linked list c programming error by inserting new element












-2















I am trying to insert an element but it get the error "Process finished with exit code 11"



struct node {
int key;
struct node *next;
};
struct node* init(){
struct node *head =NULL;
return head;
}
void create(struct node * head,int num) {
struct node * tmp = head;
struct node * prev = NULL;
struct node* new = malloc(sizeof(struct node));
new->key = num;
prev = tmp;
tmp = tmp->next;
while(tmp!= NULL && tmp->key < num){
prev = tmp;
tmp = tmp->next;
}
new->next = tmp;
prev->next = new;
if (tmp== NULL)
head=tmp;
}
int main() {
int num;
struct node* head;
head=init()
printf("Enter data:");
scanf("%d",&num);
create(head,num);
}


i am trying to insert an element into a linked list and the element should be sorted and entered at the same time.can someone tell me that the error is ? i cannot seem to find out the error.










share|improve this question




















  • 2





    Did you try to run your code under debugger? On what line an error appears?

    – Miamy
    Nov 19 '18 at 18:01











  • A node is no list. A list is no node.

    – Swordfish
    Nov 19 '18 at 18:08













  • tmp = tmp->next; i am having the error here

    – George Jose
    Nov 19 '18 at 18:14













  • how can i correct it?

    – George Jose
    Nov 19 '18 at 18:15











  • @GeorgeJose Sorry, but since there is no list in your code, there is no easy fix.

    – Swordfish
    Nov 19 '18 at 19:20
















-2















I am trying to insert an element but it get the error "Process finished with exit code 11"



struct node {
int key;
struct node *next;
};
struct node* init(){
struct node *head =NULL;
return head;
}
void create(struct node * head,int num) {
struct node * tmp = head;
struct node * prev = NULL;
struct node* new = malloc(sizeof(struct node));
new->key = num;
prev = tmp;
tmp = tmp->next;
while(tmp!= NULL && tmp->key < num){
prev = tmp;
tmp = tmp->next;
}
new->next = tmp;
prev->next = new;
if (tmp== NULL)
head=tmp;
}
int main() {
int num;
struct node* head;
head=init()
printf("Enter data:");
scanf("%d",&num);
create(head,num);
}


i am trying to insert an element into a linked list and the element should be sorted and entered at the same time.can someone tell me that the error is ? i cannot seem to find out the error.










share|improve this question




















  • 2





    Did you try to run your code under debugger? On what line an error appears?

    – Miamy
    Nov 19 '18 at 18:01











  • A node is no list. A list is no node.

    – Swordfish
    Nov 19 '18 at 18:08













  • tmp = tmp->next; i am having the error here

    – George Jose
    Nov 19 '18 at 18:14













  • how can i correct it?

    – George Jose
    Nov 19 '18 at 18:15











  • @GeorgeJose Sorry, but since there is no list in your code, there is no easy fix.

    – Swordfish
    Nov 19 '18 at 19:20














-2












-2








-2








I am trying to insert an element but it get the error "Process finished with exit code 11"



struct node {
int key;
struct node *next;
};
struct node* init(){
struct node *head =NULL;
return head;
}
void create(struct node * head,int num) {
struct node * tmp = head;
struct node * prev = NULL;
struct node* new = malloc(sizeof(struct node));
new->key = num;
prev = tmp;
tmp = tmp->next;
while(tmp!= NULL && tmp->key < num){
prev = tmp;
tmp = tmp->next;
}
new->next = tmp;
prev->next = new;
if (tmp== NULL)
head=tmp;
}
int main() {
int num;
struct node* head;
head=init()
printf("Enter data:");
scanf("%d",&num);
create(head,num);
}


i am trying to insert an element into a linked list and the element should be sorted and entered at the same time.can someone tell me that the error is ? i cannot seem to find out the error.










