Let us have 10 balls in a urn, probability that all the balls in the urn are white if…











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Let us have a urn with 10 balls, the balls are either white or black ( we don't know in which proportions ).We extract 4 balls without reintroducing them back and after each extraction the ball is white, meaning that the 4 balls extracted were all white.I need to find the probability that the urn contains only white balls.



My solution ( but I'm not so sure it's correct ):



we have a white balls and 10-a black balls



I started off by naming the events:



B = " urn contains only white balls "



A(i) = " white ball appears i times in n extractions"
for our case n=4 and i=4



and I was thought I should use bayes to find my probability:



$$ P(B/A_4)=frac{P(B)*P(A_4/B)}{P(A_4)} $$



$P(B/A_4) $- the probability of all the balls in the urn being white when we know that in 4 extractions all the balls were white



$P(A_4/B) $- probability that in 4 extractions the balls will be white knowing that the urn contains only white balls ( which is equal to 1)



$P(A_4) $-the probability that we will have 4 white balls in 4 extractions



$P(B)$-the probability of all the balls being white



And then started my calculus (at least tried):



For $P(B)$ I thought that if we extracted 1 ball from the urn the probability of it being white would be $frac{a}{10}$ so that for 10 balls it will be $frac{a}{10}^{10}$ (and here is my question should I have used the hypergeometric distribution here? I mean to calculate the probability that in 10 extractions (we don't introduce them back) all the balls will be white:$frac{{{a}choose{10}}*{{10-achoose{0}}}}{10choose{10}} $ I not sure what should I do here and I would appreciate some help.



For$ P(A_4)$ I used the hypergeometric distribution $ frac{{{a}choose{4}}*{{10-achoose{0}}}}{10choose{4}} $



I would really appreciate some help with this problem and don't hold back on criticism if you see I did some mistakes (I'm new to probabilities) and thank you in advance.










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  • Fate filled the urn with a random mechanism creating probabilites $p_k$ $,(0leq kleq 10)$ of obtaining exactly $k$ white balls in the urn. Since we don't know anything about the $p_k$ other than $p_k=0$ $,(0leq kleq 3)$ your question cannot be answered.
    – Christian Blatter
    Nov 13 at 19:11












  • Tell that to my teacher...
    – The Virtuoso
    Nov 13 at 19:50















up vote
0
down vote

favorite












Let us have a urn with 10 balls, the balls are either white or black ( we don't know in which proportions ).We extract 4 balls without reintroducing them back and after each extraction the ball is white, meaning that the 4 balls extracted were all white.I need to find the probability that the urn contains only white balls.



My solution ( but I'm not so sure it's correct ):



we have a white balls and 10-a black balls



I started off by naming the events:



B = " urn contains only white balls "



A(i) = " white ball appears i times in n extractions"
for our case n=4 and i=4



and I was thought I should use bayes to find my probability:



$$ P(B/A_4)=frac{P(B)*P(A_4/B)}{P(A_4)} $$



$P(B/A_4) $- the probability of all the balls in the urn being white when we know that in 4 extractions all the balls were white



$P(A_4/B) $- probability that in 4 extractions the balls will be white knowing that the urn contains only white balls ( which is equal to 1)



$P(A_4) $-the probability that we will have 4 white balls in 4 extractions



$P(B)$-the probability of all the balls being white



And then started my calculus (at least tried):



For $P(B)$ I thought that if we extracted 1 ball from the urn the probability of it being white would be $frac{a}{10}$ so that for 10 balls it will be $frac{a}{10}^{10}$ (and here is my question should I have used the hypergeometric distribution here? I mean to calculate the probability that in 10 extractions (we don't introduce them back) all the balls will be white:$frac{{{a}choose{10}}*{{10-achoose{0}}}}{10choose{10}} $ I not sure what should I do here and I would appreciate some help.



For$ P(A_4)$ I used the hypergeometric distribution $ frac{{{a}choose{4}}*{{10-achoose{0}}}}{10choose{4}} $



I would really appreciate some help with this problem and don't hold back on criticism if you see I did some mistakes (I'm new to probabilities) and thank you in advance.










share|cite|improve this question






















  • Fate filled the urn with a random mechanism creating probabilites $p_k$ $,(0leq kleq 10)$ of obtaining exactly $k$ white balls in the urn. Since we don't know anything about the $p_k$ other than $p_k=0$ $,(0leq kleq 3)$ your question cannot be answered.
    – Christian Blatter
    Nov 13 at 19:11












  • Tell that to my teacher...
    – The Virtuoso
    Nov 13 at 19:50













up vote
0
down vote

favorite









up vote
0
down vote

favorite











Let us have a urn with 10 balls, the balls are either white or black ( we don't know in which proportions ).We extract 4 balls without reintroducing them back and after each extraction the ball is white, meaning that the 4 balls extracted were all white.I need to find the probability that the urn contains only white balls.



