counts when condition A is met.



       date                      condition        count   
      01,01,2018 08:00 A 1
      01,01,2018 08:01 A 2
      01,01,2018 08:03 A 3
      01,01,2018 08:04 B 0
      01,01,2018 08:07 B 0
      01,01,2018 08:10 B 0
      01,01,2018 08:13 B 0
      01,01,2018 08:22 A 1
      01,01,2018 08:24 A 2
      01,01,2018 08:25 B 0
      01,01,2018 08:27 B 0
      01,01,2018 08:29 B 0
      01,01,2018 08:30 A 1


      I would like that the Count doesn't reset each time condition changes.



      date                      condition        count   
      01,01,2018 08:00 A 1
      01,01,2018 08:01 A 2
      01,01,2018 08:03 A 3
      01,01,2018 08:04 B 3
      01,01,2018 08:07 B 3
      01,01,2018 08:10 B 3
      01,01,2018 08:13 B 3
      01,01,2018 08:22 A 4
      01,01,2018 08:24 A 5
      01,01,2018 08:25 B 5
      01,01,2018 08:27 B 5
      01,01,2018 08:29 B 5
      01,01,2018 08:30 A 6


      At the Moment the code for the Count Looks like:



      df['count']= df.groupby((df['condition'] = 'A').cumsum()).cumcount()


      Thanks!







      python pandas






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 19 '18 at 17:02









      Luca91Luca91

      1808




      1808
























          2 Answers
          2






          active

          oldest

          votes


















          4














          Why not



          df['count']=df['condition'].eq('A').cumsum()





          share|improve this answer
























          • what if I have 2 conditions but I want to restart the Count each time are both met?? at the Moment I am trying df['count']= df.groupby(((df.condition1<50)&(df.condition2 < 10)).cumsum()).cumcount()+1 but it doesn't work, it simply start counting from the beginning to the end ignoring the conditions...can you help me with this please?

            – Luca91
            Nov 20 '18 at 8:46



















          1














          I think groupby.cumsum is what you're looking for



          df['count']= df.groupby((df['Date']['condition']).cumsum())


          and then later subset the df based on required condition.






          share|improve this answer























            Your Answer






            StackExchange.ifUsing("editor", function () {
            StackExchange.using("externalEditor", function () {
            StackExchange.using("snippets", function () {
            StackExchange.snippets.init();
            });
            });
            }, "code-snippets");

            StackExchange.ready(function() {
            var channelOptions = {
            tags: "".split(" "),
            id: "1"
            };
            initTagRenderer("".split(" "), "".split(" "), channelOptions);

            StackExchange.using("externalEditor", function() {
            // Have to fire editor after snippets, if snippets enabled
            if (StackExchange.settings.snippets.snippetsEnabled) {
            StackExchange.using("snippets", function() {
            createEditor();
            });
            }
            else {
            createEditor();
            }
            });

            function createEditor() {
            StackExchange.prepareEditor({
            heartbeatType: 'answer',
            autoActivateHeartbeat: false,
            convertImagesToLinks: true,
            noModals: true,
            showLowRepImageUploadWarning: true,
            reputationToPostImages: 10,
            bindNavPrevention: true,
            postfix: "",
            imageUploader: {
            brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
            contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
            allowUrls: true
            },
            onDemand: true,
            discardSelector: ".discard-answer"
            ,immediatelyShowMarkdownHelp:true
            });


            }
            });














            draft saved

            draft discarded


















            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53379461%2fpandas-counter-increasing-each-time-conditions-are-met%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown

























            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            4














            Why not



            df['count']=df['condition'].eq('A').cumsum()





            share|improve this answer
























            • what if I have 2 conditions but I want to restart the Count each time are both met?? at the Moment I am trying df['count']= df.groupby(((df.condition1<50)&(df.condition2 < 10)).cumsum()).cumcount()+1 but it doesn't work, it simply start counting from the beginning to the end ignoring the conditions...can you help me with this please?

