Getting the first characters of each string in an array in Javascript

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let animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];



let secretMessage = animals.map(function(animal) {

     for(animal = 0; animal <= animals.length-1; animal++) {

            return animals[animal].charAt(animal);

     }

});



console.log(secretMessage.join(''));

Hi, thru this piece of code i want to output the string HelloWorld, which is formed by the first characters of each string/element in the animals array. However, the output is instead HHHHHHHHHH. I don't know if the for loop is the problem here?

Could someone please tell me why the code produces such an output and how i can modify it in order for the desired result to be returned successfully?

I'm just a novice for now & that's why your help will play a tremendous part in my growth as a programmer. Thanks in advance!

edited Oct 31 '17 at 13:07

Sandeep Sukhija

8311021

asked Oct 31 '17 at 12:43

jack coltrane

1816

Possible duplicate of How to read first character of string inside an array without using string.charAt()?

– shawon191
Oct 31 '17 at 12:49

animals.map(function(s) { return s[0]; }).join("");

– Yogesh Chuahan
Oct 31 '17 at 13:01

add a comment |

let animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];



let secretMessage = animals.map(function(animal) {

     for(animal = 0; animal <= animals.length-1; animal++) {

            return animals[animal].charAt(animal);

     }

});



console.log(secretMessage.join(''));

Could someone please tell me why the code produces such an output and how i can modify it in order for the desired result to be returned successfully?

I'm just a novice for now & that's why your help will play a tremendous part in my growth as a programmer. Thanks in advance!

edited Oct 31 '17 at 13:07

Sandeep Sukhija

8311021

asked Oct 31 '17 at 12:43

jack coltrane

1816

Possible duplicate of How to read first character of string inside an array without using string.charAt()?

– shawon191
Oct 31 '17 at 12:49

animals.map(function(s) { return s[0]; }).join("");

– Yogesh Chuahan
Oct 31 '17 at 13:01

add a comment |

let animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];



let secretMessage = animals.map(function(animal) {

     for(animal = 0; animal <= animals.length-1; animal++) {

            return animals[animal].charAt(animal);

     }

});



console.log(secretMessage.join(''));

Could someone please tell me why the code produces such an output and how i can modify it in order for the desired result to be returned successfully?

I'm just a novice for now & that's why your help will play a tremendous part in my growth as a programmer. Thanks in advance!

edited Oct 31 '17 at 13:07

Sandeep Sukhija

8311021

asked Oct 31 '17 at 12:43

jack coltrane

1816

let animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];



let secretMessage = animals.map(function(animal) {

     for(animal = 0; animal <= animals.length-1; animal++) {

            return animals[animal].charAt(animal);

     }

});



console.log(secretMessage.join(''));

Could someone please tell me why the code produces such an output and how i can modify it in order for the desired result to be returned successfully?

I'm just a novice for now & that's why your help will play a tremendous part in my growth as a programmer. Thanks in advance!

javascript arrays loops

edited Oct 31 '17 at 13:07

Sandeep Sukhija

8311021

asked Oct 31 '17 at 12:43

jack coltrane

1816

edited Oct 31 '17 at 13:07

Sandeep Sukhija

8311021

asked Oct 31 '17 at 12:43

jack coltrane

1816

edited Oct 31 '17 at 13:07

Sandeep Sukhija

8311021

edited Oct 31 '17 at 13:07

Sandeep Sukhija

8311021

edited Oct 31 '17 at 13:07

Sandeep Sukhija

8311021

asked Oct 31 '17 at 12:43

jack coltrane

1816

asked Oct 31 '17 at 12:43

jack coltrane

1816

asked Oct 31 '17 at 12:43

jack coltrane

1816

Possible duplicate of How to read first character of string inside an array without using string.charAt()?

– shawon191
Oct 31 '17 at 12:49

animals.map(function(s) { return s[0]; }).join("");

– Yogesh Chuahan
Oct 31 '17 at 13:01

add a comment |

Possible duplicate of How to read first character of string inside an array without using string.charAt()?

