CSS Square background - image
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0
I tried to make some square background using CSS only, but i got just line background without the option of horizontal lines.
This is my example code:
CSS
.container{
background-color:red;
width: 400px; height:200px; margin:0 auto;
background-image: linear-gradient(90deg, rgba(255, 255, 255, .5) 95px , transparent 50%),
linear-gradient(rgba(255, 255, 255, 0) 5px, transparent 100%);
background-size: 100px 100%;
}<div class="container">
</div>And this is the result that I am looking for
This is the result that I got for now
html css background-image linear-gradients repeating-linear-gradient
edited Nov 22 '18 at 7:53
fiza khan
1,006521
asked Nov 22 '18 at 7:28
24sharon24sharon
50321036
add a comment |
0
I tried to make some square background using CSS only, but i got just line background without the option of horizontal lines.
This is my example code:
CSS
.container{
background-color:red;
width: 400px; height:200px; margin:0 auto;
background-image: linear-gradient(90deg, rgba(255, 255, 255, .5) 95px , transparent 50%),
linear-gradient(rgba(255, 255, 255, 0) 5px, transparent 100%);
background-size: 100px 100%;
}<div class="container">
</div>And this is the result that I am looking for
This is the result that I got for now
html css background-image linear-gradients repeating-linear-gradient
edited Nov 22 '18 at 7:53
fiza khan
1,006521
asked Nov 22 '18 at 7:28
24sharon24sharon
50321036
Solutions below. The answer to what goes wrong in your code is in the second linear-gradient, both colours are fully transparent, so it does not have any visible result!
– Mr Lister
Nov 22 '18 at 12:20
add a comment |
0
0
0
0
I tried to make some square background using CSS only, but i got just line background without the option of horizontal lines.
This is my example code:
CSS
.container{
background-color:red;
width: 400px; height:200px; margin:0 auto;
background-image: linear-gradient(90deg, rgba(255, 255, 255, .5) 95px , transparent 50%),
linear-gradient(rgba(255, 255, 255, 0) 5px, transparent 100%);
background-size: 100px 100%;
}<div class="container">
</div>And this is the result that I am looking for
This is the result that I got for now
html css background-image linear-gradients repeating-linear-gradient
edited Nov 22 '18 at 7:53
fiza khan
1,006521
asked Nov 22 '18 at 7:28
24sharon24sharon
50321036
I tried to make some square background using CSS only, but i got just line background without the option of horizontal lines.
This is my example code:
CSS
.container{
background-color:red;
width: 400px; height:200px; margin:0 auto;
background-image: linear-gradient(90deg, rgba(255, 255, 255, .5) 95px , transparent 50%),
linear-gradient(rgba(255, 255, 255, 0) 5px, transparent 100%);
background-size: 100px 100%;
}<div class="container">
</div>And this is the result that I am looking for
This is the result that I got for now
.container{
background-color:red;
width: 400px; height:200px; margin:0 auto;
background-image: linear-gradient(90deg, rgba(255, 255, 255, .5) 95px , transparent 50%),
linear-gradient(rgba(255, 255, 255, 0) 5px, transparent 100%);
background-size: 100px 100%;
}<div class="container">
</div>.container{
background-color:red;
width: 400px; height:200px; margin:0 auto;
background-image: linear-gradient(90deg, rgba(255, 255, 255, .5) 95px , transparent 50%),
linear-gradient(rgba(255, 255, 255, 0) 5px, transparent 100%);
background-size: 100px 100%;
}<div class="container">
</div>html css background-image linear-gradients repeating-linear-gradient
html css background-image linear-gradients repeating-linear-gradient
edited Nov 22 '18 at 7:53
fiza khan
1,006521
asked Nov 22 '18 at 7:28
24sharon24sharon
50321036
edited Nov 22 '18 at 7:53
fiza khan
1,006521
asked Nov 22 '18 at 7:28
24sharon24sharon
50321036
edited Nov 22 '18 at 7:53
fiza khan
1,006521
edited Nov 22 '18 at 7:53
fiza khan
1,006521
edited Nov 22 '18 at 7:53
fiza khan
1,006521
1,006521
asked Nov 22 '18 at 7:28
24sharon24sharon
50321036
asked Nov 22 '18 at 7:28
24sharon24sharon
50321036
asked Nov 22 '18 at 7:28
24sharon24sharon
50321036
50321036
Solutions below. The answer to what goes wrong in your code is in the second linear-gradient, both colours are fully transparent, so it does not have any visible result!
– Mr Lister
Nov 22 '18 at 12:20
add a comment |
Solutions below. The answer to what goes wrong in your code is in the second linear-gradient, both colours are fully transparent, so it does not have any visible result!
