I cannot compile gtk apps after updating to 18.04
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I try to compile a program with a user interface as a .out file, and I compiled it just the same way before and I did not edit the code, using this
`pkg-config --cflags --libs gtk+-2.0`
Back in 16.04, the code compiled into an application and I could double click and launch the app. This time, I can`t When I douuble click, it tries to open with glade and shows an error. For some reason, the compiler or the system thinks the file is supposed to be a shared library. How can I tell it to be an application? I have to execute it in the terminal like a non gtk compiled c file.
How can I compile it as an app on 18.04?
somebody heeeeeEEEEEEEEELP MEEEEEEEEEEEEE!
command-line compiling gtk c glade
asked Feb 23 at 20:26
90 9890 98
83
add a comment |
I try to compile a program with a user interface as a .out file, and I compiled it just the same way before and I did not edit the code, using this
`pkg-config --cflags --libs gtk+-2.0`
Back in 16.04, the code compiled into an application and I could double click and launch the app. This time, I can`t When I douuble click, it tries to open with glade and shows an error. For some reason, the compiler or the system thinks the file is supposed to be a shared library. How can I tell it to be an application? I have to execute it in the terminal like a non gtk compiled c file.
How can I compile it as an app on 18.04?
somebody heeeeeEEEEEEEEELP MEEEEEEEEEEEEE!
command-line compiling gtk c glade
asked Feb 23 at 20:26
90 9890 98
83
2
As of gcc-6.2 gcc is configured with the--enable-default-pieoption, that's why it's a shared object. This shouldn't normally prevent executing the file. (take a look in /usr/bin) I guess you could try using the respective compile & link options of-fno-pie -no-pie
– doug
Feb 23 at 21:12
@doug consider to write your method as answer. Reallygcc hello.c `pkg-config --cflags --libs gtk+-2.0` -no-pieallows a.out to be executable from file-manager.
– N0rbert
Feb 23 at 21:27
add a comment |
I try to compile a program with a user interface as a .out file, and I compiled it just the same way before and I did not edit the code, using this
`pkg-config --cflags --libs gtk+-2.0`
Back in 16.04, the code compiled into an application and I could double click and launch the app. This time, I can`t When I douuble click, it tries to open with glade and shows an error. For some reason, the compiler or the system thinks the file is supposed to be a shared library. How can I tell it to be an application? I have to execute it in the terminal like a non gtk compiled c file.
How can I compile it as an app on 18.04?
somebody heeeeeEEEEEEEEELP MEEEEEEEEEEEEE!
command-line compiling gtk c glade
asked Feb 23 at 20:26
90 9890 98
83
I try to compile a program with a user interface as a .out file, and I compiled it just the same way before and I did not edit the code, using this
`pkg-config --cflags --libs gtk+-2.0`
Back in 16.04, the code compiled into an application and I could double click and launch the app. This time, I can`t When I douuble click, it tries to open with glade and shows an error. For some reason, the compiler or the system thinks the file is supposed to be a shared library. How can I tell it to be an application? I have to execute it in the terminal like a non gtk compiled c file.
How can I compile it as an app on 18.04?
somebody heeeeeEEEEEEEEELP MEEEEEEEEEEEEE!
command-line compiling gtk c glade
command-line compiling gtk c glade
asked Feb 23 at 20:26
90 9890 98
83
asked Feb 23 at 20:26
90 9890 98
83
edited Feb 23 at 20:59
90 98
asked Feb 23 at 20:26
90 9890 98
83
asked Feb 23 at 20:26
90 9890 98
83
asked Feb 23 at 20:26
90 9890 98
83
83
2
As of gcc-6.2 gcc is configured with the--enable-default-pieoption, that's why it's a shared object. This shouldn't normally prevent executing the file. (take a look in /usr/bin) I guess you could try using the respective compile & link options of-fno-pie -no-pie
– doug
Feb 23 at 21:12
@doug consider to write your method as answer. Reallygcc hello.c `pkg-config --cflags --libs gtk+-2.0` -no-pieallows a.out to be executable from file-manager.
– N0rbert
Feb 23 at 21:27
add a comment |
2
As of gcc-6.2 gcc is configured with the--enable-default-pieoption, that's why it's a shared object. This shouldn't normally prevent executing the file. (take a look in /usr/bin) I guess you could try using the respective compile & link options of-fno-pie -no-pie
– doug
Feb 23 at 21:12
@doug consider to write your method as answer. Reallygcc hello.c `pkg-config --cflags --libs gtk+-2.0` -no-pieallows a.out to be executable from file-manager.
