Is there a way to predict the difference between two primes based on previous differences












0














If we know the difference between for instance
$5-3=2$ and if we also know the difference between
$7-5=2$, can we then predict the difference between
$X-7=$? Where $X = 11$.



Is there an equation/algorithm that can predict the difference without knowing $X$? Based on sums or something?










share|cite|improve this question
























  • not really but we can prove that say 5 consecutive differences can't all be the same ( unless they are 5 ( impossible in the odd primes)), in any 5 values at least 2 must share their remainders when dividing by 5. this is a straight application of the pigeonhole principle to primes in arithmetic progressions.
    – user451844
    Jul 27 '17 at 16:38










  • If the Twin Prime Conjecture mathworld.wolfram.com/TwinPrimeConjecture.html is false, then we can say there is a number M so that $p_{i+1}-p_i$>2 , where $p_i$ is the $i_th$ prime.
    – gary
    Jul 27 '17 at 16:42












  • For any sequence $a_1,a_2,a_3,cdots$ of which $a_1$ is known, knowing the sequence of differences $a_2-a_1, a_3-a_2, a_4-a_3,cdots$ is exactly the same thing as knowing the sequence itself.
    – user228113
    Jul 27 '17 at 16:46










  • we know all primes greater than 3 are 1 or 5 remainder on division by 6 ...
    – user451844
    Jul 27 '17 at 17:08
















0














If we know the difference between for instance
$5-3=2$ and if we also know the difference between
$7-5=2$, can we then predict the difference between
$X-7=$? Where $X = 11$.



Is there an equation/algorithm that can predict the difference without knowing $X$? Based on sums or something?










share|cite|improve this question
























  • not really but we can prove that say 5 consecutive differences can't all be the same ( unless they are 5 ( impossible in the odd primes)), in any 5 values at least 2 must share their remainders when dividing by 5. this is a straight application of the pigeonhole principle to primes in arithmetic progressions.
    – user451844
    Jul 27 '17 at 16:38










  • If the Twin Prime Conjecture mathworld.wolfram.com/TwinPrimeConjecture.html is false, then we can say there is a number M so that $p_{i+1}-p_i$>2 , where $p_i$ is the $i_th$ prime.
    – gary
    Jul 27 '17 at 16:42












  • For any sequence $a_1,a_2,a_3,cdots$ of which $a_1$ is known, knowing the sequence of differences $a_2-a_1, a_3-a_2, a_4-a_3,cdots$ is exactly the same thing as knowing the sequence itself.
    – user228113
    Jul 27 '17 at 16:46










  • we know all primes greater than 3 are 1 or 5 remainder on division by 6 ...
    – user451844
    Jul 27 '17 at 17:08














0












0








0







If we know the difference between for instance
$5-3=2$ and if we also know the difference between
$7-5=2$, can we then predict the difference between
$X-7=$? Where $X = 11$.



Is there an equation/algorithm that can predict the difference without knowing $X$? Based on sums or something?










share|cite|improve this question















If we know the difference between for instance
$5-3=2$ and if we also know the difference between
$7-5=2$, can we then predict the difference between
$X-7=$? Where $X = 11$.



Is there an equation/algorithm that can predict the difference without knowing $X$? Based on sums or something?







prime-numbers






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Nov 21 '18 at 13:35









Klangen

1,65411334




1,65411334










asked Jul 27 '17 at 16:27









Simon

435




435












  • not really but we can prove that say 5 consecutive differences can't all be the same ( unless they are 5 ( impossible in the odd primes)), in any 5 values at least 2 must share their remainders when dividing by 5. this is a straight application of the pigeonhole principle to primes in arithmetic progressions.
    – user451844
    Jul 27 '17 at 16:38










  • If the Twin Prime Conjecture mathworld.wolfram.com/TwinPrimeConjecture.html is false, then we can say there is a number M so that $p_{i+1}-p_i$>2 , where $p_i$ is the $i_th$ prime.
    – gary
    Jul 27 '17 at 16:42












  • For any sequence $a_1,a_2,a_3,cdots$ of which $a_1$ is known, knowing the sequence of differences $a_2-a_1, a_3-a_2, a_4-a_3,cdots$ is exactly the same thing as knowing the sequence itself.
    – user228113
    Jul 27 '17 at 16:46










  • we know all primes greater than 3 are 1 or 5 remainder on division by 6 ...
    – user451844
    Jul 27 '17 at 17:08


















  • not really but we can prove that say 5 consecutive differences can't all be the same ( unless they are 5 ( impossible in the odd primes)), in any 5 values at least 2 must share their remainders when dividing by 5. this is a straight application of the pigeonhole principle to primes in arithmetic progressions.
    – user451844
    Jul 27 '17 at 16:38










  • If the Twin Prime Conjecture mathworld.wolfram.com/TwinPrimeConjecture.html is false, then we can say there is a number M so that $p_{i+1}-p_i$>2 , where $p_i$ is the $i_th$ prime.
    – gary
    Jul 27 '17 at 16:42












  • For any sequence $a_1,a_2,a_3,cdots$ of which $a_1$ is known, knowing the sequence of differences $a_2-a_1, a_3-a_2, a_4-a_3,cdots$ is exactly the same thing as knowing the sequence itself.
    – user228113
    Jul 27 '17 at 16:46










  • we know all primes greater than 3 are 1 or 5 remainder on division by 6 ...
    – user451844
    Jul 27 '17 at 17:08
















not really but we can prove that say 5 consecutive differences can't all be the same ( unless they are 5 ( impossible in the odd primes)), in any 5 values at least 2 must share their remainders when dividing by 5. this is a straight application of the pigeonhole principle to primes in arithmetic progressions.
– user451844
Jul 27 '17 at 16:38




not really but we can prove that say 5 consecutive differences can't all be the same ( unless they are 5 ( impossible in the odd primes)), in any 5 values at least 2 must share their remainders when dividing by 5. this is a straight application of the pigeonhole principle to primes in arithmetic progressions.
– user451844
Jul 27 '17 at 16:38












If the Twin Prime Conjecture mathworld.wolfram.com/TwinPrimeConjecture.html is false, then we can say there is a number M so that $p_{i+1}-p_i$>2 , where $p_i$ is the $i_th$ prime.
– gary
Jul 27 '17 at 16:42






If the Twin Prime Conjecture mathworld.wolfram.com/TwinPrimeConjecture.html is false, then we can say there is a number M so that $p_{i+1}-p_i$>2 , where $p_i$ is the $i_th$ prime.
– gary
Jul 27 '17 at 16:42














For any sequence $a_1,a_2,a_3,cdots$ of which $a_1$ is known, knowing the sequence of differences $a_2-a_1, a_3-a_2, a_4-a_3,cdots$ is exactly the same thing as knowing the sequence itself.
– user228113
Jul 27 '17 at 16:46




For any sequence $a_1,a_2,a_3,cdots$ of which $a_1$ is known, knowing the sequence of differences $a_2-a_1, a_3-a_2, a_4-a_3,cdots$ is exactly the same thing as knowing the sequence itself.
– user228113
Jul 27 '17 at 16:46












we know all primes greater than 3 are 1 or 5 remainder on division by 6 ...
– user451844
Jul 27 '17 at 17:08




we know all primes greater than 3 are 1 or 5 remainder on division by 6 ...
– user451844
Jul 27 '17 at 17:08










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