– Mr Lister
Nov 22 '18 at 12:20
Solutions below. The answer to what goes wrong in your code is in the second linear-gradient, both colours are fully transparent, so it does not have any visible result!
– Mr Lister
Nov 22 '18 at 12:20
Solutions below. The answer to what goes wrong in your code is in the second linear-gradient, both colours are fully transparent, so it does not have any visible result!
– Mr Lister
Nov 22 '18 at 12:20
add a comment |
2 Answers
2
active
oldest
votes
2
All you need is two gradients, one to define the horizontal lines and the other the vertical ones:
.container {
background-color: red;
width: 400px;
height: 200px;
margin: 0 auto;
background:
repeating-linear-gradient(to right,
transparent 0,transparent calc(50px - 2px),
blue calc(50px - 2px),blue 50px),
repeating-linear-gradient(to bottom,
transparent 0,transparent calc(50px - 2px),
blue calc(50px - 2px),blue 50px)
red;
}<div class="container">
</div>The above example will create an homogeneous grid. You can also consider multiple gradient in order to control each line alone:
.container {
background-color: red;
width: 400px;
height: 200px;
margin: 0 auto;
background:
/*vertical ones*/
linear-gradient(blue,blue) center/2px 100%,
linear-gradient(blue,blue) 25% 0/2px 100%,
linear-gradient(blue,blue) 85% 0/2px 100%,
/*horizontal ones*/
linear-gradient(blue,blue) 0 25%/100% 2px,
linear-gradient(blue,blue) 0 75%/100% 2px,
red;
background-repeat:no-repeat;
}<div class="container">
</div>answered Nov 22 '18 at 9:06
Temani AfifTemani Afif
82.1k104794
add a comment |
2
The answer is in "repeating-linear-gradient()"
https://developer.mozilla.org/en-US/docs/Web/CSS/repeating-linear-gradient
.container{
background-color:red;
width: 400px; height:200px; margin:0 auto;
background-image:
repeating-linear-gradient(rgba(255, 255, 255, .5), rgba(255, 255, 255, .25) 95px, red 100px),
repeating-linear-gradient(0.25turn, rgba(255, 255, 255, .5), rgba(255, 255, 255, .25) 95px, red 100px),
repeating-linear-gradient(0.75turn, rgba(255, 255, 255, .5), rgba(255, 255, 255, .25) 95px, red 100px);
}<div class="container">
</div>answered Nov 22 '18 at 8:26
Carol McKayCarol McKay
1,9011711
add a comment |
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2 Answers
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active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
All you need is two gradients, one to define the horizontal lines and the other the vertical ones:
.container {
background-color: red;
width: 400px;
height: 200px;
margin: 0 auto;
background:
repeating-linear-gradient(to right,
transparent 0,transparent calc(50px - 2px),
blue calc(50px - 2px),blue 50px),
repeating-linear-gradient(to bottom,
transparent 0,transparent calc(50px - 2px),
blue calc(50px - 2px),blue 50px)
red;
}<div class="container">
</div>The above example will create an homogeneous grid. You can also consider multiple gradient in order to control each line alone:
.container {
background-color: red;
width: 400px;
height: 200px;
margin: 0 auto;
background:
/*vertical ones*/
linear-gradient(blue,blue) center/2px 100%,
linear-gradient(blue,blue) 25% 0/2px 100%,
linear-gradient(blue,blue) 85% 0/2px 100%,
/*horizontal ones*/
linear-gradient(blue,blue) 0 25%/100% 2px,
linear-gradient(blue,blue) 0 75%/100% 2px,
red;
background-repeat:no-repeat;
}<div class="container">
</div>answered Nov 22 '18 at 9:06
Temani AfifTemani Afif
82.1k104794
add a comment |
2
All you need is two gradients, one to define the horizontal lines and the other the vertical ones:
.container {
background-color: red;
width: 400px;
height: 200px;
margin: 0 auto;
background:
repeating-linear-gradient(to right,
transparent 0,transparent calc(50px - 2px),
blue calc(50px - 2px),blue 50px),
repeating-linear-gradient(to bottom,
transparent 0,transparent calc(50px - 2px),
blue calc(50px - 2px),blue 50px)
red;
}<div class="container">
</div>The above example will create an homogeneous grid. You can also consider multiple gradient in order to control each line alone:
.container {
background-color: red;
width: 400px;
height: 200px;
