Decimal representation of the set [0,1)

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I have encountered the next statement in statistics lecture (translated from german):
"From the analysis
you know that all but a countable number of $$w ∈ [0, 1)$$ represent a unique decimal representation
$$ω = 0.x_1x_2x_3...$$
for the countably many exceptions we choose that representation without period 9
".
That sounds very counterintuitive and unprovable to me, is this true?










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  • $begingroup$
    "countable" means having the cardinality of $mathbb{N}$. in german: "abzählbar".
    $endgroup$
    – trancelocation
    Dec 4 '18 at 14:19










  • $begingroup$
    What exactly sounds counterintuitive and unprovable? The countability maybe?
    $endgroup$
    – drhab
    Dec 4 '18 at 14:21










  • $begingroup$
    @drhab José Carlos Santos answered my question below.
    $endgroup$
    – AromaTheLoop
    Dec 4 '18 at 17:56
















0












$begingroup$


I have encountered the next statement in statistics lecture (translated from german):
"From the analysis
you know that all but a countable number of $$w ∈ [0, 1)$$ represent a unique decimal representation
$$ω = 0.x_1x_2x_3...$$
for the countably many exceptions we choose that representation without period 9
".
That sounds very counterintuitive and unprovable to me, is this true?










share|cite|improve this question











$endgroup$












  • $begingroup$
    "countable" means having the cardinality of $mathbb{N}$. in german: "abzählbar".
    $endgroup$
    – trancelocation
    Dec 4 '18 at 14:19










  • $begingroup$
    What exactly sounds counterintuitive and unprovable? The countability maybe?
    $endgroup$
    – drhab
    Dec 4 '18 at 14:21










  • $begingroup$
    @drhab José Carlos Santos answered my question below.
    $endgroup$
    – AromaTheLoop
    Dec 4 '18 at 17:56














0












0








0





$begingroup$


I have encountered the next statement in statistics lecture (translated from german):
"From the analysis
you know that all but a countable number of $$w ∈ [0, 1)$$ represent a unique decimal representation
$$ω = 0.x_1x_2x_3...$$
for the countably many exceptions we choose that representation without period 9
".
That sounds very counterintuitive and unprovable to me, is this true?










share|cite|improve this question











$endgroup$




I have encountered the next statement in statistics lecture (translated from german):
"From the analysis
you know that all but a countable number of $$w ∈ [0, 1)$$ represent a unique decimal representation
$$ω = 0.x_1x_2x_3...$$
for the countably many exceptions we choose that representation without period 9
".
That sounds very counterintuitive and unprovable to me, is this true?







examples-counterexamples decimal-expansion






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share|cite|improve this question













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share|cite|improve this question








edited Dec 4 '18 at 14:26









José Carlos Santos

164k22131234




164k22131234










asked Dec 4 '18 at 14:15









AromaTheLoopAromaTheLoop

444




444












  • $begingroup$
    "countable" means having the cardinality of $mathbb{N}$. in german: "abzählbar".
    $endgroup$
    – trancelocation
    Dec 4 '18 at 14:19










  • $begingroup$
    What exactly sounds counterintuitive and unprovable? The countability maybe?
    $endgroup$
    – drhab
    Dec 4 '18 at 14:21










  • $begingroup$
    @drhab José Carlos Santos answered my question below.
    $endgroup$
    – AromaTheLoop
    Dec 4 '18 at 17:56


















  • $begingroup$
    "countable" means having the cardinality of $mathbb{N}$. in german: "abzählbar".
    $endgroup$
    – trancelocation
    Dec 4 '18 at 14:19










  • $begingroup$
    What exactly sounds counterintuitive and unprovable? The countability maybe?
    $endgroup$
    – drhab
    Dec 4 '18 at 14:21










  • $begingroup$
    @drhab José Carlos Santos answered my question below.
    $endgroup$
    – AromaTheLoop
    Dec 4 '18 at 17:56
















$begingroup$
"countable" means having the cardinality of $mathbb{N}$. in german: "abzählbar".
$endgroup$
– trancelocation
Dec 4 '18 at 14:19




$begingroup$
"countable" means having the cardinality of $mathbb{N}$. in german: "abzählbar".
$endgroup$
– trancelocation
Dec 4 '18 at 14:19












$begingroup$
What exactly sounds counterintuitive and unprovable? The countability maybe?
$endgroup$
– drhab
Dec 4 '18 at 14:21




$begingroup$
What exactly sounds counterintuitive and unprovable? The countability maybe?
$endgroup$
– drhab
Dec 4 '18 at 14:21












$begingroup$
@drhab José Carlos Santos answered my question below.
$endgroup$
– AromaTheLoop
Dec 4 '18 at 17:56




$begingroup$
@drhab José Carlos Santos answered my question below.
$endgroup$
– AromaTheLoop
Dec 4 '18 at 17:56










1 Answer
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This is true if “represent a” becomes “is represented by”. The exceptions are the numbers of $(0,1)$ which can be written with finitely many digits: $x=0.d_1d_2ldots d_{n-1}d_n$ (with $d_nin{1,2,3,4,5,6,7,8,9}$), because each such number can be also written as$$0.d_1d_2ldots d_{n-1}(d_n-1)999ldots$$For instance, $0.23=0.22999ldots$ All other numbers have a single decimal expansion.






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    $begingroup$

    This is true if “represent a” becomes “is represented by”. The exceptions are the numbers of $(0,1)$ which can be written with finitely many digits: $x=0.d_1d_2ldots d_{n-1}d_n$ (with $d_nin{1,2,3,4,5,6,7,8,9}$), because each such number can be also written as$$0.d_1d_2ldots d_{n-1}(d_n-1)999ldots$$For instance, $0.23=0.22999ldots$ All other numbers have a single decimal expansion.






    share|cite|improve this answer









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      0












      $begingroup$

      This is true if “represent a” becomes “is represented by”. The exceptions are the numbers of $(0,1)$ which can be written with finitely many digits: $x=0.d_1d_2ldots d_{n-1}d_n$ (with $d_nin{1,2,3,4,5,6,7,8,9}$), because each such number can be also written as$$0.d_1d_2ldots d_{n-1}(d_n-1)999ldots$$For instance, $0.23=0.22999ldots$ All other numbers have a single decimal expansion.






      share|cite|improve this answer









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        $begingroup$

        This is true if “represent a” becomes “is represented by”. The exceptions are the numbers of $(0,1)$ which can be written with finitely many digits: $x=0.d_1d_2ldots d_{n-1}d_n$ (with $d_nin{1,2,3,4,5,6,7,8,9}$), because each such number can be also written as$$0.d_1d_2ldots d_{n-1}(d_n-1)999ldots$$For instance, $0.23=0.22999ldots$ All other numbers have a single decimal expansion.






        share|cite|improve this answer









        $endgroup$



        This is true if “represent a” becomes “is represented by”. The exceptions are the numbers of $(0,1)$ which can be written with finitely many digits: $x=0.d_1d_2ldots d_{n-1}d_n$ (with $d_nin{1,2,3,4,5,6,7,8,9}$), because each such number can be also written as$$0.d_1d_2ldots d_{n-1}(d_n-1)999ldots$$For instance, $0.23=0.22999ldots$ All other numbers have a single decimal expansion.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Dec 4 '18 at 14:25









        José Carlos SantosJosé Carlos Santos

        164k22131234




        164k22131234






























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