Extracting the date from a .txt file












0















I have a .txt file. It contains a few dates. The one I'm looking is preceded by words: "Date: dd.MM.yy Hour: HH:mm". I tried to match it by



 matches=re.findall(r'Date:sdd.dd.d{4}sHour:sdd:dd', text)


but I need to extract only numbers in specific format- "dd.MM.yy HH:mm". The file contains also a few other dates- I don't see another way to match it tha. Now I'm obviously getting "Date: 28.10.2018 Hour: 11:00".



1) Is there a better way to search in the .txt file?



2) How to extract both date and hour from the string, omitting words?










share|improve this question




















  • 1





    Please tag this question with regex for more relevant visibility

    – sean
    Nov 19 '18 at 19:46






  • 1





    Some examples of the input might help.

    – usr2564301
    Nov 19 '18 at 20:45






  • 1





    Please add the string and the expected output from it so that we can answer better.

    – Ashok KS
    Nov 20 '18 at 1:47
















0















I have a .txt file. It contains a few dates. The one I'm looking is preceded by words: "Date: dd.MM.yy Hour: HH:mm". I tried to match it by



 matches=re.findall(r'Date:sdd.dd.d{4}sHour:sdd:dd', text)


but I need to extract only numbers in specific format- "dd.MM.yy HH:mm". The file contains also a few other dates- I don't see another way to match it tha. Now I'm obviously getting "Date: 28.10.2018 Hour: 11:00".



1) Is there a better way to search in the .txt file?



2) How to extract both date and hour from the string, omitting words?










share|improve this question




















  • 1





    Please tag this question with regex for more relevant visibility

    – sean
    Nov 19 '18 at 19:46






  • 1





    Some examples of the input might help.

    – usr2564301
    Nov 19 '18 at 20:45






  • 1





    Please add the string and the expected output from it so that we can answer better.

    – Ashok KS
    Nov 20 '18 at 1:47














0












0








0








I have a .txt file. It contains a few dates. The one I'm looking is preceded by words: "Date: dd.MM.yy Hour: HH:mm". I tried to match it by



 matches=re.findall(r'Date:sdd.dd.d{4}sHour:sdd:dd', text)


but I need to extract only numbers in specific format- "dd.MM.yy HH:mm". The file contains also a few other dates- I don't see another way to match it tha. Now I'm obviously getting "Date: 28.10.2018 Hour: 11:00".



1) Is there a better way to search in the .txt file?



2) How to extract both date and hour from the string, omitting words?










share|improve this question
















I have a .txt file. It contains a few dates. The one I'm looking is preceded by words: "Date: dd.MM.yy Hour: HH:mm". I tried to match it by



 matches=re.findall(r'Date:sdd.dd.d{4}sHour:sdd:dd', text)


but I need to extract only numbers in specific format- "dd.MM.yy HH:mm". The file contains also a few other dates- I don't see another way to match it tha. Now I'm obviously getting "Date: 28.10.2018 Hour: 11:00".



1) Is there a better way to search in the .txt file?



2) How to extract both date and hour from the string, omitting words?







python regex python-3.7






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 19 '18 at 20:26









Jonah Bishop

8,88733157




8,88733157










asked Nov 19 '18 at 19:44









cptbombcptbomb

31




31








  • 1





    Please tag this question with regex for more relevant visibility

    – sean
    Nov 19 '18 at 19:46






  • 1





    Some examples of the input might help.

    – usr2564301
    Nov 19 '18 at 20:45






  • 1





    Please add the string and the expected output from it so that we can answer better.

    – Ashok KS
    Nov 20 '18 at 1:47














  • 1





    Please tag this question with regex for more relevant visibility

    – sean
    Nov 19 '18 at 19:46






  • 1





    Some examples of the input might help.

    – usr2564301
    Nov 19 '18 at 20:45






  • 1





    Please add the string and the expected output from it so that we can answer better.

