How to search for files with a pattern of 2 consecutive new lines & modify the succeeding line?
1
I have a few directories with a bunch of files that I need to change. That change involves me finding the files that includes the selector and service labels:
selector:
service: XXXXX
and replacing the service label with app:
selector:
app: XXXXX
Btw, none of the solutions in this similar stack overflow thread work.
grep yaml
asked Nov 19 '18 at 16:48
seemcatseemcat
429
add a comment |
1
I have a few directories with a bunch of files that I need to change. That change involves me finding the files that includes the selector and service labels:
selector:
service: XXXXX
and replacing the service label with app:
selector:
app: XXXXX
Btw, none of the solutions in this similar stack overflow thread work.
grep yaml
asked Nov 19 '18 at 16:48
seemcatseemcat
429
Start with reading about sed, and here's a question that may help you get some ideas: stackoverflow.com/questions/16123102/…
– dcp
Nov 19 '18 at 16:52
1
Since this is a YAML file, I suggest you read in the YAML into whatever language you're using, and then replace the element of the structure that you want to change. Then, write out the new YAML based on your modifications. In general, if you have structured data in a specific format, it's far safer and easier to read it, modify it, and rewrite it, rather than playing around with it as plain text.
– Andy Lester
Nov 19 '18 at 17:04
@dcp I tried applying all of their answers and each of them threw an invalid command code.
– seemcat
Nov 19 '18 at 17:26
add a comment |
1
1
1
I have a few directories with a bunch of files that I need to change. That change involves me finding the files that includes the selector and service labels:
selector:
service: XXXXX
and replacing the service label with app:
selector:
app: XXXXX
Btw, none of the solutions in this similar stack overflow thread work.
grep yaml
asked Nov 19 '18 at 16:48
seemcatseemcat
429
I have a few directories with a bunch of files that I need to change. That change involves me finding the files that includes the selector and service labels:
selector:
service: XXXXX
and replacing the service label with app:
selector:
app: XXXXX
Btw, none of the solutions in this similar stack overflow thread work.
grep yaml
grep yaml
asked Nov 19 '18 at 16:48
seemcatseemcat
429
asked Nov 19 '18 at 16:48
seemcatseemcat
429
edited Nov 19 '18 at 19:31
seemcat
asked Nov 19 '18 at 16:48
seemcatseemcat
429
asked Nov 19 '18 at 16:48
seemcatseemcat
429
asked Nov 19 '18 at 16:48
seemcatseemcat
429
429
Start with reading about sed, and here's a question that may help you get some ideas: stackoverflow.com/questions/16123102/…
– dcp
Nov 19 '18 at 16:52
1
Since this is a YAML file, I suggest you read in the YAML into whatever language you're using, and then replace the element of the structure that you want to change. Then, write out the new YAML based on your modifications. In general, if you have structured data in a specific format, it's far safer and easier to read it, modify it, and rewrite it, rather than playing around with it as plain text.
– Andy Lester
Nov 19 '18 at 17:04
@dcp I tried applying all of their answers and each of them threw an invalid command code.
– seemcat
Nov 19 '18 at 17:26
add a comment |
Start with reading about sed, and here's a question that may help you get some ideas: stackoverflow.com/questions/16123102/…
– dcp
Nov 19 '18 at 16:52
1
Since this is a YAML file, I suggest you read in the YAML into whatever language you're using, and then replace the element of the structure that you want to change. Then, write out the new YAML based on your modifications. In general, if you have structured data in a specific format, it's far safer and easier to read it, modify it, and rewrite it, rather than playing around with it as plain text.
– Andy Lester
Nov 19 '18 at 17:04
@dcp I tried applying all of their answers and each of them threw an invalid command code.
– seemcat
Nov 19 '18 at 17:26
Start with reading about sed, and here's a question that may help you get some ideas: stackoverflow.com/questions/16123102/…
– dcp
Nov 19 '18 at 16:52
Start with reading about sed, and here's a question that may help you get some ideas: stackoverflow.com/questions/16123102/…
– dcp
Nov 19 '18 at 16:52
1
1
Since this is a YAML file, I suggest you read in the YAML into whatever language you're using, and then replace the element of the structure that you want to change. Then, write out the new YAML based on your modifications. In general, if you have structured data in a specific format, it's far safer and easier to read it, modify it, and rewrite it, rather than playing around with it as plain text.
– Andy Lester
Nov 19 '18 at 17:04
Since this is a YAML file, I suggest you read in the YAML into whatever language you're using, and then replace the element of the structure that you want to change. Then, write out the new YAML based on your modifications. In general, if you have structured data in a specific format, it's far safer and easier to read it, modify it, and rewrite it, rather than playing around with it as plain text.
– Andy Lester
Nov 19 '18 at 17:04
@dcp I tried applying all of their answers and each of them threw an invalid command code.
– seemcat
Nov 19 '18 at 17:26
@dcp I tried applying all of their answers and each of them threw an invalid command code.
– seemcat
Nov 19 '18 at 17:26
add a comment |
1 Answer
1
active
oldest
votes
1
In case You wanna AWK (gawk) solution. Here it is.
Considering input per Your question:
$ cat v1mg1rl.txt
application:
id: 0
service: WWWWW
selector:
id: 1
service: XXXXX
cartridge:
id: 2
service: ZZZZZ
AWK:
$ awk '/^[^ ]+/ { isselector=0; } /^selector:/ { isselector=1; } /^ +service: / { if (isselector) sub(/service: /,"app: "); } { print($0); }' v1mg1rl.txt
application:
id: 0
service: WWWWW
selector:
id: 1
app: XXXXX
cartridge:
id: 2
service: ZZZZZ
answered Nov 20 '18 at 9:50
KubatorKubator
74911
Thanks, I appreciate ya' Kubator! (Lol, nice name btw.)
