Which font produces 1 and l that look similar in math mode?
up vote
1
down vote
favorite
I am looking for a font that produces number 1 and letter l that look similar (with naked eyes) in math mode. Is there such font?
documentclass[preview,border=12pt,varwidth]{standalone}
usepackage{amsmath}
begin{document}
[
f(x)=
begin{cases}
frac{x^2+2kx+l}{x+1} & x<-1\
x^2+2 & xgeq -1
end{cases}
]
Find $k$ such that $f(x)$ is continuous at $x=-1$.
end{document}
If I can make the letter l look similar to number 1 then there will be many students get trapped. :-)
fonts
|
show 1 more comment
up vote
1
down vote
favorite
I am looking for a font that produces number 1 and letter l that look similar (with naked eyes) in math mode. Is there such font?
documentclass[preview,border=12pt,varwidth]{standalone}
usepackage{amsmath}
begin{document}
[
f(x)=
begin{cases}
frac{x^2+2kx+l}{x+1} & x<-1\
x^2+2 & xgeq -1
end{cases}
]
Find $k$ such that $f(x)$ is continuous at $x=-1$.
end{document}
If I can make the letter l look similar to number 1 then there will be many students get trapped. :-)
fonts
1
Except for the blind
– AndréC
Nov 18 at 9:04
3
Your joke makes my day :))
– Dũng Vũ
Nov 18 at 9:07
3
Why would you want to trap students?
– egreg
Nov 18 at 10:47
@egreg: I want to train them to work more carefully, especially after get graduated and work in the real life. :-)
– Artificial Stupidity
Nov 18 at 10:51
3
I agree that much of what many students learn is useless in working life, but this is just adding to the list of useless stuff.
– alephzero
Nov 18 at 11:23
|
show 1 more comment
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I am looking for a font that produces number 1 and letter l that look similar (with naked eyes) in math mode. Is there such font?
documentclass[preview,border=12pt,varwidth]{standalone}
usepackage{amsmath}
begin{document}
[
f(x)=
begin{cases}
frac{x^2+2kx+l}{x+1} & x<-1\
x^2+2 & xgeq -1
end{cases}
]
Find $k$ such that $f(x)$ is continuous at $x=-1$.
end{document}
If I can make the letter l look similar to number 1 then there will be many students get trapped. :-)
fonts
I am looking for a font that produces number 1 and letter l that look similar (with naked eyes) in math mode. Is there such font?
documentclass[preview,border=12pt,varwidth]{standalone}
usepackage{amsmath}
begin{document}
[
f(x)=
begin{cases}
frac{x^2+2kx+l}{x+1} & x<-1\
x^2+2 & xgeq -1
end{cases}
]
Find $k$ such that $f(x)$ is continuous at $x=-1$.
end{document}
If I can make the letter l look similar to number 1 then there will be many students get trapped. :-)
fonts
fonts
asked Nov 18 at 9:02
Artificial Stupidity
4,6641832
4,6641832
1
Except for the blind
– AndréC
Nov 18 at 9:04
3
Your joke makes my day :))
– Dũng Vũ
Nov 18 at 9:07
3
Why would you want to trap students?
– egreg
Nov 18 at 10:47
@egreg: I want to train them to work more carefully, especially after get graduated and work in the real life. :-)
– Artificial Stupidity
Nov 18 at 10:51
3
I agree that much of what many students learn is useless in working life, but this is just adding to the list of useless stuff.
– alephzero
Nov 18 at 11:23
|
show 1 more comment
1
Except for the blind
– AndréC
Nov 18 at 9:04
3
Your joke makes my day :))
– Dũng Vũ
Nov 18 at 9:07
3
Why would you want to trap students?
– egreg
Nov 18 at 10:47
@egreg: I want to train them to work more carefully, especially after get graduated and work in the real life. :-)
– Artificial Stupidity
Nov 18 at 10:51
3
I agree that much of what many students learn is useless in working life, but this is just adding to the list of useless stuff.