share|improve this question
















I am trying to insert an element but it get the error "Process finished with exit code 11"



struct node {
int key;
struct node *next;
};
struct node* init(){
struct node *head =NULL;
return head;
}
void create(struct node * head,int num) {
struct node * tmp = head;
struct node * prev = NULL;
struct node* new = malloc(sizeof(struct node));
new->key = num;
prev = tmp;
tmp = tmp->next;
while(tmp!= NULL && tmp->key < num){
prev = tmp;
tmp = tmp->next;
}
new->next = tmp;
prev->next = new;
if (tmp== NULL)
head=tmp;
}
int main() {
int num;
struct node* head;
head=init()
printf("Enter data:");
scanf("%d",&num);
create(head,num);
}


i am trying to insert an element into a linked list and the element should be sorted and entered at the same time.can someone tell me that the error is ? i cannot seem to find out the error.







c linked-list






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 19 '18 at 17:52









Broman

6,301112341




6,301112341










asked Nov 19 '18 at 17:48









George JoseGeorge Jose

62




62








  • 2





    Did you try to run your code under debugger? On what line an error appears?

    – Miamy
    Nov 19 '18 at 18:01











  • A node is no list. A list is no node.

    – Swordfish
    Nov 19 '18 at 18:08













  • tmp = tmp->next; i am having the error here

    – George Jose
    Nov 19 '18 at 18:14













  • how can i correct it?

    – George Jose
    Nov 19 '18 at 18:15











  • @GeorgeJose Sorry, but since there is no list in your code, there is no easy fix.

    – Swordfish
    Nov 19 '18 at 19:20














  • 2





    Did you try to run your code under debugger? On what line an error appears?

    – Miamy
    Nov 19 '18 at 18:01











  • A node is no list. A list is no node.

    – Swordfish
    Nov 19 '18 at 18:08













  • tmp = tmp->next; i am having the error here

    – George Jose
    Nov 19 '18 at 18:14













  • how can i correct it?

    – George Jose
    Nov 19 '18 at 18:15











  • @GeorgeJose Sorry, but since there is no list in your code, there is no easy fix.

    – Swordfish
    Nov 19 '18 at 19:20








2




2





Did you try to run your code under debugger? On what line an error appears?

– Miamy
Nov 19 '18 at 18:01





Did you try to run your code under debugger? On what line an error appears?

– Miamy
Nov 19 '18 at 18:01













A node is no list. A list is no node.

– Swordfish
Nov 19 '18 at 18:08







A node is no list. A list is no node.

– Swordfish
Nov 19 '18 at 18:08















tmp = tmp->next; i am having the error here

– George Jose
Nov 19 '18 at 18:14







tmp = tmp->next; i am having the error here

– George Jose
Nov 19 '18 at 18:14















how can i correct it?

– George Jose
Nov 19 '18 at 18:15





how can i correct it?

– George Jose
Nov 19 '18 at 18:15













@GeorgeJose Sorry, but since there is no list in your code, there is no easy fix.

– Swordfish
Nov 19 '18 at 19:20





@GeorgeJose Sorry, but since there is no list in your code, there is no easy fix.

– Swordfish
Nov 19 '18 at 19:20












1 Answer
1






active

oldest

votes


















-1














It's not clear what your function create()




void create(struct node * head, int num) {
struct node * tmp = head;
struct node * prev = NULL;
struct node* new = malloc(sizeof(struct node));
new->key = num;
prev = tmp;
tmp = tmp->next;
while (tmp != NULL && tmp->key < num) {
prev = tmp;
tmp = tmp->next;
}
new->next = tmp;
prev->next = new;
if (tmp == NULL)
head = tmp;
}



is supposed to do. You effectively pass it a NULL pointer and return void, so everything it does is meaningless to the outside world.