– seemcat
Nov 20 '18 at 20:06
Sure thing. Glad if helped.
– Kubator
Nov 21 '18 at 16:49
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
In case You wanna AWK (gawk) solution. Here it is.
Considering input per Your question:
$ cat v1mg1rl.txt
application:
id: 0
service: WWWWW
selector:
id: 1
service: XXXXX
cartridge:
id: 2
service: ZZZZZ
AWK:
$ awk '/^[^ ]+/ { isselector=0; } /^selector:/ { isselector=1; } /^ +service: / { if (isselector) sub(/service: /,"app: "); } { print($0); }' v1mg1rl.txt
application:
id: 0
service: WWWWW
selector:
id: 1
app: XXXXX
cartridge:
id: 2
service: ZZZZZ
answered Nov 20 '18 at 9:50
KubatorKubator
74911
Thanks, I appreciate ya' Kubator! (Lol, nice name btw.)
– seemcat
Nov 20 '18 at 20:06
Sure thing. Glad if helped.
– Kubator
Nov 21 '18 at 16:49
add a comment |
1
In case You wanna AWK (gawk) solution. Here it is.
Considering input per Your question:
$ cat v1mg1rl.txt
application:
id: 0
service: WWWWW
selector:
id: 1
service: XXXXX
cartridge:
id: 2
service: ZZZZZ
AWK:
$ awk '/^[^ ]+/ { isselector=0; } /^selector:/ { isselector=1; } /^ +service: / { if (isselector) sub(/service: /,"app: "); } { print($0); }' v1mg1rl.txt
application:
id: 0
service: WWWWW
selector:
id: 1
app: XXXXX
cartridge:
id: 2
service: ZZZZZ
answered Nov 20 '18 at 9:50
KubatorKubator
74911
Thanks, I appreciate ya' Kubator! (Lol, nice name btw.)
– seemcat
Nov 20 '18 at 20:06
Sure thing. Glad if helped.
– Kubator
Nov 21 '18 at 16:49
add a comment |
1
1
1
In case You wanna AWK (gawk) solution. Here it is.
Considering input per Your question:
$ cat v1mg1rl.txt
application:
id: 0
service: WWWWW
selector:
id: 1
service: XXXXX
cartridge:
id: 2
service: ZZZZZ
AWK:
$ awk '/^[^ ]+/ { isselector=0; } /^selector:/ { isselector=1; } /^ +service: / { if (isselector) sub(/service: /,"app: "); } { print($0); }' v1mg1rl.txt
application:
id: 0
service: WWWWW
selector:
id: 1
app: XXXXX
cartridge:
id: 2
service: ZZZZZ
answered Nov 20 '18 at 9:50
KubatorKubator
74911
In case You wanna AWK (gawk) solution. Here it is.
Considering input per Your question:
$ cat v1mg1rl.txt
application:
id: 0
service: WWWWW
selector:
id: 1
service: XXXXX
cartridge:
id: 2
service: ZZZZZ
AWK:
$ awk '/^[^ ]+/ { isselector=0; } /^selector:/ { isselector=1; } /^ +service: / { if (isselector) sub(/service: /,"app: "); } { print($0); }' v1mg1rl.txt
application:
id: 0
service: WWWWW
selector:
id: 1
app: XXXXX
cartridge:
id: 2
service: ZZZZZ
answered Nov 20 '18 at 9:50
KubatorKubator
74911
answered Nov 20 '18 at 9:50
KubatorKubator
74911
answered Nov 20 '18 at 9:50
KubatorKubator
74911
answered Nov 20 '18 at 9:50
KubatorKubator
74911
74911
Thanks, I appreciate ya' Kubator! (Lol, nice name btw.)
– seemcat
Nov 20 '18 at 20:06
Sure thing. Glad if helped.
– Kubator
Nov 21 '18 at 16:49
add a comment |
Thanks, I appreciate ya' Kubator! (Lol, nice name btw.)
– seemcat
Nov 20 '18 at 20:06
Sure thing. Glad if helped.
– Kubator
Nov 21 '18 at 16:49
Thanks, I appreciate ya' Kubator! (Lol, nice name btw.)
– seemcat
Nov 20 '18 at 20:06
Thanks, I appreciate ya' Kubator! (Lol, nice name btw.)
– seemcat
Nov 20 '18 at 20:06
Sure thing. Glad if helped.
– Kubator
Nov 21 '18 at 16:49
Sure thing. Glad if helped.
– Kubator
Nov 21 '18 at 16:49
add a comment |
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Start with reading about sed, and here's a question that may help you get some ideas: stackoverflow.com/questions/16123102/…
– dcp
Nov 19 '18 at 16:52
1
Since this is a YAML file, I suggest you read in the YAML into whatever language you're using, and then replace the element of the structure that you want to change. Then, write out the new YAML based on your modifications. In general, if you have structured data in a specific format, it's far safer and easier to read it, modify it, and rewrite it, rather than playing around with it as plain text.
– Andy Lester
Nov 19 '18 at 17:04
@dcp I tried applying all of their answers and each of them threw an invalid command code.
– seemcat
Nov 19 '18 at 17:26