– shawon191
Oct 31 '17 at 12:49

animals.map(function(s) { return s[0]; }).join("");

– Yogesh Chuahan
Oct 31 '17 at 13:01

Possible duplicate of How to read first character of string inside an array without using string.charAt()?

– shawon191
Oct 31 '17 at 12:49

animals.map(function(s) { return s[0]; }).join("");

– Yogesh Chuahan
Oct 31 '17 at 13:01

add a comment |

8 Answers
8

active

oldest

votes

Map is a for loop in and of itself.

Try:

// Animals.

const animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog']

    

// Secret Message.

const secretMessage = animals.map((animal) => animal[0]).join('')

    

// Log.

console.log(secretMessage) // "HelloWorld"

Or alternatively:

// Animals.

const animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog']



// Secret Message.

const secretMessage = animals.reduce((accumulator, animal) => accumulator + animal[0], '')



// Log.

console.log(secretMessage) // "HelloWorld"

edited May 10 '18 at 7:53

answered Oct 31 '17 at 12:47

Arman Charan

3,29821121

add a comment |

The map method does the for loop for you. So all you need in the function is animal[0]

let secretMessage = animals.map(function(animal) {

     return animal[0]

});

This will return every first character in every string in the array, animals. Everything else you have is right.

answered Oct 31 '17 at 14:19

Joseph Carrick

312

add a comment |

You don't need inner loop:

let animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];



let secretMessage = animals.map(function(animal) {

  return animal.charAt(0); // or simply animal[0]

});



console.log(secretMessage.join(''));

answered Oct 31 '17 at 12:46

dfsq

168k21184213

add a comment |

The error here is that you have a loop inside the map function, which already loops the array.

The correct code is

animals.map(x=>x[0]).join('');

//or

animals.map(function(animal){

    return animal[0]; //First letter of word

}).join(''); //Array -> String

answered Oct 31 '17 at 12:46

Luca De Nardi

1,500624

add a comment |

This should be the code:

let animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];



let secretMessage = animals.map(function(animal) {

    return animal.charAt(0);

});



console.log(secretMessage.join(''));

answered Oct 31 '17 at 12:46

Kenji Mukai

60148

add a comment |

Just do this.

let animals = [

  'Hen', 'elephant', 'llama', 

  'leopard', 'ostrich', 'Whale', 

  'octopus', 'rabbit', 'lion', 'dog'

];

console.log(animals.map(e => e[0]).join(""));

edited Oct 31 '17 at 12:52

answered Oct 31 '17 at 12:46

marmeladze

4,39131433

1

For ES5 or less use this: animals.map(function(s) { return s[0]; }).join(""); For ES6: () => { }

– Yogesh Chuahan
Oct 31 '17 at 13:02

add a comment |

let animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];



let secretMessage = animals.map(function(animals) {

return animals[0];

});



console.log(secretMessage.join(''));

let animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];



let secretMessage = animals.map(animals => animals[0]);



console.log(secretMessage.join(''));

answered Mar 30 '18 at 15:08

Kenny Heenatigala

add a comment |

.map() array function take callback function as an argument and return new array so that can use this method to get our result see the syntax below:

const animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];





 const secretMessage = animals.map(animals => {



   return animals[0];

 })



console.log(secretMessage.join(''));

now when .map method is applied on the animals array its return only the first element of the each string because we use animals[0] which read only first element of each string so our output is HelloWorld

edited Nov 23 '18 at 6:13

Ram Ghadiyaram

17.6k84980

answered Nov 23 '18 at 6:07

Mukesh Suthar

add a comment |

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8 Answers
8

active

oldest

votes

8 Answers
8

active

oldest

votes

Map is a for loop in and of itself.

