Cfrgtkky

I am facing some problems while getting unique values out of strings.

Example:

string1 = "4,5"

string2 = "7,9"

string3 = "4,7,6,1"

string4 = "1"

After I need to get all unique values as an int. In this case result must be 6. But each time the number of strings can change.

Is this even possible?

Use Split and Distinct

var  input = "1,3,1,2,3,43,23,54,3,4";



var result input.Split(',')

                .Distinct();    



Console.WriteLine(string.Join(",",result));

Output

1,3,2,43,23,54,4

Full Demo Here

Additional Resources

String.Split Method

Returns a string array that contains the substrings in this instance
that are delimited by elements of a specified string or Unicode
character array.

Enumerable.Distinct Method

Returns distinct elements from a sequence.

If "number of strings can change", let's organize them into a collection:

List<string> strings = new List<string> {

  "4,5",

  "7,9",  

  "4,7,6,1",

  "1"

};

Then we can right a simple Linq:

var uniques = strings

  .SelectMany(item => item.Split(',')) // split each item and flatten the result

  .Select(item => int.Parse(item))

  .Distinct()

  .ToArray(); // let's have an array of distinct items: {4, 5, 7, 9, 6, 1}

If you want to obtain items which appears just once:

var uniques = strings

  .SelectMany(item => item.Split(',')) // split each item and flatten the result

  .Select(item => int.Parse(item))

  .GroupBy(item => item) 

  .Where(item => item.Count() == 1)

  .Select(group => group.Key)

  .ToArray(); // let's have an array of items which appear once: {5, 9, 6} 

1. Instead of using number of string variable you can you single instance of StringBuilder




2. Convert all element to array of integer.




3. Get Distinct/number which comes only one once by Linq

Something like this:

    StringBuilder sb = new StringBuilder();

    sb.Append("5,5");

    sb.Append(",");

    sb.Append("7,9");

    sb.Append(",");

    sb.Append("4,7,6,1");

    sb.Append(",");

    sb.Append("1"); 



    string arr = sb.ToString().Split(',');

    int test = Array.ConvertAll(arr, s => int.Parse(s));





    var count = test

        .GroupBy(e => e)

        .Where(e => e.Count() == 1)

        .Select(e => e.First()).ToList();



output: 



9

4

6

POC: .netFiddler

A single line can do the job

    string s = "1,3,1,2,3,43,23,54,3,4";

    string StrArry = s.Split(',');



    int IntArry = Array.ConvertAll(StrArry, int.Parse).Distinct().ToArray();

output

1,3,2,43,23,54,4

He can you try this out

var string1 = "4,5";

var string2 = "7,9";

var string3 = "4,7,6,1";

var string4 = "1";



var allStrings = string1 + ',' + string2 + ',' + string3 + ','+ string4;

var distinctNumbers = new List<string>(allStrings.Split(',').Distinct());

Output :
4
5
7
9
6
1

distinctNumbers = Count = 6

This is a longer one than the others, but it might be easier to understand how it works.

        List<string> str = new List<string> {"1", "3", "1", "2", "3", "43", "23", "54", "3"," "4 };



        List<string> foundstr = new List<string> { };



        foreach (string check in str)

        {

            bool found = false;

            //going through every single item in the list and checking if it is found in there

            for (int i = 0; i < foundstr.Count; i++)

            {

            //if found then make found(bool) true so we don't put it in the list

                if(check == foundstr[i])

                {

                    found = true;

                }  

            }

            //checking if the string has been found and if not then add to list

            if(found == false)

            {

                foundstr.Add(check);

            }

        }



        foreach(string strings in foundstr)

        {

            Console.WriteLine(strings);

        }



        Console.ReadLine();