              – Luca91
              Nov 20 '18 at 8:46
















            4














            Why not



            df['count']=df['condition'].eq('A').cumsum()





            share|improve this answer
























            • what if I have 2 conditions but I want to restart the Count each time are both met?? at the Moment I am trying df['count']= df.groupby(((df.condition1<50)&(df.condition2 < 10)).cumsum()).cumcount()+1 but it doesn't work, it simply start counting from the beginning to the end ignoring the conditions...can you help me with this please?

              – Luca91
              Nov 20 '18 at 8:46














            4












            4








            4







            Why not



            df['count']=df['condition'].eq('A').cumsum()





            share|improve this answer













            Why not



            df['count']=df['condition'].eq('A').cumsum()






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 19 '18 at 17:09









            W-BW-B

            107k83165




            107k83165













            • what if I have 2 conditions but I want to restart the Count each time are both met?? at the Moment I am trying df['count']= df.groupby(((df.condition1<50)&(df.condition2 < 10)).cumsum()).cumcount()+1 but it doesn't work, it simply start counting from the beginning to the end ignoring the conditions...can you help me with this please?

              – Luca91
              Nov 20 '18 at 8:46



















            • what if I have 2 conditions but I want to restart the Count each time are both met?? at the Moment I am trying df['count']= df.groupby(((df.condition1<50)&(df.condition2 < 10)).cumsum()).cumcount()+1 but it doesn't work, it simply start counting from the beginning to the end ignoring the conditions...can you help me with this please?

              – Luca91
              Nov 20 '18 at 8:46

















            what if I have 2 conditions but I want to restart the Count each time are both met?? at the Moment I am trying df['count']= df.groupby(((df.condition1<50)&(df.condition2 < 10)).cumsum()).cumcount()+1 but it doesn't work, it simply start counting from the beginning to the end ignoring the conditions...can you help me with this please?

            – Luca91
            Nov 20 '18 at 8:46





            what if I have 2 conditions but I want to restart the Count each time are both met?? at the Moment I am trying df['count']= df.groupby(((df.condition1<50)&(df.condition2 < 10)).cumsum()).cumcount()+1 but it doesn't work, it simply start counting from the beginning to the end ignoring the conditions...can you help me with this please?

            – Luca91
            Nov 20 '18 at 8:46













            1














            I think groupby.cumsum is what you're looking for



            df['count']= df.groupby((df['Date']['condition']).cumsum())


            and then later subset the df based on required condition.






            share|improve this answer




























              1














              I think groupby.cumsum is what you're looking for



              df['count']= df.groupby((df['Date']['condition']).cumsum())


              and then later subset the df based on required condition.






              share|improve this answer


























                1












                1








                1







                I think groupby.cumsum is what you're looking for



                df['count']= df.groupby((df['Date']['condition']).cumsum())


                and then later subset the df based on required condition.






                share|improve this answer













                I think groupby.cumsum is what you're looking for



                df['count']= df.groupby((df['Date']['condition']).cumsum())


                and then later subset the df based on required condition.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 19 '18 at 17:21









                Ken DekalbKen Dekalb

                319112




                319112






























                    draft saved

                    draft discarded




















































                    Thanks for contributing an answer to Stack Overflow!


                    • Please be sure to answer the question. Provide details and share your research!

                    But avoid



                    • Asking for help, clarification, or responding to other answers.

                    • Making statements based on opinion; back them up with references or personal experience.


                    To learn more, see our tips on writing great answers.




                    draft saved


                    draft discarded














                    StackExchange.ready(
                    function () {
                    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53379461%2fpandas-counter-increasing-each-time-conditions-are-met%23new-answer', 'question_page');
                    }
                    );

                    Post as a guest















                    Required, but never shown





















































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown

































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown







                    Popular posts from this blog

                    How to change which sound is reproduced for terminal bell?

                    Can I use Tabulator js library in my java Spring + Thymeleaf project?

                    Title Spacing in Bjornstrup Chapter, Removing Chapter Number From Contents