Correct way to execute multiple reactive operations












0














I get from a reactive repository a Mono<FooBar> based on it's value I have to create two other objects save them using reactive repositories, modify FooBar object and save it as well.



As I'm new to reactive programming I landed with the following solution, which is working, but I'm not sure if I'm using correctly the reactive API:



@Test
void createAndSave() {
Mono<FooBar> fooBarMono = findFooBar() // returns Mono<FooBar>
.map(fooBar -> {
createAndSaveLoremBar(fooBar).subscribe(); // returns Mono<LoremBar>
createAndSaveDoloremBar(fooBar).subscribe(); // returns Mono<DoloremBar>

fooBar.setActive(true);

return saveFooBar(fooBar); // returns Mono<FooBar>
}).flatMap(Function.identity());

StepVerifier.create(fooBarMono)
.expectNextMatches(Objects::nonNull)
.expectComplete()
.verify();

}


from console log:



   saved lorem bar
saved dolorem bar
saved foo bar









share|improve this question






















  • Is it required to save lorem bar and dolorem bar before activating fooBar? And what about errors on lorem and dolorem saving? Should we ignore or propagate errors?
    – Alexander Pankin
    Nov 16 '18 at 23:09












  • @AlexanderPankin the order of saving doesn't matter; errors should be propagated if possible
    – A5300
    Nov 17 '18 at 11:59


















0














I get from a reactive repository a Mono<FooBar> based on it's value I have to create two other objects save them using reactive repositories, modify FooBar object and save it as well.



As I'm new to reactive programming I landed with the following solution, which is working, but I'm not sure if I'm using correctly the reactive API:



@Test
void createAndSave() {
Mono<FooBar> fooBarMono = findFooBar() // returns Mono<FooBar>
.map(fooBar -> {
createAndSaveLoremBar(fooBar).subscribe(); // returns Mono<LoremBar>
createAndSaveDoloremBar(fooBar).subscribe(); // returns Mono<DoloremBar>

fooBar.setActive(true);

return saveFooBar(fooBar); // returns Mono<FooBar>
}).flatMap(Function.identity());

StepVerifier.create(fooBarMono)
.expectNextMatches(Objects::nonNull)
.expectComplete()
.verify();

}


from console log:



   saved lorem bar
saved dolorem bar
saved foo bar









share|improve this question






















  • Is it required to save lorem bar and dolorem bar before activating fooBar? And what about errors on lorem and dolorem saving? Should we ignore or propagate errors?
    – Alexander Pankin
    Nov 16 '18 at 23:09












  • @AlexanderPankin the order of saving doesn't matter; errors should be propagated if possible
    – A5300
    Nov 17 '18 at 11:59
















0












0








0







I get from a reactive repository a Mono<FooBar> based on it's value I have to create two other objects save them using reactive repositories, modify FooBar object and save it as well.



As I'm new to reactive programming I landed with the following solution, which is working, but I'm not sure if I'm using correctly the reactive API:



@Test
void createAndSave() {
Mono<FooBar> fooBarMono = findFooBar() // returns Mono<FooBar>
.map(fooBar -> {
createAndSaveLoremBar(fooBar).subscribe(); // returns Mono<LoremBar>
createAndSaveDoloremBar(fooBar).subscribe(); // returns Mono<DoloremBar>

fooBar.setActive(true);

return saveFooBar(fooBar); // returns Mono<FooBar>
}).flatMap(Function.identity());

StepVerifier.create(fooBarMono)
.expectNextMatches(Objects::nonNull)
.expectComplete()
.verify();

}


from console log:



   saved lorem bar
saved dolorem bar
saved foo bar









share|improve this question













I get from a reactive repository a Mono<FooBar> based on it's value I have to create two other objects save them using reactive repositories, modify FooBar object and save it as well.