Thetm starting point for every no bs linked list implementation:



#include <stdbool.h>
#include <stdlib.h>
#include <stdio.h>

typedef struct node_tag {
int value;
struct node_tag *next;
} node_t;

// write functions to encapsulate the data and provide a stable interface:

node_t* node_create_value(int value)
{
node_t *new_node = calloc(1, sizeof *new_node);
if(new_node) new_node->value = value;
return new_node;
}

node_t* node_advance(node_t const *node) { return node->next; }


typedef struct list_tag { // a list usually consists of
node_t *head; // a pointer to the first and
node_t *tail; // a pointer to the last element
// size_t size; // one might want to add that.
} list_t;

list_t list_create(void)
{
list_t list = { NULL, NULL };
return list;
}

// make code based on these functions "speak" for itself:

node_t* list_begin(list_t const *list) { return list->head; }
node_t* list_end (list_t const *list) { return list->tail; }
bool list_is_empty(list_t const *list) { return !list_begin(list); }

// common operations for lists:

node_t* list_push_front(list_t *list, int value)
{
node_t *new_node = node_create_value(value);
if (!new_node)
return NULL;

new_node->next = list->head;
return list->head = new_node;
}

node_t* list_push_back(list_t *list, int value)
{
// push_back on an empty list is push_front:
if (list_is_empty(list))
return list->tail = list_push_front(list, value);

node_t *new_node = node_create_value(value);
if (!new_node)
return NULL;

list->tail->next = new_node;
return list->tail = new_node;
}

node_t* list_insert_after(list_t *list, node_t *node, int value)
{
if (list_end(list) == node)
return list_push_back(list, value);

node_t *new_node = node_create_value(value);
if (!new_node)
return NULL;

new_node->next = node->next;
return node->next = new_node;
}

node_t* list_insert_sorted(list_t *list, int value)
{
// first handle the special cases that don't require iterating the whole list:

if (list_is_empty(list) || value < list_begin(list)->value)
return list_push_front(list, value);

if (value > list_end(list)->value)
return list_push_back(list, value);

// the general (worst) case:

for (node_t *current_node = list_begin(list); node_advance(current_node); current_node = node_advance(current_node))
if (value < node_advance(current_node)->value)
return list_insert_after(list, current_node, value);

return NULL; // should never happen
}

void list_print(list_t const *list)
{
for (node_t *current_node = list_begin(list); current_node; current_node = node_advance(current_node))
printf("%dn", current_node->value);
}

void list_free(list_t *list)
{
for(node_t *current_node = list_begin(list), *next_node; current_node; current_node = next_node) {
next_node = current_node->next;
free(current_node);
}
}

// user code should not be required to know anything about the inner workings
// of our list:

int main(void)
{
list_t list = list_create();
for (int i = 1; i < 10; i += 2) {
if (!list_push_back(&list, i)) {
list_free(&list);
fputs("Not enough memory :(nn", stderr);
return EXIT_FAILURE;
}
}

list_print(&list);
putchar('n');

for (int i = 0; i < 11; i += 2) {
if (!list_insert_sorted(&list, i)) {
list_free(&list);
fputs("Not enough memory :(nn", stderr);
return EXIT_FAILURE;
}
}

list_print(&list);
list_free(&list);
}


Output:



1
3
5
7
9

0
1
2
3
4
5
6
7
8
9
10





share|improve this answer


























  • This doesn't answer the question in any way, shape, or form.

    – n.m.
    Nov 19 '18 at 19:35











  • @n.m. If that is your opinion downvote away. Plan-B: make suggestions on how to improve it. The code in the question is fubar.

    – Swordfish
    Nov 19 '18 at 19:40








  • 1





    The question seems to be about an error that code posted by OP has. An improvement plan: remove the code from the answer, explain what the error is, how to fix it, and how to avoid it in the future. Do not present an ideal from-the-book answer to the exercise. It is rather unlikely to be helpful to someone who is struggling with basic notions of the language.

