Does L'Hopital's Rule extend to $x rightarrow infty$ and $L= infty?$











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The following is given:



Suppose that $f$ and $g$ are continuous functions on the interval $(a,b)$ and that $$lim_{x rightarrow b} frac{f(x)}{g(x)} = frac{0}{0}.$$ If $g(x),g'(x) neq 0$ for all $x in (a,b)$ and $$lim_{x rightarrow b} frac{f'(x)}{g'(x)} = L.$$ Then $$lim_{x rightarrow b} frac{f(x)}{g(x)} = L.$$ It is also given that if $x rightarrow infty$ (rather than $x rightarrow b$), the property holds.



Does the property hold if $x rightarrow infty$ and $L = infty?$










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  • 1




    It's best to not write things like $$lim_{x rightarrow b} frac{f(x)}{g(x)} = frac{0}{0}.$$ (Also, you want $xto b^-.$)
    – zhw.
    Nov 13 at 18:57












  • Well, the version where $L=infty$ is true and very crucial in some circumstances.
    – Paramanand Singh
    Nov 13 at 19:02










  • How would you write it?
    – Rafael Vergnaud
    Nov 13 at 19:17










  • Just write $lim_{xto b-} f(x) = 0$ and $lim_{xto b-} g(x)=0$.
    – Richard Martin
    Nov 14 at 9:06















up vote
0
down vote

favorite
1












The following is given:



Suppose that $f$ and $g$ are continuous functions on the interval $(a,b)$ and that $$lim_{x rightarrow b} frac{f(x)}{g(x)} = frac{0}{0}.$$ If $g(x),g'(x) neq 0$ for all $x in (a,b)$ and $$lim_{x rightarrow b} frac{f'(x)}{g'(x)} = L.$$ Then $$lim_{x rightarrow b} frac{f(x)}{g(x)} = L.$$ It is also given that if $x rightarrow infty$ (rather than $x rightarrow b$), the property holds.



Does the property hold if $x rightarrow infty$ and $L = infty?$










share|cite|improve this question


















  • 1




    It's best to not write things like $$lim_{x rightarrow b} frac{f(x)}{g(x)} = frac{0}{0}.$$ (Also, you want $xto b^-.$)
    – zhw.
    Nov 13 at 18:57












  • Well, the version where $L=infty$ is true and very crucial in some circumstances.
    – Paramanand Singh
    Nov 13 at 19:02










  • How would you write it?
    – Rafael Vergnaud
    Nov 13 at 19:17










  • Just write $lim_{xto b-} f(x) = 0$ and $lim_{xto b-} g(x)=0$.
    – Richard Martin
    Nov 14 at 9:06













up vote
0
down vote

favorite
1









up vote
0
down vote

favorite
1






1





The following is given:



Suppose that $f$ and $g$ are continuous functions on the interval $(a,b)$ and that $$lim_{x rightarrow b} frac{f(x)}{g(x)} = frac{0}{0}.$$ If $g(x),g'(x) neq 0$ for all $x in (a,b)$ and $$lim_{x rightarrow b} frac{f'(x)}{g'(x)} = L.$$ Then $$lim_{x rightarrow b} frac{f(x)}{g(x)} = L.$$ It is also given that if $x rightarrow infty$ (rather than $x rightarrow b$), the property holds.



Does the property hold if $x rightarrow infty$ and $L = infty?$










share|cite|improve this question













The following is given:



Suppose that $f$ and $g$ are continuous functions on the interval $(a,b)$ and that $$lim_{x rightarrow b} frac{f(x)}{g(x)} = frac{0}{0}.$$ If $g(x),g'(x) neq 0$ for all $x in (a,b)$ and $$lim_{x rightarrow b} frac{f'(x)}{g'(x)} = L.$$ Then $$lim_{x rightarrow b} frac{f(x)}{g(x)} = L.$$ It is also given that if $x rightarrow infty$ (rather than $x rightarrow b$), the property holds.