As I'm new to reactive programming I landed with the following solution, which is working, but I'm not sure if I'm using correctly the reactive API:



@Test
void createAndSave() {
Mono<FooBar> fooBarMono = findFooBar() // returns Mono<FooBar>
.map(fooBar -> {
createAndSaveLoremBar(fooBar).subscribe(); // returns Mono<LoremBar>
createAndSaveDoloremBar(fooBar).subscribe(); // returns Mono<DoloremBar>

fooBar.setActive(true);

return saveFooBar(fooBar); // returns Mono<FooBar>
}).flatMap(Function.identity());

StepVerifier.create(fooBarMono)
.expectNextMatches(Objects::nonNull)
.expectComplete()
.verify();

}


from console log:



   saved lorem bar
saved dolorem bar
saved foo bar






spring-data-mongodb spring-webflow project-reactor






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 16 '18 at 20:44









A5300

588




588












  • Is it required to save lorem bar and dolorem bar before activating fooBar? And what about errors on lorem and dolorem saving? Should we ignore or propagate errors?
    – Alexander Pankin
    Nov 16 '18 at 23:09












  • @AlexanderPankin the order of saving doesn't matter; errors should be propagated if possible
    – A5300
    Nov 17 '18 at 11:59




















  • Is it required to save lorem bar and dolorem bar before activating fooBar? And what about errors on lorem and dolorem saving? Should we ignore or propagate errors?
    – Alexander Pankin
    Nov 16 '18 at 23:09












  • @AlexanderPankin the order of saving doesn't matter; errors should be propagated if possible
    – A5300
    Nov 17 '18 at 11:59


















Is it required to save lorem bar and dolorem bar before activating fooBar? And what about errors on lorem and dolorem saving? Should we ignore or propagate errors?
– Alexander Pankin
Nov 16 '18 at 23:09






Is it required to save lorem bar and dolorem bar before activating fooBar? And what about errors on lorem and dolorem saving? Should we ignore or propagate errors?
– Alexander Pankin
Nov 16 '18 at 23:09














@AlexanderPankin the order of saving doesn't matter; errors should be propagated if possible
– A5300
Nov 17 '18 at 11:59






@AlexanderPankin the order of saving doesn't matter; errors should be propagated if possible
– A5300
Nov 17 '18 at 11:59














2 Answers
2






active

oldest

votes


















0














At first, mutating objects in the asynchronous (reactive) world is not a good idea.



Anyway, in your solution possible errors on lorem and dolorem saving are ignored. You can improve it like so:



Mono<FooBar> fooBarMono = findFooBar()
.flatMap(fooBar -> Flux.merge(
createAndSaveLoremBar(fooBar),
createAndSaveDoloremBar(fooBar)) // asynchronously saving lorem and dolorem
.then(Mono.fromCallable(() -> { // if there wasn't errors, mutate and save fooBar
fooBar.setActive(true);
return fooBar;
}).flatMap(fooBar1 -> saveFooBar(fooBar1))));


If you could create copy of your fooBar with true active flag, the code could be simpler. For example with lombok.



@Builder(toBuilder = true)
public class FooBar {
...
}

Mono<FooBar> fooBarMono = findFooBar()
.flatMap(fooBar -> Flux.merge(
createAndSaveLoremBar(fooBar),
createAndSaveDoloremBar(fooBar))
.then(saveFooBar(fooBar.toBuilder().active(true).build())));


And if you are not interested in the result of your saveFooBar(...) but only in the completion signal, you could make all three saves asynchronously:



Flux<Object> flux = findFooBar()
.flatMapMany(fooBar -> Flux.merge(
createAndSaveLoremBar(fooBar),
createAndSaveDoloremBar(fooBar),
saveFooBar(fooBar.toBuilder().active(true).build())));


Actually, in the last approach you could collect all three results and you should prefer this approach, but I don't have enough information about your classes and requirements for creating full example.






share|improve this answer





























    0














    I think the bellow solution is a little bit more readable. Anyway Alexander is correct you should never ever modify the input. You see we are borrowing a lot of concept form functional programming. For example you call Function.identity() this is called
    identity functor. Both Fluxand Mono are monads. And there is a concept that is secret for these guys called Referential transparency that imperative update break.