    – Ashok KS
    Nov 20 '18 at 1:47








1




1





Please tag this question with regex for more relevant visibility

– sean
Nov 19 '18 at 19:46





Please tag this question with regex for more relevant visibility

– sean
Nov 19 '18 at 19:46




1




1





Some examples of the input might help.

– usr2564301
Nov 19 '18 at 20:45





Some examples of the input might help.

– usr2564301
Nov 19 '18 at 20:45




1




1





Please add the string and the expected output from it so that we can answer better.

– Ashok KS
Nov 20 '18 at 1:47





Please add the string and the expected output from it so that we can answer better.

– Ashok KS
Nov 20 '18 at 1:47












1 Answer
1






active

oldest

votes


















0














You should use capture groups to get the information you're interested in:



import re
s = "Date: 11.19.2018 Hour: 15:23"
matches = re.findall(r'Date: (d{2}.d{2}.d{4}) Hour: (d{2}:d{2})', s)


The variable matches will then contain:



[('11.19.2018', '15:23')]





share|improve this answer
























  • if you use a group for each number you can get directly the individual numbers to build properly a Date, e.g. r'Date: (d{2}).(d{2}).(d{4}) Hour: (d{2}):(d{2})'

    – Luis Colorado
    Nov 22 '18 at 6:02











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














You should use capture groups to get the information you're interested in:



import re
s = "Date: 11.19.2018 Hour: 15:23"
matches = re.findall(r'Date: (d{2}.d{2}.d{4}) Hour: (d{2}:d{2})', s)


The variable matches will then contain:



[('11.19.2018', '15:23')]





share|improve this answer
























  • if you use a group for each number you can get directly the individual numbers to build properly a Date, e.g. r'Date: (d{2}).(d{2}).(d{4}) Hour: (d{2}):(d{2})'

    – Luis Colorado
    Nov 22 '18 at 6:02
















0














You should use capture groups to get the information you're interested in:



import re
s = "Date: 11.19.2018 Hour: 15:23"
matches = re.findall(r'Date: (d{2}.d{2}.d{4}) Hour: (d{2}:d{2})', s)


The variable matches will then contain:



[('11.19.2018', '15:23')]





share|improve this answer
























  • if you use a group for each number you can get directly the individual numbers to build properly a Date, e.g. r'Date: (d{2}).(d{2}).(d{4}) Hour: (d{2}):(d{2})'

    – Luis Colorado
    Nov 22 '18 at 6:02














0












0








0







You should use capture groups to get the information you're interested in:



import re
s = "Date: 11.19.2018 Hour: 15:23"
matches = re.findall(r'Date: (d{2}.d{2}.d{4}) Hour: (d{2}:d{2})', s)


The variable matches will then contain:



[('11.19.2018', '15:23')]





share|improve this answer













You should use capture groups to get the information you're interested in:



import re
s = "Date: 11.19.2018 Hour: 15:23"
matches = re.findall(r'Date: (d{2}.d{2}.d{4}) Hour: (d{2}:d{2})', s)


The variable matches will then contain:



[('11.19.2018', '15:23')]






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 19 '18 at 20:23









Jonah BishopJonah Bishop

8,88733157




8,88733157













  • if you use a group for each number you can get directly the individual numbers to build properly a Date, e.g. r'Date: (d{2}).(d{2}).(d{4}) Hour: (d{2}):(d{2})'

    – Luis Colorado
    Nov 22 '18 at 6:02



















  • if you use a group for each number you can get directly the individual numbers to build properly a Date, e.g. r'Date: (d{2}).(d{2}).(d{4}) Hour: (d{2}):(d{2})'

    – Luis Colorado
    Nov 22 '18 at 6:02

















if you use a group for each number you can get directly the individual numbers to build properly a Date, e.g. r'Date: (d{2}).(d{2}).(d{4}) Hour: (d{2}):(d{2})'

– Luis Colorado
Nov 22 '18 at 6:02





if you use a group for each number you can get directly the individual numbers to build properly a Date, e.g. r'Date: (d{2}).(d{2}).(d{4}) Hour: (d{2}):(d{2})'

– Luis Colorado
Nov 22 '18 at 6:02


















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