Does the property hold if $x rightarrow infty$ and $L = infty?$







calculus real-analysis limits






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asked Nov 13 at 18:46









Rafael Vergnaud

296116




296116








  • 1




    It's best to not write things like $$lim_{x rightarrow b} frac{f(x)}{g(x)} = frac{0}{0}.$$ (Also, you want $xto b^-.$)
    – zhw.
    Nov 13 at 18:57












  • Well, the version where $L=infty$ is true and very crucial in some circumstances.
    – Paramanand Singh
    Nov 13 at 19:02










  • How would you write it?
    – Rafael Vergnaud
    Nov 13 at 19:17










  • Just write $lim_{xto b-} f(x) = 0$ and $lim_{xto b-} g(x)=0$.
    – Richard Martin
    Nov 14 at 9:06














  • 1




    It's best to not write things like $$lim_{x rightarrow b} frac{f(x)}{g(x)} = frac{0}{0}.$$ (Also, you want $xto b^-.$)
    – zhw.
    Nov 13 at 18:57












  • Well, the version where $L=infty$ is true and very crucial in some circumstances.
    – Paramanand Singh
    Nov 13 at 19:02










  • How would you write it?
    – Rafael Vergnaud
    Nov 13 at 19:17










  • Just write $lim_{xto b-} f(x) = 0$ and $lim_{xto b-} g(x)=0$.
    – Richard Martin
    Nov 14 at 9:06








1




1




It's best to not write things like $$lim_{x rightarrow b} frac{f(x)}{g(x)} = frac{0}{0}.$$ (Also, you want $xto b^-.$)
– zhw.
Nov 13 at 18:57






It's best to not write things like $$lim_{x rightarrow b} frac{f(x)}{g(x)} = frac{0}{0}.$$ (Also, you want $xto b^-.$)
– zhw.
Nov 13 at 18:57














Well, the version where $L=infty$ is true and very crucial in some circumstances.
– Paramanand Singh
Nov 13 at 19:02




Well, the version where $L=infty$ is true and very crucial in some circumstances.
– Paramanand Singh
Nov 13 at 19:02












How would you write it?
– Rafael Vergnaud
Nov 13 at 19:17




How would you write it?
– Rafael Vergnaud
Nov 13 at 19:17












Just write $lim_{xto b-} f(x) = 0$ and $lim_{xto b-} g(x)=0$.
– Richard Martin
Nov 14 at 9:06




Just write $lim_{xto b-} f(x) = 0$ and $lim_{xto b-} g(x)=0$.
– Richard Martin
Nov 14 at 9:06










1 Answer
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Yes, change variable $xmapsto 1/x$ and look around $0$.






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  • That was my proof for when the limit approached some finite L. How about when the limit diverges to infinity?
    – Rafael Vergnaud
    Nov 13 at 19:16











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1 Answer
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1 Answer
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up vote
-1
down vote













Yes, change variable $xmapsto 1/x$ and look around $0$.






share|cite|improve this answer





















  • That was my proof for when the limit approached some finite L. How about when the limit diverges to infinity?
    – Rafael Vergnaud
    Nov 13 at 19:16















up vote
-1
down vote













Yes, change variable $xmapsto 1/x$ and look around $0$.






share|cite|improve this answer





















  • That was my proof for when the limit approached some finite L. How about when the limit diverges to infinity?
    – Rafael Vergnaud
    Nov 13 at 19:16













up vote
-1
down vote










up vote
-1
down vote









Yes, change variable $xmapsto 1/x$ and look around $0$.






share|cite|improve this answer












Yes, change variable $xmapsto 1/x$ and look around $0$.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Nov 13 at 18:49









Richard Martin

1,4618




1,4618












  • That was my proof for when the limit approached some finite L. How about when the limit diverges to infinity?
    – Rafael Vergnaud
    Nov 13 at 19:16


















  • That was my proof for when the limit approached some finite L. How about when the limit diverges to infinity?
    – Rafael Vergnaud
    Nov 13 at 19:16
















That was my proof for when the limit approached some finite L. How about when the limit diverges to infinity?
– Rafael Vergnaud
Nov 13 at 19:16




That was my proof for when the limit approached some finite L. How about when the limit diverges to infinity?
– Rafael Vergnaud
Nov 13 at 19:16


















 

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