– alephzero
Nov 18 at 11:23
1
1
Except for the blind
– AndréC
Nov 18 at 9:04
Except for the blind
– AndréC
Nov 18 at 9:04
3
3
Your joke makes my day :))
– Dũng Vũ
Nov 18 at 9:07
Your joke makes my day :))
– Dũng Vũ
Nov 18 at 9:07
3
3
Why would you want to trap students?
– egreg
Nov 18 at 10:47
Why would you want to trap students?
– egreg
Nov 18 at 10:47
@egreg: I want to train them to work more carefully, especially after get graduated and work in the real life. :-)
– Artificial Stupidity
Nov 18 at 10:51
@egreg: I want to train them to work more carefully, especially after get graduated and work in the real life. :-)
– Artificial Stupidity
Nov 18 at 10:51
3
3
I agree that much of what many students learn is useless in working life, but this is just adding to the list of useless stuff.
– alephzero
Nov 18 at 11:23
I agree that much of what many students learn is useless in working life, but this is just adding to the list of useless stuff.
– alephzero
Nov 18 at 11:23
|
show 1 more comment
1 Answer
1
active
oldest
votes
up vote
1
down vote
accepted
I am still waiting for other better answer. Here is my own solution.
documentclass[preview,border=12pt,varwidth]{standalone}
usepackage{amsmath}
begin{document}
[
f(x)=
begin{cases}
frac{x^2+2kx+mathrm{l}}{x+1} & x<-1\
x^2+2 & xgeq -1
end{cases}
]
Find $k$ such that $f(x)$ is continuous at $x=-1$.
end{document}
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
I am still waiting for other better answer. Here is my own solution.
documentclass[preview,border=12pt,varwidth]{standalone}
usepackage{amsmath}
begin{document}
[
f(x)=
begin{cases}
frac{x^2+2kx+mathrm{l}}{x+1} & x<-1\
x^2+2 & xgeq -1
end{cases}
]
Find $k$ such that $f(x)$ is continuous at $x=-1$.
end{document}
add a comment |
up vote
1
down vote
accepted
I am still waiting for other better answer. Here is my own solution.
documentclass[preview,border=12pt,varwidth]{standalone}
usepackage{amsmath}
begin{document}
[
f(x)=
begin{cases}
frac{x^2+2kx+mathrm{l}}{x+1} & x<-1\
x^2+2 & xgeq -1
end{cases}
]
Find $k$ such that $f(x)$ is continuous at $x=-1$.
end{document}
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
I am still waiting for other better answer. Here is my own solution.
documentclass[preview,border=12pt,varwidth]{standalone}
usepackage{amsmath}
begin{document}
[
f(x)=
begin{cases}
frac{x^2+2kx+mathrm{l}}{x+1} & x<-1\
x^2+2 & xgeq -1
end{cases}
]
Find $k$ such that $f(x)$ is continuous at $x=-1$.
end{document}
I am still waiting for other better answer. Here is my own solution.
documentclass[preview,border=12pt,varwidth]{standalone}
usepackage{amsmath}
begin{document}
[
f(x)=
begin{cases}
frac{x^2+2kx+mathrm{l}}{x+1} & x<-1\
x^2+2 & xgeq -1
end{cases}
]
Find $k$ such that $f(x)$ is continuous at $x=-1$.
end{document}
answered Nov 18 at 12:34
Artificial Stupidity
4,6641832
4,6641832
add a comment |
add a comment |
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1
Except for the blind
– AndréC
Nov 18 at 9:04
3
Your joke makes my day :))
– Dũng Vũ
Nov 18 at 9:07
3
Why would you want to trap students?
– egreg
Nov 18 at 10:47
@egreg: I want to train them to work more carefully, especially after get graduated and work in the real life. :-)
– Artificial Stupidity
Nov 18 at 10:51
3
I agree that much of what many students learn is useless in working life, but this is just adding to the list of useless stuff.
– alephzero
Nov 18 at 11:23