Does Bash imitate Locale-Specific Translation from C?
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Bash manual mentions that
3.1.2.5 Locale-Specific Translation
A double-quoted string preceded by a dollar sign (‘$’) will cause the
string to be translated according to the current locale. If the
current locale is C or POSIX, the dollar sign is ignored. If the
string is translated and replaced, the replacement is double-quoted.
Does this way of specifying a string literal exist in C language or some C library?
Does bash imitate this way from C?
bash string c
asked Nov 19 at 23:09
Ben
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up vote
3
down vote
favorite
Bash manual mentions that
3.1.2.5 Locale-Specific Translation
A double-quoted string preceded by a dollar sign (‘$’) will cause the
string to be translated according to the current locale. If the
current locale is C or POSIX, the dollar sign is ignored. If the
string is translated and replaced, the replacement is double-quoted.
Does this way of specifying a string literal exist in C language or some C library?
Does bash imitate this way from C?
bash string c
asked Nov 19 at 23:09
Ben
2788
New contributor
Ben is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
up vote
3
down vote
favorite
up vote
3
down vote
favorite
Bash manual mentions that
3.1.2.5 Locale-Specific Translation
A double-quoted string preceded by a dollar sign (‘$’) will cause the
string to be translated according to the current locale. If the
current locale is C or POSIX, the dollar sign is ignored. If the
string is translated and replaced, the replacement is double-quoted.
Does this way of specifying a string literal exist in C language or some C library?
Does bash imitate this way from C?
bash string c
asked Nov 19 at 23:09
Ben
2788
New contributor
Ben is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Bash manual mentions that
3.1.2.5 Locale-Specific Translation
A double-quoted string preceded by a dollar sign (‘$’) will cause the
string to be translated according to the current locale. If the
current locale is C or POSIX, the dollar sign is ignored. If the
string is translated and replaced, the replacement is double-quoted.
Does this way of specifying a string literal exist in C language or some C library?
Does bash imitate this way from C?
bash string c
bash string c
asked Nov 19 at 23:09
Ben
2788
New contributor
Ben is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Nov 19 at 23:09
Ben
2788
New contributor
Ben is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Nov 19 at 23:09
Ben
2788
New contributor
Ben is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Nov 19 at 23:09
Ben
2788
asked Nov 19 at 23:09
Ben
2788
2788
New contributor
Ben is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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New contributor
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1 Answer
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$"..." is Bash's way of accessing GNU gettext translations. In C code it would generally be gettext("...") or _("..."). Bash uses the system's default message catalog; a C application could also load up any catalogs it wanted to use.
The $" syntax is a Bash extension to resemble the existing parameter expansion syntax, and I suppose particularly the $' ANSI-C quoting it took from ksh and which may make it into POSIX in future. The C language does not support or have a parallel for the syntax itself.
answered Nov 19 at 23:32
Michael Homer
44.8k7117156
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
8
down vote
accepted
$"..." is Bash's way of accessing GNU gettext translations. In C code it would generally be gettext("...") or _("..."). Bash uses the system's default message catalog; a C application could also load up any catalogs it wanted to use.
The $" syntax is a Bash extension to resemble the existing parameter expansion syntax, and I suppose particularly the $' ANSI-C quoting it took from ksh and which may make it into POSIX in future. The C language does not support or have a parallel for the syntax itself.
answered Nov 19 at 23:32
Michael Homer
44.8k7117156
add a comment |
up vote
8
down vote
accepted
$"..." is Bash's way of accessing GNU gettext translations. In C code it would generally be gettext("...") or _("..."). Bash uses the system's default message catalog; a C application could also load up any catalogs it wanted to use.
The $" syntax is a Bash extension to resemble the existing parameter expansion syntax, and I suppose particularly the $' ANSI-C quoting it took from ksh and which may make it into POSIX in future. The C language does not support or have a parallel for the syntax itself.
answered Nov 19 at 23:32
Michael Homer
44.8k7117156
add a comment |
up vote
8
down vote
accepted
up vote
8
down vote
accepted
$"..." is Bash's way of accessing GNU gettext translations. In C code it would generally be gettext("...") or _("..."). Bash uses the system's default message catalog; a C application could also load up any catalogs it wanted to use.
The $" syntax is a Bash extension to resemble the existing parameter expansion syntax, and I suppose particularly the $' ANSI-C quoting it took from ksh and which may make it into POSIX in future. The C language does not support or have a parallel for the syntax itself.
answered Nov 19 at 23:32
Michael Homer
44.8k7117156
$"..." is Bash's way of accessing GNU gettext translations. In C code it would generally be gettext("...") or _("..."). Bash uses the system's default message catalog; a C application could also load up any catalogs it wanted to use.
The $" syntax is a Bash extension to resemble the existing parameter expansion syntax, and I suppose particularly the $' ANSI-C quoting it took from ksh and which may make it into POSIX in future. The C language does not support or have a parallel for the syntax itself.
answered Nov 19 at 23:32
Michael Homer
44.8k7117156
answered Nov 19 at 23:32
Michael Homer
44.8k7117156
answered Nov 19 at 23:32
Michael Homer
44.8k7117156
answered Nov 19 at 23:32
Michael Homer
44.8k7117156
44.8k7117156
add a comment |
add a comment |
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