Add time values in Python












2















I have a list of times that are in following format:



Hour:Minue:Second.Microseconds



File looks like this:



0:06:50.137529
0:08:55.439963
0:06:19.179093
0:07:16.680906
0:31:55.778010
0:16:56.940836


Is there a Python function or set of commands that will let me add all of these values together?



I initially "build" these values with the following code:



optimize_times = 
starting_time=(datetime.now())
ending_time=(datetime.now())
optimize_times.append(str(ending_time-starting_time))









share|improve this question

























  • Yes, timedelta, but it's not clear to me why you call str() on your results.

    – roganjosh
    Nov 20 '18 at 21:24











  • Without using the str function the value resulted in a timedelta function being output

    – user3299633
    Nov 20 '18 at 21:37
















2















I have a list of times that are in following format:



Hour:Minue:Second.Microseconds



File looks like this:



0:06:50.137529
0:08:55.439963
0:06:19.179093
0:07:16.680906
0:31:55.778010
0:16:56.940836


Is there a Python function or set of commands that will let me add all of these values together?



I initially "build" these values with the following code:



optimize_times = 
starting_time=(datetime.now())
ending_time=(datetime.now())
optimize_times.append(str(ending_time-starting_time))









share|improve this question

























  • Yes, timedelta, but it's not clear to me why you call str() on your results.

    – roganjosh
    Nov 20 '18 at 21:24











  • Without using the str function the value resulted in a timedelta function being output

    – user3299633
    Nov 20 '18 at 21:37














2












2








2








I have a list of times that are in following format:



Hour:Minue:Second.Microseconds



File looks like this:



0:06:50.137529
0:08:55.439963
0:06:19.179093
0:07:16.680906
0:31:55.778010
0:16:56.940836


Is there a Python function or set of commands that will let me add all of these values together?



I initially "build" these values with the following code:



optimize_times = 
starting_time=(datetime.now())
ending_time=(datetime.now())
optimize_times.append(str(ending_time-starting_time))









share|improve this question
















I have a list of times that are in following format:



Hour:Minue:Second.Microseconds



File looks like this:



0:06:50.137529
0:08:55.439963
0:06:19.179093
0:07:16.680906
0:31:55.778010
0:16:56.940836


Is there a Python function or set of commands that will let me add all of these values together?



I initially "build" these values with the following code:



optimize_times = 
starting_time=(datetime.now())
ending_time=(datetime.now())
optimize_times.append(str(ending_time-starting_time))






python string python-2.7 datetime timedelta






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share|improve this question













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share|improve this question








edited Nov 20 '18 at 21:50









jpp

101k2163112




101k2163112










asked Nov 20 '18 at 21:22









user3299633user3299633

7972823




7972823













  • Yes, timedelta, but it's not clear to me why you call str() on your results.

    – roganjosh
    Nov 20 '18 at 21:24











  • Without using the str function the value resulted in a timedelta function being output

    – user3299633
    Nov 20 '18 at 21:37



















  • Yes, timedelta, but it's not clear to me why you call str() on your results.

    – roganjosh
    Nov 20 '18 at 21:24











  • Without using the str function the value resulted in a timedelta function being output

    – user3299633
    Nov 20 '18 at 21:37

















Yes, timedelta, but it's not clear to me why you call str() on your results.

– roganjosh
Nov 20 '18 at 21:24





Yes, timedelta, but it's not clear to me why you call str() on your results.

– roganjosh
Nov 20 '18 at 21:24













Without using the str function the value resulted in a timedelta function being output

– user3299633
Nov 20 '18 at 21:37





Without using the str function the value resulted in a timedelta function being output

– user3299633
Nov 20 '18 at 21:37












1 Answer
1






active

oldest

votes


















1














You can use datetime.timedelta from the standard library:



from datetime import timedelta

L = ['0:06:50.137529', '0:08:55.439963', '0:06:19.179093',
'0:07:16.680906', '0:31:55.778010', '0:16:56.940836']

def str_to_td(x):
hrs, mins, sec_micro = x.split(':')
secs, msecs = map(int, sec_micro.split('.'))
return timedelta(hours=int(hrs), minutes=int(mins), seconds=secs, microseconds=msecs)

res = sum(map(str_to_td, L), timedelta())

# datetime.timedelta(0, 4694, 156337)


Note the output of this is a timedelta object. If this isn't the format your desire, you'll need to convert back to a string with additional logic.






share|improve this answer



















  • 1





    Thank you, that's exactly what I needed.

