Binary relations - how to find an inverse binary relation - textbook task
$begingroup$
The task is as follows:
Let R be a binary relation on the set X={1,2,3,4,5,6,7,8,9}. R =
{
(
x,y
)
|
x,y
∈
X,
3 divides
x
−
2y
}.
Find the inverse relation S. Is there a different way to define the set S than just writing S={(2, 1), (5, 1), (8, 1), ...}
If someone could give me a hint in the right direction it would be much appreciated.
discrete-mathematics
asked Dec 4 '18 at 13:59
Robert874Robert874
154
$endgroup$
add a comment |
$begingroup$
The task is as follows:
Let R be a binary relation on the set X={1,2,3,4,5,6,7,8,9}. R =
{
(
x,y
)
|
x,y
∈
X,
3 divides
x
−
2y
}.
Find the inverse relation S. Is there a different way to define the set S than just writing S={(2, 1), (5, 1), (8, 1), ...}
If someone could give me a hint in the right direction it would be much appreciated.
discrete-mathematics
asked Dec 4 '18 at 13:59
Robert874Robert874
154
$endgroup$
add a comment |
$begingroup$
The task is as follows:
Let R be a binary relation on the set X={1,2,3,4,5,6,7,8,9}. R =
{
(
x,y
)
|
x,y
∈
X,
3 divides
x
−
2y
}.
Find the inverse relation S. Is there a different way to define the set S than just writing S={(2, 1), (5, 1), (8, 1), ...}
If someone could give me a hint in the right direction it would be much appreciated.
discrete-mathematics
asked Dec 4 '18 at 13:59
Robert874Robert874
154
$endgroup$
The task is as follows:
Let R be a binary relation on the set X={1,2,3,4,5,6,7,8,9}. R =
{
(
x,y
)
|
x,y
∈
X,
3 divides
x
−
2y
}.
Find the inverse relation S. Is there a different way to define the set S than just writing S={(2, 1), (5, 1), (8, 1), ...}
If someone could give me a hint in the right direction it would be much appreciated.
discrete-mathematics
discrete-mathematics
asked Dec 4 '18 at 13:59
Robert874Robert874
154
asked Dec 4 '18 at 13:59
Robert874Robert874
154
edited Dec 4 '18 at 14:04
Robert874
asked Dec 4 '18 at 13:59
Robert874Robert874
154
asked Dec 4 '18 at 13:59
Robert874Robert874
154
asked Dec 4 '18 at 13:59
Robert874Robert874
154
154
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
You could write: $$S={(x,y)in X^2mid 3text{ divides } y-2x}$$where the roles of $x$ and $y$ are switched.
answered Dec 4 '18 at 14:13
drhabdrhab
102k545136
$endgroup$
add a comment |
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1 Answer
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1 Answer
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$begingroup$
You could write: $$S={(x,y)in X^2mid 3text{ divides } y-2x}$$where the roles of $x$ and $y$ are switched.
answered Dec 4 '18 at 14:13
drhabdrhab
102k545136
$endgroup$
add a comment |
$begingroup$
You could write: $$S={(x,y)in X^2mid 3text{ divides } y-2x}$$where the roles of $x$ and $y$ are switched.
answered Dec 4 '18 at 14:13
drhabdrhab
102k545136
$endgroup$
add a comment |
$begingroup$
You could write: $$S={(x,y)in X^2mid 3text{ divides } y-2x}$$where the roles of $x$ and $y$ are switched.
answered Dec 4 '18 at 14:13
drhabdrhab
102k545136
$endgroup$
You could write: $$S={(x,y)in X^2mid 3text{ divides } y-2x}$$where the roles of $x$ and $y$ are switched.
answered Dec 4 '18 at 14:13
drhabdrhab
102k545136
answered Dec 4 '18 at 14:13
drhabdrhab
102k545136
answered Dec 4 '18 at 14:13
drhabdrhab
102k545136
answered Dec 4 '18 at 14:13
drhabdrhab
102k545136
102k545136
add a comment |
add a comment |
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