    – n.m.
    Nov 19 '18 at 19:53













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1 Answer
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active

oldest

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1 Answer
1






active

oldest

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active

oldest

votes






active

oldest

votes









-1














It's not clear what your function create()




void create(struct node * head, int num) {
struct node * tmp = head;
struct node * prev = NULL;
struct node* new = malloc(sizeof(struct node));
new->key = num;
prev = tmp;
tmp = tmp->next;
while (tmp != NULL && tmp->key < num) {
prev = tmp;
tmp = tmp->next;
}
new->next = tmp;
prev->next = new;
if (tmp == NULL)
head = tmp;
}



is supposed to do. You effectively pass it a NULL pointer and return void, so everything it does is meaningless to the outside world.



Thetm starting point for every no bs linked list implementation:



#include <stdbool.h>
#include <stdlib.h>
#include <stdio.h>

typedef struct node_tag {
int value;
struct node_tag *next;
} node_t;

// write functions to encapsulate the data and provide a stable interface:

node_t* node_create_value(int value)
{
node_t *new_node = calloc(1, sizeof *new_node);
if(new_node) new_node->value = value;
return new_node;
}

node_t* node_advance(node_t const *node) { return node->next; }


typedef struct list_tag { // a list usually consists of
node_t *head; // a pointer to the first and
node_t *tail; // a pointer to the last element
// size_t size; // one might want to add that.
} list_t;

list_t list_create(void)
{
list_t list = { NULL, NULL };
return list;
}

// make code based on these functions "speak" for itself:

node_t* list_begin(list_t const *list) { return list->head; }
node_t* list_end (list_t const *list) { return list->tail; }
bool list_is_empty(list_t const *list) { return !list_begin(list); }

// common operations for lists:

node_t* list_push_front(list_t *list, int value)
{
node_t *new_node = node_create_value(value);
if (!new_node)
return NULL;

new_node->next = list->head;
return list->head = new_node;
}

node_t* list_push_back(list_t *list, int value)
{
// push_back on an empty list is push_front:
if (list_is_empty(list))
return list->tail = list_push_front(list, value);

node_t *new_node = node_create_value(value);
if (!new_node)
return NULL;

list->tail->next = new_node;
return list->tail = new_node;
}

node_t* list_insert_after(list_t *list, node_t *node, int value)
{
if (list_end(list) == node)
return list_push_back(list, value);

node_t *new_node = node_create_value(value);
if (!new_node)
return NULL;

new_node->next = node->next;
return node->next = new_node;
}

node_t* list_insert_sorted(list_t *list, int value)
{
// first handle the special cases that don't require iterating the whole list:

if (list_is_empty(list) || value < list_begin(list)->value)
return list_push_front(list, value);

if (value > list_end(list)->value)
return list_push_back(list, value);

// the general (worst) case:

for (node_t *current_node = list_begin(list); node_advance(current_node); current_node = node_advance(current_node))
if (value < node_advance(current_node)->value)
return list_insert_after(list, current_node, value);

return NULL; // should never happen
}

void list_print(list_t const *list)
{
for (node_t *current_node = list_begin(list); current_node; current_node = node_advance(current_node))
printf("%dn", current_node->value);
}

void list_free(list_t *list)
{
for(node_t *current_node = list_begin(list), *next_node; current_node; current_node = next_node) {
next_node = current_node->next;
free(current_node);
}
}

// user code should not be required to know anything about the inner workings
// of our list:

int main(void)
{
list_t list = list_create();
for (int i = 1; i < 10; i += 2) {
if (!list_push_back(&list, i)) {
list_free(&list);
fputs("Not enough memory :(nn", stderr);
return EXIT_FAILURE;
}
}

list_print(&list);
putchar('n');

for (int i = 0; i < 11; i += 2) {
if (!list_insert_sorted(&list, i)) {
list_free(&list);
fputs("Not enough memory :(nn", stderr);
return EXIT_FAILURE;
}
}

list_print(&list);
list_free(&list);
}


Output:



1
3
5
7
9

0
1
2
3
4
5
6
7
8
9
10





share|improve this answer


























  • This doesn't answer the question in any way, shape, or form.