margin: 0 auto;
background:
/*vertical ones*/
linear-gradient(blue,blue) center/2px 100%,
linear-gradient(blue,blue) 25% 0/2px 100%,
linear-gradient(blue,blue) 85% 0/2px 100%,
/*horizontal ones*/
linear-gradient(blue,blue) 0 25%/100% 2px,
linear-gradient(blue,blue) 0 75%/100% 2px,
red;
background-repeat:no-repeat;
}<div class="container">
</div>answered Nov 22 '18 at 9:06
Temani AfifTemani Afif
82.1k104794
add a comment |
2
2
2
All you need is two gradients, one to define the horizontal lines and the other the vertical ones:
.container {
background-color: red;
width: 400px;
height: 200px;
margin: 0 auto;
background:
repeating-linear-gradient(to right,
transparent 0,transparent calc(50px - 2px),
blue calc(50px - 2px),blue 50px),
repeating-linear-gradient(to bottom,
transparent 0,transparent calc(50px - 2px),
blue calc(50px - 2px),blue 50px)
red;
}<div class="container">
</div>The above example will create an homogeneous grid. You can also consider multiple gradient in order to control each line alone:
.container {
background-color: red;
width: 400px;
height: 200px;
margin: 0 auto;
background:
/*vertical ones*/
linear-gradient(blue,blue) center/2px 100%,
linear-gradient(blue,blue) 25% 0/2px 100%,
linear-gradient(blue,blue) 85% 0/2px 100%,
/*horizontal ones*/
linear-gradient(blue,blue) 0 25%/100% 2px,
linear-gradient(blue,blue) 0 75%/100% 2px,
red;
background-repeat:no-repeat;
}<div class="container">
</div>answered Nov 22 '18 at 9:06
Temani AfifTemani Afif
82.1k104794
All you need is two gradients, one to define the horizontal lines and the other the vertical ones:
.container {
background-color: red;
width: 400px;
height: 200px;
margin: 0 auto;
background:
repeating-linear-gradient(to right,
transparent 0,transparent calc(50px - 2px),
blue calc(50px - 2px),blue 50px),
repeating-linear-gradient(to bottom,
transparent 0,transparent calc(50px - 2px),
blue calc(50px - 2px),blue 50px)
red;
}<div class="container">
</div>The above example will create an homogeneous grid. You can also consider multiple gradient in order to control each line alone:
.container {
background-color: red;
width: 400px;
height: 200px;
margin: 0 auto;
background:
/*vertical ones*/
linear-gradient(blue,blue) center/2px 100%,
linear-gradient(blue,blue) 25% 0/2px 100%,
linear-gradient(blue,blue) 85% 0/2px 100%,
/*horizontal ones*/
linear-gradient(blue,blue) 0 25%/100% 2px,
linear-gradient(blue,blue) 0 75%/100% 2px,
red;
background-repeat:no-repeat;
}<div class="container">
</div>.container {
background-color: red;
width: 400px;
height: 200px;
margin: 0 auto;
background:
repeating-linear-gradient(to right,
transparent 0,transparent calc(50px - 2px),
blue calc(50px - 2px),blue 50px),
repeating-linear-gradient(to bottom,
transparent 0,transparent calc(50px - 2px),
blue calc(50px - 2px),blue 50px)
red;
}<div class="container">
</div>.container {
background-color: red;
width: 400px;
height: 200px;
margin: 0 auto;
background:
repeating-linear-gradient(to right,
transparent 0,transparent calc(50px - 2px),
blue calc(50px - 2px),blue 50px),
repeating-linear-gradient(to bottom,
transparent 0,transparent calc(50px - 2px),
blue calc(50px - 2px),blue 50px)
red;
}<div class="container">
</div>.container {
background-color: red;
width: 400px;
height: 200px;
margin: 0 auto;
background:
/*vertical ones*/
linear-gradient(blue,blue) center/2px 100%,
linear-gradient(blue,blue) 25% 0/2px 100%,
linear-gradient(blue,blue) 85% 0/2px 100%,
/*horizontal ones*/
linear-gradient(blue,blue) 0 25%/100% 2px,
linear-gradient(blue,blue) 0 75%/100% 2px,
red;
background-repeat:no-repeat;
}<div class="container">
</div>.container {
background-color: red;
width: 400px;
height: 200px;
margin: 0 auto;
background:
/*vertical ones*/
linear-gradient(blue,blue) center/2px 100%,
linear-gradient(blue,blue) 25% 0/2px 100%,
linear-gradient(blue,blue) 85% 0/2px 100%,
/*horizontal ones*/
linear-gradient(blue,blue) 0 25%/100% 2px,
linear-gradient(blue,blue) 0 75%/100% 2px,
red;
background-repeat:no-repeat;
}<div class="container">
</div>answered Nov 22 '18 at 9:06
Temani AfifTemani Afif