        final Mono<FooBar> fooBarMono1 = findFooBar()
    .zipWhen((fooBar) -> createAndSaveLoremBar(fooBar))
    .map(tuple -> tuple.getT1())
    .zipWhen((fooBar) -> createAndSaveDoloremBar(fooBar))
    .map(tuple -> tuple.getT1())
    .map(fooBar -> new FooBar(true))
    .flatMap(fooBar -> saveFooBar(fooBar));


    Or more concise:



        final Mono<FooBar> fooBarMono1 = findFooBar()
    .zipWhen((fooBar) -> createAndSaveLoremBar(fooBar)
    .then(createAndSaveDoloremBar(fooBar)))
    .map(tuple -> tuple.getT1())
    .map(fooBar -> new FooBar(true))
    .flatMap(fooBar -> saveFooBar(fooBar));





    share|improve this answer





















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      2 Answers
      2






      active

      oldest

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      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      0














      At first, mutating objects in the asynchronous (reactive) world is not a good idea.



      Anyway, in your solution possible errors on lorem and dolorem saving are ignored. You can improve it like so:



      Mono<FooBar> fooBarMono = findFooBar()
      .flatMap(fooBar -> Flux.merge(
      createAndSaveLoremBar(fooBar),
      createAndSaveDoloremBar(fooBar)) // asynchronously saving lorem and dolorem
      .then(Mono.fromCallable(() -> { // if there wasn't errors, mutate and save fooBar
      fooBar.setActive(true);
      return fooBar;
      }).flatMap(fooBar1 -> saveFooBar(fooBar1))));


      If you could create copy of your fooBar with true active flag, the code could be simpler. For example with lombok.



      @Builder(toBuilder = true)
      public class FooBar {
      ...
      }

      Mono<FooBar> fooBarMono = findFooBar()
      .flatMap(fooBar -> Flux.merge(
      createAndSaveLoremBar(fooBar),
      createAndSaveDoloremBar(fooBar))
      .then(saveFooBar(fooBar.toBuilder().active(true).build())));


      And if you are not interested in the result of your saveFooBar(...) but only in the completion signal, you could make all three saves asynchronously:



      Flux<Object> flux = findFooBar()
      .flatMapMany(fooBar -> Flux.merge(
      createAndSaveLoremBar(fooBar),
      createAndSaveDoloremBar(fooBar),
      saveFooBar(fooBar.toBuilder().active(true).build())));


      Actually, in the last approach you could collect all three results and you should prefer this approach, but I don't have enough information about your classes and requirements for creating full example.






      share|improve this answer


























        0














        At first, mutating objects in the asynchronous (reactive) world is not a good idea.



        Anyway, in your solution possible errors on lorem and dolorem saving are ignored. You can improve it like so:



        Mono<FooBar> fooBarMono = findFooBar()
        .flatMap(fooBar -> Flux.merge(
        createAndSaveLoremBar(fooBar),
        createAndSaveDoloremBar(fooBar)) // asynchronously saving lorem and dolorem
        .then(Mono.fromCallable(() -> { // if there wasn't errors, mutate and save fooBar
        fooBar.setActive(true);
        return fooBar;
        }).flatMap(fooBar1 -> saveFooBar(fooBar1))));


        If you could create copy of your fooBar with true active flag, the code could be simpler. For example with lombok.



        @Builder(toBuilder = true)
        public class FooBar {
        ...
        }

        Mono<FooBar> fooBarMono = findFooBar()
        .flatMap(fooBar -> Flux.merge(
        createAndSaveLoremBar(fooBar),
        createAndSaveDoloremBar(fooBar))
        .then(saveFooBar(fooBar.toBuilder().active(true).build())));


        And if you are not interested in the result of your saveFooBar(...) but only in the completion signal, you could make all three saves asynchronously:



        Flux<Object> flux = findFooBar()
        .flatMapMany(fooBar -> Flux.merge(
        createAndSaveLoremBar(fooBar),
        createAndSaveDoloremBar(fooBar),
        saveFooBar(fooBar.toBuilder().active(true).build())));


        Actually, in the last approach you could collect all three results and you should prefer this approach, but I don't have enough information about your classes and requirements for creating full example.






        share|improve this answer
























          0












          0








          0






          At first, mutating objects in the asynchronous (reactive) world is not a good idea.



