How to explort content from file into variable? [duplicate]











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  • How do I assign the output of a command to a variable?

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I need save into variable the file content (json string).



I try several methods, in particular:



#!/bin/bash



myjson=cat patch/file.jsn


but nothing not work.



How to correctly implement this task?






bash environment-variables







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marked as duplicate by muru bash
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 Nov 17 at 9:42


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    mjson=`cat patch/file.jsn` (backticks cause the command's output to replace the command)
    – guiverc
    Nov 17 at 9:38

















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0
down vote

favorite













This question already has an answer here:




  • How do I assign the output of a command to a variable?

    1 answer




I need save into variable the file content (json string).



I try several methods, in particular:



#!/bin/bash



myjson=cat patch/file.jsn


but nothing not work.



How to correctly implement this task?






bash environment-variables







share|improve this question













marked as duplicate by muru bash
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  • 1




    mjson=`cat patch/file.jsn` (backticks cause the command's output to replace the command)
    – guiverc
    Nov 17 at 9:38















up vote
0
down vote

favorite









up vote
0
down vote

favorite












This question already has an answer here:




  • How do I assign the output of a command to a variable?

    1 answer




I need save into variable the file content (json string).



I try several methods, in particular:



#!/bin/bash



myjson=cat patch/file.jsn


but nothing not work.



How to correctly implement this task?






bash environment-variables







share|improve this question














This question already has an answer here:




  • How do I assign the output of a command to a variable?

    1 answer




I need save into variable the file content (json string).



I try several methods, in particular:



#!/bin/bash



myjson=cat patch/file.jsn


but nothing not work.



How to correctly implement this task?





This question already has an answer here:




  • How do I assign the output of a command to a variable?

    1 answer







bash environment-variables




bash environment-variables






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 17 at 9:34









Valentyn Hruzytskyi

2009




2009




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 Nov 17 at 9:42


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  • 1




    mjson=`cat patch/file.jsn` (backticks cause the command's output to replace the command)
    – guiverc
    Nov 17 at 9:38
















  • 1




    mjson=`cat patch/file.jsn` (backticks cause the command's output to replace the command)
    – guiverc
    Nov 17 at 9:38










1




1




mjson=`cat patch/file.jsn` (backticks cause the command's output to replace the command)
– guiverc
Nov 17 at 9:38






mjson=`cat patch/file.jsn` (backticks cause the command's output to replace the command)
– guiverc
Nov 17 at 9:38












1 Answer
1






active

oldest

votes

















up vote
1
down vote













You can try this:



#!/bin/bash



myjson=$(cat patch/file.jsn)





share|improve this answer




























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    1
    down vote













    You can try this:



    #!/bin/bash
    

    
myjson=$(cat patch/file.jsn)





    share|improve this answer

























      up vote
      1
      down vote













      You can try this:



      #!/bin/bash
      

      
myjson=$(cat patch/file.jsn)





      share|improve this answer























        up vote
        1
        down vote










        up vote
        1
        down vote









        You can try this:



        #!/bin/bash
        

        
myjson=$(cat patch/file.jsn)





        share|improve this answer












        You can try this:



        #!/bin/bash
        

        
myjson=$(cat patch/file.jsn)






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 17 at 9:39









        kukulo

        1,260417




        1,260417















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