Concentration of Gaussian random matrices












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I know that if $X$ be a random matrix distributed as $N(0,I_n)$, then $frac{1}{n}X^TX$ is concentrated around the identity matrix. Does any body know the probability of $P(||frac{1}{n}X^TX-I||<delta)$?










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    A relatively recent paper by Vershynin (arxiv/abs/1004.3484) shows how to answer this question. He's mainly interested in asymptotics, but working through the proof of Proposition 2.1 would give you the result you want.
    $endgroup$
    – cdipaolo
    Nov 27 '18 at 4:05










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    Another approach that would be looser yet would be probably a bit easier to compute is to apply Tropp's matrix concentration inequalities and bound the norm of a Gaussian vector with high probability. See Section 1.6.3 of arxiv/abs/1501.01571 for this.
    $endgroup$
    – cdipaolo
    Nov 27 '18 at 4:18


















1












$begingroup$


I know that if $X$ be a random matrix distributed as $N(0,I_n)$, then $frac{1}{n}X^TX$ is concentrated around the identity matrix. Does any body know the probability of $P(||frac{1}{n}X^TX-I||<delta)$?










share|cite|improve this question









$endgroup$








  • 1




    $begingroup$
    A relatively recent paper by Vershynin (arxiv/abs/1004.3484) shows how to answer this question. He's mainly interested in asymptotics, but working through the proof of Proposition 2.1 would give you the result you want.
    $endgroup$
    – cdipaolo
    Nov 27 '18 at 4:05










  • $begingroup$
    Another approach that would be looser yet would be probably a bit easier to compute is to apply Tropp's matrix concentration inequalities and bound the norm of a Gaussian vector with high probability. See Section 1.6.3 of arxiv/abs/1501.01571 for this.
    $endgroup$
    – cdipaolo
    Nov 27 '18 at 4:18
















1












1








1


1



$begingroup$


I know that if $X$ be a random matrix distributed as $N(0,I_n)$, then $frac{1}{n}X^TX$ is concentrated around the identity matrix. Does any body know the probability of $P(||frac{1}{n}X^TX-I||<delta)$?










share|cite|improve this question









$endgroup$




I know that if $X$ be a random matrix distributed as $N(0,I_n)$, then $frac{1}{n}X^TX$ is concentrated around the identity matrix. Does any body know the probability of $P(||frac{1}{n}X^TX-I||<delta)$?







probability-theory normal-distribution concentration-of-measure






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share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Nov 27 '18 at 3:44









S_AlexS_Alex

1409




1409








  • 1




    $begingroup$
    A relatively recent paper by Vershynin (arxiv/abs/1004.3484) shows how to answer this question. He's mainly interested in asymptotics, but working through the proof of Proposition 2.1 would give you the result you want.
    $endgroup$
    – cdipaolo
    Nov 27 '18 at 4:05










  • $begingroup$
    Another approach that would be looser yet would be probably a bit easier to compute is to apply Tropp's matrix concentration inequalities and bound the norm of a Gaussian vector with high probability. See Section 1.6.3 of arxiv/abs/1501.01571 for this.
    $endgroup$
    – cdipaolo
    Nov 27 '18 at 4:18
















  • 1




    $begingroup$
    A relatively recent paper by Vershynin (arxiv/abs/1004.3484) shows how to answer this question. He's mainly interested in asymptotics, but working through the proof of Proposition 2.1 would give you the result you want.
    $endgroup$
    – cdipaolo
    Nov 27 '18 at 4:05










  • $begingroup$
    Another approach that would be looser yet would be probably a bit easier to compute is to apply Tropp's matrix concentration inequalities and bound the norm of a Gaussian vector with high probability. See Section 1.6.3 of arxiv/abs/1501.01571 for this.
    $endgroup$
    – cdipaolo
    Nov 27 '18 at 4:18










1




1




$begingroup$
A relatively recent paper by Vershynin (arxiv/abs/1004.3484) shows how to answer this question. He's mainly interested in asymptotics, but working through the proof of Proposition 2.1 would give you the result you want.
$endgroup$
– cdipaolo
Nov 27 '18 at 4:05




$begingroup$
A relatively recent paper by Vershynin (arxiv/abs/1004.3484) shows how to answer this question. He's mainly interested in asymptotics, but working through the proof of Proposition 2.1 would give you the result you want.
$endgroup$
– cdipaolo
Nov 27 '18 at 4:05












$begingroup$
Another approach that would be looser yet would be probably a bit easier to compute is to apply Tropp's matrix concentration inequalities and bound the norm of a Gaussian vector with high probability. See Section 1.6.3 of arxiv/abs/1501.01571 for this.
$endgroup$
– cdipaolo
Nov 27 '18 at 4:18






$begingroup$
Another approach that would be looser yet would be probably a bit easier to compute is to apply Tropp's matrix concentration inequalities and bound the norm of a Gaussian vector with high probability. See Section 1.6.3 of arxiv/abs/1501.01571 for this.
$endgroup$
– cdipaolo
Nov 27 '18 at 4:18












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