    – n.m.
    Nov 19 '18 at 19:35











  • @n.m. If that is your opinion downvote away. Plan-B: make suggestions on how to improve it. The code in the question is fubar.

    – Swordfish
    Nov 19 '18 at 19:40








  • 1





    The question seems to be about an error that code posted by OP has. An improvement plan: remove the code from the answer, explain what the error is, how to fix it, and how to avoid it in the future. Do not present an ideal from-the-book answer to the exercise. It is rather unlikely to be helpful to someone who is struggling with basic notions of the language.

    – n.m.
    Nov 19 '18 at 19:53


















-1














It's not clear what your function create()




void create(struct node * head, int num) {
struct node * tmp = head;
struct node * prev = NULL;
struct node* new = malloc(sizeof(struct node));
new->key = num;
prev = tmp;
tmp = tmp->next;
while (tmp != NULL && tmp->key < num) {
prev = tmp;
tmp = tmp->next;
}
new->next = tmp;
prev->next = new;
if (tmp == NULL)
head = tmp;
}



is supposed to do. You effectively pass it a NULL pointer and return void, so everything it does is meaningless to the outside world.



Thetm starting point for every no bs linked list implementation:



#include <stdbool.h>
#include <stdlib.h>
#include <stdio.h>

typedef struct node_tag {
int value;
struct node_tag *next;
} node_t;

// write functions to encapsulate the data and provide a stable interface:

node_t* node_create_value(int value)
{
node_t *new_node = calloc(1, sizeof *new_node);
if(new_node) new_node->value = value;
return new_node;
}

node_t* node_advance(node_t const *node) { return node->next; }


typedef struct list_tag { // a list usually consists of
node_t *head; // a pointer to the first and
node_t *tail; // a pointer to the last element
// size_t size; // one might want to add that.
} list_t;

list_t list_create(void)
{
list_t list = { NULL, NULL };
return list;
}

// make code based on these functions "speak" for itself:

node_t* list_begin(list_t const *list) { return list->head; }
node_t* list_end (list_t const *list) { return list->tail; }
bool list_is_empty(list_t const *list) { return !list_begin(list); }

// common operations for lists:

node_t* list_push_front(list_t *list, int value)
{
node_t *new_node = node_create_value(value);
if (!new_node)
return NULL;

new_node->next = list->head;
return list->head = new_node;
}

node_t* list_push_back(list_t *list, int value)
{
// push_back on an empty list is push_front:
if (list_is_empty(list))
return list->tail = list_push_front(list, value);

node_t *new_node = node_create_value(value);
if (!new_node)
return NULL;

list->tail->next = new_node;
return list->tail = new_node;
}

node_t* list_insert_after(list_t *list, node_t *node, int value)
{
if (list_end(list) == node)
return list_push_back(list, value);

node_t *new_node = node_create_value(value);
if (!new_node)
return NULL;

new_node->next = node->next;
return node->next = new_node;
}

node_t* list_insert_sorted(list_t *list, int value)
{
// first handle the special cases that don't require iterating the whole list:

if (list_is_empty(list) || value < list_begin(list)->value)
return list_push_front(list, value);

if (value > list_end(list)->value)
return list_push_back(list, value);

// the general (worst) case:

for (node_t *current_node = list_begin(list); node_advance(current_node); current_node = node_advance(current_node))
if (value < node_advance(current_node)->value)
return list_insert_after(list, current_node, value);

return NULL; // should never happen
}

void list_print(list_t const *list)
{
for (node_t *current_node = list_begin(list); current_node; current_node = node_advance(current_node))
printf("%dn", current_node->value);
}

void list_free(list_t *list)
{
for(node_t *current_node = list_begin(list), *next_node; current_node; current_node = next_node) {
next_node = current_node->next;
free(current_node);
}
}