– N0rbert
Feb 23 at 21:27
2
2
As of gcc-6.2 gcc is configured with the
--enable-default-pie option, that's why it's a shared object. This shouldn't normally prevent executing the file. (take a look in /usr/bin) I guess you could try using the respective compile & link options of -fno-pie -no-pie– doug
Feb 23 at 21:12
As of gcc-6.2 gcc is configured with the
--enable-default-pie option, that's why it's a shared object. This shouldn't normally prevent executing the file. (take a look in /usr/bin) I guess you could try using the respective compile & link options of -fno-pie -no-pie– doug
Feb 23 at 21:12
@doug consider to write your method as answer. Really
gcc hello.c `pkg-config --cflags --libs gtk+-2.0` -no-pie allows a.out to be executable from file-manager.– N0rbert
Feb 23 at 21:27
@doug consider to write your method as answer. Really
gcc hello.c `pkg-config --cflags --libs gtk+-2.0` -no-pie allows a.out to be executable from file-manager.– N0rbert
Feb 23 at 21:27
add a comment |
1 Answer
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As of gcc-6.2 gcc in Ubuntu is configured with the --enable-default-pie option, (Position Independent Executable), that's why it's a shared object. (- LSB shared object
The compiler override for this is -fno-pie , the linker override is -no-pie
Apparently for an a.out file you only need to apply the linker -no-pie though both options together also work.
Also a factor may be your file manager, some will allow marking & running the shared object as exectubale. Nautilus doesn't anymore.(nemo does
answered Feb 23 at 22:14
dougdoug
14.3k13553
add a comment |
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As of gcc-6.2 gcc in Ubuntu is configured with the --enable-default-pie option, (Position Independent Executable), that's why it's a shared object. (- LSB shared object
The compiler override for this is -fno-pie , the linker override is -no-pie
Apparently for an a.out file you only need to apply the linker -no-pie though both options together also work.
Also a factor may be your file manager, some will allow marking & running the shared object as exectubale. Nautilus doesn't anymore.(nemo does
answered Feb 23 at 22:14
dougdoug
14.3k13553
add a comment |
As of gcc-6.2 gcc in Ubuntu is configured with the --enable-default-pie option, (Position Independent Executable), that's why it's a shared object. (- LSB shared object
The compiler override for this is -fno-pie , the linker override is -no-pie
Apparently for an a.out file you only need to apply the linker -no-pie though both options together also work.
Also a factor may be your file manager, some will allow marking & running the shared object as exectubale. Nautilus doesn't anymore.(nemo does
answered Feb 23 at 22:14
dougdoug
14.3k13553
add a comment |
As of gcc-6.2 gcc in Ubuntu is configured with the --enable-default-pie option, (Position Independent Executable), that's why it's a shared object. (- LSB shared object
The compiler override for this is -fno-pie , the linker override is -no-pie
Apparently for an a.out file you only need to apply the linker -no-pie though both options together also work.
Also a factor may be your file manager, some will allow marking & running the shared object as exectubale. Nautilus doesn't anymore.(nemo does
answered Feb 23 at 22:14
dougdoug
14.3k13553
As of gcc-6.2 gcc in Ubuntu is configured with the --enable-default-pie option, (Position Independent Executable), that's why it's a shared object. (- LSB shared object
The compiler override for this is -fno-pie , the linker override is -no-pie
Apparently for an a.out file you only need to apply the linker -no-pie though both options together also work.
Also a factor may be your file manager, some will allow marking & running the shared object as exectubale. Nautilus doesn't anymore.(nemo does
answered Feb 23 at 22:14
dougdoug
14.3k13553
edited Mar 12 at 21:02
answered Feb 23 at 22:14
dougdoug
14.3k13553
answered Feb 23 at 22:14
dougdoug
14.3k13553
answered Feb 23 at 22:14
dougdoug
14.3k13553
14.3k13553
add a comment |
add a comment |
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As of gcc-6.2 gcc is configured with the
--enable-default-pieoption, that's why it's a shared object. This shouldn't normally prevent executing the file. (take a look in /usr/bin) I guess you could try using the respective compile & link options of-fno-pie -no-pie– doug
Feb 23 at 21:12
@doug consider to write your method as answer. Really
gcc hello.c `pkg-config --cflags --libs gtk+-2.0` -no-pieallows a.out to be executable from file-manager.– N0rbert
Feb 23 at 21:27