Try:

// Animals.

const animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog']

    

// Secret Message.

const secretMessage = animals.map((animal) => animal[0]).join('')

    

// Log.

console.log(secretMessage) // "HelloWorld"

Or alternatively:

// Animals.

const animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog']



// Secret Message.

const secretMessage = animals.reduce((accumulator, animal) => accumulator + animal[0], '')



// Log.

console.log(secretMessage) // "HelloWorld"

edited May 10 '18 at 7:53

answered Oct 31 '17 at 12:47

Arman Charan

3,29821121

add a comment |

Map is a for loop in and of itself.

Try:

// Animals.

const animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog']

    

// Secret Message.

const secretMessage = animals.map((animal) => animal[0]).join('')

    

// Log.

console.log(secretMessage) // "HelloWorld"

Or alternatively:

// Animals.

const animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog']



// Secret Message.

const secretMessage = animals.reduce((accumulator, animal) => accumulator + animal[0], '')



// Log.

console.log(secretMessage) // "HelloWorld"

edited May 10 '18 at 7:53

answered Oct 31 '17 at 12:47

Arman Charan

3,29821121

add a comment |

Map is a for loop in and of itself.

Try:

// Animals.

const animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog']

    

// Secret Message.

const secretMessage = animals.map((animal) => animal[0]).join('')

    

// Log.

console.log(secretMessage) // "HelloWorld"

Or alternatively:

// Animals.

const animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog']



// Secret Message.

const secretMessage = animals.reduce((accumulator, animal) => accumulator + animal[0], '')



// Log.

console.log(secretMessage) // "HelloWorld"

edited May 10 '18 at 7:53

answered Oct 31 '17 at 12:47

Arman Charan

3,29821121

Map is a for loop in and of itself.

Try:

// Animals.

const animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog']

    

// Secret Message.

const secretMessage = animals.map((animal) => animal[0]).join('')

    

// Log.

console.log(secretMessage) // "HelloWorld"

Or alternatively:

// Animals.

const animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog']



// Secret Message.

const secretMessage = animals.reduce((accumulator, animal) => accumulator + animal[0], '')



// Log.

console.log(secretMessage) // "HelloWorld"

// Animals.

const animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog']

    

// Secret Message.

const secretMessage = animals.map((animal) => animal[0]).join('')

    

// Log.

console.log(secretMessage) // "HelloWorld"

// Animals.

const animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog']

    

// Secret Message.

const secretMessage = animals.map((animal) => animal[0]).join('')

    

// Log.

console.log(secretMessage) // "HelloWorld"

// Animals.

const animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog']



// Secret Message.

const secretMessage = animals.reduce((accumulator, animal) => accumulator + animal[0], '')



// Log.

console.log(secretMessage) // "HelloWorld"

// Animals.

const animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog']



// Secret Message.

const secretMessage = animals.reduce((accumulator, animal) => accumulator + animal[0], '')



// Log.

console.log(secretMessage) // "HelloWorld"

edited May 10 '18 at 7:53

answered Oct 31 '17 at 12:47

Arman Charan

3,29821121

edited May 10 '18 at 7:53

answered Oct 31 '17 at 12:47

Arman Charan

3,29821121

answered Oct 31 '17 at 12:47

Arman Charan

3,29821121

answered Oct 31 '17 at 12:47

Arman Charan

3,29821121

add a comment |

The map method does the for loop for you. So all you need in the function is animal[0]

let secretMessage = animals.map(function(animal) {

     return animal[0]

});

This will return every first character in every string in the array, animals. Everything else you have is right.

answered Oct 31 '17 at 14:19

Joseph Carrick

312

add a comment |

The map method does the for loop for you. So all you need in the function is animal[0]

let secretMessage = animals.map(function(animal) {

     return animal[0]

});

This will return every first character in every string in the array, animals. Everything else you have is right.

answered Oct 31 '17 at 14:19

Joseph Carrick

312

add a comment |

The map method does the for loop for you. So all you need in the function is animal[0]

let secretMessage = animals.map(function(animal) {

     return animal[0]