// user code should not be required to know anything about the inner workings
// of our list:

int main(void)
{
list_t list = list_create();
for (int i = 1; i < 10; i += 2) {
if (!list_push_back(&list, i)) {
list_free(&list);
fputs("Not enough memory :(nn", stderr);
return EXIT_FAILURE;
}
}

list_print(&list);
putchar('n');

for (int i = 0; i < 11; i += 2) {
if (!list_insert_sorted(&list, i)) {
list_free(&list);
fputs("Not enough memory :(nn", stderr);
return EXIT_FAILURE;
}
}

list_print(&list);
list_free(&list);
}


Output:



1
3
5
7
9

0
1
2
3
4
5
6
7
8
9
10





share|improve this answer


























  • This doesn't answer the question in any way, shape, or form.

    – n.m.
    Nov 19 '18 at 19:35











  • @n.m. If that is your opinion downvote away. Plan-B: make suggestions on how to improve it. The code in the question is fubar.

    – Swordfish
    Nov 19 '18 at 19:40








  • 1





    The question seems to be about an error that code posted by OP has. An improvement plan: remove the code from the answer, explain what the error is, how to fix it, and how to avoid it in the future. Do not present an ideal from-the-book answer to the exercise. It is rather unlikely to be helpful to someone who is struggling with basic notions of the language.

    – n.m.
    Nov 19 '18 at 19:53
















-1












-1








-1







It's not clear what your function create()




void create(struct node * head, int num) {
struct node * tmp = head;
struct node * prev = NULL;
struct node* new = malloc(sizeof(struct node));
new->key = num;
prev = tmp;
tmp = tmp->next;
while (tmp != NULL && tmp->key < num) {
prev = tmp;
tmp = tmp->next;
}
new->next = tmp;
prev->next = new;
if (tmp == NULL)
head = tmp;
}



is supposed to do. You effectively pass it a NULL pointer and return void, so everything it does is meaningless to the outside world.



Thetm starting point for every no bs linked list implementation:



#include <stdbool.h>
#include <stdlib.h>
#include <stdio.h>

typedef struct node_tag {
int value;
struct node_tag *next;
} node_t;

// write functions to encapsulate the data and provide a stable interface:

node_t* node_create_value(int value)
{
node_t *new_node = calloc(1, sizeof *new_node);
if(new_node) new_node->value = value;
return new_node;
}

node_t* node_advance(node_t const *node) { return node->next; }


typedef struct list_tag { // a list usually consists of
node_t *head; // a pointer to the first and
node_t *tail; // a pointer to the last element
// size_t size; // one might want to add that.
} list_t;

list_t list_create(void)
{
list_t list = { NULL, NULL };
return list;
}

// make code based on these functions "speak" for itself:

node_t* list_begin(list_t const *list) { return list->head; }
node_t* list_end (list_t const *list) { return list->tail; }
bool list_is_empty(list_t const *list) { return !list_begin(list); }

// common operations for lists:

node_t* list_push_front(list_t *list, int value)
{
node_t *new_node = node_create_value(value);
if (!new_node)
return NULL;

new_node->next = list->head;
return list->head = new_node;
}

node_t* list_push_back(list_t *list, int value)
{
// push_back on an empty list is push_front:
if (list_is_empty(list))
return list->tail = list_push_front(list, value);

node_t *new_node = node_create_value(value);
if (!new_node)
return NULL;

list->tail->next = new_node;
return list->tail = new_node;
}

node_t* list_insert_after(list_t *list, node_t *node, int value)
{
if (list_end(list) == node)
return list_push_back(list, value);

node_t *new_node = node_create_value(value);
if (!new_node)
return NULL;

new_node->next = node->next;
return node->next = new_node;
}

node_t* list_insert_sorted(list_t *list, int value)
{
// first handle the special cases that don't require iterating the whole list:

if (list_is_empty(list) || value < list_begin(list)->value)
return list_push_front(list, value);

if (value > list_end(list)->value)
return list_push_back(list, value);

