Transformation Law for Tensor of Rank Two
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Okay, I am sorry if this question seems absurd, but I am really having a difficult time understanding it.
In the book by H. Jeffreys chapter Cartesian tensors, he defines a second order tensor as $ omega_{jl},' = a_{ij}, a_{kl},omega_{ik}$.
Then he goes on to demonstrate that we change the variables 'j' and 'l' in the equation , and also shows "dummy indices" can be changed without any trouble, after which he arrives at $ omega_{lj},' = a_{kl}, a_{ij},omega_{ki}$ which makes sense, then in the same line he says that $ omega_{lj},' = a_{ij}, a_{kl},omega_{ki}$.
Which is a bit troubling for me, because $a_{ij}$ and $a_{kl} $ are transformation matrices(like operators), and the order of application is important.
tensor-products
$endgroup$
add a comment |
$begingroup$
Okay, I am sorry if this question seems absurd, but I am really having a difficult time understanding it.
In the book by H. Jeffreys chapter Cartesian tensors, he defines a second order tensor as $ omega_{jl},' = a_{ij}, a_{kl},omega_{ik}$.
Then he goes on to demonstrate that we change the variables 'j' and 'l' in the equation , and also shows "dummy indices" can be changed without any trouble, after which he arrives at $ omega_{lj},' = a_{kl}, a_{ij},omega_{ki}$ which makes sense, then in the same line he says that $ omega_{lj},' = a_{ij}, a_{kl},omega_{ki}$.
Which is a bit troubling for me, because $a_{ij}$ and $a_{kl} $ are transformation matrices(like operators), and the order of application is important.
tensor-products
$endgroup$
add a comment |
$begingroup$
Okay, I am sorry if this question seems absurd, but I am really having a difficult time understanding it.
In the book by H. Jeffreys chapter Cartesian tensors, he defines a second order tensor as $ omega_{jl},' = a_{ij}, a_{kl},omega_{ik}$.
Then he goes on to demonstrate that we change the variables 'j' and 'l' in the equation , and also shows "dummy indices" can be changed without any trouble, after which he arrives at $ omega_{lj},' = a_{kl}, a_{ij},omega_{ki}$ which makes sense, then in the same line he says that $ omega_{lj},' = a_{ij}, a_{kl},omega_{ki}$.
Which is a bit troubling for me, because $a_{ij}$ and $a_{kl} $ are transformation matrices(like operators), and the order of application is important.
tensor-products
$endgroup$
Okay, I am sorry if this question seems absurd, but I am really having a difficult time understanding it.
In the book by H. Jeffreys chapter Cartesian tensors, he defines a second order tensor as $ omega_{jl},' = a_{ij}, a_{kl},omega_{ik}$.
Then he goes on to demonstrate that we change the variables 'j' and 'l' in the equation , and also shows "dummy indices" can be changed without any trouble, after which he arrives at $ omega_{lj},' = a_{kl}, a_{ij},omega_{ki}$ which makes sense, then in the same line he says that $ omega_{lj},' = a_{ij}, a_{kl},omega_{ki}$.
Which is a bit troubling for me, because $a_{ij}$ and $a_{kl} $ are transformation matrices(like operators), and the order of application is important.
tensor-products
tensor-products
asked Dec 3 '18 at 21:59
Ashutosh SinghAshutosh Singh
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