          Anyway, in your solution possible errors on lorem and dolorem saving are ignored. You can improve it like so:



          Mono<FooBar> fooBarMono = findFooBar()
          .flatMap(fooBar -> Flux.merge(
          createAndSaveLoremBar(fooBar),
          createAndSaveDoloremBar(fooBar)) // asynchronously saving lorem and dolorem
          .then(Mono.fromCallable(() -> { // if there wasn't errors, mutate and save fooBar
          fooBar.setActive(true);
          return fooBar;
          }).flatMap(fooBar1 -> saveFooBar(fooBar1))));


          If you could create copy of your fooBar with true active flag, the code could be simpler. For example with lombok.



          @Builder(toBuilder = true)
          public class FooBar {
          ...
          }

          Mono<FooBar> fooBarMono = findFooBar()
          .flatMap(fooBar -> Flux.merge(
          createAndSaveLoremBar(fooBar),
          createAndSaveDoloremBar(fooBar))
          .then(saveFooBar(fooBar.toBuilder().active(true).build())));


          And if you are not interested in the result of your saveFooBar(...) but only in the completion signal, you could make all three saves asynchronously:



          Flux<Object> flux = findFooBar()
          .flatMapMany(fooBar -> Flux.merge(
          createAndSaveLoremBar(fooBar),
          createAndSaveDoloremBar(fooBar),
          saveFooBar(fooBar.toBuilder().active(true).build())));


          Actually, in the last approach you could collect all three results and you should prefer this approach, but I don't have enough information about your classes and requirements for creating full example.






          share|improve this answer












          At first, mutating objects in the asynchronous (reactive) world is not a good idea.



          Anyway, in your solution possible errors on lorem and dolorem saving are ignored. You can improve it like so:



          Mono<FooBar> fooBarMono = findFooBar()
          .flatMap(fooBar -> Flux.merge(
          createAndSaveLoremBar(fooBar),
          createAndSaveDoloremBar(fooBar)) // asynchronously saving lorem and dolorem
          .then(Mono.fromCallable(() -> { // if there wasn't errors, mutate and save fooBar
          fooBar.setActive(true);
          return fooBar;
          }).flatMap(fooBar1 -> saveFooBar(fooBar1))));


          If you could create copy of your fooBar with true active flag, the code could be simpler. For example with lombok.



          @Builder(toBuilder = true)
          public class FooBar {
          ...
          }

          Mono<FooBar> fooBarMono = findFooBar()
          .flatMap(fooBar -> Flux.merge(
          createAndSaveLoremBar(fooBar),
          createAndSaveDoloremBar(fooBar))
          .then(saveFooBar(fooBar.toBuilder().active(true).build())));


          And if you are not interested in the result of your saveFooBar(...) but only in the completion signal, you could make all three saves asynchronously:



          Flux<Object> flux = findFooBar()
          .flatMapMany(fooBar -> Flux.merge(
          createAndSaveLoremBar(fooBar),
          createAndSaveDoloremBar(fooBar),
          saveFooBar(fooBar.toBuilder().active(true).build())));


          Actually, in the last approach you could collect all three results and you should prefer this approach, but I don't have enough information about your classes and requirements for creating full example.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 17 '18 at 16:32









          Alexander Pankin

          63126




          63126

























              0














              I think the bellow solution is a little bit more readable. Anyway Alexander is correct you should never ever modify the input. You see we are borrowing a lot of concept form functional programming. For example you call Function.identity() this is called
              identity functor. Both Fluxand Mono are monads. And there is a concept that is secret for these guys called Referential transparency that imperative update break.



                  final Mono<FooBar> fooBarMono1 = findFooBar()
              .zipWhen((fooBar) -> createAndSaveLoremBar(fooBar))
              .map(tuple -> tuple.getT1())
              .zipWhen((fooBar) -> createAndSaveDoloremBar(fooBar))
              .map(tuple -> tuple.getT1())
              .map(fooBar -> new FooBar(true))
              .flatMap(fooBar -> saveFooBar(fooBar));