});

This will return every first character in every string in the array, animals. Everything else you have is right.

answered Oct 31 '17 at 14:19

Joseph Carrick

312

The map method does the for loop for you. So all you need in the function is animal[0]

let secretMessage = animals.map(function(animal) {

     return animal[0]

});

This will return every first character in every string in the array, animals. Everything else you have is right.

answered Oct 31 '17 at 14:19

Joseph Carrick

312

answered Oct 31 '17 at 14:19

Joseph Carrick

312

answered Oct 31 '17 at 14:19

Joseph Carrick

312

answered Oct 31 '17 at 14:19

Joseph Carrick

312

add a comment |

You don't need inner loop:

let animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];



let secretMessage = animals.map(function(animal) {

  return animal.charAt(0); // or simply animal[0]

});



console.log(secretMessage.join(''));

answered Oct 31 '17 at 12:46

dfsq

168k21184213

add a comment |

You don't need inner loop:

let animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];



let secretMessage = animals.map(function(animal) {

  return animal.charAt(0); // or simply animal[0]

});



console.log(secretMessage.join(''));

answered Oct 31 '17 at 12:46

dfsq

168k21184213

add a comment |

You don't need inner loop:

let animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];



let secretMessage = animals.map(function(animal) {

  return animal.charAt(0); // or simply animal[0]

});



console.log(secretMessage.join(''));

answered Oct 31 '17 at 12:46

dfsq

168k21184213

You don't need inner loop:

let animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];



let secretMessage = animals.map(function(animal) {

  return animal.charAt(0); // or simply animal[0]

});



console.log(secretMessage.join(''));

let animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];



let secretMessage = animals.map(function(animal) {

  return animal.charAt(0); // or simply animal[0]

});



console.log(secretMessage.join(''));

let animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];



let secretMessage = animals.map(function(animal) {

  return animal.charAt(0); // or simply animal[0]

});



console.log(secretMessage.join(''));

answered Oct 31 '17 at 12:46

dfsq

168k21184213

answered Oct 31 '17 at 12:46

dfsq

168k21184213

answered Oct 31 '17 at 12:46

dfsq

168k21184213

answered Oct 31 '17 at 12:46

dfsq

168k21184213

add a comment |

The error here is that you have a loop inside the map function, which already loops the array.

The correct code is

animals.map(x=>x[0]).join('');

//or

animals.map(function(animal){

    return animal[0]; //First letter of word

}).join(''); //Array -> String

answered Oct 31 '17 at 12:46

Luca De Nardi

1,500624

add a comment |

The error here is that you have a loop inside the map function, which already loops the array.

The correct code is

animals.map(x=>x[0]).join('');

//or

animals.map(function(animal){

    return animal[0]; //First letter of word

}).join(''); //Array -> String

answered Oct 31 '17 at 12:46

Luca De Nardi

1,500624

add a comment |

The error here is that you have a loop inside the map function, which already loops the array.

The correct code is

animals.map(x=>x[0]).join('');

//or

animals.map(function(animal){

    return animal[0]; //First letter of word

}).join(''); //Array -> String

answered Oct 31 '17 at 12:46

Luca De Nardi

1,500624

The error here is that you have a loop inside the map function, which already loops the array.

The correct code is

animals.map(x=>x[0]).join('');

//or

animals.map(function(animal){

    return animal[0]; //First letter of word

}).join(''); //Array -> String

answered Oct 31 '17 at 12:46

Luca De Nardi

1,500624

answered Oct 31 '17 at 12:46

Luca De Nardi

1,500624

answered Oct 31 '17 at 12:46

Luca De Nardi

1,500624

answered Oct 31 '17 at 12:46

Luca De Nardi

1,500624

add a comment |

This should be the code:

let animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];



let secretMessage = animals.map(function(animal) {

    return animal.charAt(0);