My solution ( but I'm not so sure it's correct ):



we have a white balls and 10-a black balls



I started off by naming the events:



B = " urn contains only white balls "



A(i) = " white ball appears i times in n extractions"
for our case n=4 and i=4



and I was thought I should use bayes to find my probability:



$$ P(B/A_4)=frac{P(B)*P(A_4/B)}{P(A_4)} $$



$P(B/A_4) $- the probability of all the balls in the urn being white when we know that in 4 extractions all the balls were white



$P(A_4/B) $- probability that in 4 extractions the balls will be white knowing that the urn contains only white balls ( which is equal to 1)



$P(A_4) $-the probability that we will have 4 white balls in 4 extractions



$P(B)$-the probability of all the balls being white



And then started my calculus (at least tried):



For $P(B)$ I thought that if we extracted 1 ball from the urn the probability of it being white would be $frac{a}{10}$ so that for 10 balls it will be $frac{a}{10}^{10}$ (and here is my question should I have used the hypergeometric distribution here? I mean to calculate the probability that in 10 extractions (we don't introduce them back) all the balls will be white:$frac{{{a}choose{10}}*{{10-achoose{0}}}}{10choose{10}} $ I not sure what should I do here and I would appreciate some help.



For$ P(A_4)$ I used the hypergeometric distribution $ frac{{{a}choose{4}}*{{10-achoose{0}}}}{10choose{4}} $



I would really appreciate some help with this problem and don't hold back on criticism if you see I did some mistakes (I'm new to probabilities) and thank you in advance.










share|cite|improve this question













Let us have a urn with 10 balls, the balls are either white or black ( we don't know in which proportions ).We extract 4 balls without reintroducing them back and after each extraction the ball is white, meaning that the 4 balls extracted were all white.I need to find the probability that the urn contains only white balls.



My solution ( but I'm not so sure it's correct ):



we have a white balls and 10-a black balls



I started off by naming the events:



B = " urn contains only white balls "



A(i) = " white ball appears i times in n extractions"
for our case n=4 and i=4



and I was thought I should use bayes to find my probability:



$$ P(B/A_4)=frac{P(B)*P(A_4/B)}{P(A_4)} $$



$P(B/A_4) $- the probability of all the balls in the urn being white when we know that in 4 extractions all the balls were white



$P(A_4/B) $- probability that in 4 extractions the balls will be white knowing that the urn contains only white balls ( which is equal to 1)



$P(A_4) $-the probability that we will have 4 white balls in 4 extractions



$P(B)$-the probability of all the balls being white



And then started my calculus (at least tried):



For $P(B)$ I thought that if we extracted 1 ball from the urn the probability of it being white would be $frac{a}{10}$ so that for 10 balls it will be $frac{a}{10}^{10}$ (and here is my question should I have used the hypergeometric distribution here? I mean to calculate the probability that in 10 extractions (we don't introduce them back) all the balls will be white:$frac{{{a}choose{10}}*{{10-achoose{0}}}}{10choose{10}} $ I not sure what should I do here and I would appreciate some help.



For$ P(A_4)$ I used the hypergeometric distribution $ frac{{{a}choose{4}}*{{10-achoose{0}}}}{10choose{4}} $



I would really appreciate some help with this problem and don't hold back on criticism if you see I did some mistakes (I'm new to probabilities) and thank you in advance.







probability probability-distributions conditional-probability






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asked Nov 13 at 18:17









The Virtuoso

407




407












  • Fate filled the urn with a random mechanism creating probabilites $p_k$ $,(0leq kleq 10)$ of obtaining exactly $k$ white balls in the urn. Since we don't know anything about the $p_k$ other than $p_k=0$ $,(0leq kleq 3)$ your question cannot be answered.
    – Christian Blatter
    Nov 13 at 19:11












  • Tell that to my teacher...
    – The Virtuoso
    Nov 13 at 19:50


















  • Fate filled the urn with a random mechanism creating probabilites $p_k$ $,(0leq kleq 10)$ of obtaining exactly $k$ white balls in the urn. Since we don't know anything about the $p_k$ other than $p_k=0$ $,(0leq kleq 3)$ your question cannot be answered.
    – Christian Blatter
    Nov 13 at 19:11












  • Tell that to my teacher...
    – The Virtuoso
    Nov 13 at 19:50
















Fate filled the urn with a random mechanism creating probabilites $p_k$ $,(0leq kleq 10)$ of obtaining exactly $k$ white balls in the urn. Since we don't know anything about the $p_k$ other than $p_k=0$ $,(0leq kleq 3)$ your question cannot be answered.
– Christian Blatter
Nov 13 at 19:11






Fate filled the urn with a random mechanism creating probabilites $p_k$ $,(0leq kleq 10)$ of obtaining exactly $k$ white balls in the urn. Since we don't know anything about the $p_k$ other than $p_k=0$ $,(0leq kleq 3)$ your question cannot be answered.
– Christian Blatter
Nov 13 at 19:11














Tell that to my teacher...
– The Virtuoso
Nov 13 at 19:50




Tell that to my teacher...
– The Virtuoso
Nov 13 at 19:50















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