    – user3299633
    Nov 20 '18 at 21:48











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














You can use datetime.timedelta from the standard library:



from datetime import timedelta

L = ['0:06:50.137529', '0:08:55.439963', '0:06:19.179093',
'0:07:16.680906', '0:31:55.778010', '0:16:56.940836']

def str_to_td(x):
hrs, mins, sec_micro = x.split(':')
secs, msecs = map(int, sec_micro.split('.'))
return timedelta(hours=int(hrs), minutes=int(mins), seconds=secs, microseconds=msecs)

res = sum(map(str_to_td, L), timedelta())

# datetime.timedelta(0, 4694, 156337)


Note the output of this is a timedelta object. If this isn't the format your desire, you'll need to convert back to a string with additional logic.






share|improve this answer



















  • 1





    Thank you, that's exactly what I needed.

    – user3299633
    Nov 20 '18 at 21:48
















1














You can use datetime.timedelta from the standard library:



from datetime import timedelta

L = ['0:06:50.137529', '0:08:55.439963', '0:06:19.179093',
'0:07:16.680906', '0:31:55.778010', '0:16:56.940836']

def str_to_td(x):
hrs, mins, sec_micro = x.split(':')
secs, msecs = map(int, sec_micro.split('.'))
return timedelta(hours=int(hrs), minutes=int(mins), seconds=secs, microseconds=msecs)

res = sum(map(str_to_td, L), timedelta())

# datetime.timedelta(0, 4694, 156337)


Note the output of this is a timedelta object. If this isn't the format your desire, you'll need to convert back to a string with additional logic.






share|improve this answer



















  • 1





    Thank you, that's exactly what I needed.

    – user3299633
    Nov 20 '18 at 21:48














1












1








1







You can use datetime.timedelta from the standard library:



from datetime import timedelta

L = ['0:06:50.137529', '0:08:55.439963', '0:06:19.179093',
'0:07:16.680906', '0:31:55.778010', '0:16:56.940836']

def str_to_td(x):
hrs, mins, sec_micro = x.split(':')
secs, msecs = map(int, sec_micro.split('.'))
return timedelta(hours=int(hrs), minutes=int(mins), seconds=secs, microseconds=msecs)

res = sum(map(str_to_td, L), timedelta())

# datetime.timedelta(0, 4694, 156337)


Note the output of this is a timedelta object. If this isn't the format your desire, you'll need to convert back to a string with additional logic.






share|improve this answer













You can use datetime.timedelta from the standard library:



from datetime import timedelta

L = ['0:06:50.137529', '0:08:55.439963', '0:06:19.179093',
'0:07:16.680906', '0:31:55.778010', '0:16:56.940836']

def str_to_td(x):
hrs, mins, sec_micro = x.split(':')
secs, msecs = map(int, sec_micro.split('.'))
return timedelta(hours=int(hrs), minutes=int(mins), seconds=secs, microseconds=msecs)

res = sum(map(str_to_td, L), timedelta())

# datetime.timedelta(0, 4694, 156337)


Note the output of this is a timedelta object. If this isn't the format your desire, you'll need to convert back to a string with additional logic.







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 20 '18 at 21:43









jppjpp

101k2163112




101k2163112








  • 1





    Thank you, that's exactly what I needed.

    – user3299633
    Nov 20 '18 at 21:48














  • 1





    Thank you, that's exactly what I needed.

    – user3299633
    Nov 20 '18 at 21:48








1




1





Thank you, that's exactly what I needed.

– user3299633
Nov 20 '18 at 21:48





Thank you, that's exactly what I needed.

– user3299633
Nov 20 '18 at 21:48




















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