});



console.log(secretMessage.join(''));

answered Oct 31 '17 at 12:46

Kenji Mukai

60148

add a comment |

This should be the code:

let animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];



let secretMessage = animals.map(function(animal) {

    return animal.charAt(0);

});



console.log(secretMessage.join(''));

answered Oct 31 '17 at 12:46

Kenji Mukai

60148

add a comment |

This should be the code:

let animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];



let secretMessage = animals.map(function(animal) {

    return animal.charAt(0);

});



console.log(secretMessage.join(''));

answered Oct 31 '17 at 12:46

Kenji Mukai

60148

This should be the code:

let animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];



let secretMessage = animals.map(function(animal) {

    return animal.charAt(0);

});



console.log(secretMessage.join(''));

answered Oct 31 '17 at 12:46

Kenji Mukai

60148

answered Oct 31 '17 at 12:46

Kenji Mukai

60148

answered Oct 31 '17 at 12:46

Kenji Mukai

60148

answered Oct 31 '17 at 12:46

Kenji Mukai

60148

add a comment |

Just do this.

let animals = [

  'Hen', 'elephant', 'llama', 

  'leopard', 'ostrich', 'Whale', 

  'octopus', 'rabbit', 'lion', 'dog'

];

console.log(animals.map(e => e[0]).join(""));

edited Oct 31 '17 at 12:52

answered Oct 31 '17 at 12:46

marmeladze

4,39131433

1

For ES5 or less use this: animals.map(function(s) { return s[0]; }).join(""); For ES6: () => { }

– Yogesh Chuahan
Oct 31 '17 at 13:02

add a comment |

Just do this.

let animals = [

  'Hen', 'elephant', 'llama', 

  'leopard', 'ostrich', 'Whale', 

  'octopus', 'rabbit', 'lion', 'dog'

];

console.log(animals.map(e => e[0]).join(""));

edited Oct 31 '17 at 12:52

answered Oct 31 '17 at 12:46

marmeladze

4,39131433

1

For ES5 or less use this: animals.map(function(s) { return s[0]; }).join(""); For ES6: () => { }

– Yogesh Chuahan
Oct 31 '17 at 13:02

add a comment |

Just do this.

let animals = [

  'Hen', 'elephant', 'llama', 

  'leopard', 'ostrich', 'Whale', 

  'octopus', 'rabbit', 'lion', 'dog'

];

console.log(animals.map(e => e[0]).join(""));

edited Oct 31 '17 at 12:52

answered Oct 31 '17 at 12:46

marmeladze

4,39131433

Just do this.

let animals = [

  'Hen', 'elephant', 'llama', 

  'leopard', 'ostrich', 'Whale', 

  'octopus', 'rabbit', 'lion', 'dog'

];

console.log(animals.map(e => e[0]).join(""));

let animals = [

  'Hen', 'elephant', 'llama', 

  'leopard', 'ostrich', 'Whale', 

  'octopus', 'rabbit', 'lion', 'dog'

];

console.log(animals.map(e => e[0]).join(""));

let animals = [

  'Hen', 'elephant', 'llama', 

  'leopard', 'ostrich', 'Whale', 

  'octopus', 'rabbit', 'lion', 'dog'

];

console.log(animals.map(e => e[0]).join(""));

edited Oct 31 '17 at 12:52

answered Oct 31 '17 at 12:46

marmeladze

4,39131433

edited Oct 31 '17 at 12:52

answered Oct 31 '17 at 12:46

marmeladze

4,39131433

answered Oct 31 '17 at 12:46

marmeladze

4,39131433

answered Oct 31 '17 at 12:46

marmeladze

4,39131433

1

For ES5 or less use this: animals.map(function(s) { return s[0]; }).join(""); For ES6: () => { }

– Yogesh Chuahan
Oct 31 '17 at 13:02

add a comment |

1

For ES5 or less use this: animals.map(function(s) { return s[0]; }).join(""); For ES6: () => { }