// the general (worst) case:

for (node_t *current_node = list_begin(list); node_advance(current_node); current_node = node_advance(current_node))
if (value < node_advance(current_node)->value)
return list_insert_after(list, current_node, value);

return NULL; // should never happen
}

void list_print(list_t const *list)
{
for (node_t *current_node = list_begin(list); current_node; current_node = node_advance(current_node))
printf("%dn", current_node->value);
}

void list_free(list_t *list)
{
for(node_t *current_node = list_begin(list), *next_node; current_node; current_node = next_node) {
next_node = current_node->next;
free(current_node);
}
}

// user code should not be required to know anything about the inner workings
// of our list:

int main(void)
{
list_t list = list_create();
for (int i = 1; i < 10; i += 2) {
if (!list_push_back(&list, i)) {
list_free(&list);
fputs("Not enough memory :(nn", stderr);
return EXIT_FAILURE;
}
}

list_print(&list);
putchar('n');

for (int i = 0; i < 11; i += 2) {
if (!list_insert_sorted(&list, i)) {
list_free(&list);
fputs("Not enough memory :(nn", stderr);
return EXIT_FAILURE;
}
}

list_print(&list);
list_free(&list);
}


Output:



1
3
5
7
9

0
1
2
3
4
5
6
7
8
9
10





share|improve this answer















It's not clear what your function create()




void create(struct node * head, int num) {
struct node * tmp = head;
struct node * prev = NULL;
struct node* new = malloc(sizeof(struct node));
new->key = num;
prev = tmp;
tmp = tmp->next;
while (tmp != NULL && tmp->key < num) {
prev = tmp;
tmp = tmp->next;
}
new->next = tmp;
prev->next = new;
if (tmp == NULL)
head = tmp;
}



is supposed to do. You effectively pass it a NULL pointer and return void, so everything it does is meaningless to the outside world.



Thetm starting point for every no bs linked list implementation:



#include <stdbool.h>
#include <stdlib.h>
#include <stdio.h>

typedef struct node_tag {
int value;
struct node_tag *next;
} node_t;

// write functions to encapsulate the data and provide a stable interface:

node_t* node_create_value(int value)
{
node_t *new_node = calloc(1, sizeof *new_node);
if(new_node) new_node->value = value;
return new_node;
}

node_t* node_advance(node_t const *node) { return node->next; }


typedef struct list_tag { // a list usually consists of
node_t *head; // a pointer to the first and
node_t *tail; // a pointer to the last element
// size_t size; // one might want to add that.
} list_t;

list_t list_create(void)
{
list_t list = { NULL, NULL };
return list;
}

// make code based on these functions "speak" for itself:

node_t* list_begin(list_t const *list) { return list->head; }
node_t* list_end (list_t const *list) { return list->tail; }
bool list_is_empty(list_t const *list) { return !list_begin(list); }

// common operations for lists:

node_t* list_push_front(list_t *list, int value)
{
node_t *new_node = node_create_value(value);
if (!new_node)
return NULL;

new_node->next = list->head;
return list->head = new_node;
}

node_t* list_push_back(list_t *list, int value)
{
// push_back on an empty list is push_front:
if (list_is_empty(list))
return list->tail = list_push_front(list, value);

node_t *new_node = node_create_value(value);
if (!new_node)
return NULL;

list->tail->next = new_node;
return list->tail = new_node;
}

node_t* list_insert_after(list_t *list, node_t *node, int value)
{
if (list_end(list) == node)
return list_push_back(list, value);

node_t *new_node = node_create_value(value);
if (!new_node)
return NULL;

new_node->next = node->next;
return node->next = new_node;
}

node_t* list_insert_sorted(list_t *list, int value)
{
// first handle the special cases that don't require iterating the whole list:

if (list_is_empty(list) || value < list_begin(list)->value)
return list_push_front(list, value);

if (value > list_end(list)->value)
return list_push_back(list, value);