82.1k104794
edited Nov 23 '18 at 6:26
answered Nov 22 '18 at 9:06
Temani AfifTemani Afif
82.1k104794
answered Nov 22 '18 at 9:06
Temani AfifTemani Afif
82.1k104794
answered Nov 22 '18 at 9:06
Temani AfifTemani Afif
82.1k104794
82.1k104794
add a comment |
add a comment |
2
The answer is in "repeating-linear-gradient()"
https://developer.mozilla.org/en-US/docs/Web/CSS/repeating-linear-gradient
.container{
background-color:red;
width: 400px; height:200px; margin:0 auto;
background-image:
repeating-linear-gradient(rgba(255, 255, 255, .5), rgba(255, 255, 255, .25) 95px, red 100px),
repeating-linear-gradient(0.25turn, rgba(255, 255, 255, .5), rgba(255, 255, 255, .25) 95px, red 100px),
repeating-linear-gradient(0.75turn, rgba(255, 255, 255, .5), rgba(255, 255, 255, .25) 95px, red 100px);
}<div class="container">
</div>answered Nov 22 '18 at 8:26
Carol McKayCarol McKay
1,9011711
add a comment |
2
The answer is in "repeating-linear-gradient()"
https://developer.mozilla.org/en-US/docs/Web/CSS/repeating-linear-gradient
.container{
background-color:red;
width: 400px; height:200px; margin:0 auto;
background-image:
repeating-linear-gradient(rgba(255, 255, 255, .5), rgba(255, 255, 255, .25) 95px, red 100px),
repeating-linear-gradient(0.25turn, rgba(255, 255, 255, .5), rgba(255, 255, 255, .25) 95px, red 100px),
repeating-linear-gradient(0.75turn, rgba(255, 255, 255, .5), rgba(255, 255, 255, .25) 95px, red 100px);
}<div class="container">
</div>answered Nov 22 '18 at 8:26
Carol McKayCarol McKay
1,9011711
add a comment |
2
2
2
The answer is in "repeating-linear-gradient()"
https://developer.mozilla.org/en-US/docs/Web/CSS/repeating-linear-gradient
.container{
background-color:red;
width: 400px; height:200px; margin:0 auto;
background-image:
repeating-linear-gradient(rgba(255, 255, 255, .5), rgba(255, 255, 255, .25) 95px, red 100px),
repeating-linear-gradient(0.25turn, rgba(255, 255, 255, .5), rgba(255, 255, 255, .25) 95px, red 100px),
repeating-linear-gradient(0.75turn, rgba(255, 255, 255, .5), rgba(255, 255, 255, .25) 95px, red 100px);
}<div class="container">
</div>answered Nov 22 '18 at 8:26
Carol McKayCarol McKay
1,9011711
The answer is in "repeating-linear-gradient()"
https://developer.mozilla.org/en-US/docs/Web/CSS/repeating-linear-gradient
.container{
background-color:red;
width: 400px; height:200px; margin:0 auto;
background-image:
repeating-linear-gradient(rgba(255, 255, 255, .5), rgba(255, 255, 255, .25) 95px, red 100px),
repeating-linear-gradient(0.25turn, rgba(255, 255, 255, .5), rgba(255, 255, 255, .25) 95px, red 100px),
repeating-linear-gradient(0.75turn, rgba(255, 255, 255, .5), rgba(255, 255, 255, .25) 95px, red 100px);
}<div class="container">
</div>.container{
background-color:red;
width: 400px; height:200px; margin:0 auto;
background-image:
repeating-linear-gradient(rgba(255, 255, 255, .5), rgba(255, 255, 255, .25) 95px, red 100px),
repeating-linear-gradient(0.25turn, rgba(255, 255, 255, .5), rgba(255, 255, 255, .25) 95px, red 100px),
repeating-linear-gradient(0.75turn, rgba(255, 255, 255, .5), rgba(255, 255, 255, .25) 95px, red 100px);
}<div class="container">
</div>.container{
background-color:red;
width: 400px; height:200px; margin:0 auto;
background-image:
repeating-linear-gradient(rgba(255, 255, 255, .5), rgba(255, 255, 255, .25) 95px, red 100px),
repeating-linear-gradient(0.25turn, rgba(255, 255, 255, .5), rgba(255, 255, 255, .25) 95px, red 100px),
repeating-linear-gradient(0.75turn, rgba(255, 255, 255, .5), rgba(255, 255, 255, .25) 95px, red 100px);
}<div class="container">
</div>answered Nov 22 '18 at 8:26
Carol McKayCarol McKay
1,9011711
answered Nov 22 '18 at 8:26
Carol McKayCarol McKay
1,9011711
answered Nov 22 '18 at 8:26
Carol McKayCarol McKay
1,9011711
answered Nov 22 '18 at 8:26
Carol McKayCarol McKay
1,9011711
1,9011711
add a comment |
add a comment |
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Solutions below. The answer to what goes wrong in your code is in the second linear-gradient, both colours are fully transparent, so it does not have any visible result!
– Mr Lister
Nov 22 '18 at 12:20