– Yogesh Chuahan
Oct 31 '17 at 13:02

For ES5 or less use this: animals.map(function(s) { return s[0]; }).join(""); For ES6: () => { }

– Yogesh Chuahan
Oct 31 '17 at 13:02

add a comment |

let animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];



let secretMessage = animals.map(function(animals) {

return animals[0];

});



console.log(secretMessage.join(''));

let animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];



let secretMessage = animals.map(animals => animals[0]);



console.log(secretMessage.join(''));

answered Mar 30 '18 at 15:08

Kenny Heenatigala

add a comment |

let animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];



let secretMessage = animals.map(function(animals) {

return animals[0];

});



console.log(secretMessage.join(''));

let animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];



let secretMessage = animals.map(animals => animals[0]);



console.log(secretMessage.join(''));

answered Mar 30 '18 at 15:08

Kenny Heenatigala

add a comment |

let animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];



let secretMessage = animals.map(function(animals) {

return animals[0];

});



console.log(secretMessage.join(''));

let animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];



let secretMessage = animals.map(animals => animals[0]);



console.log(secretMessage.join(''));

answered Mar 30 '18 at 15:08

Kenny Heenatigala

let animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];



let secretMessage = animals.map(function(animals) {

return animals[0];

});



console.log(secretMessage.join(''));

let animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];



let secretMessage = animals.map(animals => animals[0]);



console.log(secretMessage.join(''));

answered Mar 30 '18 at 15:08

Kenny Heenatigala

answered Mar 30 '18 at 15:08

Kenny Heenatigala

answered Mar 30 '18 at 15:08

Kenny Heenatigala

answered Mar 30 '18 at 15:08

Kenny Heenatigala

add a comment |

.map() array function take callback function as an argument and return new array so that can use this method to get our result see the syntax below:

const animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];





 const secretMessage = animals.map(animals => {



   return animals[0];

 })



console.log(secretMessage.join(''));

edited Nov 23 '18 at 6:13

Ram Ghadiyaram

17.6k84980

answered Nov 23 '18 at 6:07

Mukesh Suthar

add a comment |

.map() array function take callback function as an argument and return new array so that can use this method to get our result see the syntax below:

const animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];





 const secretMessage = animals.map(animals => {



   return animals[0];

 })



console.log(secretMessage.join(''));

edited Nov 23 '18 at 6:13

Ram Ghadiyaram

17.6k84980

answered Nov 23 '18 at 6:07

Mukesh Suthar

add a comment |

.map() array function take callback function as an argument and return new array so that can use this method to get our result see the syntax below:

const animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];





 const secretMessage = animals.map(animals => {



   return animals[0];

 })



console.log(secretMessage.join(''));

edited Nov 23 '18 at 6:13

Ram Ghadiyaram

17.6k84980

answered Nov 23 '18 at 6:07

Mukesh Suthar

.map() array function take callback function as an argument and return new array so that can use this method to get our result see the syntax below:

const animals = ['Hen', 'elephant', 'llama', 'leopard', 'ostrich', 'Whale', 'octopus', 'rabbit', 'lion', 'dog'];





 const secretMessage = animals.map(animals => {



   return animals[0];

 })



console.log(secretMessage.join(''));

edited Nov 23 '18 at 6:13

Ram Ghadiyaram

17.6k84980

answered Nov 23 '18 at 6:07

Mukesh Suthar

edited Nov 23 '18 at 6:13

Ram Ghadiyaram

17.6k84980

edited Nov 23 '18 at 6:13

Ram Ghadiyaram

17.6k84980

edited Nov 23 '18 at 6:13

Ram Ghadiyaram

17.6k84980

answered Nov 23 '18 at 6:07

Mukesh Suthar

answered Nov 23 '18 at 6:07

Mukesh Suthar

answered Nov 23 '18 at 6:07

Mukesh Suthar

add a comment |

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