              Or more concise:



                  final Mono<FooBar> fooBarMono1 = findFooBar()
              .zipWhen((fooBar) -> createAndSaveLoremBar(fooBar)
              .then(createAndSaveDoloremBar(fooBar)))
              .map(tuple -> tuple.getT1())
              .map(fooBar -> new FooBar(true))
              .flatMap(fooBar -> saveFooBar(fooBar));





              share|improve this answer


























                0














                I think the bellow solution is a little bit more readable. Anyway Alexander is correct you should never ever modify the input. You see we are borrowing a lot of concept form functional programming. For example you call Function.identity() this is called
                identity functor. Both Fluxand Mono are monads. And there is a concept that is secret for these guys called Referential transparency that imperative update break.



                    final Mono<FooBar> fooBarMono1 = findFooBar()
                .zipWhen((fooBar) -> createAndSaveLoremBar(fooBar))
                .map(tuple -> tuple.getT1())
                .zipWhen((fooBar) -> createAndSaveDoloremBar(fooBar))
                .map(tuple -> tuple.getT1())
                .map(fooBar -> new FooBar(true))
                .flatMap(fooBar -> saveFooBar(fooBar));


                Or more concise:



                    final Mono<FooBar> fooBarMono1 = findFooBar()
                .zipWhen((fooBar) -> createAndSaveLoremBar(fooBar)
                .then(createAndSaveDoloremBar(fooBar)))
                .map(tuple -> tuple.getT1())
                .map(fooBar -> new FooBar(true))
                .flatMap(fooBar -> saveFooBar(fooBar));





                share|improve this answer
























                  0












                  0








                  0






                  I think the bellow solution is a little bit more readable. Anyway Alexander is correct you should never ever modify the input. You see we are borrowing a lot of concept form functional programming. For example you call Function.identity() this is called
                  identity functor. Both Fluxand Mono are monads. And there is a concept that is secret for these guys called Referential transparency that imperative update break.



                      final Mono<FooBar> fooBarMono1 = findFooBar()
                  .zipWhen((fooBar) -> createAndSaveLoremBar(fooBar))
                  .map(tuple -> tuple.getT1())
                  .zipWhen((fooBar) -> createAndSaveDoloremBar(fooBar))
                  .map(tuple -> tuple.getT1())
                  .map(fooBar -> new FooBar(true))
                  .flatMap(fooBar -> saveFooBar(fooBar));


                  Or more concise:



                      final Mono<FooBar> fooBarMono1 = findFooBar()
                  .zipWhen((fooBar) -> createAndSaveLoremBar(fooBar)
                  .then(createAndSaveDoloremBar(fooBar)))
                  .map(tuple -> tuple.getT1())
                  .map(fooBar -> new FooBar(true))
                  .flatMap(fooBar -> saveFooBar(fooBar));





                  share|improve this answer












                  I think the bellow solution is a little bit more readable. Anyway Alexander is correct you should never ever modify the input. You see we are borrowing a lot of concept form functional programming. For example you call Function.identity() this is called
                  identity functor. Both Fluxand Mono are monads. And there is a concept that is secret for these guys called Referential transparency that imperative update break.



                      final Mono<FooBar> fooBarMono1 = findFooBar()
                  .zipWhen((fooBar) -> createAndSaveLoremBar(fooBar))
                  .map(tuple -> tuple.getT1())
                  .zipWhen((fooBar) -> createAndSaveDoloremBar(fooBar))
                  .map(tuple -> tuple.getT1())
                  .map(fooBar -> new FooBar(true))
                  .flatMap(fooBar -> saveFooBar(fooBar));


                  Or more concise:



                      final Mono<FooBar> fooBarMono1 = findFooBar()
                  .zipWhen((fooBar) -> createAndSaveLoremBar(fooBar)
                  .then(createAndSaveDoloremBar(fooBar)))
                  .map(tuple -> tuple.getT1())
                  .map(fooBar -> new FooBar(true))
                  .flatMap(fooBar -> saveFooBar(fooBar));






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 25 '18 at 22:24









                  piotr szybicki

                  511210




                  511210






























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