// the general (worst) case:

for (node_t *current_node = list_begin(list); node_advance(current_node); current_node = node_advance(current_node))
if (value < node_advance(current_node)->value)
return list_insert_after(list, current_node, value);

return NULL; // should never happen
}

void list_print(list_t const *list)
{
for (node_t *current_node = list_begin(list); current_node; current_node = node_advance(current_node))
printf("%dn", current_node->value);
}

void list_free(list_t *list)
{
for(node_t *current_node = list_begin(list), *next_node; current_node; current_node = next_node) {
next_node = current_node->next;
free(current_node);
}
}

// user code should not be required to know anything about the inner workings
// of our list:

int main(void)
{
list_t list = list_create();
for (int i = 1; i < 10; i += 2) {
if (!list_push_back(&list, i)) {
list_free(&list);
fputs("Not enough memory :(nn", stderr);
return EXIT_FAILURE;
}
}

list_print(&list);
putchar('n');

for (int i = 0; i < 11; i += 2) {
if (!list_insert_sorted(&list, i)) {
list_free(&list);
fputs("Not enough memory :(nn", stderr);
return EXIT_FAILURE;
}
}

list_print(&list);
list_free(&list);
}


Output:



1
3
5
7
9

0
1
2
3
4
5
6
7
8
9
10






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 19 '18 at 20:10

























answered Nov 19 '18 at 18:20









SwordfishSwordfish

9,38811436




9,38811436













  • This doesn't answer the question in any way, shape, or form.

    – n.m.
    Nov 19 '18 at 19:35











  • @n.m. If that is your opinion downvote away. Plan-B: make suggestions on how to improve it. The code in the question is fubar.

    – Swordfish
    Nov 19 '18 at 19:40








  • 1





    The question seems to be about an error that code posted by OP has. An improvement plan: remove the code from the answer, explain what the error is, how to fix it, and how to avoid it in the future. Do not present an ideal from-the-book answer to the exercise. It is rather unlikely to be helpful to someone who is struggling with basic notions of the language.

    – n.m.
    Nov 19 '18 at 19:53





















  • This doesn't answer the question in any way, shape, or form.

    – n.m.
    Nov 19 '18 at 19:35











  • @n.m. If that is your opinion downvote away. Plan-B: make suggestions on how to improve it. The code in the question is fubar.

    – Swordfish
    Nov 19 '18 at 19:40








  • 1





    The question seems to be about an error that code posted by OP has. An improvement plan: remove the code from the answer, explain what the error is, how to fix it, and how to avoid it in the future. Do not present an ideal from-the-book answer to the exercise. It is rather unlikely to be helpful to someone who is struggling with basic notions of the language.

    – n.m.
    Nov 19 '18 at 19:53



















This doesn't answer the question in any way, shape, or form.

– n.m.
Nov 19 '18 at 19:35





This doesn't answer the question in any way, shape, or form.

– n.m.
Nov 19 '18 at 19:35













@n.m. If that is your opinion downvote away. Plan-B: make suggestions on how to improve it. The code in the question is fubar.

– Swordfish
Nov 19 '18 at 19:40







@n.m. If that is your opinion downvote away. Plan-B: make suggestions on how to improve it. The code in the question is fubar.

– Swordfish
Nov 19 '18 at 19:40






1




1





The question seems to be about an error that code posted by OP has. An improvement plan: remove the code from the answer, explain what the error is, how to fix it, and how to avoid it in the future. Do not present an ideal from-the-book answer to the exercise. It is rather unlikely to be helpful to someone who is struggling with basic notions of the language.

– n.m.
Nov 19 '18 at 19:53







The question seems to be about an error that code posted by OP has. An improvement plan: remove the code from the answer, explain what the error is, how to fix it, and how to avoid it in the future. Do not present an ideal from-the-book answer to the exercise. It is rather unlikely to be helpful to someone who is struggling with basic notions of the language.

– n.m.
Nov 19 '18 at 19:53




















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